Answer: solanka 6-procentowa=3 kg
solanka 9-procentowa = 6 kg
Step-by-step explanation:
Let solanka 6-procentowa=x kg
Let solanka 9-procentowa = y kg
So x+y=9
=> x=9-y (1)
6%=0.06 9%=0.09 8%=0.08
So pure salt is 0.06*x +0.09*y= 9*0.08 (2)
Lets put 9-y instead x in (2)
0.06*(9-y) +0.09*y=0.72
0.54-0.06*y +0.09*y=0.72
0.03*y=0.18
y=6kg => x=9-y => x=9-6=3 kg
Tamar is measuring the sides and angles of Triangle T U V to determine whether it is congruent to the triangle below. For triangle K L M, side K M is 27 millimeters, side L M is 20 millimeters, and side K L is 12 millimeters. Angle K is 45 degrees, angle M is 25 degrees, angle L is 110 degrees. Which pair of measurements would eliminate the possibility that the triangles are congruent? Measure of angle T = 25 degrees and Measure of angle U = 45 degrees Measure of angle T = 110 degrees and Measure of angle V = 25 degrees Measure of angle T = 25 degrees and TU = 12 Measure of angle T = 110 degrees and UV = 27
Answer: Measure of angle T = 25 degrees and Measure of angle U = 45 degrees
Step-by-step explanation:
Measure of angle T = 25 degrees and TU = 12 is the pair of measurements would eliminate the possibility that the triangles are congruent.
What are congruent triangles?
" Triangles are said to be congruent if the corresponding sides and angles of the one triangle are equals to the other triangles."
According to the question,
In triangle KLM,
KM =27millimeters
LM = 20millimeters
KL = 12 millimeters
∠K= 45degrees
∠M= 25 degrees
∠L = 110degrees
From the given measurements of the triangle we have,
side with measure 27millimeters is opposite to angle 110° .
side with measure 12millimeters is opposite to angle 25° .
side with measure 20millimeters is opposite to angle 45°.
From the conditions in triangle TUV to be congruent to triangle KLM ,
Measure of angle T = 25 degrees and TU = 12 is against the given condition of congruent triangle.
As angle T and side TU are adjacent to each other, which is against the correspondence of the given triangle.
Hence, measure of angle T = 25 degrees and TU = 12 is the pair of measurements would eliminate the possibility that the triangles are congruent.
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A real estate agent has 1313 properties that she shows. She feels that there is a 40%40% chance of selling any one property during a week. The chance of selling any one property is independent of selling another property. Compute the probability of selling at least 11 property in one week. Round your answer to four decimal places.
Answer:
0.0013
Step-by-step explanation:
The probability of selling a property is 40%, so the probability of not selling it is 60%.
To find the probability of selling at least 11 properties, we can calculate the following cases:
Selling 11:
P(11) = C(13,11) * P(sell)^11 * P(not sell)^2
P(11) = (13! / (11! * 2!)) * 0.4^11 * 0.6^2
P(11) = 13*12/2 * 0.4^11 * 0.6^2 = 0.001178
Selling 12:
P(12) = C(13,12) * P(sell)^12 * P(not sell)^1
P(11) = (13! / (12! * 1!)) * 0.4^12 * 0.6^1
P(11) = 13 * 0.4^12 * 0.6 = 0.000131
Selling 13:
P(13) = C(13,13) * P(sell)^13 * P(not sell)^0
P(11) = 1 * 0.4^13 * 0.6^0
P(11) = 1 * 0.4^13 * 1 = 0.000007
Final probability:
P(at least 11) = P(11) + P(12) + P(13)
P(at least 11) = 0.001178 + 0.000131 + 0.000007 = 0.001316
P(at least 11) = 0.0013
Solve the system of equations. \begin{aligned} & -5y-10x = 45 \\\\ &-3y+10x=-5 \end{aligned} −5y−10x=45 −3y+10x=−5
Answer:
x = -2
y = -5
Step-by-step explanation:
We can solve this algebraically (substitution or elimination) or graphically. I will be using elimination:
Step 1: Add the 2 equations together
-8y = 40
y = -5
Step 2: Plug y into an original equation to find x
-3(-5) + 10x = -5
15 + 10x = -5
10x = -20
x = -2
And we have our final answers!
Answer:
[tex]\boxed{\sf \ \ \ x=-2 \ \ \ and \ \ \ y=-5 \ \ \ }[/tex]
Step-by-step explanation:
let s solve the following system
(1) -5y-10x=45
(2) -3y+10x=-5
let s do (1) + (2) it comes
-5y-10x-3y+10x=45-5=40
<=>
-8y=40
<=>
y = -40/8=-20/4=-5
so y = -5
let s replace y in (1)
25-10x=45
<=>
10x=25-45=-20
<=>
x = -20/10=-2
so x = -2
What is the simplified form of square root of 10,000x64 ?
Answer:
800
Step-by-step explanation:
10,000 x 64 = 640,000
Square Root It Makes It
800
Answer:
6,400
Step-by-step explanation:
The square root of 10,000 times 64 is simplified to 6,400
I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
Answer:
(x-1)(x-4)
Step-by-step explanation:
I used long division with polynomials to help me find the other factor to this problem. Divide x cubed -5x squared -6x+8 by x+2 to get x squared -5x+4.
Hope this helps!
Answer: (x + 2) (x - 4) (x - 1)
Step-by-step explanation:
Use synthetic division. If the remainder (last digit) is zero, then it is a factor. The other digits represent the coefficients of the reduced polynomial.
x³ - 3x² - 6 + 8 ; x + 2 = 0 --> x = -2
-2 | 1 -3 -6 8
| ↓ -2 10 -8
1 -5 4 0 → remainder is 0
Reduced polynomial: x² -5x + 4
= (x - 4) (x - 1)
Factored form: (x + 2) (x - 4) (x - 1)
I’ll give out Brainly-ist to the correct one
Use your calculator to estimate the value of
log740.
Click on the correct answer.
1.519
1.896
1.354
Answer:
1.896
Step-by-step explanation:
You can answer this just using your number sense.
[tex]\log_7{(40)}\approx 1.896[/tex]
You know that 49 = 7², so log₇(49) = 2. The log function has a fairly small slope, so log₇(40) will not be far from 2.
_____
If you want to use your calculator, you can use the "change of base formula".
log₇(49) = log(49)/log(7) ≈ 1.602060/0.845098 ≈ 1.896
Identify the Type II error if the null hypothesis, H0, is: The capacity of Anna's car gas tank is 10 gallons. And, the alternative hypothesis, Ha, is: Anna believes the capacity of her car's gas tank is not 10 gallons.
Answer:
20gallons
Step-by-step explanation:
Which of the following is the equation of the function below?
Answer:
Step-by-step explanation:
its B
Answer:
the answer is B
Step-by-step explanation:
Help please if your good at maths ?
Answer:
Year 7 = 75 students
Year 9 = 25 students
Step-by-step explanation:
Year 7 has 3/8 of the total since the circle is divided into 8 sections and has 3 of the 8 sections
3/8 * 200 students = 75
Year 9 has 1/8 of the total since the circle is divided into 8 sections and has 1 of the 8 sections
1/8 * 200 =25
Will give BRAINLIEST! Find the set of x values that satisfy this inequality. 2 | 5x − 4 | > 6 Select one:a. x ≤ 7 / 5 and x ≥ 1 / 5b. x > 7 / 5c. x > 7 / 5 or x < 1 / 5d. 1 / 5 ≤ x ≤ 7 / 5
Answer:
c. x > 7 / 5 or x < 1 / 5
Step-by-step explanation:
2 | 5x − 4 | > 6
| 5x - 4 | > 3
5x -4 > 3 ⇒ 5x > 7 ⇒ x > 7/55x -4 < -3 ⇒ 5x < 1 ⇒ x < 1/5So combining the 2 above we get:
x > 7/5 or x < 1/5Correct choice is c.
Answer:
x>7/5 or x <1/5
Step-by-step explanation:
2 | 5x − 4 | > 6
Divide by 2
2/2 | 5x − 4 | > 6/2
| 5x − 4 | > 3
There are two solutions one positive and one negative ( the negative flips the inequality)
5x-4 >3 or 5x-4 < -3
Add 4 to each side
5x-4 +4>3+4 or 5x-4+4 < -3+4
5x >7 or 5x <1
Divide by 5
x>7/5 or x <1/5
State whether the data described below are discrete or continuous, and explain why.
The exact lengths (in kilometers) of the ocean coastlines of different countries.
a. The data are continuous because the data can only take on specific values.
b. The data are discrete because the data can only take on specific values.
c. The data are continuous because the data can take on any value in an interval.
d. The data are discrete because the data can take on any value in an interval.
Answer:
c. The data are continuous because the data can take on any value in an interval.
Step-by-step explanation:
A variable is said to be continuous if it can take on any value in an interval. Examples are lengths, temperature, etc
A discrete variable, on the other hand, can only take on specific values. Examples of discrete variables are the number of students and age.
The exact lengths (in kilometers) of the ocean coastlines of different countries is a continuous variable because it can take on any value in an interval.
A stated earlier, Lengths are in general, continuous variables.
Consider the diagram and the proof below.
Given: In △ABC, AD ⊥ BC
Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction
Triangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.
A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.
What is the missing statement in Step 6?
b = c
StartFraction h Over b EndFraction = StartFraction h Over c EndFraction
csin(B) = bsin(C)
bsin(B) = csin(C)
Answer:
c- the right triangle altitude theorem
Step-by-step explanation:
i did it on edge! ; )
The missing statement in Step 6 is ,c- The right triangle altitude theorem.
We have given that,
In △ABC, AD ⊥ BC
Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction.
Triangle A B C is shown.
What is the right triangle altitude theorem?The right triangle altitude theorem or geometric mean theorem is a result in elementary geometry that describes a relation between the altitude on the hypotenuse in a right triangle and the two-line segments it creates on the hypotenuse
Therefore we have,
A perpendicular bisector is drawn from point A to point D on side C B forming a right angle.
The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.
So the missing statement in Step 6
b = c
c=The right triangle altitude theorem.
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(06.02)A six-sided number cube labeled 1 through 6 is rolled 200 times. An even number is rolled 115 times. Compare the theoretical probability of rolling an even number with the relative frequency of rolling an even number and select one of the statements below that best describes the situation. The theoretical probability and relative frequency are the same. The theoretical probability is larger than the relative frequency. The theoretical probability is smaller than the relative frequency. There is not enough information to determine the relative frequency.
Answer:
The theoretical probability is smaller than the relative frequency
Step-by-step explanation:
6-sided cube rolled 200 times
Probability of an even number is 1/2= 0.5
200*1/2= 100- theoretical probability
Experimental frequency= 115
Relative frequency= 115/200= 0.575
0.575 > 0.5
The theoretical probability is smaller than the relative frequency
Answer:
The theoretical probability is smaller than the relative frequency.
Step-by-step explanation:
Points a, b, and c are midpoints of the sides of right triangle def. Which statements are true select three options. A B C D E
Answer : The correct statements are,
AC = 5 cm
BA = 4 cm
The perimeter of triangle ABC is 12 cm.
Step-by-step explanation :
As we know that a, b, and c are midpoints of the sides of right triangle that means midpoint divide the side in equal parts.
Now we have to calculate the sides of triangle ABC by using Pythagoras theorem.
Using Pythagoras theorem in ΔACF :
[tex](AC)^2=(FA)^2+(CF)^2[/tex]
Now put all the values in the above expression, we get the value of side AC.
[tex](AC)^2=(3)^2+(4)^2[/tex]
[tex]AC=\sqrt{(9)^2+(16)^2}[/tex]
[tex]AC=5cm[/tex]
Using Pythagoras theorem in ΔDAB :
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](BD)^2=(AD)^2+(BA)^2[/tex]
Now put all the values in the above expression, we get the value of side BA.
