Yes, but only up to a certain height since the corner cube maintains the angle of the light's incidence. No, as any position of a corner cube sends the beam back to the window. Yes, the beam is parallel to itself when the cube travels slightly.
What are corner cubes and how do they function?An optical element having the exceptional capability of returning an entering beam of light straight at its place of origin irrespective of the beam's angle of entry is a corner cube, often called as a retroreflector.
A corners cube retroreflector (CCR) is what, exactly?Three adjacent, mutually orthogonal plane-reflecting surfaces make up a corner cube retroreflector, also called as a CCR or trihedral prism, which is an optical structure an angle of a cube. Independent of the prism, the corner cube returns an incident ray at a certain angle.
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A circular loop of wire with a radius of 13.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.5 T is directed along the positive z-direction, which is upward.part.aIf the loop is removed from the field region in a time interval of 2.7 msms , find the average emf that will be induced in the wire loop during the extraction process.
A circular loop of wire with a radius of 13.0 cm and oriented in the horizontal XY-plane is located in a region of the uniform magnetic field. A field of 1.7 T is directed along the positive z-direction, which is upward. A) If the loop is removed from the field region in a time interval of 2.9 ms,
The average emf that will be induced in the wire loop during the extraction process=
e =(pi) r^2B/t
e = pi*169*10^-4*1.7/(2.9*10^-3) = 31.12 V
In classical geometry, a radius of a circle or sphere is any of the line segments from its middle to its perimeter, and in greater present-day usage, it is also their length. The call comes from the latin radius, which means ray but additionally, the spoke of a chariot wheel.
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When wind speeds up as it blows over the top of a hill, atmospheric pressure there.
When wind speeds up as it blows over the top of a hill, atmospheric pressure there increases.
Atmospheric pressure is defined as the force per unit area exerted against a surface by the weight of the air molecules above the earth surface.The atmospheric pressure is not distributed uniformly over the earth. The amount of pressure increases or decreases, according to the amount of molecules, that exerts the force on the surface.When temperature of the air increases, the air expands and reduces the number of molecules over the unit area. It leads to reduction in pressure.Similarly, when the temperature falls, the air contracts and the pressure increase. Therefore, the temperature and atmospheric pressure are inversely related.
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What is the voltage drop across resistors r2 in volts
The voltage drop across resistors r2 in volts is 6.6 volts.
What is resistor?Resistor is defined as an electrical component that regulates voltage and temperature. Resistors are frequently employed in electronic circuits to reduce current flow, divide voltages, impede transmission signals, and bias active parts. The resistor controls the electron flow to prevent overly rapid current from damaging the breadboard, wires, battery,
The Voltage drop can be calculated as
Give voltage of battery = 113 V
R2 has current = 1.9 A
And resistance = 4.7 ohms
Voltage = 1.9 + 4.7
= 6.6 V
Thus, the voltage drop across resistors r2 in volts is 6.6 volts.
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he mass of a bugatti veyron car is 1834 kg. the shape of the car is such that the aerodynamic drag coefficient c is 0.342 kg/m for quatratic drag. neglecting all other sources of friction, calculate the maximum speed in m/s if the veyron's engine can impart a force of 4522 n on the road.
To calculate the maximum speed of the Bugatti Veyron, we can use the equation $F_d = \frac{1}{2} \rho v^2 c A$,
which relates the drag force $F_d$ acting on an object to the density of the fluid $\rho$, the speed $v$ of the object, the drag coefficient $c$, and the cross-sectional area $A$ of the object.
In this case, we are given the mass of the car, the drag coefficient, and the force that the engine can impart on the road, so we can solve for the maximum speed.
First, we need to convert the mass of the car to its weight, which is the force of gravity acting on the car. The weight of the car is given by the equation $W = mg$, where $m$ is the mass of the car and $g$ is the acceleration due to gravity.
