Answer:
[tex] 303.3 \leq \mu \leq 413.6[/tex]
We need to remember that the confidence interval for the true mean is given by:
[tex] \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]
Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim
Step-by-step explanation:
We know that they use a sample size of n =20 and the confidence interval for the true mean skidding distance along a new road in a European forest is given by:
[tex] 303.3 \leq \mu \leq 413.6[/tex]
We need to remember that the confidence interval for the true mean is given by:
[tex] \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]
Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim
Zed went to the store and bought a bag of chips. He estimated there would 1 point
be 350 chips in the package, but realized there were only 210 chips in that
package. What was his percent error?'
Answer:
66.67%
Step-by-step explanation:
They do not say that I estimate a value of 350 chips but in reality there were 210 chips in total, we have that the error formula is:
Percentage error (%) = (estimated value - actual value) / actual value × 100 (in absolute value)
replacing:
Percentage error (%) = | 350 - 210 | / 210 × 100
Percentage error (%) = 140/210 * 100
Percentage error (%) = 66.67
Which means that the percentage error is 66.67%
In a grinding operation, there is an upper specification of 3.150 in. on a dimension of a certain part after grinding. Suppose that the standard deviation of this normally distributed dimension for parts of this type ground to any particular mean dimension LaTeX: \mu\:is\:\sigma=.002 μ i s σ = .002 in. Suppose further that you desire to have no more than 3% of the parts fail to meet specifications. What is the maximum (minimum machining cost) LaTeX: \mu μ that can be used if this 3% requirement is to be met?
Answer:
Step-by-step explanation:
Let X denote the dimension of the part after grinding
X has normal distribution with standard deviation [tex]\sigma=0.002 in[/tex]
Let the mean of X be denoted by [tex]\mu[/tex]
there is an upper specification of 3.150 in. on a dimension of a certain part after grinding.
We desire to have no more than 3% of the parts fail to meet specifications.
We have to find the maximum [tex]\mu[/tex] such that can be used if this 3% requirement is to be meet
[tex]\Rightarrow P(\frac{X- \mu}{\sigma} <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{0.002} )\leq 0.03[/tex]
We know from the Standard normal tables that
[tex]P(Z\leq -1.87)=0.0307\\\\P(Z\leq -1.88)=0.0300\\\\P(Z\leq -1.89)=0.0293[/tex]
So, the value of Z consistent with the required condition is approximately -1.88
Thus we have
[tex]\frac{3.15- \mu}{0.002} =-1.88\\\\\Rrightarrow \mu =1.88\times0.002+3.15\\\\=3.15[/tex]
which of the following equations have no soltuions? 4x+5=4x+5 -4x+5=-4x-5 5x+5=-4x-5 -4x+5=-4x-4 choose all the answers that apply
Answer:
2nd
Step-by-step explanation:
What is the probability that the hand is a two of a kind? A two of a kind has two cards of the same rank (called the pair). Among the remaining three cards, not in the pair, no two have the same rank and none of them have the same rank as the pair. For example, {4♠, 4♦, J♠, K♣, 8♥} is a two of a kind.
Question:
A 5-card hand is dealt from a perfectly shuffled deck of playing cards.
What is the probability that the hand is a two of a kind?
A two of a kind has two cards of the same rank (called the pair). Among the remaining three cards, not in the pair, no two have the same rank and none of them have the same rank as the pair. For example, {4♠, 4♦, J♠, K♣, 8♥} is a two of a kind.
Answer:
P(two of a kind) = 42.3%
Step-by-step explanation:
The probability that the hand is a two of a kind is given by
P(two of a kind) = No. of ways to produce two of a kind/Total no. of ways to deal 5-hand cards
There are total 52 cards in a standard deck of playing cards.
Total number of ways to deal 5-card hand is given by
Total number of ways = ₅₂C₅
Total number of ways = 2595960
So there are 2595960 different ways of dealing 5-card hands
Now we will find out the number of ways to produce two of a kind.
