In a study, researchers wanted to estimate the true mean skidding distance along a new road in a European forest. The skidding distance (in meters) were measured at 20 randomly selected road sites. The 95% confidence interval constructed based on the data collected was (303.3, 413.6). A logger working on the road claims that the mean skidding distance is at least 425 meters. Does the confidence interval supports the loggers claim

Answers

Answer 1

Answer:

[tex] 303.3 \leq \mu \leq 413.6[/tex]

We need to remember that the confidence interval for the true mean is given by:

[tex] \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]

Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim

Step-by-step explanation:

We know that they use a sample size of n =20 and the confidence interval for the true mean skidding distance along a new road in a European forest is given by:

[tex] 303.3 \leq \mu \leq 413.6[/tex]

We need to remember that the confidence interval for the true mean is given by:

[tex] \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]

Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim


Related Questions

Zed went to the store and bought a bag of chips. He estimated there would 1 point
be 350 chips in the package, but realized there were only 210 chips in that
package. What was his percent error?'​

Answers

Answer:

66.67%

Step-by-step explanation:

They do not say that I estimate a value of 350 chips but in reality there were 210 chips in total, we have that the error formula is:

Percentage error (%) = (estimated value - actual value) / actual value × 100 (in absolute value)

replacing:

Percentage error (%) = | 350 - 210 | / 210 × 100

Percentage error (%) = 140/210 * 100

Percentage error (%) = 66.67

Which means that the percentage error is 66.67%

In a grinding operation, there is an upper specification of 3.150 in. on a dimension of a certain part after grinding. Suppose that the standard deviation of this normally distributed dimension for parts of this type ground to any particular mean dimension LaTeX: \mu\:is\:\sigma=.002 μ i s σ = .002 in. Suppose further that you desire to have no more than 3% of the parts fail to meet specifications. What is the maximum (minimum machining cost) LaTeX: \mu μ that can be used if this 3% requirement is to be met?

Answers

Answer:

Step-by-step explanation:

Let X denote the dimension of the part after grinding

X has normal distribution with standard deviation [tex]\sigma=0.002 in[/tex]

Let the mean of X be denoted by [tex]\mu[/tex]

there is an upper specification of 3.150 in. on a dimension of a certain part after grinding.

We desire to have no more than 3% of the parts fail to meet specifications.

We have to find the maximum [tex]\mu[/tex] such that can be used if this 3% requirement is to be meet

[tex]\Rightarrow P(\frac{X- \mu}{\sigma} <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{0.002} )\leq 0.03[/tex]

We know from the Standard normal tables that

[tex]P(Z\leq -1.87)=0.0307\\\\P(Z\leq -1.88)=0.0300\\\\P(Z\leq -1.89)=0.0293[/tex]

So, the value of Z consistent with the required condition is approximately -1.88

Thus we have

[tex]\frac{3.15- \mu}{0.002} =-1.88\\\\\Rrightarrow \mu =1.88\times0.002+3.15\\\\=3.15[/tex]

which of the following equations have no soltuions? 4x+5=4x+5 -4x+5=-4x-5 5x+5=-4x-5 -4x+5=-4x-4 choose all the answers that apply

Answers

Answer:

2nd

Step-by-step explanation:

What is the probability that the hand is a two of a kind? A two of a kind has two cards of the same rank (called the pair). Among the remaining three cards, not in the pair, no two have the same rank and none of them have the same rank as the pair. For example, {4♠, 4♦, J♠, K♣, 8♥} is a two of a kind.

Answers

Question:

A 5-card hand is dealt from a perfectly shuffled deck of playing cards.

What is the probability that the hand is a two of a kind?

A two of a kind has two cards of the same rank (called the pair). Among the remaining three cards, not in the pair, no two have the same rank and none of them have the same rank as the pair. For example, {4♠, 4♦, J♠, K♣, 8♥} is a two of a kind.

Answer:

P(two of a kind) = 42.3%

Step-by-step explanation:

The probability that the hand is a two of a kind is given by

P(two of a kind) = No. of ways to produce two of a kind/Total no. of ways to deal 5-hand cards

There are total 52 cards in a standard deck of playing cards.