We can convert the mass of the car from kilograms to newtons by multiplying it by $g$, which is approximately 9.8 m/s$^2$. This gives us a weight of $W = 1834 \text{ kg} \times 9.8 \text{ m/s}^2 = 17983.2 \text{ N}$.
Next, we need to calculate the cross-sectional area of the car. Since we are given the shape of the car and the drag coefficient, we can assume that the car has a streamlined shape with a length $L$ that is much greater than its width or height.
In this case, the cross-sectional area of the car is approximately equal to its width $w$ times its height $h$, or $A \approx wh$. If we assume that the width of the car is $w = 1.8$ meters and the height is $h = 1.2$ meters, then the cross-sectional area is $A \approx 2.16 \text{ m}^2$.
Now that we have all of the required information, we can solve for the maximum speed of the car. The maximum speed is achieved when the drag force acting on the car is equal to the force that the engine can impart on the road. This means that the maximum speed $v_\text{max}$ is given by the equation
$$F_d = \frac{1}{2} \rho v_\text{max}^2 c A = F_\text{engine}$$
where $\rho$ is the density of the air, $c$ is the drag coefficient, $A$ is the cross-sectional area of the car, and $F_\text{engine}$ is the maximum force that the engine can impart on the road.
We are given that the drag coefficient is 0.342 kg/m and the maximum force that the engine can impart on the road is 4522 N. The density of the air is approximately 1.225 kg/m$^3$ at sea level. Plugging these values into the equation, we get
$$\frac{1}{2} \times 1.225 \text{ kg/m}^3 \times v_\text{max}^2 \times 0.342 \text{ kg/m} \times 2.16 \text{ m}^2 = 4522 \text{ N}$$
Solving for the maximum speed, we get $v_\text{max} \approx 242.5$ m/s. This is the maximum speed of the Bugatti Veyron if we neglect all other sources of friction and assume that the car has a streamlined.
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A wooden loop and a wire loop, both with the same shape and size, are placed next to the north poles of identical magnets. Then, the loops are moved closer to and farther from the magnets in exactly the same way. The emf generated around the wooden loop is zero. O less than the emf generated around the wire loop. equal to the emf generated around the wire loop. O greater than the emf generated around the wire loop.
The emf created around the wooden loop is equivalent to the emf generated around the wire loop if the loops are moved precisely the same distance from and closer to the magnets.
Give an explanation about EMF.
The electric potential created by either modifying the magnetic field or by an electrochemical cell is known as electromotive force (emf).
Due to the fact that Faraday's law is independent of the material and only considers how the flux is changing, the emf produced around the wooden loop is equivalent to the emf produced around the wire loop. Due to the fact that the loop material moves close to the end of the bar magnet, modifying the magnetic flux through the loop, even though it is not a part of the magnetic flux expression, an emf is nevertheless produced.
Hence, the answer is the emf created around the wooden loop is equivalent to the emf generated around the wire loop if the loops are moved precisely the same distance from and closer to the magnets.
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your friend is 1.7 m tall. (a) when she stands 3.2 m from you, what is the height of her image formed on the retina of your eye? (consider the eye to consist of a thin lens 2.5 cm from the retina.) (b) what is the height of her image when she is 4.2 m from you?
(a) Formulae for magnification (m) = distance of image/image of object
=.025/3.2 = 0.00781
so, magnification of eye = 0.00781
now. m = image size / actual size
so, image size = actual size x m
= 1.7 x 0.00781
= 0.0132 m
(b) similarly, in this case the size of the image can be calculated as follows:
m = distance of image/image of object = 0.00595
image size = actual size x m = 0.0101
What is magnification?
Magnification in physics can be defined as the ratio of size of the image to the size of the object. Magnification in simple terms means enlargement in the size of the image of an object.
It can be denoted by the formulae:
[tex]magnification = \frac{size of the image}{size of the object}[/tex]
It has no SI unit.
Why Magnification has no SI unit?
It has no SI unit because it is a ratio of length.