The number of ways to select the rank of two matching cards is given by
Rank of matching cards = ₁₃C₁ = 13
Since the matching cards must be of same rank.
The number of ways to select the rank of remaining 3 cards is given by
Rank of remaining 3 cards = ₁₂C₃ = 220
Since the remaining ranks are now 12.
The number of ways to select the suits of two matching cards is given by
Suits of two matching cards = ₄C₂ = 6
The number of ways to select the suits of 1st non-matching card is given by
Suits of 1st non-matching card = ₄C₁ = 4
The number of ways to select the suits of 2nd non-matching card is given by
Suits of 2nd non-matching card = ₄C₁ = 4
The number of ways to select the suits of 3rd non-matching card is given by
Suits of 3rd non-matching card = ₄C₁ = 4
Finally, the probability is
P(two of a kind) = No. of ways to produce two of a kind/Total no. of ways to deal 5-hand cards
P(two of a kind) = (₁₃C₁ × ₁₂C₃ × ₄C₂ × ₄C₁ × ₄C₁ × ₄C₁) / ₅₂C₅
P(two of a kind) = (13 × 220 × 6 × 4 × 4 × 4) / 2595960
P(two of a kind) = 1098240/2595960
P(two of a kind) = 0.423
P(two of a kind) = 42.3%
So I’m taking geometry online as a summer course since I failed my 1st semester. After completing it, when I return back to school do I have to take a test in order to advance and move on to another math?
Answer:
Since you are taking it online all the tests that you will have to do will be on there so as long as you pass the class you should be able to move on next school year. Good luck!
A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x. Find the break-even point and express it as an ordered pair in the form (x,y).
Answer:
The break-even point is when x is equal to 3.75
Step-by-step explanation:
At the break-even point, total cost function is equal to the total revenue function. In that regard, break-even is when;
C = 12x + 30 is equal to R = 20x.
thus, 12x + 30 = 20x
then, 12x - 12x + 30 = 20x - 12x
therefore, 30 = 8x
then, 30/8 = 8x/8
finally, x = 15/4 or 3.75
A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x, the Break even point is (3.75,75)
Given :
A stuffed animal business has a total cost of production C=12x+30 and a revenue function R=20x.
Break even point occurs when revenue = cost
R=C
Replace the expression and solve for x
[tex]R=C\\20x=12x+30\\20x-12x=30\\8x=30\\divide \; by \; 8\\x=\frac{15}{4}\\x=3.75[/tex]
Now we find out y using Revenue
[tex]R= 20x\\R=20(3.75)\\R=75[/tex]
So y is 75
Break even point is (3.75,75)
Learn more : brainly.com/question/15281855
In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized. Assume that the rate at which material is forgotten is proportional to the amount memorized. Suppose M denotes the total amount of a subject to be memorized and A(t) is the amount memorized in time t > 0. Determine a differential equation for the amount A(t) when forgetfulness is taken into account. (Assume the constants of proportionality for the rate at which material is memorized and the rate at which material is forgotten are k1 > 0 and k2 > 0, respectively. Use A for A(t).)
dA/dt =
Answer:
dA/dt = k1(M-A) - k2(A)
Step-by-step explanation:
If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)
Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:
Rate Memorized = k1(M-A)
Where k1 is the constant of proportionality for the rate at which material is memorized.
At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:
Rate forgotten = k2(A)
Where k2 is the constant of proportionality for the rate at which material is forgotten.
Finally, the differential equation for the amount A(t) is equal to:
dA/dt = Rate Memorized - Rate Forgotten
dA/dt = k1(M-A) - k2(A)
6 x 6 x 6 x 6 x 6 x 6 x 6= 6^x
Answer:
[tex] 6^7 [/tex]
Step-by-step explanation:
[tex]6 \times 6 \times 6 \times 6 \times 6 \times 6 \times 6 = 6^7 \\ [/tex]
Hey there!