Total number of ways to deal 5-card hand is given by

Total number of ways = ₅₂C₅

Total number of ways = 2595960

So there are 2595960 different ways of dealing 5-card hands

Now we will find out the number of ways to produce two of a kind.

The number of ways to select the rank of two matching cards is given by

Rank of matching cards = ₁₃C₁ = 13

Since the matching cards must be of same rank.

The number of ways to select the rank of remaining 3 cards is given by

Rank of remaining 3 cards = ₁₂C₃ = 220

Since the remaining ranks are now 12.

The number of ways to select the suits of two matching cards is given by

Suits of two matching cards = ₄C₂ = 6

The number of ways to select the suits of 1st non-matching card is given by

Suits of 1st non-matching card = ₄C₁ = 4

The number of ways to select the suits of 2nd non-matching card is given by

Suits of 2nd non-matching card = ₄C₁ = 4

The number of ways to select the suits of 3rd non-matching card is given by

Suits of 3rd non-matching card = ₄C₁ = 4

Finally, the probability is

P(two of a kind) = No. of ways to produce two of a kind/Total no. of ways to deal 5-hand cards

P(two of a kind) = (₁₃C₁ × ₁₂C₃ × ₄C₂ × ₄C₁ × ₄C₁ × ₄C₁) / ₅₂C₅

P(two of a kind) = (13 × 220 × 6 × 4 × 4 × 4) / 2595960

P(two of a kind) = 1098240/2595960

P(two of a kind) = 0.423

P(two of a kind) = 42.3%

So I’m taking geometry online as a summer course since I failed my 1st semester. After completing it, when I return back to school do I have to take a test in order to advance and move on to another math?

Answers

Answer:

Since you are taking it online all the tests that you will have to do will be on there so as long as you pass the class you should be able to move on next school year. Good luck!

A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x. Find the break-even point and express it as an ordered pair in the form (x,y).

Answers

Answer:

The break-even point is when x is equal to 3.75

Step-by-step explanation:

At the break-even point, total cost function is equal to the total revenue function. In that regard, break-even is when;

C = 12x + 30 is equal to R = 20x.

thus, 12x + 30 = 20x

then, 12x - 12x + 30 = 20x - 12x

therefore, 30 = 8x

then, 30/8 = 8x/8

finally, x = 15/4 or 3.75

A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x, the Break even point is (3.75,75)

Given :

A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x.

Break even point occurs when revenue = cost

R=C

Replace the expression and solve for x

[tex]R=C\\20x=12x+30\\20x-12x=30\\8x=30\\divide \; by \; 8\\x=\frac{15}{4}\\x=3.75[/tex]

Now we find out y using Revenue

[tex]R= 20x\\R=20(3.75)\\R=75[/tex]

So y is 75

Break even point is (3.75,75)

Learn more : brainly.com/question/15281855

In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized. Assume that the rate at which material is forgotten is proportional to the amount memorized. Suppose M denotes the total amount of a subject to be memorized and A(t) is the amount memorized in time t > 0. Determine a differential equation for the amount A(t) when forgetfulness is taken into account. (Assume the constants of proportionality for the rate at which material is memorized and the rate at which material is forgotten are k1 > 0 and k2 > 0, respectively. Use A for A(t).)
dA/dt =

Answers

Answer:

dA/dt = k1(M-A) - k2(A)

Step-by-step explanation:

If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)

Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:

Rate Memorized = k1(M-A)

Where k1 is the constant of proportionality for the rate at which material is memorized.

At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:

Rate forgotten = k2(A)

Where k2 is the constant of proportionality for the rate at which material is forgotten.

Finally, the differential equation for the amount A(t) is equal to:

dA/dt = Rate Memorized - Rate Forgotten

dA/dt = k1(M-A)  - k2(A)

6 x 6 x 6 x 6 x 6 x 6 x 6= 6^x

Answers

Answer:

[tex] 6^7 [/tex]

Step-by-step explanation:

[tex]6 \times 6 \times 6 \times 6 \times 6 \times 6 \times 6 = 6^7 \\ [/tex]

Hey there!


