Answer:
Index numbers are intended to measure the degree of economic changes over time. These numbers are values stated as a percentage of a single base figure. Index numbers are important in economic statistics. ... Index numbers are intended to study the change in the effects of such factors which cannot be measured directly.
Answer:Index numbers are important in economic statistics. In simple terms, an index (or index number) is a number displaying the level of a variable relative to its level (set equal to 100) in a given base period. Index numbers are intended to study the change in the effects of such factors which cannot be measured directly.
Step-by-step explanation:
Marie plants 12 packages of vegetable seeds in a community garden. Each package costs $1.97. What is the total cost of the seeds?
Answer:
$23.64
Step-by-step explanation:
12 * $1.97 = $23.64
State whether the data described below are discrete or continuous, and explain why.
The exact lengths (in kilometers) of the ocean coastlines of different countries.
a. The data are continuous because the data can only take on specific values.
b. The data are discrete because the data can only take on specific values.
c. The data are continuous because the data can take on any value in an interval.
d. The data are discrete because the data can take on any value in an interval.
Answer:
c. The data are continuous because the data can take on any value in an interval.
Step-by-step explanation:
A variable is said to be continuous if it can take on any value in an interval. Examples are lengths, temperature, etc
A discrete variable, on the other hand, can only take on specific values. Examples of discrete variables are the number of students and age.
The exact lengths (in kilometers) of the ocean coastlines of different countries is a continuous variable because it can take on any value in an interval.
A stated earlier, Lengths are in general, continuous variables.
Shanice wants to make a 72% alcojol solution. She has already poured 2L of pure water into a beaker. How many L of a 90% alcohol solution must she add to this to create the desired mixture
Answer:
8 L
Step-by-step explanation:
If x is the volume of 90% alcohol, then:
(0.90)(x) + (0)(2) = 0.72(x + 2)
0.90x = 0.72x + 1.44
0.18x = 1.44
x = 8
Find the volume of the cone.
Diameter: 20 m, Slant Height: 26 m
Round to the nearest whole number.
Volume
=
[?] m3
Answer:
2513the step-by-step explanation for height first :
[tex]h=\sqrt{h^{2} } +r^{2} =26[/tex]
[tex]h=\sqrt{h^{2} } +10^{2} =676[/tex]
[tex]h=\sqrt{h^{2} } + 100 = 676[/tex]
[tex]100-100 = 0[/tex]
[tex]676-100=576[/tex]
[tex]\sqrt{576}[/tex]
[tex]height =[/tex] 24 m
________________
step-by-step explanation for the problem :
FORMULA : [tex]v = \frac{1}{3}[/tex] · [tex]\pi[/tex] · [tex]r^{2}[/tex] · [tex]h[/tex]
v = [tex]\frac{1}{3}[/tex] · [tex]\pi[/tex] · [tex]10^{2}[/tex] · [tex]24[/tex] = [tex]800\pi[/tex] = [tex]2513.27412[/tex] = 2513
Consider the set of sequences of seven letters chosen from W and L. We may think of these sequences as representing the outcomes of a match of seven games, where W means the first team wins the game and L means the second team wins the game. The match is won by the first team to win four games (thus, some games may never get played, but we need to include their hypothetical outcomes in the points in order that we have a probability space of equally likely points).A. What is the probability that a team will win the match, given that it has won the first game?B. What is the probability that a team will win the match, given that it has won the first two games? C. What is the probability that a team will win the match, given that it has won two out of the first three games?
Answer:
a) Probability that a team will win the match given that it has won the first game = 0.66
b) Probability that a team will win the match given that it has won the first two games= 0.81
c) Probability that a team will win the match, given that it has won two out of the first three games = 0.69
Step-by-step explanation:
There are a total of seven games to be played. Therefore, W and L consists of 2⁷ equi-probable sample points
a) Since one game has already been won by the team, there are 2⁶ = 64 sample points left. If the team wins three or more matches, it has won.
