in a hydraulic garage the small piston has a radius of 5 cm and the large piston has radius of 15 cm what force must be applied to the small piston in order to lift a car weighting 20000 N on the large piston

Answer:

Explanation:

The relation between orbital period T and orbital radius R is as follows .

T² ∝ R³

T ∝ R¹°⁵

So time period of orbit is proportional to radius of orbit . Higher the height , larger the orbital period . As the orbital period is larger than required , the altitude of satellite must have been larger than required .

As mass of satellite  is not involved in the formula of orbital period , this is independent of mass of the satellite .

Hence the option C is correct .

Answer:

Explanation:

When two north magnetic poles are  placed close to each other , they will repel each other . If distance between them is increased due to mutual repulsion from x to 12 x , work is done by the magnetic field . This results in decrease of magnetic field energy .

Hence , when the distance between the poles becomes 12x from x , the magnitude of the field energy between them decreases .

Answer:

8.5 hours

Explanation:

Answer:

The time that passes until the police catch the speeder is 82.6204 seconds.

Explanation:

A body performs a uniformly accelerated rectilinear motion or uniformly varied rectilinear motion when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases its modulus in a uniform way.

The position is calculated by the expression:

x = x0 + v0*t + 1/2*a*t²

where:

First, let’s look at the police car’s equations of motion. In this case:

So: x = 50 m/s*t + 1/2*2 m/s²*t²

Now for the speeder’s car’s equations of motion you know:

So: x = 3,000 m + 55 m/s*t + 1/2*1 m/s²*t²

When the police catch the speeder they are both in the same position. So:

50 m/s*t + 1/2*2 m/s²*t²= 3,000 m + 55 m/s*t + 1/2*1 m/s²*t²

Solving:

0= 3,000 m + 55 m/s*t + 1/2*1 m/s²*t² - 50 m/s*t - 1/2*2 m/s²*t²

0= 3,000  + 55 *t + 1/2*t² - 50*t - 1*t²

0= 3,000  + 55 *t - 50*t - 1*t² + 1/2*t²

0= 3,000  + 5*t - 1/2*t²

Applying the quadratic formula:

[tex]x1,x2=\frac{-5+-\sqrt{5^{2}-4*(-\frac{1}{2})*3000 } }{2*(-\frac{1}{2} )}[/tex]

x1= -72.6209

and x2= 82.6209

Since you are calculating the value of a time and it cannot be negative, then the time that passes until the police catch the speeder is 82.6204 seconds.

Answer:

100 Kg * 3.5 m/sec = 350 Kg-m/s

Explanation:

Momentum= F= Δ(mv) with m= mass, v= velocity, and Δ the change in mass and velocity

In this problem you are given all the factors you need to solve the equation you simply just plug in  your mass (1,000 Kg) and Velocity (3.5m/s) and multiply them by each other to get your answer

Answer:

Explanation:

The answer is "Infrared"

Hope this helps

Answer:

x-rays

Explanation:

Answer:

i). (a) in the same direction as , (d) lower

ii). (f) opposite the direction of, (g) higher

Explanation:

An proton may be defined as a sub atomic particle and it has a positive electrical charge. Its mass is slightly less than that of a neutron. When a proton is placed in an electrical field that is uniformly charged, it is at rest. When the proton first moves out from rest from the uniform electric field, it will move in a direction which is same as that of the electric field and it will move to a region of higher potential.

An electron is defined as the subatomic particle having negative electric charge. When an electron is released form rest from an uniform electric field, it will move in the opposite direction of the uniform electric field and will move to the region of lower electric potential.

Answer:

1.5 * 10^-2 Tm^2

Explanation:

Electric Flux = B.A cos(theta)

B = 0.055 T

A = 0.32 m^2

theta = 30

Electric Flux = (0.055 T).(0.32 m^2).Cos(30) = 0.0152 = 1.5 * 10^-2 Tm^2

Kinetic energy = mv²

Therfore kinetic energy =14175 joule

Answer:

Distance, S = 440 meters.

Explanation:

Given the following data;

Initial velocity, u = 17m/s

Time, t = 20 seconds

Final velocity, v = 27m/s

To find the distance;

First of all, we would determine the acceleration of the truck.

Acceleration = (v-u)/t

Substituting the given values into the equation, we have;

Acceleration = (27 - 17)/20

Acceleration = 10/20

Acceleration = 0.5m/s²

Now, we would use the second equation of motion to find the distance traveled.

S = ut + ½at²

S = 17*20 + ½*0.5*20²

S = 340 + 0.25*400

S = 340 + 100

S = 440m

The equations of motion can be used to obtain the distance covered as 440 m.