[tex](5)^2=(3)^2+(BA)^2[/tex]
[tex]BA=\sqrt{(5)^2-(3)^2}[/tex]
[tex]BA=4cm[/tex]
Using Pythagoras theorem in ΔBEC :
[tex](Hypotenuse)^2=(Perpendicular)^2+(Base)^2[/tex]
[tex](BE)^2=(CE)^2+(CB)^2[/tex]
Now put all the values in the above expression, we get the value of side CB.
[tex](5)^2=(4)^2+(CB)^2[/tex]
[tex]CB=\sqrt{(5)^2-(4)^2}[/tex]
[tex]CB=3cm[/tex]
Now we have to calculate the perimeter of ΔABC.
Perimeter of ΔABC = Side AB + Side CB+ Side AC
Perimeter of ΔABC = 4 + 3 + 5
Perimeter of ΔABC = 12 cm
Now we have to calculate the area of ΔABC.
Area of ΔABC = [tex]\frac{1}{2}\times 4\times 3=6cm^2[/tex]
Now we have to calculate the area of ΔDEF.
Area of ΔDEF = [tex]\frac{1}{2}\times 8\times 6=24cm^2[/tex]
Area of ΔABC = [tex]\frac{6}{24}\times[/tex] Area of ΔDEF
Area of ΔABC = [tex]\frac{1}{4}[/tex] Area of ΔDEF
Find an explicit formula for the following sequence, an which starts with a1=−1. −1,1/2,−1/3,1/4,−1/5,…
Answer:
The sequence can be represented by the formula of its nth term:
[tex]a_n=\frac{(-1)^n}{n}[/tex]
Step-by-step explanation:
Notice that we are in the presence of an alternate sequence (the values alternate from negative to positive. Therefore we need to take into account that there should be a factor "-1" raised to the "n" value for the sequence. Also, given that the sequence looks in absolute value like the harmonic sequence, we conclude upon the following general form for the "nth" term of the sequence:
[tex]a_n=\frac{(-1)^n}{n}[/tex]
A manufacturer knows that their items have a normally distributed length, with a mean of 18.1 inches, and standard deviation of 3.7 inches. If one item is chosen at random, what is the probability that it is less than 28.9 inches long
Answer:
Step-by-step explanation:
z = (X - μ) / σ, where X = date, μ = mean, σ = standard deviation
z = (28.9 - 18.1) / 3.7
z = 18.6
0.06681 is the area for this z.
6.681% shall be shorter than 18.6 inches.
How can you use an equilateral triangle to find the lengths of the sides in a 30-60-90 triangle?
Answer:
Step-by-step explanation:
1) divide equilateral tri from the middle you will get two 30-60-90 triangles
2) by using pythagorean law & trigimintory, you will get two unknowns (height and side length) and two functions
Marie plants 12 packages of vegetable seeds in a community garden. Each package costs $1.97. What is the total cost of the seeds?
Answer:
$23.64
Step-by-step explanation:
12 * $1.97 = $23.64
What is the product? (3x-b)(2x^2-7x+1) A. -12x^2+42x-6 B. -12x^2+21x+6 C. 6x^3-33x^2+45x-6 D. 6x^3-27x^2-39x+6
Answer:
C.6x³-33x² + 45x-6
Step-by-step explanation:
(3x-6)(2x^2-7x+1)
= 3x(2x² - 21x +1) -6(2x² - 7x+1)
= (6x³ - 21x² + 3x) - (12x² - 42x+6)
= 6x³ - 21x² + 3x -12x² + 42x -6
= 6x³-33x² + 45x-6
The weight of high school football players is normally distributed with a mean of 195 pounds and a standard deviation of 20 pounds.The probability of a player weighing more than 238 pounds is a.0.0334 b.0.0486 c.0.0158 d.0.9842
Answer:
c)
The probability of a player weighing more than 238
P( X > 238) = 0.0174
Step-by-step explanation:
Step(i):-
Given mean of the normally distribution = 195 pounds
Given standard deviation of the normally distribution
= 20 pounds.