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with what initial velocity must an object be thrown upward from ground level to reach the top of the washington monument
Beginning velocity is required for a projectile to be launched from the ground up to the Washington Monument's 555-feet summit.
The Washington Monument is 555 feet 5 inches tall, so why?Casey was convinced to make the height of the tower 10 times the width of the base, which meant that the Washington Monument's ideal height was 555 feet rather than the 600 feet that Mills had originally envisioned.
The Washington Monument is not a memorial, so why?When compared to a memorial, why is the Washington Monument a "monument"? A memorial honors or pays tribute to a person who has passed away. A monument has a crucial distinction: it is created to honor or remember a living person.
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Light having a wavelength in vacuum of 600 nm enters a liquid of refractive index 2. 0. In this liquid, its wavelength will be
The frequency is 5 x 10^14 Hz, the speed of light in the medium is 2 x 10 m/s and the wavelength is
4 x 10^-7 m
Given that,
Wavelength X = 600 nm
Refractive index n = 1.5
We know that,
The frequency is the ratio of the speed of light and wavelength of the light.
f = c/λ
f = 3 x 10^8/600 × 10^-9
f = 5 x 10^14 Hz
The speed in the medium is the ratio of the speed of the light in the vacuum and the refractive index.
n = c/v
1.5 = 3 x 10^8/υ
v = 2 × 10^8 m/s
The wave length is the ratio of the speed of the light in the medium and frequency.
λ = v/f
λ = 2 × 10^8/5 x 10^14
λ = 4 × 10^-7 m
Hence, The frequency is 5 x 10^14 Hz, the speed of light in the medium is 2 x 10^8 m/s and the wavelength is 4 x 10^-7 m
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a cannon sits on a stationary railroad flatcar with a mass of 1000 kg. when a 10-kg cannonball is fired to the left at a speed of 50 m/s, what is the recoil speed of the flatcar? the recoil speed of the flatcar is m/s.
The recoil speed of the flatcar is0.5 m/s.
Step by Step Explanation:The cannon's momentum equals the flatcar's momentum according to Newton's third law of motion.
mv = MV........................ Equation 1:
where m is the cannon's mass, v is its velocity, and m is the flatcar's mass, v is its velocity.
Assign V as the subject of the equation V = mv/M... Equation 2
Given: M = 1000 kg
m = 10 kg,
and v = 50 m/s
Replace with V = 1050/1000 V = 500/1000
V = 0.5 m/s in equation 2.
Consequently, the flatcar's speed is equal to 0.5 meters per second.
What is Newton's Third Law of Momentum?An object interacts with another object when a push or pull is applied to it. A product of an interaction is force. Frictional force, for example, falls into the category of contact force. Non-contact force, on the other hand, includes gravitational force. Newton's third rule of motion explains that when two bodies interact, they exert force on one another. This force is referred to as an action and reaction pair.According to Newton's third law of motion,The first body receives a force that is equivalent in magnitude to the force applied in the opposite direction when one body exerts a force on another.To learn more about Newton's Third Law of Momentum refer to:
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An elastic cord is 61 cm long when a weight of 75 N hangs from it but is 85 cm long when a weight of 210 N hangs from it. What is the "spring" constant k of this elastic cord? also, find the frequency of the motion with the 210N object hanging on it (Physics 'Algebra base')
The spring constant of this elastic cord is 562.64 Nm.The frequency of the motion with the 210 N is 0.817Hz.
Elastic cord is a fairly versatile stretchy rope. it is small diameter makes it ideal for indoor craft makes use of and light duty strapping. Use this elastic string for sewing initiatives, scrapbooking, and kids' crafts.
Calculation:-
Spring constant K = f/x
= 75/0.61 - L
= 75/0.61 - 0.4767
= 562.64 Nm
Frequency when 210 N is hanging is
extension X = 0.85 -L
= 0.87 - 0.4767
= 0.3733
Frequency = 1/2π√g/X
= 1/2π √9.8/0.3733
= 0.816 Hz.