Number of ways of winning the three or more matches left = [tex]6C3 + 6C4 + 6C5 + 6C6[/tex]
= 20 + 15 + 6 + 1 = 42
P( a team will win the match given that it has won the first game) = 42/64 = 0.66
b) Since two games have already been won by the team, there are 2⁵ = 32 sample points left. If the team wins two or more matches, it has won.
Number of ways of winning the three or more matches left = [tex]5C2 + 5C3 + 5C4 + 5C5[/tex] = 10 + 10 + 5 +1 = 26
P( a team will win the match given that it has won the first two games) = 26/32 = 0.81
c) Probability that a team will win the match, given that it has won two out of the first three games
They have played 3 games out of 7, this means that there are 4 more games to play. The sample points remain 2⁴ = 16
They have won 2 games already, it means they have two or more games to win.
Number of ways of winning the three or more matches left = [tex]4C2 + 4C3 + 4C4[/tex] = 6 + 4 + 1 = 11
Probability that a team will win the match, given that it has won two out of the first three games = 11/16
Probability that a team will win the match, given that it has won two out of the first three games = 0.69
How can you use an equilateral triangle to find the lengths of the sides in a 30-60-90 triangle?
Answer:
Step-by-step explanation:
1) divide equilateral tri from the middle you will get two 30-60-90 triangles
2) by using pythagorean law & trigimintory, you will get two unknowns (height and side length) and two functions
A study of women’s weights found that a randomly selected sample of 234 women had a mean weight of 157.3 lb. Assuming that the population standard deviation is 15.6 lb., construct a 95% confidence interval estimate of the mean weight of all women.
A. (145.3, 160.5)
B. (155.3, 159,3)
C. (165.5, 173.5)
D. (185.7, 199.3)
Answer:
[tex]157.3-1.96\frac{15.6}{\sqrt{234}}=155.301[/tex]
[tex]157.3+1.96\frac{15.6}{\sqrt{234}}=159.299[/tex]
So on this case the 95% confidence interval would be given by (155.301;159.299)
And the best option would be:
B. (155.3, 159,3)
Step-by-step explanation:
Information given
[tex]\bar X=157.3[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
[tex]\sigma =15.6[/tex] represent the population standard deviation
n=234 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex] (1)
The Confidence level is is 0.95 or 95%, the significance is [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], the critical value for this case would be [tex]z_{\alpha/2}=1.96[/tex]
And replacing we got:
[tex]157.3-1.96\frac{15.6}{\sqrt{234}}=155.301[/tex]
[tex]157.3+1.96\frac{15.6}{\sqrt{234}}=159.299[/tex]
So on this case the 95% confidence interval would be given by (155.301;159.299)
And the best option would be:
B. (155.3, 159,3)
Insurance companies track life expectancy information to assist in determining the cost of life insurance policies. AIB Insurance randomly sampled 100 recently paid policies and determined the average age of clients in this sample to be 77.7 years with a standard deviation of 3.6. The 90% confidence interval for the true mean age of its life insurance policy holders is
A. (76.87, 80.33)
B. (72.5, 82.9)
C. (77.1, 78.3)
D. (74.1, 81.3)
E. (74.5, 80)
Answer:
[tex]77.7-1.66\frac{3.6}{\sqrt{100}} =77.102[/tex]
[tex]77.7+1.66\frac{3.6}{\sqrt{100}} =78.30[/tex]
And the best option would be:
C. (77.1, 78.3)
Step-by-step explanation:
Information given
[tex]\bar X=77.7[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s=3.6 represent the sample standard deviation
n=100 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The degrees of freedom are given by:
[tex]df=n-1=100-1=99[/tex]
Since the Confidence is 0.90 or 90%, the significance would be [tex]\alpha=0.1[/tex] and [tex]\alpha/2 =0.05[/tex], and the critical value for this case would be [tex]t_{\alpha/2}=1.66[/tex]
And replacing we got:
[tex]77.7-1.66\frac{3.6}{\sqrt{100}} =77.10[/tex]
[tex]77.7+1.66\frac{3.6}{\sqrt{100}} =78.30[/tex]
And the best option would be:
C. (77.1, 78.3)
Which lists the ratios in order from least to greatest 2:9,1:6,7:36
Answer:
1:6, 7:36, 2:9
Step-by-step explanation:
2 : 9 → 8 : 36
1 : 6 → 6 : 36
7 : 36
Least → Greatest
1:6, 7:36, 2:9
What is the product? (3x-b)(2x^2-7x+1) A. -12x^2+42x-6 B. -12x^2+21x+6 C. 6x^3-33x^2+45x-6 D. 6x^3-27x^2-39x+6
Answer:
C.6x³-33x² + 45x-6
Step-by-step explanation:
(3x-6)(2x^2-7x+1)
= 3x(2x² - 21x +1) -6(2x² - 7x+1)
= (6x³ - 21x² + 3x) - (12x² - 42x+6)
= 6x³ - 21x² + 3x -12x² + 42x -6
= 6x³-33x² + 45x-6
A real estate agent has 1313 properties that she shows. She feels that there is a 40%40% chance of selling any one property during a week. The chance of selling any one property is independent of selling another property. Compute the probability of selling at least 11 property in one week. Round your answer to four decimal places.