6 * 6 * 6 * 6 * 6 * 6 * 6 ➡️ 6^7
= 36 * 36 * 36 * 6
= 1,296 * 36 * 6
= 46,656 * 6
= 279,936
Therefore, your answer is: 6^7
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
In a recent year, the Better Business Bureau settled 75% of complaints they received. You have been hired by the Bureau to investigate complaints this year involving computer stores. You plan to select a random sample of complaints to estimate the proportion of complaints the Bureau is able to settle. Suppose your sample size is 113. What is the probability that the sample proportion will be at most 2 percent more than the population proportion
Answer:
what
Step-by-step explanation:
The pool at the apartment building is 30 feet long, 20 feet wide, and 5 feet deep. It has been fikked 4 feet deep. How many more cubic feet of water are needed to finish filling the pool?
Answer:
600 cubic feet of water
Step-by-step explanation:
If the pool is filled 4 feet and the pool is 5 feet deep, that leaves 1 foot of depth left to fill. This makes the volume equation 30 x 20 x 1 which equals 600.
PLEASE HELP!!! Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i.e. "/") for all fractions (e.g. 1/2 for 12). m= _____ What would the perpendicular slope be? m= _____ Step 2: Use the slope to find the y-intercept of the perpendicular line. b= ____ Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10 y= ____ x+ Answer
Linear equations are typically organized in slope-intercept form:
[tex]y=mx+b[/tex]
m = slopeb = y-interceptPerpendicular lines have slopes that are negative reciprocals.
Example: 2 and -1/2Example: 3/4 and -4/3SolutionWe're given:
Perpendicular to [tex]4x-5y=-10[/tex]Passes through (6,3)1) Determine the slope
Let's first rearrange this equation into slope-intercept form:
[tex]4x-5y=-10\\-5y=-4x-10\\\\y=\dfrac{4}{5}x+2[/tex]
Notice how [tex]\dfrac{4}{5}[/tex] is in the place of m in y = mx + b. This is the slope of the give line.
Since perpendicular lines are negative reciprocals, we know the slope of the other line is [tex]-\dfrac{5}{4}[/tex]. Plug this into y = mx + b:
[tex]y=-\dfrac{5}{4}x+b[/tex]
2) Determine the y-intercept
We're also given that the line passes through (6,3). Plug this point into our equation and solve for b:
[tex]y=-\dfrac{5}{4}x+b\\\\3=-\dfrac{5}{4}(6)+b\\\\b=3+\dfrac{5}{4}(6)\\\\b=\dfrac{21}{2}[/tex]
Plug this back into our original equation:
[tex]y=-\dfrac{5}{4}x+\dfrac{21}{2}[/tex]
Answer[tex]y=-\dfrac{5}{4}x+\dfrac{21}{2}[/tex]
Each limit represents the derivative of some function f at some number a. State such an f and a in each case.
lim √9 + h - 3 / h
h-->0
Answer:
a = 0f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]limit of the function is 1/6Step-by-step explanation:
The general form representing limit of a function is expressed as shown below;
[tex]\lim_{h \to a} f(h)[/tex] where a is the value that h will take and use in the function f(h). It can be expressed in words as limit of function f as h tends to a. Comparing the genaral form of the limit to the limit given in question [tex]\lim_{h \to 0} \frac{\sqrt{9+h} - 3}{h}[/tex], it can be seen that a = 0 and f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]
Taking the limit of the function
[tex]\lim_{h \to 0} \frac{\sqrt{9+h} -3}{h}\\= \frac{\sqrt{9+0}-3 }{0}\\= \frac{0}{0}(indeterminate)[/tex]
Applying l'hopital rule
[tex]\lim_{h \to 0} \frac{\frac{d}{dh} (\sqrt{9+h} - 3)} {\frac{d}{dh} (h)}\\= \lim_{h \to 0} \frac{1}{2} (9+h)^{-1/2} /1\\=\frac{1}{2} (9+0)^{-1/2}\\= \frac{1}{2} * \frac{1}{\sqrt{9} } \\= 1/2 * 1/3\\= 1/6[/tex]
Enter the y-coordinate of the solution. Round to the nearest tenth. 5x+2y=7 -2x+6y=9
Answer:
59/34
Step-by-step explanation:
5x+2y=7
-2x+6y=9
Multiply the top equation by 3:
15x+6y=21
Subtract the second equation from the first:
17x=12
x=12/17
Plug this back into one of the other equations to find y:
5(12/17)+2y=7
60/17+2y=7
2y=59/17
y=59/34
Hope this helps!
