In a survery of 154 households, a Food Marketing Institute found that 106 households spend more than $125 a week on groceries. Please find the 95% confidence interval for the true proportion of the households that spend more than $125 a week on groceries.

Answer:

The area formula of a triangle is (base * height) / 2 and the area of a square is s² where s is the length of one side.

Options

Answer:

[tex](E)0.7+0.4-0.2=0.9[/tex]

Step-by-step explanation:

In probability theory

[tex]P$(A or B)=P(A)+P(B)$-$P(A and B)[/tex]

Let the event that the show had animals in it = A

P(A)=0.7

Let the event that the show aired more than 10 times =B

P(B)=0.4

P(A and B)= 0.2

[tex]P$(A or B)$=0.7+0.4-0.2=0.9[/tex]

Therefore, the equation which  shows the correct use of the addition rule to determine the probability that a randomly selected show had animals in it or aired more than 10 times is:

[tex]0.7+0.4-0.2=0.9[/tex]

The correct option is E.

Answer:

b at most 199

Step-by-step explanation:so the total was 121 and there is a flat fee of 21.50 so you subtract that out and gat 99.5 since its .5 per mile its going to be divided giving 199 and that is the most she could have driven.

Answer:

This question should be worth atleast 20 points

Step-by-step explanation:

a. For the vertex, input the funtion into the calculator, and see where the turning piont is, that is the vertex.

b. Solve using this vormula.

x= (-b ±[tex]\sqrt{b^2 - 4ac}[/tex])/2a

you will get two asnwrs, both are correct.

Answer:

Step-by-step explanation:

f(x)=-x+4

f(-2)=-(-2)+4

f(-2)=+2+4

f(-2)=6

Answer:

6

Step-by-step explanation:

-(-2)+4=___

+(+2)+4=6

Answer:

The answer is option 1.

Step-by-step explanation:

Given that the volume of pyramid formula is:

[tex]v = \frac{1}{3} \times base \: area \times height[/tex]

The base area for this pyramid:

[tex]base \: area = area \: of \: rectangle[/tex]

[tex]base \: area = 10 \times 6[/tex]

Then you have to substitute the following values into the formula:

[tex]let \: base \: area = 10 \times 6 \\ let \: height = 12[/tex]

[tex]v = \frac{1}{3} \times 10 \times 6 \times 12[/tex]

Answer:

A. V = 1/3 (10)(6)(12)

Step-by-step explanation:

Just took the test and got it right

Answer:

  23.29 lbs

Step-by-step explanation:

The force on Jenny due to gravity can be resolved into components perpendicular to the hillside and down the slope. The down-slope force is ...

  (90 lbs)sin(15°) ≈ 23.29 lbs

In order to keep Jenny in position, that force must be balanced by an up-slope force of the same magnitude.

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

 therefore it would be:

[tex]W = \int\limits^b_ a {F(x)} \, dx[/tex]

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

[tex]W = \int\limits^b_a {0.4*x} \, dx[/tex]

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

Following are the calculation to the given value:

Given:

[tex]length= 30 \ ft\\\\mass= 0.4 \ \frac{lb}{ft}\\\\edge= 80 \ ft \\\\[/tex]

To find:

work=?

Solution:

Using formula:

[tex]\to W=fd[/tex]

[tex]\to W=\int^{30}_{0} 0.4 \ x\ dx\\\\[/tex]

[tex]= [0.4 \ \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{4}{10} \times \frac{x^2}{2}]^{30}_{0} \\\\= [\frac{2}{10} \times x^2]^{30}_{0} \\\\= [\frac{1}{5} \times x^2]^{30}_{0} \\\\= [\frac{x^2}{5}]^{30}_{0} \\\\= [\frac{30^2}{5}- 0] \\\\= [\frac{900}{5}] \\\\=180[/tex]

Therefore, the final answer is "[tex]180\ \frac{ lb}{ft}[/tex]".

Learn more:

brainly.com/question/15333493

Answer:

The general term is

Sn = -(-2)ⁿ.3¹⁻ⁿ

step by step Explanation:

we were told to find a general term of the above sequence, what should come to mind is that the terms will follow an order....

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Answer: 6

Step-by-step explanation:

A=bh plus 120 for A and 20 for B

120=20b

/20 divide by 20 each side

H=6

Answer:

D

Step-by-step explanation:

Parallel lines are those that have the same slope, or coefficient of x.

Here, let's calculate the slope of the given line. Slope is the difference in the y-coordinates divided by the difference in the x-coordinates, so given the two coordinates (12, 6) and (0, -4):

slope = m = (-4 - 6) / (0 - 12) = -10 / (-12) = 10/12 = 5/6

So the slope is 5/6. That means the equation we want should also have a slope of 5/6. Already, we can eliminate A, B, and C, leaving D as our answer. But, let's check.

The equation of a line can be written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is the coordinates of a given point.

Here, our slope is 5/6 and our given point is (12, -2). So plug these in:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-(-2)=(5/6)(x-12)[/tex]

[tex]y+2=\frac{5}{6} x-10[/tex]

[tex]y=\frac{5}{6} x-12[/tex]

This matches D, so we know that it's the correct answer.

