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Data & Statistics REQ ACTIVITY
Question 10
10 pts
10. Mrs. Hamilton tallies her students test grades in
the table below. What percent of the class received an
A or a B?
GRADE
TALLY
A
B
с
NNI INI
F
F.4%
G. 12%
H. 30%
J. 40%

Answer:

A single outlier does not affect the values of the quartiles.

Step-by-step explanation:

It is given that data are collected for each band member that spends time on practicing in minutes.

We know that the interquartile range is defined as [tex]$\text{the difference between the upper quartile,}$[/tex] [tex]Q_3[/tex] and the lower quartile, [tex]Q_1[/tex].

This interquartile range describes the middle i.e. the 50 percent of the values when it is ordered from the lowest to the highest or may be from the highest value to the lowest values.

Therefore, the IQR is considered to be a better measure of the spread then the range since the values are not affected by the outliers.

Therefore, we see that the single outlier does not affect the values of the quartiles, it does not change the lower quartile as well as the upper quartiles.

Answer:

Hello! Your answer would be, 400

Step-by-step explanation:

Hope I helped! Ask me anything if you have questions! Brainiest plz. Hope You make a 100%! Have a nice day! -Amelia♥

Answer:64.88

Step-by-step explanation:

1000==35

249 times 0.12=29.88

29.88+25=64.88

Answer:

Below

Step-by-step explanation:

First, find the difference. You would do

-19 - (-9) = -10

-9 - 1 = -10 and so on...

The difference is -10

Now you need to find what number will make 11 when added to -10.

11 - (-10) = 21

The equation:

y = -10x + 21

Answer:

#2 64, 79, 95, 83, 81, 90, 67, 86, 91, 84, 81, 69, 83, 92

Step-by-step explanation:

A stem-and-leaf plot is a detailed graphical presentation of quantitative data on special kind of table that promotes visualizing the individual numbers in the data with the number at the stem being the first digits of the numbers in the data set while the leaf represent the last digit of each number in the data set

Following the above rule, the data in the given stem-and-leaf plot are;

64, 67, 69, 79, 81, 81, 83, 83, 84, 86, 90, 91, 92, 95

Therefore, the set of data that could have been used to create the stem-and-leaf plot is the data set that has all the numbers in the given stem-and-leaf plot which is the data set;

64, 79, 95, 83, 81, 90, 67, 86, 91, 84, 81, 69, 83, 92.

Answer:

C

Step-by-step explanation:

I hope it helps !!! :)

Answer:

i believe its b but i may be wrong i don know. hope this helped

Step-by-step explanation:

Answer:

To find the left triangle we make the two right triangles equal 1 square, making the area of that 2x2 or 4

Then we take the uppermost triangle on the left and find the area of that which is 2x2 / 2 or 2. Then we find the right uppermost triangle which is 5x 2 /2 or 5. Then we take the rightmost triangle and find that 4x 4 /2 or 8. Then we add the square in the middle which is 3 x 4 or 12.

Add those area 4 + 2 + 5 + 8 + 12. You should get 31.

Hope that helps somewhat. You need to divide the shape into easily usable shapes like squares and triangles.

Answer:

Step-by-step explanation:

they aarre 38 left

Answer:

the answer is 9.5

Step-by-step explanation:

Answer:

6700

3 rounds down so 7 stays the same

Answer:

160

Step-by-step explanation:

How many 3/16 are in 30.

30 ÷ 3/16

160

Question:

What is the m∠ACB in the circle shown below?

Answer:

45

Step-by-step explanation:

So we know it is less than a right angle and it is not a obtuse angle it is less than 90 degrees. 45 is less, 90 is equal(not what we are looking for) , 120, is greater, and 180 is greater which leaves us to our answer 45.

Answer:

[tex]\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}[/tex]

Step-by-step explanation:

We are given that:

[tex]\displaystyle \cos(\theta)=\frac{8}{9}[/tex]

Where θ is in QIV.

And we want to find the value of tan(θ).

Recall that cosine is the ratio of the adjacent side over the hypotenuse.

Therefore, the opposite side is:

[tex]o=\sqrt{9^2-8^2}=\sqrt{17}[/tex]

Next, in QIV, only cosine is positive: sine and tangent are both negative.

