in a right triangular prism the area of the Triangular base is 12 square centimeters the height of the prism is 7 cm what is the volume of the prism?

A) 60cm³

B) 84cm³

C) 72cm³

D) 98cm³​

In A Right Triangular Prism The Area Of The Triangular Base Is 12 Square Centimeters The Height Of The

Answers

Answer 1

Answer:

84cm cubic.

Step-by-step explanation:

That is how it is done.Hope it will help.

In A Right Triangular Prism The Area Of The Triangular Base Is 12 Square Centimeters The Height Of The

Related Questions

Help Please 100 pts for the answer! Need answer ASAP

Answers

Answer:

-25/1 or -25

Step-by-step explanation:

Answer:

-25/1 or -25

Step-by-step explanation:

there hope this will help a lot

What is 87 x (495 - 475) + 1084 - 864

Answers

Answer:

1960

Step-by-step explanation:

First, carry out the operation inside the parentheses: 495-475= 20. Next, follow the order of operations and do 87*20= 1740. Then, go from left to right, adding 1740 + 1084= 2824. Now, subtract all of that by 864. 2824-864= 1960.

Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.
.

Answers

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4)  so 2 x 2 x 5 x 4 = 80.

One week Culver earned $375.50 regular pay and $65.50 overtime pay. His net pay for the week was $230.90. How much did he have withheld for deductions?

Answers

Answer:

He had $210.1 after deductions.

Step-by-step explanation:

Add his regular pay and overtime pay together

$375.50 + $65.50 = $441

Now subtract his net pay from the total that he makes before deductions - with his overtime and regular pay.

$441 - $230.90 = $210.1

Which of the following is equivalent to the expression below? (2^5)(2^6)
(A) 2^11
(B) 2^30
(C) 4^11
(D) 4^30

Answers

Answer:

(A) 2^11

Step-by-step explanation:

2^11. These are like bases, which means you can add the exponents. You can not do this if the base, in this case 2, is not the same. You can also not add, for example, 2^3 + 2^4 does not equal 2^7.

Ralph is on a diet. He currently weighs 248
pounds. How many pounds would he need
to lose if he wishes to weigh at most 195
pounds?

Answers

Answer:

53

Step-by-step explanation:

248-195 is 53

you should take his weight and then subtract the amount he wants to weigh

Answer:

53 pounds

Step-by-step explanation:

248 minus 195 which gives you 53

He needs to lose 53 pounds.

Hope that helped!

3. Rich has t dollars in his checking account. On June 3, he deposited
w, h, and v dollars, and cashed a check for k dollars. Write an alge-
braic expression that represents the amount of money in his account
after the transactions.

Answers

b=(t-whv)+k
b = his end total after the transactions

Consider the function g(x) shown below over a domain of [1,∞).

g(x) = 2(x – 1)2 – 3

Part A
Determine g–1(x).


Part B
Identify the domain and range of g(x) and g–1(x). Represent the domains and ranges in inequality, interval, and set notation. Describe the relationship between the domains and ranges of g(x) and g–1(x).


Part C
Graph g(x) and g–1(x). Describe the relationship between the graphs of g(x) and g–1(x).

Answers

The inverse of a function may or may not be a function

The function g(x) is given as:

[tex]g(x) = 2(x - 1)^2 - 3[/tex]

(a) Inverse function g^-1(x)

We have:

[tex]g(x) = 2(x - 1)^2 - 3[/tex]

Replace g(x) with y

[tex]y = 2(x - 1)^2 - 3[/tex]

Swap the positions of x and y

[tex]x = 2(y - 1)^2 - 3[/tex]

Add 3 to both sides

[tex]x + 3 = 2(y - 1)^2[/tex]

Divide both sides by 2

[tex]\frac{x + 3}2 = (y - 1)^2[/tex]

Take square roots of both sides

[tex]\sqrt{\frac{x + 3}2} = y - 1[/tex]

Add 1 to both sides

[tex]1 + \sqrt{\frac{x + 3}2} = y[/tex]

Rewrite as:

[tex]y = 1 + \sqrt{\frac{x + 3}2}[/tex]

Express as inverse function of g

[tex]g^{-1}(x) = 1 + \sqrt{\frac{x + 3}2}[/tex]

Hence, the inverse function of g is [tex]g^{-1}(x) = 1 + \sqrt{\frac{x + 3}2}[/tex]

(b) The domain, and the range of g(x) and g^-1(x)

Function g(x)

The function g(x) is a quadratic function.