6 * 6 * 6 * 6 * 6 * 6 * 6 ➡️ 6^7
= 36 * 36 * 36 * 6

= 1,296 * 36 * 6

= 46,656 * 6

= 279,936


Therefore, your answer is: 6^7


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

In a recent year, the Better Business Bureau settled 75% of complaints they received. You have been hired by the Bureau to investigate complaints this year involving computer stores. You plan to select a random sample of complaints to estimate the proportion of complaints the Bureau is able to settle. Suppose your sample size is 113. What is the probability that the sample proportion will be at most 2 percent more than the population proportion

Answers

Answer:

what

Step-by-step explanation:

The pool at the apartment building is 30 feet long, 20 feet wide, and 5 feet deep. It has been fikked 4 feet deep. How many more cubic feet of water are needed to finish filling the pool?

Answers

Answer:

600 cubic feet of water

Step-by-step explanation:

If the pool is filled 4 feet and the pool is 5 feet deep, that leaves 1 foot of depth left to fill. This makes the volume equation 30 x 20 x 1 which equals 600.

PLEASE HELP!!! Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i.e. "/") for all fractions (e.g. 1/2 for 12). m= _____ What would the perpendicular slope be? m= _____ Step 2: Use the slope to find the y-intercept of the perpendicular line. b= ____ Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10 y= ____ x+ Answer

Answers

Perpendicular Lines

Linear equations are typically organized in slope-intercept form:

[tex]y=mx+b[/tex]

m = slopeb = y-intercept

Perpendicular lines have slopes that are negative reciprocals.

Example: 2 and -1/2Example: 3/4 and -4/3

Solution

We're given:

Perpendicular to [tex]4x-5y=-10[/tex]Passes through (6,3)

1) Determine the slope

Let's first rearrange this equation into slope-intercept form:

[tex]4x-5y=-10\\-5y=-4x-10\\\\y=\dfrac{4}{5}x+2[/tex]

Notice how [tex]\dfrac{4}{5}[/tex] is in the place of m in y = mx + b. This is the slope of the give line.

Since perpendicular lines are negative reciprocals, we know the slope of the other line is [tex]-\dfrac{5}{4}[/tex]. Plug this into y = mx + b:

[tex]y=-\dfrac{5}{4}x+b[/tex]

2) Determine the y-intercept

We're also given that the line passes through (6,3). Plug this point into our equation and solve for b:

[tex]y=-\dfrac{5}{4}x+b\\\\3=-\dfrac{5}{4}(6)+b\\\\b=3+\dfrac{5}{4}(6)\\\\b=\dfrac{21}{2}[/tex]

Plug this back into our original equation:

[tex]y=-\dfrac{5}{4}x+\dfrac{21}{2}[/tex]

Answer

[tex]y=-\dfrac{5}{4}x+\dfrac{21}{2}[/tex]

Each limit represents the derivative of some function f at some number a. State such an f and a in each case.
lim √9 + h - 3 / h
h-->0

Answers

Answer:

a = 0f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]limit of the function is 1/6

Step-by-step explanation:

The general form representing limit of a function is expressed as shown below;

[tex]\lim_{h \to a} f(h)[/tex] where a is the value that h will take and use in the function f(h). It can be expressed in words as limit of function f as h tends to a. Comparing the genaral form of the limit to the limit given in question [tex]\lim_{h \to 0} \frac{\sqrt{9+h} - 3}{h}[/tex], it can be seen that a = 0 and f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]

Taking the limit of the function

[tex]\lim_{h \to 0} \frac{\sqrt{9+h} -3}{h}\\= \frac{\sqrt{9+0}-3 }{0}\\= \frac{0}{0}(indeterminate)[/tex]