Tangent is the ratio of the opposite side to the adjacent. So:

[tex]\displaystyle \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}[/tex]

Substitute. Tangent is negative in QIV. Hence:

[tex]\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}[/tex]

Answer: X = 3

Step-by-step explanation:

5x - 2 = 3x + 4

5x = 3x + 6 (+2 to both sides)

2x = 6

x = 3

Answer:

[tex]\text{A) }190[/tex]

Step-by-step explanation:

Similar to the handshake problem, if every student must talk with another person, each student will talk to 19 other students. However, a conversation consists of two people, so we must divide the number of ways we can rearrange the two people ([tex]2![/tex]). Therefore, our answer is [tex]\frac{20\cdot 19}{2!}=\boxed{\text{A) }190}[/tex]

Answer:

nice laptop

Step-by-step explanation:

Answer:

N=22.815≈23  

Step-by-step explanation:

SIN N=19/49

N=\sin^{-1}(\frac{19}{49})

N=sin

N=22.815≈23  

Answer:

2:7 4:14  10 times original: 20/70

Step-by-step explanation:

if you multiply 2/7 by 10 it is 20/70

Answer:

B

Step-by-step explanation:

B because it's more close to the line and the dote goes through more of the dots.

Hope this help, LSB

mark brainest

Answer:

1.33cm

Step-by-step explanation:

if 2cm is representing 75 miles, that means that .66 (repeating) is representative of 25 miles. This is because .66 (repeating) times 3 is equal to 2, and 25 times 3 is equal to 75. The reason 1.33cm would be equal to 50 miles is because if 25 miles is equal to .66, and 50/25 = 2, then you would have 2x.66 (repeating), to get 1.33.

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that [tex]\overline{RP}[/tex] = [tex]\overline{SP}[/tex], the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

Step-by-step explanation:

Distance = √[(-6)²+(7)²]

= √[ 36+49]

= √(85)

Answer:

100

Step-by-step explanation:

Given :

Terms ( n ) = 100

First term ( a ) = 100

Series = > 100 + 98 + 96 .......

Common difference ( d ) = 98 - 100 = > - 2

We know sum formula:

S_n = ( n / 2 ) ( 2 a + ( n - 1 ) d )

= > S_100 = ( 100 / 2 ) ( 200 + ( 100 - 1 ) - 2 )

= > S_100 = 50 ( 200 - 198 )

= > S_100 = 50 ( 2 )

= > S_100 = 100

Therefore, sum of first 100 terms is 100.

Answer:

Answer is in picture

Step-by-step explanation:

Hope it is helpful...

Answer is about 20, because theres about 20 blocks shaded in total.

Answer:

Each day she has read 1/6 of the book.

Step-by-step explanation:

Monica has read 5/6 of book .

Each day she read the same number of pages  for 5 days

Each day she read 5/6/5= 5/6*5= 1/6

Each day she has read 1/6 of the book.

So that in 5 days it makes

1/6+1/6+1/6+1/6+1/6= 5/6

Answer:

an equilateral triangle

Step-by-step explanation:

A triangle is a three-sided polygon with three edges and three vertices. the sum of angles in a triangle is 180 degrees

Area of a triangle = 1/2 x base x height

the perimeter of a triangle = sum of the side lengths

An equilateral triangle is a triangle with three equal sides. the distance travelled her all equal to 10 miles.

Answer:

[tex]9\pi -18[/tex]

Step-by-step explanation:

Answer:

A. Parallelogram LMNP

B. 33

C. 98°

Step-by-step explanation:

LMNP is a parallelogram.

Adjacent angles of a parallelogram are Supplementary.

[tex] \therefore 82\degree +(3x - 1)\degree =180\degree [/tex]

[tex] \therefore (3x - 1+82)\degree =180\degree [/tex]

[tex] \therefore (3x +81)\degree =180\degree [/tex]

[tex] \therefore 3x +81 =180 [/tex]

[tex] \therefore 3x =180-81 [/tex]

[tex] \therefore 3x =99 [/tex]

[tex] \therefore x =\frac{99}{3} [/tex]

[tex] \therefore x =33 [/tex]

[tex] \implies m\angle N= (3x - 1)\degree=(3*33 - 1)\degree=(99-1)\degree = 98\degree [/tex]

[tex] \because m\angle L =m\angle N[/tex]

(Opposite angles of a parallelogram)

[tex] \therefore m\angle L =98\degree [/tex]

Answer:

1 no the quadilateral is parallelogram

2 no .82+82+3x-1+3x-1=360

162+6x=360

6x=198

x=198/6

x=33

3 no angle L =3x-1(opposite angles of a parallelogram are equal)

3*33-1

99-1

98

Step-by-step explanation: