Imagine you followed all steps correctly, with multiple attempts, and found that the purity of recombinant DHFR isolated through IMAC was not good enough. Hypothesize two changes to the procedure or experimental design that you could consider trying next to increase the purity of our DHFR sample and why you anticipate each to increase protein purity. (5pt)

Answer:

9.95mL is the volume of NaOH that you must use

Explanation:

In the problem, you have in your blanck the presence of an acid as sulfuric acid. That means the blank requires an amount of NaOH to neutraliz its solution.

The volume required for the sample will be:

Volume of the sample - Volume of the blank

Beacuse we don't have to take into account the acidity of the blanck

12.92mL - 2.97mL =

Answer: MCCCMC

Please. Mark as brainliest

Answer:

The empty space between the atomic cloud of an atom and its nucleus is just that: empty space, or vacuum. ... Electrons are thus 'spread out' quite a bit in their orbits about the nucleus. In fact, the wave-functions for electrons in s-orbitals about a nucleus actually extend all the way down into the nucleus itself.

Answer:

2000 (km)

Explanation:

:)

Answer:

Cup of volume [tex]0.0675[/tex] cubic centimeter is required

Explanation:

Given

Density of the Cup [tex]= 1.325[/tex] g/cm^3

Total weight of the chocolates [tex]= 20,000[/tex] mg or 20 grams

Density is equal to mass divided by volume

Volume of the chocolates

[tex]\frac{1.325}{20} \\= 0.0675[/tex] cubic centimeter

Answer:

7

Explanation:

just add p has 1 o has 4 and h has 2

Light travels in a straight line as a wave. It does not require any medium or material to travel like sound waves which means it can travel in vacuum.The speed of the light  from the special theory of relativity is a constant value of 38x10^8m/second

(つ ◕.◕ )つ Hey there again!

Answer → Last one Spreading Plates on the Sea Floor

✨Hope this helps✨

Answer:

110 g

Explanation:

Step 1: Write the balanced equation for the decomposition of calcium carbonate

CaCO₃(s) ⇒ CaO(s) + CO₂(g)

Step 2: Convert 260.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 260.0 + 273.15 = 533.2 K

Step 3: Calculate the moles of CO₂ produced

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T = 1 atm × 48.0 L/0.0821 atm.L/mol.K × 533.2 K = 1.10 mol

Step 4: Calculate the moles of CaCO₃ that reacted to produce 1.10 moles of CO₂

The molar ratio of CaCO₃ to CO₂ is 1:1. The moles of CaCO₃ that reacted are 1/1 × 1.10 mol = 1.10 mol.

Step 5: Calculate the mass corresponding to 1.10 moles of CaCO₃

The molar mass of CaCO₃ is 100.09 g/mol.

1.10 mol × 100.09 g/mol = 110 g

The option A describes an exothermic reaction.

i.e, ΔHt,reactant > ΔHt, product

The reaction in which energy is release during the formation of reaction is called exothermic reaction.

Mathematically,

ΔHf = ΔH(product) - ΔH(reactant)

For exothermic reaction, ΔHt,reactant > ΔHt, product

So,for exothermic reaction, ΔHf is negative.

Where,

ΔHf = Enthalpy of formation of reaction

ΔH(product) = enthalpy of formation of product

ΔH(reactant) = enthalpy of formation of reactant

To learn more about exothermic reaction here.

https://brainly.com/question/10373907

#SPJ3

Answer: Metalloids

Explanation:

The dark “stair step” line on the right side of the periodic table is where the metalloids are. Metalloids “touch” the SSL. (Stair step line)

The metals are to the left of the SSL and the non metals are to the right of the SSL.

Answer:

rough surface

Explanation:

Diffuse reflection occurs when parallel light waves strike a rough surface

Answer:

Rippling fountain

Explanation:

Answer:

False!

Explanation:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases equals the original mass of the charcoal and the oxygen when it first reacted.

Answer: B

Explanation:

A is evaporation. B is condensation. C is precipitation.

Answer:

it would be b

Explanation:

b would be condensation

Answer:

0.0225 M

Explanation:

In one liter of this solution, there are 45 mEq of Ca⁺².

1 mEq of Ca⁺² is equal to 20 mg of Ca⁺. We know this by dividing its molar mass (40) by the charge of the ion (2).

Meaning that 45 mEq of Ca⁺² is equal to (45 * 20) 900 mg of Ca⁺².

Now we convert 900 mg of Ca⁺² into moles, using its molar mass:

Finally we calculate the molarity of the solution:

Answer: The %w/w protein in the sample is 15.2 %

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}[/tex]    

[tex]\text{Moles of} HCl={0.09552\times 50.00}{1000}=0.0047moles[/tex]

[tex]\text{Moles of} NaOH={0.05992\times 37.84}{1000}=0.0023moles[/tex]

[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]  

According to stoichiometry :

1 mole of [tex]NaOH[/tex] require 1 mole of [tex]HCl[/tex]

Thus 0.0023 moles of [tex]NaOH[/tex] will require=[tex]\frac{1}{1}\times 0.0023=0.0023moles[/tex]  of [tex]HCl[/tex]

moles of HCl used = (0.0047-0.0023) = 0.0024

[tex]NH_3+HCl\rightarrow NH_4Cl[/tex]

1 mole of HCl uses = 1 mole of ammonia

Thus 0.0024 moles uses = [tex]\frac{1}{1}\times 0.0024=0.0024moles[/tex] of ammonia

Mass of ammonia= [tex]moles\times {\text {Molar mass}}=0.0024\times 17g/mol=0.0408g[/tex]

17 g of ammonia contains = 14 g of Nitrogen

Thus 0.0408 g of ammonia contains = [tex]\frac{14}{17}\times 0.0408=0.034 g[/tex] of Nitrogen

Now 17.45 g of Nitrogen is present in = 100 g of protein

Thus 0.034 g of Nitrogen is present in =[tex]\frac{100}{17.45}\times 0.034=0.195g[/tex] of protein

Now % w/w of protein = [tex]\frac{0.195}{1.2846}\times 100=15.2\%[/tex]

Thus %w/w protein in the sample is 15.2%

If the proteins in grains average 17.54% w/w N, the % w/w protein in the sample is 15.2 %.

It is a process of converting nitrogen present in any compound into ammonium sulfate.

Step1: calculating the moles by the formula of molarity

molarity × volume

M = 0.09552, V =  50.00 mL =0.05 L

Moles of HCl

[tex]0.09552 \times 0.05 = 0.0047\;mol\\[/tex]

Moles of NaOH

[tex]0.05992 \times 0.03784 = 0.0023 \;mol[/tex]

Moles of HCl used is  0.0047 - 0.0023 = 0.0024

Step2: calculating the mass of ammonia

moles × molar mass

[tex]0.024 \times 17\;g/mol = 0.0408\;g[/tex]

Now, 17 grams of ammonia have 14 grams of nitrogen

so, 0.0408 g ammonia have [tex]\dfrac{14}{17} \times 0.0408 = 0.034[/tex]

In 100 g of protein, there is 17.45 g of nitrogen

So, 0.034 g N have [tex]\dfrac{100}{17.45} \times 0.034 = 0.195 g.\\[/tex]

Step3: calculating the % w/w

[tex]\dfrac{0.195}{1.2846} \times 100 = 15.2 \%[/tex]

Thus, the % w/w is 15.2 %

Learn more about Kjeldahl analysis

https://brainly.com/question/18120623

Answer:

b tissues,cells,organs,organ system,organisms,populations

Tissues, Cells, Organs, Organ Systems, Organsims, Population. the correct answer is B

Answer: Thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat is the flow of thermal energy. ... This energy is usually in the form of low-level thermal energy. Here, low-level means that the temperature associated with the thermal energy is close to that of the environment. hope this helps. Can u pls give me brainliest

Explanation:

Answer:

Explanation:

Ratio of mass of C , N , H and O

= .8007 :0.9333:0.2016:2.133

Ratio of moles of C , N , H and O

= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16

= .0667 : .0667: .2016 : .1333

= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667

= 1 : 1 : 3: 2

Hence empirical formula = CNH₃O₂

7 .

