In order for us to see the red apple, where do the wavelengths of light have to go?

Answer:

Simple answer: Yes

Explanation:

Even if you touch an item with a stick you re still doing work to it, most of the time something sitting on a table not being disturbed is having work done to it. Everything has the force of gravity working on it to essentially keep the items from floating away so workis being done to it.

Work done can be something so small (e.g) a pencil sitting on a table) or as big as an earthquake or kicking a ball through a window and smashing the glass.

Answer:

Yes

Explanation:

Answer:

25N

Explanation:

Given parameters:

Potential energy expended  = 500J

Height  = 20m

Unknown:

The force used = ?

Solution:

To solve this problem, we use the expression below:

       Potential energy  = Force applied x height

         500  = Force applied  x 20

     Force applied  = 25N

Answer:

the current flowing in the circuit is 0.1 A.

Explanation:

Given;

potential difference, V = 12 V

resistance of the circuit, R = 120 ohms

The current flowing in the circuit is calculated as;

V = IR

I = V/R

where;

I is the current flowing in the circuit

I = 12 / 120

I = 0.1 A

Therefore, the current flowing in the circuit is 0.1 A.

Answer:

true

Explanation:

Answer:

D: 50 s

Explanation:

We are told that the sidewalk has a velocity of 1.3 m/s north.

Also, we are told that the man walks south on the sidewalk at a speed of 0.9 m/s.

Thus, it means they are moving in opposite directions. The net velocity of the man will be;

v_net = 1.3 - 0.9

v_net = 0.4 m/s

We want to find how long does it take him to travel 20 m relative to a stationary observer,thus;

We we know that;

Time = distance/speed

Time = 20/0.4

Time = 50 s

Answer:

Nutrients for animals

Explanation:

Producers are organisms that produce their food, they do not need to depend on other animals for their food. They possess photosynthetic properties that enable them to produce their food.

These set of organisms are located at the bottom of the food chain, they can convert components like water, sunlight and air into carbohydrate through the unique process of photosynthesis.

Without these producers, the food chain would not exist as they form the base and foundation of the food chain, some lower animals depend on them as their source of food.

Answer:

B. When the average speed of particles is the same throughout the liquid

it is possible that, when oil reaches a high enough temperature, it can ignite and burn very fiercely, being difficult to extinguish.

Explanation:

Given parameters:

Force  = 500N

Acceleration  =

Unknown:

Weight can be used to this problem = ?

Solution:

Weight is the vertical force on a body;

       Weight  = mass x acceleration

So from this we can find the mass and then convert to the second wealth.

Answer:

your question dosent make sense?

Explanation:

Answer:

The time is always in the x axis.

Explanation:

Answer:

It stays and remains at rest

Explanation:

When no forces acts on an object or all the forces on it are balanced, the body stays at rest or remains stationary.

This is based on the Newton's law of inertia which states that "an object will remain in a state of uniform motion or at rest unless an external force acts on it".

If the forces acting on a body is balanced, the object will perpetually remain and keep at rest

Answer:

a) The time it takes the ball to reach maximum height is approximately 3.06 seconds

b) The distance of the ball from the home plate once it is at the top is approximately 38.78 m

c) No

d) The height of the ball when it is at the top is approximately 45.92 m

e) The time it takes the ball to travel 100 m horizontally is 5 seconds

F) The height of the ball when it is 100 m away from the home plate is 27.5 m

G) The height of the ball above the ground when it 100 m away from the home plate, is 27.5 m

The height of the ball above the wall at 100 m from home plate is 3.5 m

Explanation:

The given parameters for the motion of the ball are;

The upward (vertical) velocity of the ball, [tex]u_y[/tex] = 30 m/s

The across (horizontal) velocity of the ball, uₓ = 20 m/s

The distance from the home plate to the outfield fence = 100 m

The height of the outfield fence = 24 m

a) The time, '[tex]t_{mh}[/tex]', it takes the ball to reach maximum height is by the following kinematic equation of motion;

[tex]v_y[/tex] = [tex]u_y[/tex] - g·t

Where;

[tex]u_y[/tex] = 30 m/s

g = The acceleration due to gravity ≈ 9.8 m/s²

At maximum height, we have;

[tex]v_y[/tex] = 0 m/s, t = [tex]t_{mh}[/tex]

∴ 0 m/s = [tex]u_y[/tex] - g·[tex]t_{mh}[/tex]

[tex]u_y[/tex] = g·[tex]t_{mh}[/tex]

[tex]t_{mh}[/tex] = [tex]u_y[/tex]/g

∴ [tex]t_{mh}[/tex] = [tex]u_y[/tex]/g = (30 m/s)/(9.8 m/s²) = 150/49 s ≈ 3.06 seconds

The time it takes the ball to reach maximum height, [tex]t_{mh}[/tex] ≈ 3.06 seconds

b) The horizontal distance travelled by the ball, when it is at maximum height, [tex]x_{mh}[/tex], is given as follows;

[tex]x_{mh}[/tex] = uₓ × [tex]t_{mh}[/tex] = 20 m/s × 150/49 s

[tex]x_{mh}[/tex] = 20 m/s × 150/49 s = 3000/49 m

[tex]x_{mh}[/tex] = 3000/49 m

The distance of the ball from the home plate, 'd', once it is at the top (maximum height), is given as follows;

d = 100 m - [tex]x_{mh}[/tex]

∴ d = 100 m - 3000/49 m = 1900/49 m ≈ 38.78 m

The distance of the ball from the home plate once it is at the top = d ≈ 38.78 m

c) The ball is yet to reach the fence when it gets to the top

The ball has approximately 38.78 meters to reach the fence

d) The height of the ball, [tex]h_{max}[/tex], when it is at the top is given by the following kinematic equation