Let 'x' be the random variable of the normally distribution
Let X = 238
[tex]Z = \frac{x-mean}{S.D} = \frac{238-195}{20} = 2.15[/tex]
Step(ii):-
The probability of a player weighing more than 238
P( X > 238) = P( Z> 2.15)
= 1 - P( Z < 2.15)
= 1 - ( 0.5 + A(2.15)
= 1 - 0.5 - A(2.15)
= 0.5 - 0.4821 ( from normal table)
= 0.0174
The probability of a player weighing more than 238
P( X > 238) = 0.0174
Shanice wants to make a 72% alcojol solution. She has already poured 2L of pure water into a beaker. How many L of a 90% alcohol solution must she add to this to create the desired mixture
Answer:
8 L
Step-by-step explanation:
If x is the volume of 90% alcohol, then:
(0.90)(x) + (0)(2) = 0.72(x + 2)
0.90x = 0.72x + 1.44
0.18x = 1.44
x = 8
Pls Help!
Given the polynomial function below, find F(3).
F(x) = 2x3 - 7x + 1
A. 34
B. -8
C. 26
D. -2
Answer:
34
Step-by-step explanation:
F(x) = 2x^3 - 7x + 1
Let x= 3
F(3) = 2* 3^3 - 7*3 + 1
= 2 * 27 -21+1
= 54 -21 + 1
= 34
Answer: 34
Step-by-step explanation:
Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants and x the independent variable. Enter c1 as c1 and c2 as c2.
Answer:
[tex]y(x)=c_1e^{2ix}+c_2e^{-2ix}[/tex]
Step-by-step explanation:
You have the following differential equation:
[tex]3y''+12y=0[/tex] (1)
In order to find the solution to the equation, you can use the method of the characteristic polynomial.
The characteristic polynomial of the given differential equation is:
[tex]3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i[/tex]
The solution of the differential equation is:
[tex]y(x)=c_1e^{m_1x}+c_2e^{m_2x}[/tex] (2)
where m1 and m2 are the roots of the characteristic polynomial.
You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:
[tex]y(x)=c_1e^{2ix}+c_2e^{-2ix}[/tex]
Which statements describe the sequence –3, 5, –7, 9, –11, …?
Answer:
The next set of numbers are 13,-15.Step-by-step explanation:
There are obviously two different sequence the first difference is (-4) while the other one is (+4)which makes the next numbers 13,-15.
The owner of a small machine shop has just lost one of his largest customers. The solution to his problem,he says, is to fire three machinists to balance his workforce with his current level of business. The owner says that it is a simple problem with a simple solution. The three machinists disagree. Why
Answer:
It may look simple to the owner because he is not the one losing a job. For the three machinists it represents a major event with major consequences
A college surveys 300 graduates and finds 98 graduated with honors and 207 had one or both parents graduate from college. Of the 98 students with honors, 79 had one or both parents graduate from college. Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Answer:
20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Graduated with honors:
98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.
Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.
Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Of the 93 with no graduated parent, 19 earned honors
19/93 = 0.2043
20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Consider the set of sequences of seven letters chosen from W and L. We may think of these sequences as representing the outcomes of a match of seven games, where W means the first team wins the game and L means the second team wins the game. The match is won by the first team to win four games (thus, some games may never get played, but we need to include their hypothetical outcomes in the points in order that we have a probability space of equally likely points).A. What is the probability that a team will win the match, given that it has won the first game?B. What is the probability that a team will win the match, given that it has won the first two games? C. What is the probability that a team will win the match, given that it has won two out of the first three games?
Answer:
a) Probability that a team will win the match given that it has won the first game = 0.66
b) Probability that a team will win the match given that it has won the first two games= 0.81
c) Probability that a team will win the match, given that it has won two out of the first three games = 0.69
Step-by-step explanation:
There are a total of seven games to be played. Therefore, W and L consists of 2⁷ equi-probable sample points
a) Since one game has already been won by the team, there are 2⁶ = 64 sample points left. If the team wins three or more matches, it has won.