So, the domain is:

Inequality: [tex]-\infty < x < \infty[/tex]Interval: [tex](-\infty ,\infty)[/tex]Set: {R}

The range is:

Inequality: [tex]f(x) \ge -3[/tex]Interval: [tex][-3 ,\infty)[/tex]Set: [tex]\{y|y\ge -3\}[/tex]

Function g^-1(x)

The function g^-1(x) is a square root function.

So, the domain is:

Inequality: [tex]x \ge -3[/tex]Interval: [tex][-3 ,\infty)[/tex]Set: [tex]\{x|x\ge -3\}[/tex]

The range is:

Inequality: [tex]-\infty < y < \infty[/tex]Interval: [tex](-\infty ,\infty)[/tex]Set: {R}

The domain of g(x) is the range of g^-1(x), while the range of g(x) is the domain of g^-1(x).

(c) The graph

See attachment for the graph

Read more about inverse functions at:

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Find DY if PY= 6
and DP= 10.

Answers

The relationship between sides DY, PY and DP is that they form a right-angled triangle.

The value of side length DY is 8 units

Side length DY can be calculated using the following Pythagoras theorem.

So, we have:

[tex]DP^2 =DY^2 + PY^2[/tex]

Substitute values for DP, DY and PY

[tex]10^2 =DY^2 + 6^2[/tex]

Evaluate the squares

[tex]100 =DY^2 + 36[/tex]

Subtract 36 from both sides

[tex]64 =DY^2[/tex]

Take square roots of both sides

[tex]8 =DY[/tex]

Rewrite as:

[tex]DY = 8[/tex]

Hence, the value of side length DY is 8 units

Read more about Pythagoras theorems at:

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What is 2/3, 7/6, 3 1/9, and 5 5/18 written as a decimal?

Please give an explanation and a correct answer!

I will give brainliest to whoever answers first!

Answers

Step-by-step explanation:

[tex] \frac{2}{3} = 2 \times \frac{1}{3} = 2 \times 0.333 = 0.666 \\ \\ \frac{7}{6} = 7 \times \frac{1}{6} = 7 \times \frac{1}{2} \times \frac{1}{3} = 7 \times 0.5 \times 0.333 = 1.1655 \\ \\ 3 \frac{1}{9} = 3 + \frac{1}{9} = 3 + ( \frac{1}{3} \times \frac{1}{ 3} ) = 3 + (0.333 \times 0.333) = 3 \times 0.11088 = 3.11088 \\ \\ 5 \frac{5}{18} = 5 + (5 \times \frac{1}{18} ) = 5 + (5 \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{2} ) = 5 +(5 \times 0.333 \times 0.333 \times 0.5) = 5 + 0.27722 = 5.27722[/tex]

Ok done. Thank to me :>

i need atleast 5 volunteers for the magic trick

Answers

What magic trick??

Are you gonna do a magic??

Sorry for a lot of questions.

helppppppppppppppppppppppppppppppppppppppp

Answers

4 in each and 2 left

A rental car company charges $35 per day to rent a car and $0.15 for every mile driven. Enola wants to rent a car, knowing that:
She plans to drive 450 miles.
She has at most $260 to spend.

Write and solve an inequality which can be used to determine xx, the number of days Enola can afford to rent while staying within her budget.

Answers

Answer:

260≤67.5+35x

Step-by-step explanation:

A number is les than or equal to -11

Answers

Answer:

-12 is the answer for this question

Step-by-step explanation:

make me as brainlist

Answer:

[tex]x\leq-11[/tex]

Step-by-step explanation:

Need help ASAP!!!!!!​

Answers

Answer:

graph b

Step-by-step explanation:

I need help plz asp

Answers

9

Step-by-step explanation:

woody is 5

buzz is 3

mr potato head is 3

rex is 7

alien is 1

show that
[tex] \frac{2}{3 + \sqrt{7} } = 3 - \sqrt{7} [/tex]
I don't know what to do
please help with the steps.
for brainliest ​

Answers

Answer:

  multiply by (3-√7)/(3 -√7) and simplify

Step-by-step explanation:

When there are radicals or complex numbers in the denominator, you can rewrite the expression so it has a real, rational denominator. You do this by multiplying numerator and denominator by the conjugate of the denominator. That value is the denominator with its sign changed.

This takes advantage of the factoring of the difference of squares.

  (a -b)(a +b) = a² -b²

__

  [tex]\dfrac{2}{3+\sqrt{7}}=\dfrac{2}{3+\sqrt{7}}\times\dfrac{3-\sqrt{7}}{3-\sqrt{7}}=\dfrac{2(3-\sqrt{7})}{3^2-(\sqrt{7})^2}=\dfrac{2}{9-7}\times(3-\sqrt{7})\\\\=\boxed{3-\sqrt{7}}[/tex]

what is (2i)^2? and is it a real or imaginary number?