[tex]h_{max}[/tex] = [tex]u_y[/tex]²/(2·g)

Where;

[tex]u_y[/tex] = 30 m/s

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ [tex]h_{max}[/tex] = (30 m/s)²/(2×9.8 m/s²) = 2,250/49 m ≈ 45.92 m

The height of the ball when it is at the top, [tex]h_{max}[/tex] ≈ 45.92 m

e) The time, t₁₀₀, it will take the ball to get 100 m from home plate is found from the following relationship;

Velocity, u = Distance, x/(time, t)

∴ Time = Distance/(Velocity)

t = x/v

The given distance is the horizontal distance, therefore, we use the horizontal component of the velocity as follows;

v = Horizontal velocity of the softball = uₓ = 20 m/s

x = The given horizontal distance travelled by the ball = 100 m

t₁₀₀ = The time it takes the ball to travel 100 m horizontally

∴ t₁₀₀ = x/(uₓ) = 100 m/(20 m/s) = 5 s

The time it takes the ball to travel 100 m horizontally, t₁₀₀ = 5 seconds

F) The height of the ball above ground when it is 100 m away from the home plate is given as follows;

When the ball is 100 m from the home plate, the time, t₁₀₀ = 5 seconds

The height of the ball at 100m, [tex]h_{t_{(100 \, m)}}[/tex], is given according to the kinematic equation of motion for vertical height reached by an object as follows;

h = [tex]u_y[/tex]·t - 1/2·g·t²

∴ [tex]h_{t_{(100 \, m)}}[/tex] =  [tex]u_y[/tex]·t₁₀₀ - 1/2·g·t₁₀₀²

Plugging in the known values gives;

[tex]h_{t_{(100 \, m)}}[/tex] =  30 m/s × 5 s  - 1/2 × 9.8 m/s × (5 s)² = 27.5 m

The height of the ball when it is 100 m away from the home plate, [tex]h_{t_{(100 \, m)}}[/tex] = 27.5 m.

G) The height of the ball above the ground when it 100 m away from the home plate, is  [tex]h_{t_{(100 \, m)}}[/tex] = 27.5 m

The height of the ball above the wall at 100 m from the home plate = The height of the ball when it is 100 m away from the home plate - The height of the wall at 100 m away from the home plate

∴ The height of the ball above the wall at 100 m from home plate = 27.5 m - 24 m = 3.5 m.

Answer:

Nope.

Explanation:

No. The Moon rotates on its own axis at the same rate that it orbits around Earth. That means we always see the same side of the Moon from our position on Earth. The side we don't see gets just as much light, so a more accurate name for that part of the Moon is the "far side."

No, we can't see the similar quantity of the illuminated side of the Moon from the planet (Earth).

Thus the above answer is correct.

Learn more:

https://brainly.com/question/11606610

Answer:

0.002 m or 2 mm

Explanation:

Given that:

Force, F = 50N

Area = 1 * 10^-5

Length, L = 10m

Shear modulus, = 2.5 * 10^10

Using the relation ;

D = (50 ÷ 1*10^-5) ÷ (2.5 * 10^10 ÷ 10)

D = 5000000 ÷ 2.5 * 10^9

D = 5 * 10^6 ÷ 2.5 * 10^9

D = (5/2.5) * 10^(6-9)

D = 2 * 10^-3

D = 0.002 m

1m = 1000 mm

0.002m = (1000 * 0.002) = 2 mm

Answer:

yes.

Explanation:

becausehjjkvfdssaajkkbcsssddhkkgddd

Answer:

163.5m

this is how far the doggo would go

(In theory)

If I'm wrong I apologize

Answer:

im soo sad brainly wouldnt let me in the account that asked this question now i have to start everything over

Explanation:

Answer:

3.  When energy is used, it can transform to new types but can never disappear.

Explanation: it can transform into heat, light, ect and will never disapear unlessed turned of.

Answer:

mv=11700

m=900

v=11700/900=13m/s in west

Answer:

To lose weight, you must use more weight than you consume. (D.)

Explanation:

I took the test and got a 100

Answer:

The main sequence stretching from the upper left (hot, luminous stars) to the bottom right (cool, faint stars) dominates the HR diagram. It is here that stars spend about 90% of their lives burning hydrogen into helium in their cores. Main sequence stars have a Morgan-Keenan luminosity class labelled V.

Explanation:

Answer:

28.7m

Explanation:

Given parameters;

Work done  = 430J

Force applied  = 15N

Unknown:

Distance moved  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

     Work done  = Force x distance

So;

         430  = 15 x distance

      Distance  = 28.7m

Answer:

s=62.5m

Explanation:

Use the equation v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.

0²=25²+2(-5)s

10s=625

s=62.5m

Answer:

The first one is true.

Explanation:

Here it is

Answer:

In the explanation

Explanation:

After erosion and eruptions which is a primary occuration for sediments, this will create heat and tough pressure leading the sediment to be extremely stable and Hard.

Answer:

 a = 1600 m / s²

Explanation:

For this exercise we use the kinematics relations,

         v² = v₀² + 2 a x

where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m

         a = [tex]\frac{v^2}{2x}[/tex]

let's calculate

         a = [tex]\frac{80^2}{2 \ 2}[/tex]

         a = 1600 m / s²

Answer:

11 ounces

Explanation:

The patient gets 11 ounces of liquid.

From the description of this problem:

        Xavier administers  four cups of liquid each containing two ounces

The number of ounces in the four cups = 2 x 4  = 8ounces

Also,

   One cup of the liquid contains 3 ounces.

Total number of ounces administered  = 8 + 3  = 11 ounces.