The free movement of a frame with appreciate to time is called motion. for example-the fan, the dirt falling from the carpet, the water that flows from the tap, a ball rolling around, a shifting car etc. Even the universe is in chronic motion.
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metallic bonding occurs when a. a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction b. positive metallic ions are bonded with delocalized free electrons. c. the negative side of one molecule bonds with the positive side of a neighboring molecule d. two metallic atoms share electrons in their outer valence shells
The answer is A. Metallic bonding occurs when a negative metallic ion is attracted to a positive metallic ion through electrostatic attraction
Metallic bonds are formed when the charge is spread over a larger distance than the size of single atoms in solids. Metallic bonding is a chemical bonding that arises from the attractive electrostatic force between conduction electrons (in the form of an electron cloud of delocalized electrons) and positively charged metal ions. It may be described as the sharing of free electrons among a structure of positively charged ions (cations). Metallic bonding is not the only type of chemical bonding a metal can exhibit, even as a pure substance.
Metallic bonding occurs when you have a metal in a solid or liquid state. The s and p valence electrons of metals are loosely held. They leave their “own” metal atoms. This forms a "sea" of electrons that surrounds the metal cations. The electrons are free to move throughout this electron sea. A strong metallic bond will be the result of more delocalized electrons, which causes the effective nuclear charge on electrons on the cation to increase, in effect making the size of the cation smaller.
Metallic bonds are strong and require a great deal of energy to break, and therefore metals have high melting and boiling points. A metallic bonding theory must explain how so much bonding can occur with such few electrons (since metals are located on the left side of the periodic table and do not have many electrons in their valence shells). The theory must also account for all of a metal's unique chemical and physical properties.
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an ideal gas is compressed from 900 cm3 to 425 cm3 while 125 j of heat energy is removed from it. if the gas's pressure remains constant at 400 kpa during the compression, how much work was done by the gas?
The work done by the gas is 190,000 J.
What is work?
Work in physics is the energy that is transferred to or from a object when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that moves the point of application, or it is said to have positive work. If the component of a force at the point of application is in the opposite direction of the displacement, the force is said to do negative work.
The work done by the gas can be calculated using the equation W = P∆V. In this equation, P represents the constant pressure of 400 kPa, ∆V is the change in volume, and W is the work done by the gas.
Since the volume of the gas changed from 900 cm3 to 425 cm3, the change in volume is ∆V = 900 cm3 - 425 cm3 = 475 cm3. Plugging this into the equation above, we get W = 400 kPa x 475 cm3 = 190,000 J.
Therefore, the work done by the gas is 190,000 J.
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A lever requires an energy input of 10,000 J to move a 35 kg box up a distance of 18 m. What is the efficiency of this lever?
The efficiency of the lever will be 62%
What is Efficiency?Efficiency is the ratio of the work performed by a machine to the total energy expended or heat consumed.
Efficiency refers to how close we can get to a particular outcome of the given input with as much less wastage as possible. Efficiency is the ability to minimise wasting materials, efforts, energy and time in performing something or producing the desired result.
The ratio of energy transferred to a useful form compared to the total energy supplied initially is called the efficiency of the device.
Efficiency (%) = (work output/work input) x 100%
work output = mgh
work input = 10,000J
Efficiency (%) = (35 x 18 x 9.8/10,000) x 100
Efficiency (%) = 0.62 x 100
Efficiency (%) = 62%
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v high - speed stroboscopic photographs show that the head of a 2.00 3 102 - g golf club is traveling at 55.0 m/s just before it strikes a 46.0 - g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40.0 m/s. find the speed of the golf ball just after impact.
Velocity of golf ball after collision with golf club using law of conservation of momentum is 65.21 m/s
What is momentum ?
Momentum seem to be directly dependent on the value of mass as well as velocity of the object in the direction of motion. it is quantified by "mass velocity". Since mass is a scalar quantity but velocity is a vector, momentum is a vector quantity.
From the given information-
mass of golf club = 200 g
mass golf ball = 46 g
velocity of club before collision = 55 m/s
velocity club after collision =40 m/s
velocity of golf ball before collision = 0 m/s
You need to use conservation of momentum here.
momentum = mass x velocity
Prior to impact, the golf club has a momentum of 0.200 kg * 55 m/s = 11.00 kg m/s.
The ball's not moving before impact, so it has a momentum of zero. Therefore the total momentum before impact will be 11.00 kg m/s. Conservation of momentum dictates the total momentum of the two objects after impact will also be 11.00 kg m/s.
We know the speed of the club after the impact, so the momentum of the club after impqact is 0.200 kg * 40 m/s =8 kg m/s.
So the momentum of the ball must be 11.00 kg m/s - 8 kg m/s = 3 kg m/s, and dividing by the mass of the ball (0.046 kg) gives the speed of the ball, 65.217 m/s
Velocity of golf ball after collision wit golf club is 65.21 m/s
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while checking out the front end of a vehicle, the technician grabs the driver’s side tire and steers the wheels manually left and right. while he does this, he notices that the center link moves up and down. what component is most likely at fault?
The worn idler arm is the component that is most likely at fault.
What occurs when a wheel hits a dip or home and moves downward?
When you hit any bump or dip in a road, your vehicle's suspension and springs move so the tire can stay in contact with the road and absorb the energy. The shock absorbers dampen the movement of the springs by converting the spring's kinetic energy into thermal (heat) energy.
What are the symptoms of a bad idler arm?
What are the warning signs of a bad idler arm? If you notice your steering wheel feels loose or has extra play before the tires respond, this may be a sign of an issue with your idler arm or pitman's arm. If these arms fail completely, you will lose all steering in your vehicle.
Can a worn idler arms cause play?
A steering wheel with too much play that shimmies, shakes, or vibrates too loosely can be a symptom of a bad idler arm. Poor steering likely means the ball joints are worn.
How important is an idler arm?
Idler's arms are particularly important for two reasons. First, as mentioned, the idler arm supports the right end of the track rod. Without it, the track rod would not hold the right wheel in place or turn it effectively, if at all. Second, the idler arm maintains proper toe angle.
Thus, a worn idler arm is a correct answer.
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A car is moving east at 28.8 m/s before applying it’s breaks. The car comes to a stop after 74 meters. How long does it take for the car to stop?
Answer:
Below
Explanation:
AVERAGE velocity = ( 28.8 - 0 ) / 2 = 14.4 m/s
74 m / 14.4 m/s = 5.14 s
how much force should be applied on the piston (radius 0.012 meter ) so that a car of 1500 kg is completely supported by a piston of radius 0.15 meter.
Answer:
Force = 93 N
Explanation:
Given:
m₁ = 1500 kg
R₁ = 0.15 m
R₂ = 0.012 m
g = 9.8 m/s²
_____________
F₂ - ?
1)
Piston area:
S₁ = π·R₁² = 3.14·0.15² ≈ 71·10⁻³ m²
S₂ = π·R₂² = 3.14·0.012² ≈ 0.45·10⁻³ m²
2)
Force:
F₁ = m₁·g = 1500·9.8 = 14 700 N
F₂ = F₁· (S₂ / S₁)
F₂ = 14 700· (0.45·10⁻³ / (71·10⁻³) ≈ 93 N
An automobile moves on a level horizontal road in a circle of radius 30 m. The coefficient of friction between tires and road is 0. 50. The maximum speed with which this car can round this curve is:.
The maximum speed with which the car can round the curve is 12.1 m/s
What is Frictional force ?The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
The force produced between surfaces that slide against one another is known as the frictional force. Because frictional force develops when two surfaces come into contact with one another, it is referred to be a contact force. Walking on the road is an illustration of frictional force.
According to the given information
radius, [tex]$r=30 \mathrm{~m}$[/tex]
coefficient of friction, [tex]$\mu_k=0.50$[/tex]
Here friction : force will balance centripetal force.
[tex]$\begin{aligned} &\left(F_k=\text { Friction force })\right. \\ & F_k=\frac{m v^2}{r} \\ & \mu m_g=\frac{m v^2}{r} \\ & \mu g=\frac{v^2}{r} \\ & v^2=r \mu g=30 \times 0.5 \times 9.8 \\ & v=12.1 \mathrm{~m} / \mathrm{s}\end{aligned}$[/tex]
The maximum speed with which the car can round the curve is 12.1 m/s
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A force of 1.0 x 104 n is exerted on a 50 g bullet throughout the 10 cm length of a gun barrel. how much work was done on the bullet? how much ke did the bullet have when it left the gun barrel? what was the speed of the bullet when it left the gun barrel?
The kinetic energy of the bullet when it left the gun barrel is 1000J.
We know that ,
K.E. = F d
where, K.E. = kinetic energy
F = force
d = distance
Given, F = 1* 10^4 N
d = 10cm = 0.1 m
Putting these values in above equation we get,
K.E. = 1000J
So the kinetic energy of the bullet when it left the gun barrel is 1000J.
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a fluid flows through a horizontal pipe of radius 1.5 cm at a speed of 5.0 m/s. the density of the fluid is 900 kg/m3 and the pressure is 1.30 x 105 n/m2. when the fluid flows into a connecting pipe of radius 1.0 cm, the speed is increases to 11.0 m/s. what is the pressure in the connecting pipe in pa?
The pressure in the connecting pipe is 88 pa.
Stress is the pressure applied perpendicular to the floor of an object according to unit place over which that force is sent. Gauge strain is the strain relative to the ambient pressure. diverse gadgets are used to explicit strain.
Calculation:-
radius of pipe = 1.5 cm
speed = 5 m/s
The speed is increases to 11.0 m/s
density of the fluid = 900 kg kg/m³
Pressure = 1.30 × 10⁵ N/m²
The pressure in the connecting pipe in pa = ρdv/dl
= 88 pa.
Stress is defined because the bodily pressure exerted on an item. The force applied is perpendicular to the surface of objects in step with unit place. The primary components for strain is F/A (force in keeping with unit location). Unit of pressure is Pascals (Pa). forms of Pressures are Absolute, Atmospheric, Differential, and Gauge pressure.
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if quasars are at the distances most astronomers believe they are, then (for the most luminous ones) their luminosities must be:
If quasars are located at the distances that the majority of astronomers think they are, then their luminosities must equal the sum of one hundred trillion (1014) Suns.
What kind of brilliance is that?Something's luminosity is determined by how much light it emits or reflects. A big, sparkling diamond's brightness is its most distinguishing feature. You might talk about the luminosity of an energetic and vibrant oil painting or be in awe of the luminosity of a spectacular sunset.
Does light improve intelligence?Small (2–3 point) training benefits are obtained via lumosity training. If you exercise for 12 and a half hours over several weeks, you can enhance your IQ, working memory, and other cognitive abilities by about 2-3 points.
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Keiko is riding a skateboard 2 m/s, west. How long will it take her to reach a velocity of 8 m/s, west if her acceleration is 2 m/s2?By definition, acceleration is the measure of a velocity change in time. In a particular case when the acceleration is constant, the velocity of an object is changed uniformly (linearly) with time.
If we denote the initial velocity as V_0, the constant acceleration as a and the time since the initial moment as t, then the new speed V at time t will be
V=V_0+at.
In our problem the velocities and the acceleration are given, and we need to solve the above equation for t. It is simple:
t=(V-V_0)/a=(8-2)/2=3(s).This is the answer. Note that it is important that the initial velocity and the final velocity have the same direction (west). If they would have opposite direction, one of them should be taken with a minus sign, and the acceleration might be negative.