We have to use of the equations that are used for uniformly accelerated motion in solving the problem. The chosen equation must be;

v^2 = u^2 + 2as and v = u + at

v = final velocity

u = initial velocity

a = acceleration

s = distance

To obtain the acceleration;

27 = 17 + 20(a)

27 - 17 = 20a

a = 0.5 ms-2

Now, to obtain the distance;

v^2 = u^2 + 2as

v^2 - u^2/as = s

s = (27)^2 - (17)^2/2(0.5)

s = 440 m

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Answer:

[tex]4.77\ \text{A}[/tex]

Explanation:

F = Magnetic force = 4.11 N

[tex]I_n[/tex] = Net current

[tex]I_2[/tex] = Current in one of the wires = 7.68 A

B = Magnetic field = 0.59 T

[tex]\theta[/tex] = Angle between current and magnetic field = [tex]65^{\circ}[/tex]

[tex]l[/tex] = Length of wires = 2.64 m

[tex]I[/tex] = Current in the other wire

Magnetic force is given by

[tex]F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}[/tex]

Net current is given by

[tex]I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}[/tex]

The current I is [tex]4.77\ \text{A}[/tex].

Answer:

Explanation:

Kinetic energy ( KE ) = 1/2 m v²

= m²v² / 2 m = p² / 2m where p is momentum

KE = p² / 2m

p² = 2m KE

KE is constant

p is proportional to mass

So car having higher mass will have higher momentum .

p₁ = √ ( 2 m x KE )

p₂ = √ ( 6 m x KE )

p₂ - p₁ =  √ ( 6 m x KE ) - √ ( 2 m x KE )

= √KE m ( √6 - √2 )

Kinetic energy ( K.E )

[tex]= \frac{1}{2} m v^2\\\\= \frac{m^2 v^2}{2 m} \\\\= \frac{p^2}{2m}[/tex]

where p is momentum

[tex]K.E =\frac{p^2}{2m}\\\\p^2 = 2m. KE[/tex]

KE is constant

p is proportional to mass

So car having higher mass will have higher momentum .  

[tex]p_1 =\sqrt{(2m*K.E)}\\\\p_2 = \sqrt{(6m*K.E)} \\\\p_2 - p_1 = \sqrt{(6m*K.E)} -\sqrt{(2M*K.E} \\\\p_2 - p_1 = \sqrt{K.E m(\sqrt{6}-\sqrt{2}) }[/tex]

The difference is shown above.

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Answer:

[tex]a=20.14\ m/s^2[/tex]

Explanation:

The time period of the simple pendulum is given by :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

l is the length of the pendulum

g is the acceleration due to gravity

We have,

T = 1.4 s, l = 1 m

So,

[tex]T^2=\dfrac{4\pi^2 l}{g}\\\\g= \dfrac{4\pi^2 l}{T^2}\\\\g= \dfrac{4\pi^2 \times 1}{(1.4)^2}\\\\g=20.14\ m/s^2[/tex]

So, the acceleration due to gravity of that planet is [tex]20.14\ m/s^2[/tex].

Answer:

Explanation:

Force of friction = μ N , where μ is coefficient of friction , N is normal force on the body .

a )

Given,

Normal force N = 400 N

Force of friction = 300 N

μ = coefficient of static friction = ?

Putting the values ,

300 = 400 μ

μ = .75

b )

Normal force N = 400 N

Force of friction = 200 N

μ = coefficient of kinetic  friction = ?

Putting the values ,

200 = 400 μ

μ = .50

c ) see attached file .

Answer:

The balls velocity is 1 divided by 3

The velocity of the ball is 18.85 m/s.

The ball’s centripetal acceleration is 236.87 m/s².

The ball's centripetal force is  118.44 Newton.

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Given parameters:

length of the string: l = 1.5 meters.

Time interval = 60 seconds.

Total number of complete rotation = 120.

Hence, the velocity of the ball = 120×2π×1.5/60 m/s

= 18.85 m/s.

The ball’s centripetal acceleration = (velocity)²/ radius

= (18.85)²/1.5 m/s²

= 236.87 m/s²

The ball's centripetal force = mass × centripetal acceleration

= 0.5 × 236.87 Newton

= 118.44 Newton

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Answer:

This is somewhat of a confusing question.

 Zero potential energy is usually used to refers to the zero potential energy of objects at infinity. Thus, bringing an object from infinity requires negative work because work is done by the object. One could also choose the pivot point of the pendulum as zero potential. Then any objects above the pivot point would be at a positive potential, and objects below the pivot point would have a negative potential (the object does work moving to a point of lower potential).