Answer:
0.0013
Step-by-step explanation:
The probability of selling a property is 40%, so the probability of not selling it is 60%.
To find the probability of selling at least 11 properties, we can calculate the following cases:
Selling 11:
P(11) = C(13,11) * P(sell)^11 * P(not sell)^2
P(11) = (13! / (11! * 2!)) * 0.4^11 * 0.6^2
P(11) = 13*12/2 * 0.4^11 * 0.6^2 = 0.001178
Selling 12:
P(12) = C(13,12) * P(sell)^12 * P(not sell)^1
P(11) = (13! / (12! * 1!)) * 0.4^12 * 0.6^1
P(11) = 13 * 0.4^12 * 0.6 = 0.000131
Selling 13:
P(13) = C(13,13) * P(sell)^13 * P(not sell)^0
P(11) = 1 * 0.4^13 * 0.6^0
P(11) = 1 * 0.4^13 * 1 = 0.000007
Final probability:
P(at least 11) = P(11) + P(12) + P(13)
P(at least 11) = 0.001178 + 0.000131 + 0.000007 = 0.001316
P(at least 11) = 0.0013
Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants and x the independent variable. Enter c1 as c1 and c2 as c2.
Answer:
[tex]y(x)=c_1e^{2ix}+c_2e^{-2ix}[/tex]
Step-by-step explanation:
You have the following differential equation:
[tex]3y''+12y=0[/tex] (1)
In order to find the solution to the equation, you can use the method of the characteristic polynomial.
The characteristic polynomial of the given differential equation is:
[tex]3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i[/tex]
The solution of the differential equation is:
[tex]y(x)=c_1e^{m_1x}+c_2e^{m_2x}[/tex] (2)
where m1 and m2 are the roots of the characteristic polynomial.
You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:
[tex]y(x)=c_1e^{2ix}+c_2e^{-2ix}[/tex]
Need help ASAP!! thank you sorry if u can’t see it good :(
Answer/Step-by-step explanation:
==>Given:
=>Rectangular Pyramid:
L = 5mm
W = 3mm
H = 4mm
=>Rectangular prism:
L = 5mm
W = 3mm
H = 4mm
==>Required:
a. Volume of pyramid:
Formula for calculating volume of a rectangular pyramid us given as L*W*H
V = 5*3*4
V = 60 mm³
b. Volume of prism = ⅓*L*W*H
thus,
Volume of rectangular prism given = ⅓*5*3*4
= ⅓*60
= 20mm³
c. Volume of the prism = ⅓ x volume of the pyramid
Thus, 20 = ⅓ × 60
As we can observe from our calculation of the solid shapes given, the equation written above is true for all rectangular prism and rectangular pyramid of the same length, width and height.