Answers

Answer:

4i

Step-by-step explanation:

Distribute the 2, you get 4i.

It's imaginary because it has an i with it

Answer:

-4, real

Step-by-step explanation:

Hi there!

‘i’ is characterized as the sqrt of -1 or, alternatively, i^2= -1

If the problem is asking us to square i, then we know that it is going to equal -1. If we distribute the exponent, we would also square the 2, making it become 4. Now that we have done that, we multiply -1 and 4 to get a final answer of -4. This would be a real number as it is not imaginary.

I hope this can help!

how to do theoretical probability on calculator

Answers

Answer:

below!

Step-by-step explanation:

Theoretical probability is used in mathematics to express the likelihood that a specific phenomenon will occur. Learn about the definition, formula, and real-world examples of theoretical probability like which flavor gumball a machine is most likely to dispense

An airplane is 280 feet long. Charlie makes a scale model of the airplane at 1:140 of its actual size. How long is the model?

Answers

Answer:

2 feet long

Step-by-step explanation:

Is x+2y=6
2x-3y=26
have no solution,one solution, or infinity many solution

Answers

Answer:

1

Step-by-step explanation:

x + 2y = 6, multiply by 2 = 2x + 4y = 12

2nd equation:                    2x - 3y = 26

It has one solution

Answer: One solution

Step-by-step explanation:

Convert both equations into slope-intercept form:

x+2y=6

2y=6-x

[tex]y=\frac{6-x}{2}[/tex]

Slope = 6/2 = 3

2x-3y=26

y=2x-26/3

Slope = 2/3

Therefore, he system of equations have one solution because their slopes are not equal.  

The quotient of 45% -31. - 15) and a polynomial is (-3). What is the pokyrıcaiak
A
Ox5% -6% -30% * 944 45
0-5
O % 45
O % * 5% 46% - 30% * 944 45

Answers

Answer:

A

Step-by-step explanation:

A function f(x) is graphed on the coordinate plane.

What is the function rule in slope-intercept form?


Enter your answer in the box below.

f(x) = ____



Answers

Answer:

mx+b

Step-by-step explanation:

One way to express linear function rules is called slope-intercept form. Sometimes, f(x)=mx+b is used. In either case, m and b describe the general characteristics of the line. m indicates the slope, and b indicates the y-intercept.

The required function of the line would be y = 2x + 1 which is shown in the given graph.

What is the function rule in slope-intercept form?

The slope-intercept form is one rule to represent linear function rules. f(x)=mx+b is sometimes used. In any scenario, m and b describe the line's overall features. The slope is denoted by m, while the y-intercept is denoted by b.

According to the given figure,

We clearly see that the coordinates of the y-intercept would be (0, 1).

The value of the x-coordinate is 1 when y-coordinate is 3.

Here the line passes through points (0, 1) and (1, 3).

Let the required linear function would be y - y₁ = (y₂ - y₁)/(x₂ -x₁ )[x₂ -x]

x₁ = 0, y₁ = 1

x₂ = 1, y₂ = 3

⇒ y - y₂ = (y₂ - y₁)/(x₂ -x₁ )[x -x₂]

⇒ y - 3 = (3 - 1)/(1 - 0 )[x -1]

⇒ y - 3 = (2)[x -1]

⇒ y - 3 = 2x - 2

⇒ y = 2x - 2 + 3

⇒ y = 2x + 1

Therefore, the required function of the line would be y = 2x + 1 which is shown in the given graph.

Learn more about the Linear function here:

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What is the smallest integer $k>2000$ such that both $\dfrac{17k}{66}$ and $\dfrac{13k}{105}$ are terminating decimals?.

Answers

The smallest integer greater than 2000 for both the fractions [tex]\frac{17k}{66} \ and \ \frac{13k}{105}[/tex] to be terminating decimals is 2079.

Given

K is greater than 2000.

[tex]k&gt; 2000\\[/tex].

Given fractions are

[tex]\dfrac{17k}{66} \ and \ \dfrac{13k}{105}[/tex].

How to find the smallest integer greater than 2000 for the fractions to be terminating decimals?

In order for the decimal equivalents to be terminating, the only factors that can remain in the denominators are 2 and 5.

Here, the given denominators are 66 and 105 respectively.

Now factors of 66 will be 2,3,11.

And the factors of 105 will be 3,5,7.