The time taken to reach a velocity of 8 m/s, west if her acceleration is 2 m/s is 3 seconds
Given,
Velocity of Keiko's skateboard = 2 m/s
Velocity to reach = 8 m/s
Acceleration = 2 m/s²
Velocity is known to be the total displacement that occurred in a particular given time.
It is a vector quantity that has both magnitude and direction.
By the 1st equation of motion regarding velocities,
v = u + at ...........(1)
where,
v = final velocity = 8 m/s
u = initial velocity = 2 m/s
t = time = ?
a = acceleration = 2 m/s²
Now put all the given values in the above equation 1, we get:
8 m/s = 2m/s + (2 m/s²)t
t = 3 seconds
Therefore, using the velocities, we got the the time taken will be 3 seconds.
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To make the pattern bigger and easier to see, should you move the slide closer tothe screen or closer to the laser? Explain. Be sure to comment on what variableschange (e.g. wavelength, angles to the minima, distance to the screen, position ofthe minima, etc.)
So, by moving the slit towards the laser will increase the slit and screen distance and the screen and the fringe will be bigger, angle of diffraction, wavelength will remain unaltered in this case
What is diffraction?
When waves flow through an aperture or around objects, they spread out, which is referred to as diffraction. It happens when the wavelength of the incident wave and the size of the aperture or obstruction are on the same order of magnitude. The majority of the wave is blocked at extremely small aperture diameters. Large apertures prevent severe diffraction from occurring as the wave passes past or through the obstruction.
What is wavelength?
Wavelength is the separation between the corresponding points of two successive waves. When two points or particles are referred to be "corresponding points," it means that they are both in the same phase means, points that have completed identical fractions of their periodic motion.
Hence, by moving the slit towards the laser will increase the slit and screen distance, and the screen and the fringe will be bigger, angle of diffraction, wavelength will remain unaltered in this case.
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g two pool balls, each moving at 2 m/s, roll toward each other and collide. suppose after bouncing apart, each moves at 2 m/s. assume the positive direction is to the right. this collision violates conservation of group of answer choices kinetic energy momentum both kinetic and momentum none of the above
This collision violates conservation of both energy and momentum i.e, third option is correct.
According to the law of conservation of momentum, when two bodies collide their total momentum and energy before and after collision are equal.
According to the law of conservation of energy, energy can neither be created nor destroyed. However, it can be transformed from one form to another. It is also known as the first law of thermodynamics.
Given that, the two bodies move with same velocities after collision, means that the law has not been violated since, momentum = mass*velocity (where mass is said to be constant)
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What is the maximum speed at which a car can safely travel around a circular track of radius 55. 0 m if the coefficient of friction between the tire and road is 0. 350?.
The maximum speed at which a car can safely travel around a circular track of radius 55. 0 m is 10.84 m/s
What does it imply to speak of centripetal forces?Any object is drawn toward the center of a curved surface by a centripetal force. Imagine that you are a yo-yo being spun. The yo-yo is set in motion by your arm movement, and as you twirl it, the tension of the string keeps it spinning.
Given : r=30 m
μ=0.4
g=9.8m/s
2The maximum speed
v max =μgr= 0.4×9.8×30 =10.84 m/s
How would you describe centripetal force to a young person?A force known as centripetal force keeps things moving in a circular motion. The object will keep rotating in a circle as long as the centripetal force persists and all other forces are equally balanced. One object that moves in a circle as a result of centripetal force is a yo-yo.
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another pendulum swings to and fro at a regular rate of 2 times per second. what is its period? (in s)
Five times per second is the typical frequency at which another pendulum swings back and forth. 2S
Describe the pendulum ?The back-and-forth motion of a pendulum can be used to demonstrate how potential energy transforms into kinetic energy and vice versa.Another pendulum swings back and forth with a normal frequency of five times per second. 2SThe formula for the period is T = t N.Time it takes for things to happen. Number of occurrences tAn oscillation of a pendulum takes a certain amount of time, or simply "period," to complete.It is obvious that the pendulum's mass or weight have nothing to do with the time period.To learn more about pendulum refer to:
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to date, we've found few planets orbiting their stars at distances comparable to the distances of the jovian planets in our solar system. why do astronomers think this is the case?