A homogeneous second-order linear differential equation, two functions y 1y1 and y 2y2, and a pair of initial conditions are given. First verify that y 1y1 and y 2y2 are solutions of the differential equation. Then find a particular solution of the form y = c1y1 + c2y2 that satisfies the given initial conditions. Primes denote derivatives with respect to x.
y'' + 49y = 0; y1 = cos(7x) y2 = sin(7x); y(0) = 10 y(0)=-4
1.Why is the function y, = e * a solution to the differential equation?
A. The function y1 =e 4X is a solution because when the function and its indefinite integral, , are substituted into the equation, the result is a true statement.
B. The function y1 = e 4X is a solution because when the function and its second derivative, y1" = 16 e 4x, are substituted into the equation, the result is a true statement.
2. Why is the function y2 solution the differential equation?
A. The function y2 = e 4x is a solution because when the function and its indefinite integral, are substituted into the equation, the result a true statement. The function y2 = e 4X is a solution because when the function and its second derivative, y2" = 16 e -4x are substituted into the equation, the result is a true statement. The particular solution of the form y = c, y, +c,y2 that satisfies the initial conditions y(0) 2 and y'(0) = 9 is y =.
Answer:
[tex]y = 10cos (7x) - \frac{4}{7}sin ( 7x )[/tex]
B.
B.
[tex]y = \frac{17}{8}e^4^x - \frac{1}{8}e^-^4^x[/tex]
Step-by-step explanation:
Question 1:
- We are given a homogeneous second order linear ODE as follows:
[tex]y'' + 49y = 0[/tex]
- A pair of independent functions are given as ( y1 ) and ( y2 ):
[tex]y_1 = cos ( 7x )\\\\y_2 = sin ( 7x )[/tex]
- The given ODE is subjected to following initial conditions as follows:
[tex]y ( 0 ) = 10\\\\y ' ( 0 ) = -4[/tex]
- We are to verify that the given independent functions ( y1 ) and ( y2 ) are indeed the solution to the given ODE. If the functions are solutions then find the complete solution of the homogeneous ODE of the form:
[tex]y = c_1y_1 + c_2y_2[/tex]
Solution:-
- To verify the functions are indeed the solution to the given ODE. We will plug the respective derivatives of each function [ y1 and y2 ] into the ODE and prove whether the equality holds true or not.
- Formulate the second derivatives of both functions y1 and y2 as follows:
[tex]y'_1 = -7sin(7x) , y''_1 = -49cos(7x)\\\\y'_2 = -7cos(7x) , y''_2 = -49sin(7x)\[/tex]
- Now plug the second derivatives of each function and the functions itself into the given ODE and verify whether the equality holds true or not.
[tex]y''_1 + 49y_1 = 0\\\\-49cos(7x) + 49cos ( 7x ) = 0\\0 = 0\\\\y''_2 + 49y_2 = 0\\\\-49sin(7x) + 49sin ( 7x ) = 0\\0 = 0\\\\[/tex]
- We see that both functions [ y1 and y2 ] holds true as the solution to the given homogeneous second order linear ODE. Hence, are the solution to given ODE.
- The complete solution to a homogeneous ODE is given in the form as follows:
[tex]y = c_1y_1 + c_2y_2\\\\y = c_1*cos(7x) + c_2*sin(7x)\\[/tex]
- To complete the above solution we need to determine the constants [ c1 and c2 ] using the initial conditions given. Therefore,
[tex]y (0) = c_1cos ( 0 ) + c_2sin ( 0 ) = 10\\\\y'(0) = -7c_1*sin(0) + 7c_2*cos(0) = -4\\\\c_1 ( 1 ) + c_2 ( 0 ) = 10, c_1 = 10\\\\-7c_1(0) + 7c_2( 1 ) = -4 , c_2 = -\frac{4}{7}[/tex]
- Now we can write the complete solution to the given homogeneous second order linear ODE as follows:
[tex]y = 10cos (7x) - \frac{4}{7}sin ( 7x )[/tex] .... Answer
Question 2
- We are given a homogeneous second order linear ODE as follows:
[tex]y'' -16y =0[/tex]
- A pair of independent functions are given as ( y1 ) and ( y2 ):
[tex]y_1 = e^4^x\\\\y_2 = e^-^4^x[/tex]
- The given ODE is subjected to following initial conditions as follows:
[tex]y( 0 ) = 2\\y'( 0 ) = 9[/tex]
- We are to verify that the given independent functions ( y1 ) and ( y2 ) are indeed the solution to the given ODE. If the functions are solutions then find the complete solution of the homogeneous ODE of the form:
[tex]y = c_1y_1 + c_2y_2[/tex]
Solution:-
- To verify the functions are indeed the solution to the given ODE. We will plug the respective derivatives of each function [ y1 and y2 ] into the ODE and prove whether the equality holds true or not.