 Basically, work done "on" an object requires positive potential energy input while work done "by" the object requires negative energy input.

 Those are the basic considerations in solving potential energy problems.

Answer:

*The work of the Normal (N) y Wy are zero  answer a

*The work of the applied force (F1)  is positive answer c

*The work of the friction force (fr) is negative, answer b

*The work of the Wy isnegative, answer d

Explanation:

In this exercise it is asked to identify the type of work, unfortunately the diagram cannot be seen, but in the attached we can see the diagram of a body moving upward on an inclined plane, the existing forces are shown.

As the body moves at constant speed the accelerations are zero. Let's look for the job that is defined

           W = F. d

            W = F d cos θ

where the dot represents the dot product and the bold letters are vectors.

* The work of the Normal (N) and the y component of the weight (Wy) are zero because they are perpendicular to the motion

    answer a

* The work of the applied force (F1) is positive because it is in the same direction of motion

        W = F1 Δx

answer c

* The work of the friction force (fr) is negative because the force in the displacement have opposite directions

        W = -fr Δx

answer b

* the work the x component of the weight (Wx) in this case is negative

answer d

Answer:

distance travelled by the block is 0.796 m

{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }

Explanation:

Given that;

mass of block m = 0.200 kg

distance travelled d = 0.796 m

time t = 2.00 s

m₂ = 0.400 kg

If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?

Now, using the second equation of motion;

d = ut + ([tex]\frac{1}{2}[/tex] × at²)

as the object started from rest, u=0

so, we substitute

0.796  = 0×2 + ([tex]\frac{1}{2}[/tex] × a(2)²)

0.796  = 0 + ([tex]\frac{1}{2}[/tex] × 4a)

0.796  = 2a

a = 0.796 / 2

a = 0.398 m/s²

using first equation of motion

[tex]V_{f}[/tex] = u + at

we substitute

[tex]V_{f}[/tex] = 0 + 0.398 × 2

[tex]V_{f}[/tex] = 0.796 m/s

now, average velocity is given as;

[tex]V_{avg}[/tex] = ( 0.796 m/s  + 0 ) / 2

[tex]V_{avg}[/tex] = ( 0.796 m/s  + 0 ) / 2

now, distance as the block moves in 2s will be;

D = [( 0.796 m/s  + 0 ) / 2 ] × 2

D = 0.796 m

Therefore, distance travelled by the block is 0.796 m

{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }

The distance traveled by the object with the uniform motion can be given by the second equation of the motion.

The distance traveled by the big block with weight in 2 seconds is.

What is second equation of motion?

The distance traveled by the object with the uniform motion can be given by the second equation of the motion. It can be given as,

[tex]s=ut+\dfrac{1}{2} at^2[/tex]

Given information-

The mass of the small block is 0.200 kg.

The total distance traveled by the block is 0.796.

Initial velocity of small block is zero.

Total time taken by the block to travel this distance is 2 seconds.

Put the values in the above equation as,

[tex]0.796=0\times 2+\dfrac{1}{2} a\times 2^2\\0.796=2a\\a=0.398[/tex]

Thus the acceleration of the small block is 0.398 meter per second.

Now the mass is doubled which is, 0.400 kg. As the acceleration does not depends on the mass, thus the acceleration for both cases is 0.398.

The velocity of the big block can be given as,

[tex]V=u+0.398\times2\\V=0+0.796\\V=0.796[/tex]

The velocity of the big block is 0.796.

The average velocity of the big block is given by,

[tex]V_{avg}=(\dfrac{0.796+0}{2} })\\V_{avg}=0.398[/tex]

The distance traveled by the object is the ratio of the velocity of the body to the time taken by it. Thus the distance traveled by the big block in 2 seconds is,

[tex]d={{0.398} \times2}\\d=0.796[/tex]

Thus the distance traveled by the big block with weight in 2 seconds is.

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Answer:

Explanation:

individual and then net

hope that helps I could be wrong about this one though

Answer:

Explanation:

Power, by definition, is the amount of work per unit of time. We arent given work in this question, but we can find it because work is how much force per unit of distance.

[tex]P=\frac{W}{t_f-t_i} =\frac{F*d}{t_f-t_i}[/tex]

Plug in all the values, and its algebra at this point

[tex]500=\frac{F*96}{12}[/tex]

6000 = 96F

F = 62.5 Newtons

The force which is being applied to the object with the power of 500 Watt is 62.5 N.

