II
Homework: Secti...
Question 2, 7.1.5
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Find the critical value Za/2 that corresponds to the given confidence level.
95%
.....
za/2
(Round to two decimal places as needed.)
(

Answer:

Step-by-step explanation:

The progression of sums is ...

  1, 5, 15, 34, 65, ...

So, first differences are ...

  4, 10, 19, 31

Second differences are ...

  6, 9, 12, ...

Third differences are constant:

  3, 3, ...

This means the expression for Sn will be a cubic expression. If dn is the first of the n-th differences, then the equation can be written as ...

  Sn = S1 +(n -1)(d1 +(n -2)/2(d2 +(n -3)/3(d3)))

And this simplifies a little bit to ...

  Sn = 1 +(n -1)(4 +(n -2)(n +3)/2)

In simpler form, we have ...

  Sn = 1/2(n³ +n)

Then the two terms we're interested in are ...

  S7 = (1/2)(7³ +7) = 175

  S17 = (1/2)(17³ +17) = 2465

Each term Sₙ consists of the sum of a triangular number of terms, which are given by

[tex]T_n = \displaystyle \sum_{k=1}^n k = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]

The triangular numbers are given recursively for n ≥ 1 by

[tex]T_n = T_{n-1} + n[/tex]

starting with T₀ = 0.

For example,

• S₁ = 1 and

[tex]\displaystyle S_1 = \sum_{k=T_0+1}^{T_1} k = \sum_{k=1}^1 k = 1[/tex]

• S₂ = 2 + 3 and

[tex]\displaystyle S_2 = \sum_{k=T_1+1}^{T_2} k = \sum_{k=2}^3 k = 2 + 3[/tex]

• S₃ = 4 + 5 + 6 and

[tex]\displaystyle S_3 = \sum_{k=T_2+1}^{T_3} k = \sum_{k=4}^6 k = 4 + 5 + 6[/tex]

Then the n-th term of the sequence we're considering is

[tex]S_n = \displaystyle \sum_{k=T_{n-1}+1}^{T_n} k = \sum_{k=T_{n-1}+1}^{T_{n-1}+n} k[/tex]

Expanding this sum, we have

[tex]S_n = \left(T_{n-1}+1\right) + \left(T_{n-1}+2\right) + \left(T_{n-1}+3\right) + \cdots + \left(T_{n-1}+n\right)[/tex]

There are n terms on the right side, and hence n copies of [tex]T_{n-1}[/tex], and the rest of the terms make up the next triangular number [tex]T_n[/tex] :

[tex]S_n = nT_{n-1} + 1 + 2 + 3 + \cdots + n[/tex]

[tex]S_n = nT_{n-1} + \displaystyle \sum_{k=1}^n k[/tex]

[tex]S_n = nT_{n-1} + T_n[/tex]

We have a closed form for [tex]T_n[/tex], so we end up with

[tex]S_n = n \cdot \dfrac{(n-1)n}2 + \dfrac{n(n+1)}2 \implies \boxed{S_n=\dfrac{n^3+n}2}[/tex]

From here it's easy to find S₇ and S₁₇.

[tex]S_7 = \dfrac{7^3+7}2 \implies \boxed{S_7 = 175}[/tex]

[tex]S_{17} = \dfrac{17^3+17}2 \implies \boxed{S_{17} = 2465}[/tex]

Answer:

LCM of 6 and 9 are 18

1/6 = 1×3/6×3

= 3/18

= 3×10/18×10

= 30/180

1/9 = 1×2/9×2

= 2/18

=2×10/18×10

= 20/180

therefore rational no.s between 1/6 & 1/9 are

21/180,22/180,23/180,24/180,25/180,26/180,27/180,28/180,29/180

Step-by-step explanation:

sorry if im wrong

Answer:

1/18.

Step-by-step explanation:

-1/6 = -3/18 and 1/9 = 2/18

so one rational number between these values is  1/18.

well, first off, when it comes to volumes by rotation, we'd want to graph them, Check the picture below.  Our rotation over the axis will give us a "washer", so we'll be using the washer method.

now, our axis of rotation is the y-axis or namely x = 0, x = 0 is a vertical line, meaning we have to put the functions in y-terms, that is in f(y) form

[tex]y = x^2\implies \pm\sqrt{y}=x\implies \boxed{\pm\sqrt{y}=f(y)} \\\\\\ y = 4x\implies \cfrac{y}{4}=x\implies \boxed{\cfrac{y}{4}=g(y)}[/tex]

if we look at the picture, the parabola is the farthest from the axis of rotation and the line is the closest, or namely R² and r² respectively.

the way I get the area for R² and r², is by using the same I do with "area under the curve", so if I say call the axis of rotation h(y), the way I get the area is

R => f(y) - h(y)

r => g(y) - h(y)

so let's proceed.