~ an aesthetics lover

The answer is D I just took the test

Answer:

Solution = 46

Step-by-step explanation:

I believe you meant standard deviation. Standard deviation is defined as the variation of the data set, or the differences between the values in this set. In order for the standard deviation to be 0, all values should be the same.

Now if the mean is 46, the smallest possible number of each value in the data set should be 46 as well.  This is considering the mean is the average of the values, and hence any number of values in the data set being 46 will always have a mean of 46. Let me give you a demonstration -

[tex]Ex. [ 46, 46, 46 ], and, [46, 46, 46, 46, 46]\\Average = 46 + 46 + 46 / 3 = 46,\\Average = 46 + 46 + 46 + 46 + 46 / 5 = 46[/tex]

As you can see, the average is 46 in each case. This proves that a data set consisting of n number of values in it, each value being 46, or any constant value for that matter, always has a mean similar to the value inside the set, in this case 46. And, that the value of the smallest standard deviation is 46.

Answer:

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.

The slope greater than one would be the last image, because for every step in x, you get more than one y step.

The slope between 1 and 0 would be the second image

And the slope less than 0 would be the third image

Answer:

IT'S NOT -15 FOR SUREEE

Step-by-step explanation:

I Believe it's 15

Answer:

174 square cm

Step-by-step explanation:

2(9×4) + 2(6×4)+ 9×6

2(36) + 2(24) + 54

72 + 48 + 54

120 + 54

174

Answer:

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

P(920≤ x≤1730) = 0.7078

Step-by-step explanation:

Step(i):-

Given mean of the Population = 1100 lbs

Standard deviation of the Population = 300 lbs

Let 'X' be the random variable in Normal distribution

Let x₁ = 920

[tex]Z = \frac{x-mean}{S.D} = \frac{920-1100}{300} = - 0.6[/tex]

Let x₂ = 1730

[tex]Z = \frac{x-mean}{S.D} = \frac{1730-1100}{300} = 2.1[/tex]

Step(ii)

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

P(x₁≤ x≤x₂) = P(Z₁≤ Z≤ Z₂)

                  = P(-0.6 ≤Z≤2.1)

                  = P(Z≤2.1) - P(Z≤-0.6)

                 = 0.5 + A(2.1) - (0.5 - A(-0.6)

                 =  A(2.1) +A(0.6)               (∵A(-0.6) = A(0.6)

                 =  0.4821 + 0.2257

                 = 0.7078

Conclusion:-

The probability that the weight of a randomly selected steer is between 920 and 1730 lbs

            P(920≤ x≤1730) = 0.7078

Answer:

0.7975

Step-by-step explanation:

Answer:

if m is supposed to be the equals (=) sign then x = 25

Step-by-step explanation:

45 = (2x-5)

+5         +5

50 = (2x)

÷2     ÷2

25 = x

Answer: 70

Step-by-step explanation:

Answer:

[tex] P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)[/tex]

And replacing using the mass function we got:

[tex]P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156[/tex]  

[tex]P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211[/tex]  

[tex]P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217[/tex]  

[tex]P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161[/tex]  

[tex]P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759[/tex]  

[tex]P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172[/tex]  

And adding the values we got:

[tex] P(X\geq 20) = 0.8381[/tex]

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

[tex]X \sim Binom(n=25, p=0.85)[/tex]  

The probability mass function for the Binomial distribution is given as:  

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]  

Where (nCx) means combinatory and it's given by this formula:  

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]  

We want to find the following probability:

[tex] P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)[/tex]

And replacing using the mass function we got:

[tex]P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156[/tex]  

[tex]P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211[/tex]  

[tex]P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217[/tex]  

[tex]P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161[/tex]  

[tex]P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759[/tex]  

[tex]P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172[/tex]  

And adding the values we got:

[tex] P(X\geq 20) = 0.8381[/tex]

Answer:

C.

Step-by-step explanation:

When two lines are parallel, their slopes are the same.

Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.

The answer is C.

Answer:

C. 2/7

Step-by-step explanation:

Parallel lines are lines that have the same slopes.

We know that line l is parallel to line m.

Therefore, the slope of line l is equal to the slope of line m.

[tex]m_{l} =m_{m}[/tex]

We know that line l has a slope of 2/7.