What is the next term of this sequence? -5, 5, -6, 6, -7, 7, -8, ..
Answer:
8
Step-by-step explanation:
There are two series in one
-5, -6, -7, -8, ...and
5, 6, 7, and 8 is the next termWrite down the 1st term in the sequence given by:t(n) =n^2+4
Answer:
5
Step-by-step explanation:
t(1) = [tex]1^{2} + 4 = 5[/tex]
Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals.
a. .09
b. .6
c. .9
d. .3
Answer:
Answer D is correct
Please help! Correct answer only, please! Which of the following is one of the cheapest routes to pass through each vertex once starting and ending with Vertex "A" and using the Nearest Neighbor Algorithm. A. ABDCA, $890 B. ACDBA, $900 C. ABCDA, $960 D. None of the Above
Answer: c) ABCDA, $960
Step-by-step explanation:
The nearest Neighbor Algorithm states to choose the next vertex based only on the weights of the neighbor of that vertex.
Starting at A: Options are B = 220, C = 240, D = 310
Choose B because it has the smallest value.
From B: Options are C = 200, D = 210
Choose C because it has the smallest value.
From C: There is only one option --> D = 230 (we cannot choose A because it was our starting point and we haven't touched every vertex, yet).
From D: We touched all of the vertices so return to the starting point, A = 310
A → B → C → D → A --> 220 + 200 + 230 + 310 = 960
Notice that if we looked at the entire circuit first, this is NOT the optimum path. But this is the result using the Nearest Neighbor Algorithm.
Leah is 2 less than 3 times Rachel's age. 3 years from now, Leah will be 7 more than twice Rachel's age. How old will Rachel be in 3 years from now?
Answer:
15
Step-by-step explanation:
Let's call Leah's age l and Rachel's age r. We can write:
l = 3r - 2 (1)
l + 3 = 2(r + 3) + 7 (2)
Substituting (1) into (2) we get:
(3r - 2) + 3 = 2(r + 3) + 7
3r + 1 = 2r + 13
r = 12
In 3 years Rachel will be 12 + 3 = 15 years old.
The dean of the School of Fine Arts is trying to decide whether to purchase a copy machine to place in the lobby of the building. The machine would add to student convenience, but the dean feels compelled to earn an 10 percent return on the investment of funds. Estimates of cash inflows from copy machines that have been placed in other university buildings indicate that the copy machine would probably produce incremental cash inflows of approximately $14,000 per year. The machine is expected to have a three-year useful life with a zero salvage value. (Use appropriate factor(s) from the tables provided.)
Required:
Use Present Value PV of $1 to determine the maximum amount of cash the dean should be willing to pay for a copy machine. (Round intermediate calculations and final answer to 2 decimal places.)
Answer:
$34,816.60
Step-by-step explanation:
The computation of the maximum amount of cash should willing to pay for the copy machine by using the present value is shown below:
Present value is
[tex]= Incremental\ cash\ flows \times PVIFA\ factor[/tex]
where,
Incremental cash flows is $14,000 per year
Discount rate is 10%
And, the number of years is three years
PVIFA factor for 10% at 3 years is 2.4869
Refer to the PVIFA factor table
Now placing these values to the above formula
So, the present value is
[tex]= \$14,000 \times 2.4869[/tex]
= $34,816.60
there are 47 students in the science club. all but 5 of them went on a field trip to the planetarium. what is the total cost if each student who went on the field trip paid $7?