The answer is (b), meaning that we haven't been looking for planets so at distances for long enough.
What are the definitions of the 12 planets?(Astronomy) The solar system is made up of the sun and the objects gravitationally attracted to it, such as the planets Mercury, Venus, Mars, Mars, Octavian, Saturn, Uranus, and Neptune, as well as the minor planets Eris, Pluto, and Ceres.
What are the planets' roles?The world sustains us and gives us the resources we require. Last but not least, experts claim that if our planet disappeared, we and everything else on the world would have died. The one and only planet capable of supporting life is Earth.
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what is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at 8.00 cm? take the lens-to-retina distance to be 2.00 cm.
Given details :
a) For this exercise we use the equation for thin lenses
1 / f = 1 / p + 1 / q
where f is the focal length, p the distance to the object and q the distance to the image
In this case q is the distance from the lens to the retina q = 2.00 cmThe distance p is the distance from the object to the lens p = 8.00 cm1 / f = 1 / 8.00 + 1/2
1 / f = 0.625 cm⁻¹
power is the inverse of the focal length in meters
P = 1 / f [m]
P = 0.625
P = 62.5 diopter
b) the size of the image
m = - p / q
m = - 2 / 8.00
m = -0.25 X
if we assume that the object is right
m = h´ / h
h´ = m h
h´ = -0.25 x 2
h´ = -0.5 mm
if the height of the object h is straight the image and inverted
c) if the object were at p = 25.0 cm
m = - 2/25
m = -0.08
h´ = -0.08 x 2
h´ = -0.16 mm
the image would be much smaller
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if a pendulum-driven clock gains 7.2 s/day, what fractional change in pendulum length must be made for it to keep perfect time?
Pendulum length must be made for it to keep perfect time of 100 or 0.0167 % or 0.017 % nearly.
What is time?Time is the measure of to non-stop, consistent change by in our surroundings, or it is usually from a specific to viewpoint.
Total number of seconds in a normal day is 24×60×60 = 86400 seconds
We know that time period of pendulum is
T= 2π √l/g
Then we use fractional error method
∆T/T = 1/2 ( ∆l /l )
Here l is length of pendulum string
So 7.2/86400 = 1/2 ( ∆l/l)
∆l/l = 0.000167
So percentage change is
∆l/l *100 or 0.0167 % or 0.017 % nearly.
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step 2 of 2 : suppose a sample of 1350 floppy disks is drawn. of these disks, 67 were defective. using the data, construct the 85% confidence interval for the population proportion of disks which are defective. round your answers to three decimal places.
The 85% confidence interval estimate of the true population proportion of disks which are defective is 0.100 +/- 0.010
= (0.095, 0.110),Lower: 0.095 ,Upper: 0.110
Confidence intervals are a set of values with a known probability that the value of a parameter will fall within them.
The confidence interval of statistical data can be written as.
p+/-z√(p(1-p)/n)
We are given that,
Proportion of disks that are not defective = p' = 1283/1475 = 0.950
Proportion of disks that are defective = p = 1 - p' = 1 - 0.950 = 0.05
Thus , p = 0.05
Number of samples= n = 1350
Confidence interval = 85%
z value(at 85% confidence) = 1.28
Substituting the values we have;
0.100 +/- 1.28√(0.100(1-0.05)/1350)
0.100 +/- 1.28(0.00703703)
0.100 +/- 0.0090073984
0.100 +/- 0.010
= (0.095, 0.110)
According to the 85% confidence interval, the actual population percentage of defective discs is 0.100 +/- 0.010
Therefore, interval = (0.095, 0.110), Lower: 0.095, Upper: 0.110 can be used to describe the population portion.
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