[tex]\textit{area under the curve}\\ \begin{array}{llll} \sqrt{y}- 0\implies &\sqrt{y}\\ \frac{y}{4}-0\implies &\frac{y}{4} \end{array}\qquad \qquad \begin{array}{llll} \stackrel{R^2}{(\sqrt{y})^2}-\stackrel{r^2}{\left( \frac{y}{4} \right)^2}\\[-0.5em] \hrulefill\\ y\qquad -\qquad \frac{y^2}{16} \end{array}[/tex]

now, we want to get the area enclosed by both, and thus we'd need their points of intersection, setting both to [tex]\sqrt{y}=\cfrac{y}{4}[/tex]  which in short gives us the bounds of 0 and 16.

[tex]\pi \displaystyle\int_{0}^{16}\left( y - \cfrac{y^2}{16} \right)dy\implies \pi \int_{0}^{16}y\cdot dy-\pi \int_{0}^{16}\cfrac{y^2}{16}\cdot dy\\\\\\\pi \cdot \left. \cfrac{y^2}{2} \right]_{0}^{16}-\pi \cdot \left. \cfrac{y^3}{48} \right]_{0}^{16}\implies 128\pi -\cfrac{256\pi }{3}\implies \boxed{\cfrac{128\pi }{3}}[/tex]

Answer:

x=28°

Step-by-step explanation:

supplementary angles equal 180°

So:

3x+2x+x+12=180°

6x+12=180

6x=168

x=28°

Therefore:

3x:

3(28)=84°

2x:

2(28)=26°

x+12:

28+12=40°

Answer:

B. 70

Step-by-step explanation:

If 199.50 PHP gets you 2.85KG of rice.

A kilogram of rice would cost = Total Amount / Total Weight.

199.50/2.85

= 70PHP

we need the image to solve the problem

Answer:

A. x²- 4x+ 1

option A is the answer

Answer:

7½ cups of sugar

Step-by-step explanation:

2 cups of flour needs 3 cups of sugar

1 cups of flour needs 3/2=1.5 cups of sugar

1×5 cups of flour needs 1.5×5=7.5 cups of sugar=7½ cups of sugar ANS

Answer:

[tex]\frac{\sqrt{6} }{4}[/tex], 1.538..., [tex]\frac{19}{7}[/tex], [tex]\sqrt{29}[/tex]

Step-by-step explanation:

Solve them each on the calculator and then put in order

[tex]\frac{\sqrt{6} }{4}[/tex] = 0.6123...

19/7 = 2.714

[tex]\sqrt{29}[/tex] = 5.385...

Answer:

= 130°

Step-by-step explanation:

a far away exterior angle is equal to the sum of two far interior angles

50+80 = x

Answer:

4

Step-by-step explanation:

-4+3=-1

-1+5=4

Answer:

$20,000

Step-by-step explanation:

20,000 / 0.07 = 1400

Answer:

x=sqrt(7)

Step-by-step explanation:

Since this is a right triangle, we can use the pythagorean theorem

a^2 + b^2 =c^2  where a and b are the legs and c is the hypotenuse

x^2 + ( sqrt(7))^2 = (sqrt(14))^2

x^2+7 = 14

x^2 = 14-7

x^2 = 7

Take the square root of each side

sqrt(x^2) = sqrt(7)

x=sqrt(7)

The least common multiple is the smallest expression that can be divided by both of the given expressions.

x^2 - 16 = (x - 4)(x + 4)

x^2 + 4x - 32 = (x + 8)(x - 4)

Both of the factored versions of the expressions have an (x - 4) in them. Thus, that will automatically be included in the LCM. Next, we have to include the (x + 4) and the (x + 8) in our LCM.

LCM = (x - 4)(x + 4)(x + 8)

Hope this helps! :)

Answer:

Step-by-step explanation:

Factorize the given expressions:

The LCM is the product of all unique  factors of both expressions:

Answer:

7=4m +c( y intercept)

Step-by-step explanation:

use the formula y= mx +c

Answer:

DC

Step-by-step explanation:

If we rotate a segment around a point 360 degrees, we have rotated it around to its original point. Similarly, if we rotate it 180 degrees, we have rotated it to the side opposite of where it once was relative to the point.