[tex]\frac{2}{7} =m_{m}[/tex]

So, line m also has a slope of 2/7. The answer is C. 2/7

Answer:

[tex]P(X<0.4375)=P(\frac{X-\mu}{\sigma}<\frac{0.4375-\mu}{\sigma})=P(Z<\frac{0.4375-0.635}{0.082})=P(z<-2.41)[/tex]

And we can find this probability using the z table and we got:

[tex]P(z<-2.41)=0.0080[/tex]

Step-by-step explanation:

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(0.635,0.082)[/tex]  

Where [tex]\mu=0.635[/tex] and [tex]\sigma=0.032[/tex]

We are interested on this probability

[tex]P(X<0.4375)[/tex]

And the best way to solve this problem is using the normal standard distribution and the z score given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

If we apply this formula to our probability we got this:

[tex]P(X<0.4375)=P(\frac{X-\mu}{\sigma}<\frac{0.4375-\mu}{\sigma})=P(Z<\frac{0.4375-0.635}{0.082})=P(z<-2.41)[/tex]

And we can find this probability using the z table and we got:

[tex]P(z<-2.41)=0.0080[/tex]

Step-by-step explanation:

Maybe the page numbers can be 143 and 246

143 + 246 = 389

Answer:

194 and 195

Step-by-step explanation:

x = 1st page

x + 1 = 2nd page

x + x + 1 = 389

2x + 1 = 389

2x = 388

x = 194

x + 1 = 195

The equation that represents the line that passes through the points A and C is y = x + 1

A linear equation is an equation that has a constant rate or slope, and is represented by a straight line

The points are given as:

(x,y) = (2,3) and (-4,-3)

Calculate the slope, m using:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{-3 -3}{-4 - 2}[/tex]

Evaluate

m = 1

The equation is then calculated as:

y = m *(x - x1) + y1

So, we have:

y = 1 * (x - 2) + 3

Evaluate

y = x - 2 + 3

This gives

y = x + 1

Hence, the equation that represents the line that passes through the points A and C is y = x + 1

Read more about linear equations at:

https://brainly.com/question/14323743

#SPJ2

Answer:

y = x + 1

Step-by-step explanation:

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Answer:

C. c = (xv - x) / (v - 1).

Step-by-step explanation:

v = (x + c) / (x - c)

(x - c) * v = x + c

vx - vc = x + c

-vc - c = x - vx

vc + c = -x + vx

c(v + 1) = -x + vx

c = (-x + vx) / (v + 1)

c = (-x + xv) / (v + 1)

c = (xv - x) / (v + 1)

So, the answer should be C. c = (xv - x) / (v + 1).

Hope this helps!

Answer:

A) A = {RRR, LLL, SSS}

B) B = {LRS. LSR, RLS, RSL, SLR, SRL}

C) C = {RRL, RRS, RSR, RLR, LRR, SRR}

D) D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}

E) D' ={RRR, LLL, SSS, LRS. LSR, RLS, RSL, SLR, SRL}

F) C ∪ D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}

G) C ∩ D = {RRL, RRS, RSR, RLR, LRR, SRR}

Step-by-step explanation:

A) All vehicles must go right, left or straight ahead (three possibilities):

A = {RRR, LLL, SSS}

B) One vehicle must go right, one must go left, and the remaining one must go straight ahead (six possibilities):

B = {LRS. LSR, RLS, RSL, SLR, SRL}

C) There are three ways that exactly two vehicles go right (1 and 3, 2 and 3, 1 and 2), there are then two options for the remaining vehicle (left and straight) for a total of six possibilities:

C = {RRL, RRS, RSR, RLR, LRR, SRR}

D) Follow the same reasoning from the previous item, but multiply the number of possibilities by 3 (for each direction in which both cars can go: right, left or straight):

D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}

E) D' is the set containing all possibilities not present in set D. D' is comprised by the possibilities of all vehicles going in the same direction, or each vehicle in a different direction:

D' ={RRR, LLL, SSS, LRS. LSR, RLS, RSL, SLR, SRL}

F) The outcomes in C ∪ D is the union of elements from set C and D (neglecting repeated values), which happens to be all values in set D.

C ∪ D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}

G) The outcomes in C ∩ D is the list of values present in both sets C and D, which happens to be all values in set C:

C ∩ D = {RRL, RRS, RSR, RLR, LRR, SRR}

Answer:

z = 1.476

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.86}{2} = 0.07[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.07 = 0.93[/tex], so [tex]z = 1.476[/tex]

The answer is z = 1.476

Answer:

The  UCL  is  [tex]UCL = 0.054[/tex]

The LCL  is  [tex]LCL \approx 0[/tex]

Step-by-step explanation:

From the question we are told that  

     The quantity of each sample is  n =  30

     The  average of defective products is  [tex]p = 0.025[/tex]

Now  the upper control limit [UCL] is  mathematically represented as

      [tex]UCL = p + 3 \sqrt{\frac{p(1-p)}{n} }[/tex]

substituting values  

      [tex]UCL = 0.025 + 3 \sqrt{\frac{0.025 (1-0.025)}{30} }[/tex]

      [tex]UCL = 0.054[/tex]

The  upper control limit (LCL) is mathematically represented as

       [tex]LCL = p - 3 \sqrt{\frac{p(1-p)}{n} }[/tex]

substituting values  

      [tex]LCL = 0.025 - 3 \sqrt{\frac{0.025 (1-0.025)}{30} }[/tex]

       [tex]LCL = -0.004[/tex]

        [tex]LCL \approx 0[/tex]

Answer:

a) 4 cm

b) 5 cm

c) 10 cm

Step-by-step explanation:

The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same.  From there, it is just addition.

Hope it helps <3

Answer:

A) 4

B) 5

C) 10

Step-by-step explanation:

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