- Formulate the second derivatives of both functions y1 and y2 as follows:
[tex]y'_1 = 4e^4^x , y''_1 = 16e^4^x\\\\y'_2 = -4e^-^4^x , y''_2 = 16e^-^4^x[/tex]
- Now substitute the second derivatives of each function and the functions itself into the given ODE and verify whether the equality holds true or not.
[tex]y''_1 - 16y_1 = 0\\\\16e^4^x - 16e^4^x = 0\\\\0 = 0\\\\y''_2 - 16y_2 = 0\\\\16e^-^4^x - 16e^-^4^x = 0\\\\0 = 0[/tex]
- We see that both functions [ y1 and y2 ] holds true as the solution to the given homogeneous second order linear ODE. Hence, are the solution to given ODE.
- The complete solution to a homogeneous ODE is given in the form as follows:
[tex]y = c_1y_1 + c_2y_2\\\\y = c_1*e^4^x + c_2*e^-^4^x[/tex]
- To complete the above solution we need to determine the constants [ c1 and c2 ] using the initial conditions given. Therefore,
[tex]y ( 0 ) = c_1 * e^0 + c_2 * e^0 = 2\\\\y' ( 0 ) = 4 c_1 * e^0 - 4c_2 * e^0 = 9\\\\c_1 + c_2 = 2 , 4c_1 - 4c_2 = 9\\\\c_1 = \frac{17}{8} , c_2 = -\frac{1}{8}[/tex]
- Now we can write the complete solution to the given homogeneous second order linear ODE as follows:
[tex]y = \frac{17}{8} e^4^x - \frac{1}{8}e^-^4^x[/tex] .... Answer
Which statements describe the sequence –3, 5, –7, 9, –11, …?
Answer:
The next set of numbers are 13,-15.Step-by-step explanation:
There are obviously two different sequence the first difference is (-4) while the other one is (+4)which makes the next numbers 13,-15.
I’ll give out Brainly-ist to the correct one
Use your calculator to estimate the value of
log740.
Click on the correct answer.
1.519
1.896
1.354
Answer:
1.896
Step-by-step explanation:
You can answer this just using your number sense.
[tex]\log_7{(40)}\approx 1.896[/tex]
You know that 49 = 7², so log₇(49) = 2. The log function has a fairly small slope, so log₇(40) will not be far from 2.
_____
If you want to use your calculator, you can use the "change of base formula".
log₇(49) = log(49)/log(7) ≈ 1.602060/0.845098 ≈ 1.896
The weight of high school football players is normally distributed with a mean of 195 pounds and a standard deviation of 20 pounds.The probability of a player weighing more than 238 pounds is a.0.0334 b.0.0486 c.0.0158 d.0.9842
Answer:
c)
The probability of a player weighing more than 238
P( X > 238) = 0.0174
Step-by-step explanation:
Step(i):-
Given mean of the normally distribution = 195 pounds
Given standard deviation of the normally distribution
= 20 pounds.
Let 'x' be the random variable of the normally distribution
Let X = 238
[tex]Z = \frac{x-mean}{S.D} = \frac{238-195}{20} = 2.15[/tex]
Step(ii):-
The probability of a player weighing more than 238
P( X > 238) = P( Z> 2.15)
= 1 - P( Z < 2.15)
= 1 - ( 0.5 + A(2.15)
= 1 - 0.5 - A(2.15)
= 0.5 - 0.4821 ( from normal table)
= 0.0174
The probability of a player weighing more than 238
P( X > 238) = 0.0174
Identify the Type II error if the null hypothesis, H0, is: The capacity of Anna's car gas tank is 10 gallons. And, the alternative hypothesis, Ha, is: Anna believes the capacity of her car's gas tank is not 10 gallons.