Answer:
$294
Step-by-step explanation:
First do 47-5=42
Next do 42x7=294
so the total is 294
3. A metal fabricating plant currently has five major pieces under contract each with a deadline for completion. Let X be the number of pieces completed by their deadlines, and suppose it's PMF p(x) is given by x 0 1 2 3 4 5 p(x) .05 .1 .15 .25 .35 .1 (a) Find and plot the CDF of X. (b) Use the CDF to find the probability that between one and four pieces, inclusive, are completed by their deadline
Answer:
a) The cumulative distribution function would be given by:
x 0 1 2 3 4 5
F(X) 0.05 0.15 0.30 0.55 0.9 1
b) [tex] P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85 [/tex]
And replacing we got:
[tex]P(1 \leq X \leq 4) =0.85[/tex]
Step-by-step explanation:
For this case we have the following probability distribution function given:
x 0 1 2 3 4 5
P(X) 0.05 0.1 0.15 0.25 0.35 0.1
We satisfy the conditions in order to have a probability distribution:
1) [tex] \sum_{i=1}^n P(X_i)=1[/tex]
2) [tex] P(X_i) \geq 0, i=1,2,..,n[/tex]
Part a
The cumulative distribution function would be given by:
x 0 1 2 3 4 5
F(X) 0.05 0.15 0.30 0.55 0.9 1
Part b
For this case we want to find this probability:
[tex] P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85 [/tex]
And replacing we got:
[tex]P(1 \leq X \leq 4) =0.85[/tex]
Helppppppppp?!!??please
Answer:
[tex]7.00[/tex]
Step-by-step explanation:
[tex]7.00+.48=7.48[/tex]
Answer:
The answer to the question is B) 7.00
Step-by-step explanation:
It says that
[tex]7.00 + 0.48=6.48[/tex]
But, That is wrong
So the correct version would be
[tex]7.00+0.48=7.48[/tex]
Hope this helps
what is the solution to linear system x-y=4 and x+y=2
Answer:
Step-by-step explanation:
x - y = 4
x + y = 2
2x = 6
x = 3
3 + y = 2
y = -1
(3, -1)
Which expression can be used to find 45% of 54?
Answer:
54 · 0.45
Step-by-step explanation:
This expression will give you 45% of 54, since 54 will be multiplied by the decimal equivalent to 45%
Answer:
0.45 · 54
Step-by-step explanation:
In math, 45% is equal to 0.45, because percents are out of a hundre. ’of’ is just another way of putting a multiplicative sign, so it would be 0.45 · 54
You have $150 to spend at a store. If you shoes cost $30 and belts cost $25, write an equation that represents the different ways that you could spend a total of $150
Answer:
you could buy a pair of shoes and a belt still have 95 dollars to spend
Isaac is organizing a 5-kilometer road race. The safety committee
recommends having a volunteer every 1 of a kilometer and at
the finish.
| Are 10 volunteers enough?
Answer:
10 volunteers are more than recommendedStep-by-step explanation:
The recommended number of volunteers is five (5)
Since the the distance of the race is 5km,
and the safety committees recommends 1 volunteer per kilometre.
Hence ten (10) volunteers is more than enough
8x - 4 < - 12 or 8x + 7 >23 i need help to find answer
Answer:
x>4/3 and x<1
Step-by-step explanation:
8x-4 < -12
8x<-12+4
x<8/8
x<1
8x+7> 23
8x>23-7
x>12/8
simplify : x>4/3
Dan buys a car for £2100.
It depreciates at a rate of 2.2% per year.
How much will it be worth in 6 years?
Give your answer to the nearest penny where appropriate.
Answer:
£472.92
Step-by-step explanation:
£2100(0.78)^6
Suppose we roll 10 fair six sided dice
What is the probability that there are exactly two 2’s showing ?
Answer: 40%
Step-by-step explanation:
What’s the correct answer for this question?
Answer:
Step-by-step explanation:
the event of drawing a spade card