Weight of titanium Ti = 1.916 g

Weight of oxygen = 3.196 - 1.916 = 1.28 g

Ratio of weight of Ti and O

= 1.916 : 1.28

Ratio of moles  of Ti and O

1.916/48 : 1.28/16  [ Molecular  weight of Titanium is 48 ]

= .04 : .08

= .04/.04 : .08/.04

= 1 :2 .

Empirical formula

TiO₂

Answer:

The couch will not move because the people are not working together. Maybe if they call someone to help they can make some progress.

Chlorine is a halogen, not a noble gas.

The last two groups of the periodic table is named as halogen family and Nobel gas family.

The group 17 is composed of gases collectively called as halogen and it includes the following gases:

Fluorine

Chlorine

Bromine

Iodine

Astatine

Tennessine

The group 18 is composed of elements which are collectively called as Nobel gas and it includes:

Helium

Neon

Argon

Krypton

Xenon

Radon

Oganesson

these are some

Hope this helped!!

Answer:

Weak acids and weak bases are only partially dissociated.

Explanation:

When a small amount of an acid or a base is added to water (or a solution of some strong acid or base of some certain [tex]pH \![/tex],) the [tex]pH[/tex] of that solution tends to change significantly.

In contrast, when the same amount of acid or base is added to a buffer system of some certain [tex]pH\![/tex], the [tex]pH[/tex] of this system tends to change by a much smaller amount.

Weak acids and weak bases dissociate only partially. That allows the buffer solutions to contain a large reservoir of both the (undissociated) weak acid (or weak base) and the corresponding conjugate ion, while maintaining the required [tex]pH[/tex].

This reservoir of the partially-dissociated weak acid (or weak base) and its conjugate ion allows the buffer system to absorb [tex]\rm H^{+}[/tex] and [tex]\rm OH^{-}[/tex] that were added to the solution without much change to the [tex]pH[/tex].

For example, consider a [tex]1\; \rm L[/tex] buffer solution that initially included [tex]0.1\; \rm mol[/tex] of acetic acid [tex]\rm CH_3COOH[/tex] (a weak acid with [tex]pK_\text{a} = 4.765[/tex]) and [tex]0.1\; \rm mol\![/tex] of sodium acetate [tex]\rm CH_3COONa[/tex]. The [tex]pH[/tex] of this solution would be [tex]4.765[/tex].

In contrast, if a solution of [tex]\rm HCl[/tex] (a strong acid) and an equal amount of [tex]\rm NaCl[/tex] also needs to be [tex]4.765[/tex], only [tex]10^{-4.765}\; \rm mol \approx 0.0000172\; \rm mol[/tex] of each species could be included.

Assume that [tex]0.001\; \rm mol[/tex] of [tex]{\rm NaOH}\, (s)[/tex] is added to the buffer solution of [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COONa[/tex]. The quantity of the partially-dissociated weak acid in this solution is much larger than that of the [tex]\rm OH^{-}[/tex] added to the solution.

Only a small portion of the weak base would be consumed.The [tex]pH[/tex] of the solution would likely change by less than [tex]0.001[/tex].

In contrast, assume that [tex]0.001\; \rm mol[/tex] of [tex]{\rm NaOH}\, (s)[/tex] is added to the [tex]1\; \rm L[/tex] solution with [tex]0.0000172\; \rm mol[/tex] of [tex]\rm HCl[/tex] (fully-dissociated) and [tex]\rm NaCl[/tex].

All the [tex]\rm HCl\![/tex] in this solution would be consumed. The [tex]pH[/tex] of this solution would go well above [tex]7[/tex].

Answer:

Weak acids and weak bases are partially dissociate

Explanation:

I took the test and got 100%

~My Answer~:

Water is the enabler of fast oxidation of iron so freshwater will also cause rust. However, salt water is a very good conductor (lots of dissociated ions) and so there are a number of electrolysis reactions that tremendously accelerate corrosion in salt water.

Answer:

Some nutrients also act as antioxidants. These may be vitamins, minerals, proteins, or other types of molecules. They help the body remove toxic substances known as free radicals, or reactive oxygen species. If too many of these substances remain in the body, cell damage and disease can result.

Answer:

aajajjajajajajajajajajdsjsjjx jajajjajajajajaisjn

Explanation:

Answer:

Explanation:

Hehs

Answer:

1.281 Latm/molK