Applying l'hopital rule

[tex]\lim_{h \to 0} \frac{\frac{d}{dh} (\sqrt{9+h} - 3)} {\frac{d}{dh} (h)}\\= \lim_{h \to 0} \frac{1}{2} (9+h)^{-1/2} /1\\=\frac{1}{2} (9+0)^{-1/2}\\= \frac{1}{2} * \frac{1}{\sqrt{9} } \\= 1/2 * 1/3\\= 1/6[/tex]

Enter the y-coordinate of the solution. Round to the nearest tenth. 5x+2y=7 -2x+6y=9

Answers

Answer:

59/34

Step-by-step explanation:

5x+2y=7

-2x+6y=9

Multiply the top equation by 3:

15x+6y=21

Subtract the second equation from the first:

17x=12

x=12/17

Plug this back into one of the other equations to find y:

5(12/17)+2y=7

60/17+2y=7

2y=59/17

y=59/34

Hope this helps!

What is the next term of this sequence? -5, 5, -6, 6, -7, 7, -8, ..

Answers

Answer:

8

Step-by-step explanation:

There are two series in one

-5, -6, -7, -8, ...

and

5, 6, 7,  and 8 is the next term

Write down the 1st term in the sequence given by:t(n) =n^2+4

Answers

Answer:

5

Step-by-step explanation:

t(1) = [tex]1^{2} + 4 = 5[/tex]

Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals.
a. .09
b. .6
c. .9
d. .3

Answers

Answer:

Answer D is correct

Please help! Correct answer only, please! Which of the following is one of the cheapest routes to pass through each vertex once starting and ending with Vertex "A" and using the Nearest Neighbor Algorithm. A. ABDCA, $890 B. ACDBA, $900 C. ABCDA, $960 D. None of the Above

Answers

Answer: c) ABCDA, $960

Step-by-step explanation:

The nearest Neighbor Algorithm states to choose the next vertex based only on the weights of the neighbor of that vertex.

Starting at A: Options are B = 220, C = 240, D = 310

Choose B because it has the smallest value.

From B: Options are C = 200, D = 210

Choose C because it has the smallest value.

From C: There is only one option --> D = 230 (we cannot choose A because it was our starting point and we haven't touched every vertex, yet).

From D: We touched all of the vertices so return to the starting point, A = 310

A → B → C → D → A --> 220 + 200 + 230 + 310 = 960

Notice that if we looked at the entire circuit first, this is NOT the optimum path. But this is the result using the Nearest Neighbor Algorithm.

Leah is 2 less than 3 times Rachel's age. 3 years from now, Leah will be 7 more than twice Rachel's age. How old will Rachel be in 3 years from now?

Answers

Answer:

15

Step-by-step explanation:

Let's call Leah's age l and Rachel's age r. We can write:

l = 3r - 2 (1)

l + 3 = 2(r + 3) + 7 (2)

Substituting (1) into (2) we get:

(3r - 2) + 3 = 2(r + 3) + 7

3r + 1 = 2r + 13

r = 12

In 3 years Rachel will be 12 + 3 = 15 years old.

The dean of the School of Fine Arts is trying to decide whether to purchase a copy machine to place in the lobby of the building. The machine would add to student convenience, but the dean feels compelled to earn an 10 percent return on the investment of funds. Estimates of cash inflows from copy machines that have been placed in other university buildings indicate that the copy machine would probably produce incremental cash inflows of approximately $14,000 per year. The machine is expected to have a three-year useful life with a zero salvage value. (Use appropriate factor(s) from the tables provided.)
Required:
Use Present Value PV of $1 to determine the maximum amount of cash the dean should be willing to pay for a copy machine. (Round intermediate calculations and final answer to 2 decimal places.)

Answers

Answer:

$34,816.60

Step-by-step explanation:

The computation of the maximum amount of cash should willing to pay for the copy machine by using the present value is shown below:

Present value is

[tex]= Incremental\ cash\ flows \times PVIFA\ factor[/tex]

where,

Incremental cash flows is $14,000 per year

Discount rate is 10%

And, the number of years is three years

PVIFA factor for 10% at 3 years is 2.4869

Refer to the PVIFA factor table

Now placing these values to the above formula

So, the present value is

[tex]= \$14,000 \times 2.4869[/tex]

= $34,816.60

there are 47 students in the science club. all but 5 of them went on a field trip to the planetarium. what is the total cost if each student who went on the field trip paid $7?