What we can do is see how much 144 degrees is of 360 and use that to determine how far around we rotate AE around F.

144/360

divide by 12 because that is a common factor of both the numerator and denominator

12 / 30

divide by 2 because that is a common factor

6/15

divide by 3 because that is a common factor

2/5

Therefore, 144/360 = 2/5. This means that we rotate segment AE 2/5 of the way around point F. We have 5 sides in the polygon ABCDE, and each represents 1/5 of the way around. Going counterclockwise, ED represents 1/5, DC represents 2/5, and so on. We are looking for 2/5, so DC is our answer

Answer:

[tex]-\frac{1}{4}(\sqrt{2}+\sqrt{6})[/tex]

Step-by-step explanation:

[tex]cos(\frac{11\pi}{12})[/tex]

[tex]cos(\frac{2\pi}{3}+\frac{\pi}{4})[/tex]

[tex]cos(\frac{2\pi}{3})cos(\frac{\pi}{4})-sin(\frac{2\pi}{3})sin(\frac{\pi}{4})[/tex]

[tex](-\frac{1}{2})(\frac{\sqrt{2}}{2})-(\frac{\sqrt{3}}{2})(\frac{\sqrt{2}}{2})[/tex]

[tex]-\frac{\sqrt{2}}{4}- \frac{\sqrt{6}}{4}[/tex]

[tex]-\frac{1}{4}(\sqrt{2}+\sqrt{6})[/tex]

Helpful Tips:

Sum Identity: [tex]cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)[/tex]

Answer: - 0.3

Step-by-step explanation:

Correct me if I am incorrect.

Answer:

Step-by-step explanation:

The rule when you divide two values with the same base is to subtract the exponents.

Answer:

16:1

Step-by-step explanation:

Since there are 85 total people and 80 are students that means 5 are chaperones.(85-5) Therefore the ratio of students to chaperones is 80:5 or simplified 16:1.

2b + 21 < 22

b is the unknown number so multiply it by 2 to get 2b then add 21, bring the less than sign and write the 22 after the less than sign

Answer:

Hello There!

According to the question,

Base=6

And

Height =4

Let's know the formula

[tex] \frac{1}{2} \times base \times height \\ so \\ \frac{1}{2} \times 6 \times 4 \\ [/tex]

simplify 2 with 6 then it will look like this

[tex] \frac{1}{1} \times3 \times 4 \\ \\ [/tex]

1 has no value so

[tex]3 \times 4 = 12 {ft}^{2} \\ [/tex]

So third option

[tex]a = 12 {ft}^{2} [/tex]

is correct.

[tex]\Large\textsf{Hope \: It \: Helped}[/tex]

Answer:

Area = 12 sq ft

Step-by-step explanation:

The formula to find the area of a triangle is

1/2 bh so we will replace the letters with their number value

1/2 (6x4)

1/2 x 24 = 12

So, 12 is your answer!

Using the midpoint formula, the coordinates of endpoint H are (4, -6).

The midpoint formula is given as: [tex](x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )[/tex]

Where,

[tex](x_m, y_m)[/tex] = coordinates of the midpoint

[tex](x_1, y_1)[/tex] = coordinates of the first point

[tex](x_2, y_2)[/tex] = coordinates of the second point

Given the following:

[tex](x_m, y_m)[/tex] = M( 6,-4)

[tex](x_1, y_1)[/tex] = G(8,-2)

[tex](x_2, y_2)[/tex] = H(?, ?)

Plug in the values into the midpoint formula

[tex]M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )[/tex]

Solve for the x-coordinate and y-coordinate separately

[tex]6 = \frac{8 + x_2}{2}[/tex]

[tex]6 \times 2 = 8 + x_2\\\\12 = 8 + x_2\\\\12 - 8 = x_2\\\\4 = x_2\\\\\mathbf{x_2 = 4}[/tex]

[tex]-4 = \frac{-2 + y_2}{2}\\\\-8 = -2 + y_2\\\\-8 + 2 = y_2\\\\-6 = y_2\\\\\mathbf{y_2 = -6}[/tex]

Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

https://brainly.com/question/13115533

22/3 sorry I accidentally deleted steps