Answer:
20gallons
Step-by-step explanation:
g In a large midwestern university (the class of entering freshmen is 6000 or more students) respectively, who graduated in the bottom third of their high school class. A 99% confidence interval for p1 – p2 is:
Answer:
–0.029 to 0.229.
Step-by-step explanation:
So, we are given the following data or information or values/parameters which are going to help us in solving this particular equation:
=>" A class of entering freshmen = 6000 or more students) respectively"
=> "The class of entering freshmen graduated in the bottom third of their high school class."
=>" 99% confidence interval for p1 – p2"
Let p1 = k1 and p2 = k2
Here, we can deduce that p1 > p2; k1 > k2. Hence,
a = (1 - 0.99)/2 = 0.005.
b = 513 × 0.005 = 2.6.
c = standard deviation = ✓ [ k1 (1 - k1) / j1 + k2 (1 - k2) / j2] = 0.05.
99% confidence interval for p1 – p2 =
k1 - k2 - b × c = –0.029
Also, k1 - k2 + b × c = 0.029.
Which are the lower and upper boundaries respectively.
Points a, b, and c are midpoints of the sides of right triangle def. Which statements are true select three options. A B C D E
Answer : The correct statements are,
AC = 5 cm
BA = 4 cm
The perimeter of triangle ABC is 12 cm.
Step-by-step explanation :
As we know that a, b, and c are midpoints of the sides of right triangle that means midpoint divide the side in equal parts.
Now we have to calculate the sides of triangle ABC by using Pythagoras theorem.
Using Pythagoras theorem in ΔACF :
[tex](AC)^2=(FA)^2+(CF)^2[/tex]
Now put all the values in the above expression, we get the value of side AC.
[tex](AC)^2=(3)^2+(4)^2[/tex]
[tex]AC=\sqrt{(9)^2+(16)^2}[/tex]
[tex]AC=5cm[/tex]
Using Pythagoras theorem in ΔDAB :
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](BD)^2=(AD)^2+(BA)^2[/tex]
Now put all the values in the above expression, we get the value of side BA.
[tex](5)^2=(3)^2+(BA)^2[/tex]
[tex]BA=\sqrt{(5)^2-(3)^2}[/tex]
[tex]BA=4cm[/tex]
Using Pythagoras theorem in ΔBEC :
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](BE)^2=(CE)^2+(CB)^2[/tex]
Now put all the values in the above expression, we get the value of side CB.
[tex](5)^2=(4)^2+(CB)^2[/tex]
[tex]CB=\sqrt{(5)^2-(4)^2}[/tex]
[tex]CB=3cm[/tex]
Now we have to calculate the perimeter of ΔABC.
Perimeter of ΔABC = Side AB + Side CB+ Side AC
Perimeter of ΔABC = 4 + 3 + 5
Perimeter of ΔABC = 12 cm
Now we have to calculate the area of ΔABC.
Area of ΔABC = [tex]\frac{1}{2}\times 4\times 3=6cm^2[/tex]
Now we have to calculate the area of ΔDEF.
Area of ΔDEF = [tex]\frac{1}{2}\times 8\times 6=24cm^2[/tex]
Area of ΔABC = [tex]\frac{6}{24}\times[/tex] Area of ΔDEF
Area of ΔABC = [tex]\frac{1}{4}[/tex] Area of ΔDEF
1/5divided by (-5/7)
Answer:
-0.28
Step-by-step explanation:
(1/5) : (-5/7)=(1*5)/(5*(-5))=-(7/25)=-0.28
Answer:
[tex]-7/25[/tex]
Step-by-step explanation:
[tex]1/5 \div -5/7[/tex]
Do the reciprocal of the second fraction.