Answers

the total cost would be $294
47-5=42
42*7=294

Answer:

$294

Step-by-step explanation:

First do 47-5=42

Next do 42x7=294

so the total is 294

3. A metal fabricating plant currently has five major pieces under contract each with a deadline for completion. Let X be the number of pieces completed by their deadlines, and suppose it's PMF p(x) is given by x 0 1 2 3 4 5 p(x) .05 .1 .15 .25 .35 .1 (a) Find and plot the CDF of X. (b) Use the CDF to find the probability that between one and four pieces, inclusive, are completed by their deadline

Answers

Answer:

a) The cumulative distribution function would be given by:

x         0         1       2        3      4      5

F(X)  0.05   0.15  0.30  0.55  0.9    1

b) [tex] P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85 [/tex]

And replacing we got:

[tex]P(1 \leq X \leq 4) =0.85[/tex]

Step-by-step explanation:

For this case we have the following probability distribution function given:

x        0       1       2       3       4       5

P(X)  0.05  0.1  0.15  0.25  0.35  0.1

We satisfy the conditions in order to have a probability distribution:

1) [tex] \sum_{i=1}^n P(X_i)=1[/tex]

2) [tex] P(X_i) \geq 0, i=1,2,..,n[/tex]

Part a

The cumulative distribution function would be given by:

x         0         1       2        3      4      5

F(X)  0.05   0.15  0.30  0.55  0.9    1

Part b

For this case we want to find this probability:

[tex] P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85 [/tex]

And replacing we got:

[tex]P(1 \leq X \leq 4) =0.85[/tex]

Helppppppppp?!!??please

Answers

Answer:

[tex]7.00[/tex]

Step-by-step explanation:

[tex]7.00+.48=7.48[/tex]

Answer:

The answer to the question is B) 7.00

Step-by-step explanation:

It says that

[tex]7.00 + 0.48=6.48[/tex]

But, That is wrong

So the correct version would be

[tex]7.00+0.48=7.48[/tex]

Hope this helps

what is the solution to linear system x-y=4 and x+y=2

Answers

Answer:

Step-by-step explanation:

x - y = 4

x + y = 2

2x = 6

x = 3

3 + y = 2

y = -1

(3, -1)

Which expression can be used to find 45% of 54?

Answers

Answer:

54 · 0.45

Step-by-step explanation:

This expression will give you 45% of 54, since 54 will be multiplied by the decimal equivalent to 45%

Answer:

0.45 · 54

Step-by-step explanation:

In math, 45% is equal to 0.45, because percents are out of a hundre. ’of’ is just another way of putting a multiplicative sign, so it would be 0.45 · 54

You have $150 to spend at a store. If you shoes cost $30 and belts cost $25, write an equation that represents the different ways that you could spend a total of $150

Answers

Answer:

you could buy a pair of shoes and a belt still have 95 dollars to spend

Isaac is organizing a 5-kilometer road race. The safety committee
recommends having a volunteer every 1 of a kilometer and at
the finish.
| Are 10 volunteers enough?​

Answers

Answer:

10 volunteers are more than recommended

Step-by-step explanation:

  The recommended number of volunteers is five (5)

  Since the the distance of the race is 5km,

and the safety committees recommends 1 volunteer per kilometre.

Hence ten (10) volunteers is more than enough

8x - 4 < - 12 or 8x + 7 >23 i need help to find answer

Answers

Answer:

x>4/3 and x<1

Step-by-step explanation:

8x-4 < -12

8x<-12+4

x<8/8

x<1

8x+7> 23

8x>23-7

x>12/8

simplify : x>4/3

Dan buys a car for £2100.
It depreciates at a rate of 2.2% per year.
How much will it be worth in 6 years?
Give your answer to the nearest penny where appropriate.

Answers

Answer:

£472.92

Step-by-step explanation:

£2100(0.78)^6

Suppose we roll 10 fair six sided dice
What is the probability that there are exactly two 2’s showing ?

