Integrating sums of functions

Integrating Sums Of Functions

Answers

Answer 1

Answer:

(a) -12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Calculus

Integrals

Integration Rule [Reverse Power Rule]:                                                                    [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Swapping Limits]:                                                                [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = -\int\limits^a_b {f(x)} \, dx[/tex]

Integration Property [Multiplied Constant]:                                                           [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                         [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Property [Splitting Integral]:                                                                [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                      [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]  

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int\limits^6_4 {f(x)} \, dx = 5[/tex]

[tex]\displaystyle \int\limits^4_{10} {f(x)} \, dx = 8[/tex]

[tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx[/tex]

Step 2: Solve Pt. 1

[Integral] Rewrite [Integration Property - Addition]:                                     [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = \int\limits^{10}_6 {4f(x)} \, dx + \int\limits^{10}_6 {10} \, dx[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]:                   [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4\int\limits^{10}_6 {f(x)} \, dx + 10\int\limits^{10}_6 {} \, dx[/tex]

Step 3: Redefine

Manipulate the given integral values.

[Integrals] Combine [Integration Property - Splitting Integral]:                     [tex]\displaystyle \int\limits^6_4 {f(x)} \, dx + \int\limits^4_{10} {f(x)} \, dx = \int\limits^6_{10} {f(x)} \, dx[/tex][Integral] Rewrite:                                                                                           [tex]\displaystyle \int\limits^6_{10} {f(x)} \, dx = \int\limits^6_4 {f(x)} \, dx + \int\limits^4_{10} {f(x)} \, dx[/tex][Integral] Substitute in integrals:                                                                    [tex]\displaystyle \int\limits^6_{10} {f(x)} \, dx = 5 + 8[/tex][Integral] Add:                                                                                                 [tex]\displaystyle \int\limits^6_{10} {f(x)} \, dx = 13[/tex][Integral] Rewrite [Integration Property - Swapping Limits]:                        [tex]\displaystyle -\int\limits^{10}_6 {f(x)} \, dx = 13[/tex][Integral] [Division Property of Equality] Isolate integral:                             [tex]\displaystyle \int\limits^{10}_6 {f(x)} \, dx = -13[/tex]

Step 4: Solve Pt. 2

[Integral] Substitute in integral:                                                                     [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10\int\limits^{10}_6 {} \, dx[/tex][Integral] Integrate [Integration Rule - Reverse Power Rule]:                      [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10(x) \bigg| \limits^{10}_6[/tex][Integral] Evaluate [Integration Rule - FTC 1]:                                               [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10(10 - 6)[/tex][Integral] (Parenthesis) Subtract:                                                                   [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = 4(-13) + 10(4)[/tex][Integral] Multiply:                                                                                           [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = -52 + 40[/tex][Integral] Add:                                                                                                 [tex]\displaystyle \int\limits^{10}_6 {[4f(x) + 10]} \, dx = -12[/tex]

Topic: AP Calculus AB/BC

Unit: Integration

Book: College Calculus 10e


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The transformations are ...

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