[tex]1/5 \times 7/-5[/tex]
Multiply the first fraction by the reciprocal of the second fraction.
[tex]7/-25=-0.28[/tex]
The answer in decimal form is -0.28.
Please answer this correctly
Answer:
50
Step-by-step explanation:
The probability of it landing on yellow or blue is 5 out of 7 total possibilities.
5/7
Multiply by 70.
5/7 × 70
350/7
= 50
Answer:
50 times
Step-by-step explanation:
Yellow or blue is 5/7 of the spinner
Multiply 70 by 5/7 to find the prediction of the number of times it will land there
70(5/7) = 50
The owner of a small machine shop has just lost one of his largest customers. The solution to his problem,he says, is to fire three machinists to balance his workforce with his current level of business. The owner says that it is a simple problem with a simple solution. The three machinists disagree. Why
Answer:
It may look simple to the owner because he is not the one losing a job. For the three machinists it represents a major event with major consequences
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer:
(x-1)(x-4)
Step-by-step explanation:
I used long division with polynomials to help me find the other factor to this problem. Divide x cubed -5x squared -6x+8 by x+2 to get x squared -5x+4.
Hope this helps!
Answer: (x + 2) (x - 4) (x - 1)
Step-by-step explanation:
Use synthetic division. If the remainder (last digit) is zero, then it is a factor. The other digits represent the coefficients of the reduced polynomial.
x³ - 3x² - 6 + 8 ; x + 2 = 0 --> x = -2
-2 | 1 -3 -6 8
| ↓ -2 10 -8
1 -5 4 0 → remainder is 0
Reduced polynomial: x² -5x + 4
= (x - 4) (x - 1)
Factored form: (x + 2) (x - 4) (x - 1)
Which of the following is the equation of the function below?
Answer:
Step-by-step explanation:
its B
Answer:
the answer is B
Step-by-step explanation:
Find the diagonal of a square whose sides measure 3x square root of 2
Answer:
that means each side equals 8
Step-by-step explanation:
Decide whether the method of undetermined coefficients together with superposition can be applied to find a particular solution of the given equation. Do not solve the equation Can the method of undetermined coefficients together with superposition be applied to find a particular solution of the given equation?
A. No, because the right side of the given equation is not the correct type of function
B, Yes °
C. No, because the differential equation is not linear.
D. No, because the differential equation does not have constant coefficients.
Answer:
D. No, because the differential equation does not have constant coefficients.
Step-by-step explanation:
The undetermined coefficient method cannot be applied to non homogeneous variables. The differential equation does not have constant variables therefore the method of undetermined superposition can not be applied. To complete a solution of non homogeneous equation the particular solution must be added to the homogeneous equation.
What is the simplified form of square root of 10,000x64 ?
Answer:
800
Step-by-step explanation:
10,000 x 64 = 640,000
Square Root It Makes It
800
Answer:
6,400
Step-by-step explanation:
The square root of 10,000 times 64 is simplified to 6,400
A college surveys 300 graduates and finds 98 graduated with honors and 207 had one or both parents graduate from college. Of the 98 students with honors, 79 had one or both parents graduate from college. Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Answer:
20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Graduated with honors:
98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.
Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.
Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Of the 93 with no graduated parent, 19 earned honors
19/93 = 0.2043
20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
The average lifetime of a set of tires is 3.4 years. The manufacturer will replace any set of tires failing within three years of the date of purchase. The lifetime of these tires is known to follow an exponential distribution. What is the probability that the tires will fail within three years of the date of purchase?
Answer: the probability that the tires will fail within three years of the date of purchase is 0.12
Step-by-step explanation:
The average lifetime of a set of tires is 3.4 years. It means that μ = 3.4
Decay parameter, m = 1/3.4 = 0.294
The probability density function is
f(x) = me^-mx
Where x is a continuous random variable representing the time interval of interest(the reliability period that we are testing)
Since x = 3 years,
Therefore, the probability that the tires will fail within three years of the date of purchase is
f(3) = 0.294e^-(0.294 × 3)
f(3) = 0.294e^- 0.882
f(3) = 0.12