Number of ways of winning the three or more matches left = [tex]6C3 + 6C4 + 6C5 + 6C6[/tex]
= 20 + 15 + 6 + 1 = 42
P( a team will win the match given that it has won the first game) = 42/64 = 0.66
b) Since two games have already been won by the team, there are 2⁵ = 32 sample points left. If the team wins two or more matches, it has won.
Number of ways of winning the three or more matches left = [tex]5C2 + 5C3 + 5C4 + 5C5[/tex] = 10 + 10 + 5 +1 = 26
P( a team will win the match given that it has won the first two games) = 26/32 = 0.81
c) Probability that a team will win the match, given that it has won two out of the first three games
They have played 3 games out of 7, this means that there are 4 more games to play. The sample points remain 2⁴ = 16
They have won 2 games already, it means they have two or more games to win.
Number of ways of winning the three or more matches left = [tex]4C2 + 4C3 + 4C4[/tex] = 6 + 4 + 1 = 11
Probability that a team will win the match, given that it has won two out of the first three games = 11/16
Probability that a team will win the match, given that it has won two out of the first three games = 0.69
In its first month of operations, Weatherall Company made three purchases of merchandise in the following sequence: (1) 120 units at $5, (2) 460 units at $6, and (3) 100 units at $7. Collapse question part (a1) Calculate the average unit cost. (Round answer to 2 decimal places, e.g. 15.25.) Average unit cost
Answer: 4h4hj4h44 n4
Step-by-step explanation: b4jb4j 4 n4
1) Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equation.
2 x − x2 + 1 = 0, x1 = 2
What is x3 =?
2) Use Newton's method to find all solutions of the equation correct to six decimal places.
x + 4 = x^2 - x
What is X =?
3) Use Newton's method to find all solutions of the equation correct to six decimal places.
5 cos(x) = x + 1
What is X =?
4) A graphing calculator is recommended.
Use Newton's method to find all solutions of the equation correct to eight decimal places. Start by drawing a graph to find initial approximations.
5A) Use Newton's method to find the critical numbers of the function
f(x) = x6 ? x4 + 3x3 ? 4x
What is X =?
B) Find the absolute minimum value of f correct to four decimal places.
Answer:
Check below, please
Step-by-step explanation:
Hello!
1) In the Newton Method, we'll stop our approximations till the value gets repeated. Like this
[tex]x_{1}=2\\x_{2}=2-\frac{f(2)}{f'(2)}=2.5\\x_{3}=2.5-\frac{f(2.5)}{f'(2.5)}\approx 2.4166\\x_{4}=2.4166-\frac{f(2.4166)}{f'(2.4166)}\approx 2.41421\\x_{5}=2.41421-\frac{f(2.41421)}{f'(2.41421)}\approx \mathbf{2.41421}[/tex]
2) Looking at the graph, let's pick -1.2 and 3.2 as our approximations since it is a quadratic function. Passing through theses points -1.2 and 3.2 there are tangent lines that can be traced, which are the starting point to get to the roots.
We can rewrite it as: [tex]x^2-2x-4=0[/tex]
[tex]x_{1}=-1.1\\x_{2}=-1.1-\frac{f(-1.1)}{f'(-1.1)}=-1.24047\\x_{3}=-1.24047-\frac{f(1.24047)}{f'(1.24047)}\approx -1.23607\\x_{4}=-1.23607-\frac{f(-1.23607)}{f'(-1.23607)}\approx -1.23606\\x_{5}=-1.23606-\frac{f(-1.23606)}{f'(-1.23606)}\approx \mathbf{-1.23606}[/tex]
As for
[tex]x_{1}=3.2\\x_{2}=3.2-\frac{f(3.2)}{f'(3.2)}=3.23636\\x_{3}=3.23636-\frac{f(3.23636)}{f'(3.23636)}\approx 3.23606\\x_{4}=3.23606-\frac{f(3.23606)}{f'(3.23606)}\approx \mathbf{3.23606}\\[/tex]
3) Rewriting and calculating its derivative. Remember to do it, in radians.