So, the value of k must be multiples of 3, 7, and 11. The LCM of these numbers will be,

[tex]3\times 7\times 11=231[/tex]

Now the value of K must be greater than 2000, so the multiple of 231 which is greater than 2000 is its [tex]9^{th}[/tex] multiple,

[tex]231\times9=2079[/tex]

Hence 2079 is the smallest integer greater than 2000 for both the fractions [tex]\frac{17k}{66} \ and \ \frac{13k}{105}[/tex] to be terminating decimals.

For more details on terminating decimals follow the link:

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if we changed the –0.14 to a 2 in the equation, what would happen to the graph?

Answers

If -0.14 is changed to 2, the graph would become a positive graph, or it would be steeper, because it has a positive slope

The equation of the graph is given as:

[tex]y = -0.14x + 3[/tex]

The above equation is a linear equation, which is represented as:

[tex]y =mx + c[/tex]

Where m represents the slope of the linear equation.

By comparison, we have:

[tex]m = -0.14[/tex]

i.e. the slope of the equation [tex]y = -0.14x + 3[/tex] is -0.14

When -0.14 is replaced with 2, the equation becomes

[tex]y = 2x + 3[/tex]

And the slope of the new equation [tex]y = 2x + 3[/tex] is

[tex]m =2[/tex]

2 is greater than -0.14, and 2 is positive.

This means that the graph would become a positive graph, or it would be steeper, because it has a positive slope

Read more linear equations at:

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In \triangle KLM,△KLM, \overline{KL}\cong \overline{MK} KL ≅ MK and \text{m}\angle M = 43^{\circ}.m∠M=43 ∘ . Find \text{m}\angle L.m∠L.

Answers

Based on the definition of an isosceles triangle, the measure of angle L is: 43°

Recall:

An isosceles triangle has two side lengths that are equal in size, and also the angles opposite the equal sides are congruent.

Given that KL ≅ MK in △KLM, it means △KLM is an isosceles triangle.

If m∠M = 43°, therefore, m∠M = m∠L (equal angles directly opposite KL and MK).

This implies that: m∠L = 43°

In summary, based on the definition of an isosceles triangle, the measure of angle L is: 43°

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pls help on my maths question

Answers

Answer:

Somewhat illegible but looks like the equation should be:

S = u t + 1/2 a t^2

100 = 20 + 1/2 * a * 4    where t = 2

a* 4 = 160

a = 40

Roberto is a fan of the Los Angeles Angels baseball team. Since he works at night he only

goes to day games. Last year he attended all 16 home day games and saw his team win 11

and lose only 5 games, for a winning percentage of 68.8%. In their other games the team won

69 and lost 77, for a winning percentage of 47.3%.


Even though the p-value for a test

comparing these winning percentages is very small, explain how confounding prevents us

from concluding that Roberto’s attendance at those games is the cause of the Angels success

in those games.

Answers

Step-by-step explanation:

There are other factors than Roberto coming that could have affected the outcome of the game. For example, maybe the night games were against better teams to generate better ratings in prime time. Moreover, maybe the Angels do better at home due to home-field advantage. There are many factors such as these that could explain why Roberto witnessed such a high win rate at the games he went to, so it cannot be concluded that Roberto's attendance caused the Angels to win.

estimate quotients using compatible numbers lesson 4.5 answer key

Answers

4 its the correct answer do it

Step-by-step explanation:

its correct

Using ruler and compasses only, construct a parallelogram KLMN, so that KL = 8 cm, LM = 6 cm and angle KLM = 135°.​

Answers

The steps to construct a parallelogram using a ruler and a compass are;

1. Draw a starting line segment l linger than 8 cm.

2. Mark point K on the line segment.

3. Widen the compass to a radius of 8 cm using the ruler.

4. Place the compass at point K and with the 8 cm radius mark point L on the line l.

5. At point L construct a 45° angle as follows;

Draw arcs that intersect line l on both sides of point L.From each of the intersection points, draw arcs that intersect each other on on the upper area adjacent to line l.From the intersection point in the previous step, draw a line to point L to get a perpendicular line to line l.Draw arcs to intersect the perpendicular line and line l on the other side of point L from K.From the points the arc intersects the perpendicular line draw arcs of the same radius to intersect at a point X to the right of the perpendicular line.

The above steps bisects the 90° angle of the perpendicular lines.

Join point X to point L with a straight line to form ∠XLM = 135° (90° + 45° = 135°)

6. Adjust the radius of the compass to give an opening of 6 cm and from point L draw an arc to intersect XL at M.

7. At point M construct a line YM at 45° angle to the line l.

8. From point M draw an arc to intersect YM and label the point as point N.

9. Join point M and N to complete the construction of the parallelogram KLMN.

Learn more about construction using a compass and a ruler here:

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