Power can be defined as the rate of doing work. It is the work done in unit time. The SI unit of power is Watt (W) which is equal to joules per second (J/s). Sometimes, the power of motor vehicles and other machines is given in terms of Horsepower (hp), This unit is approximately equal to 745.7 watts of power.

The power of a system can be calculated as the product of force applied and distance travelled by the system per unit time taken.

Therefore, the force of the object with power 500W can be calculated as:

P = f × d/ t

where, P = Power of the object,

f = Force applied,

d = distance travelled,

t = time taken to cover the distance

f = (P × t)/ d

f = (500 × 12) / 96

f = 6000/ 96

f = 62.5 N

Therefore, the force which is being applied to the object is 62.5N (Newton).

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Answer:

miami because it is closer to the equator26. cleveland because of its location 27. The top of the atmosphere absorbs and reflects the radiation before it can reach the surface.Explanation:

In the month of June and July, Cleveland will have solar radiation more than that of Miami.

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Answer:

Water > Box of books > Stone > Ball

Explanation:

We'll begin by calculating the potential energy of each object. This can be obtained as follow:

For stone:

Mass (m) = 15 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 3 m

Potential energy (PE) =?

PE = mgh

PE = 15 × 10 × 3

PE = 450 J

For water:

Mass (m) = 10 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 9 m

Potential energy (PE) =?

PE = mgh

PE = 10 × 10 × 9

PE = 900 J

For ball:

Mass (m) = 1 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 20 m

Potential energy (PE) =?

PE = mgh

PE = 1 × 10 × 20

PE = 200 J

For box of books:

Mass (m) = 25 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 2 m

Potential energy (PE) =?

PE = mgh

PE = 25 × 10 × 2

PE = 500 J

Summary:

Object >>>>>>>> Potential energy

Stone >>>>>>>>> 450 J

Water >>>>>>>>> 900 J

Ball >>>>>>>>>>> 200 J

Box of books >>> 500 J

Arranging from greatest to least, we have:

Object >>>>>>>> Potential energy

Water >>>>>>>>> 900 J

Box of books >>> 500 J

Stone >>>>>>>>> 450 J

Ball >>>>>>>>>>> 200 J

Water > Box of books > Stone > Ball

Answer:

The answer is below

Explanation:

Let us assume that the slower truck which is the FedEx truck travels d mile. The pass started when the Walmart truck was 45 ft behind the FedEx truck and ended when the Walmart truck is 45 ft in front of the FedEx truck.

The additional distance covered by the truck Walmart = 45 ft + 60 ft (length of FedEx truck) + 45 ft = 150 ft

1 mile = 5280 ft

150 ft = 150 ft * 1 mile/5280 ft = 0.0284 mile

Therefore the Walmart truck covered an additional 0.0284 mile. Hence the distance covered by the walmart truck = d + 0.0284

Let us say it took t hours for the pass to be completed. Hence:

For FedEx; 53 mph = d / t.   t =d / 53

For Walmart; 61 mph = (d + 0.0284) / t.   t = (d + 0.0284) / 61

Since it took the trucks the same time. Hence:

d / 53 = (d + 0.0284) / 61

61d = 53d + 1.506

8d = 1.506

d = 1.506/8

d = 0.1882 mile = 993.75 ft

The FedEx truck traveled 993.75 mile while the Walmart truck traveled 1143.75 ft (993.75 + 150 ft)

The time (t) = d / 53 = 0.1882 / 53

t=0.00355 h = 12.8 seconds

Frequency = (speed) / (wavelength)

Frequency = (3 x 10⁸ m/s) / (124 x 10⁻⁹ m)

Frequency = 2.42 x 10¹⁵ Hz

Answer:The 50-kg has the greater potential energy because it has greater mass

Explanation:

Answer:

1.8 m/s

Explanation:

Distance = 2*50 +2*40 [m] = 180 [m]

Time = 100 [s]

Velocity = Distance/Time = 1.8 m/s

Average velocity for the lap is 1.8 m/s

GIven:

Length of rectangular track = 50 m

Width of rectangular track = 40 m

Time taken to cover a lap = 100 seconds

Find:

Average velocity for the lap

Computation:

Perimeter of rectangle = Length of one lap

So,

Perimeter of rectangle = 2(l + b)

So,

Length of one lap = 2[50 + 40]

Length of one lap = 2[90]

Length of one lap = 180 meter

Average velocity = Distance / Time

Average velocity for the lap = 180 / 100

Average velocity for the lap = 1.8 m/s

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Answer:

blue

Explanation:

nswer the following about two objects, A and B, whose motion produced ihe following ... "A" starts with a greater (t) position. Since they ... since you are moving away from the origin