[tex]5\cos(x)-x-1=0 \:and f'(x)=-5\sin(x)-1[/tex]
[tex]x_{1}=1\\x_{2}=1-\frac{f(1)}{f'(1)}=1.13471\\x_{3}=1.13471-\frac{f(1.13471)}{f'(1.13471)}\approx 1.13060\\x_{4}=1.13060-\frac{f(1.13060)}{f'(1.13060)}\approx 1.13059\\x_{5}= 1.13059-\frac{f( 1.13059)}{f'( 1.13059)}\approx \mathbf{ 1.13059}[/tex]
For the second root, let's try -1.5
[tex]x_{1}=-1.5\\x_{2}=-1.5-\frac{f(-1.5)}{f'(-1.5)}=-1.71409\\x_{3}=-1.71409-\frac{f(-1.71409)}{f'(-1.71409)}\approx -1.71410\\x_{4}=-1.71410-\frac{f(-1.71410)}{f'(-1.71410)}\approx \mathbf{-1.71410}\\[/tex]
For x=-3.9, last root.
[tex]x_{1}=-3.9\\x_{2}=-3.9-\frac{f(-3.9)}{f'(-3.9)}=-4.06438\\x_{3}=-4.06438-\frac{f(-4.06438)}{f'(-4.06438)}\approx -4.05507\\x_{4}=-4.05507-\frac{f(-4.05507)}{f'(-4.05507)}\approx \mathbf{-4.05507}\\[/tex]
5) In this case, let's make a little adjustment on the Newton formula to find critical numbers. Remember their relation with 1st and 2nd derivatives.
[tex]x_{n+1}=x_{n}-\frac{f'(n)}{f''(n)}[/tex]
[tex]f(x)=x^6-x^4+3x^3-2x[/tex]
[tex]\mathbf{f'(x)=6x^5-4x^3+9x^2-2}[/tex]
[tex]\mathbf{f''(x)=30x^4-12x^2+18x}[/tex]
For -1.2
[tex]x_{1}=-1.2\\x_{2}=-1.2-\frac{f'(-1.2)}{f''(-1.2)}=-1.32611\\x_{3}=-1.32611-\frac{f'(-1.32611)}{f''(-1.32611)}\approx -1.29575\\x_{4}=-1.29575-\frac{f'(-1.29575)}{f''(-4.05507)}\approx -1.29325\\x_{5}= -1.29325-\frac{f'( -1.29325)}{f''( -1.29325)}\approx -1.29322\\x_{6}= -1.29322-\frac{f'( -1.29322)}{f''( -1.29322)}\approx \mathbf{-1.29322}\\[/tex]
For x=0.4
[tex]x_{1}=0.4\\x_{2}=0.4\frac{f'(0.4)}{f''(0.4)}=0.52476\\x_{3}=0.52476-\frac{f'(0.52476)}{f''(0.52476)}\approx 0.50823\\x_{4}=0.50823-\frac{f'(0.50823)}{f''(0.50823)}\approx 0.50785\\x_{5}= 0.50785-\frac{f'(0.50785)}{f''(0.50785)}\approx \mathbf{0.50785}\\[/tex]
and for x=-0.4
[tex]x_{1}=-0.4\\x_{2}=-0.4\frac{f'(-0.4)}{f''(-0.4)}=-0.44375\\x_{3}=-0.44375-\frac{f'(-0.44375)}{f''(-0.44375)}\approx -0.44173\\x_{4}=-0.44173-\frac{f'(-0.44173)}{f''(-0.44173)}\approx \mathbf{-0.44173}\\[/tex]
These roots (in bold) are the critical numbers
Please answer this correctly
Answer:
25%
Step-by-step explanation:
less than 30 is from minimum to lower quartile. so, 25%