Answers

Answer: 40%

Step-by-step explanation:

What’s the correct answer for this question?

Answers

Answer:

Step-by-step explanation:

the event of drawing a spade card

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Not all tiles will be used.Read this excerpt from Oliver Twist by Charles Dickens, and identify the meaning of the words in bold based on their context.It chanced one morning, while Oliver's affairs were in this auspicious and comfortable state, that Mr. Gamfield, chimney-sweep, went hisway down the High Street, deeply cogitating in his mind his ways and means of paying certain arrears of rent, for which his landlord hadbecome rather pressing. Mr. Gamfield's most sanguine estimate of his finances could not raise them within full five pounds of the desiredamount; and, in a species of arithmetical desperation, he was alternately cudgelling his brains and his donkey, when passing theworkhouse, his eyes encountered the bill on the gate.Wo-o!" said Mr. Gamfield to the donkey.The donkey was in a state of profound abstraction: wondering, probably, whether he was destined to be regaled with a cabbage-stalk ortwo when he had disposed of the two sacks of soot with which the little cart was laden; so, without noticing the word of command, hejogged onward.strainingpunishedcontemplatingrewardedinventingconfrontedbeatingyellingbelittling Based on the following passage from John Ralstons story, what can we infer? Eventually, John read about a California-based recovery group called LifeRing. There were no LifeRing meetings in his area of Pennsylvania, so he began to attend virtual meetings online and learn all he could about the organization. LifeRing was completely secular, not religious. In contrast to AAs motto, One day at a time, LifeRings is, Dont drink, no matter what. That approach appealed to John. For me, someone who finally wanted to live my life and make plans, I liked the idea that I could look ahead a month, a year, and assume that Id be sober then, he said. And I couldnt make God my way to be sober. Question 9 options: there are differences among recovery programs, and no single program is right for everyone. John is planning to move to California. all the people who attend AA meetings should instead go to LifeRing meetings. attending virtual meetings via the Internet was not helpful to Joh In 1867, the United States purchased the Alaska territory from Russia for $7.2 x 10^6. The total area was about 6 x 10^5 sq miles. What was the price per square mile? A major distinction between a conventional bank and an Islamic bank is that Islamic banks Group of answer choices are supposed to refrain from making a profit through any source. are allowed to charge higher interest rates on loans. cannot pay or charge interest. are not subject to any form of law. If It took 40 sec for avehicle or weight 40,000newton to move round 7meltesWhat time will it achieve samereat for anothercircular pathor radius 21 metres giventhatthe conditionCondition of thevehicle remains the same What is the best summary of this paragraph? Another thing that changed very little in the years between the wars was the means of obtaining military intelligence. Although the use of photography and the telegraph brought some technological advances, the craft of spying on the enemy's army still relied on fieldwork. For the most part, intelligence was gathered in simple ways. Prisoners of war and deserters were interrogated. The Union army was always interested in hearing what runaway slaves had to report. And, of course, both armies relied on cavalry scouts, signal intercepts, visual observation, and captured correspondence. A.During the Civil War, intelligence was gathered in the same ways it had been gathered in previous wars. B.Photography and the telegraph were some of the technological advances that were used in Civil War espionage. C.Most espionage during the Civil War was fieldwork that included observation, scouting, and interrogation of prisoners. D.Enslaved persons that ran away, as well as prisoners from the Union Army, were good sources of information during the Civil War. Write systems of equations from context Lincoln is preparing many gifts for a family holiday party each gift must either be wrapped with wrapping paper or prepared in a gift bag. Lincoln can wrap a single gift in 6.5 minutes and he can do a gift bag in 2 minutes Lincoln prepared a total 13 gifts in 57.5 minutes. Write a system of equations that could be used to determine the number of gifts Lincoln wrapped and the number of gift bags he prepared define the variables that you use to write the system. Jims heart rate was monitored during periods of exercise and periods of rest. The graph shows the result of one 50-minute test.Which statement is an inference that can be made by using the graph?