aswer: protactinium-234 is more dang erous than uranium
There can be emissions of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore protactinium-234 is more dangerous than uranium-234.
What is nuclear decay?Nuclear decay is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle. Protactinium-234 and uranium-234 are radioactive element.
If we were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials then protactinium-234 is more dangerous than uranium-234. The half-life of protactinium-234 is smaller than that of uranium-234. So, protactinium-234 is more active than uranium-234 and hence more harmful than uranium-234.
Therefore, protactinium-234 is more dangerous than uranium-234.
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Which of the following is the Brønsted-Lowry definition of an acid?
Answer:
A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).
A student said, "You can't see the full Moon during the day because it rises close to sunset."
Which diagram supports this statement? (Diagrams are not to scale. You are looking down from
a north polar view fisa person standing on Earth at sunset.)
Oq. Ooo
Ooo
OD
ОА
OB
ОС
OD
Answer:
I think it would be B.
Explanation:
what energy is stored
Answer: potential energy is stored
Explanation:
Question #37.P.2A.2
Which statement about the periodic table is true?
a. Elements in the same column share similar properties.
b. Elements in the same row share similar properties.
c. Elements on the left have a larger nucleus than elements on the right.
d. Elements at the top of each column have the highest atomic mass in that column.
Knowing that Boyle's Law is P1V1 = P2V2, How would we rearrange the formula if we needed to solve for P1?
A. P1 = V1 -P2
B. P1 = P2V2 - V1
C. P1 = P2V2/V1
D. P1= V1/V2
Answer:
your answer is C
Explanation:
because when u make P1 the subject formula then P2 V2 will be divided with V1
HELP ANYONE THERE
At a research lab, a scientist carelessly pours cultures of living microbes down the drain. Which type of pollution is this?
Question 4 options:
toxic
sediment
nutrient
bacterial
A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
What is bacterial pollution?Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.
Bacterial pollution can be a subject of concern because bacteria may be pathogenic microorganisms.Bacterial pollution may cause serious harm to the public health and the well-being of a population.In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
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Which of the following is the correct definition of "weathering"? *
The movement of rocks
The breakdown of rocks.
The dropping off of rocks
All of the above
8. A liquid boils when the vapor pressure of the liquid equals the atmospheric pressure on the surface
of the liquid. Using Reference Table H, determine the boiling point of water when the atmospheric
pressure is 90. kPa
Answer:
It is 98 degrees C.
Explanation:
1. Which kingdom is made up of only autotrophs?
A. Protista
I
B. Animalia
C. Plantae
D. Phylum
Answer: I believe it's C
Hope this helped<3
Can you please make my answer brainly
_BaS + _PtF2 → _BaF2 + _Pts
[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]
_BaS + _PtF2 → _BaF2 + _Pts
Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.
=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS
[tex]\\\\\\[/tex]
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PLEASE MARK ME BRAINLIEST☺️
How many moles of gold atoms do 3.45x10^24 gold atoms constitute?
Answer:
3.45E24
Explanation:
calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m2 at 500C. Assume a diffusion coefficient of 1.0 108 m2 /s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
Answer:
the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
Explanation:
Given the data in the question;
thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
concentration high pressure side C[tex]_A[/tex] = 2.4
concentration low pressure side C[tex]_B[/tex] = 0.6 kg
from the question, we calculate the concentration gradient
dc/dx = (C[tex]_A[/tex] - C[tex]_B[/tex])/dt
so we substitute
dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )
dc/dx = -360
now, mass of hydrogen per hour that diffuse through a pd sheet
M = -∝AT(dc/dx)
where time t is 1 hour ( 3600 sec )
we substitute
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per one hour
Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.
Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.
According to the question, given data is:
Thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
Concentration high pressure side [tex]C_A[/tex] = 2.4
Concentration low pressure side[tex]C_B[/tex]= 0.6 kg
from the question, we calculate the concentration gradient,
[tex]dc/dx = (C _A- C_B)/dt[/tex]
so, we substitute the values,
[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)
[tex]dc/dx = -360[/tex]
Now, mass of hydrogen per hour that diffuse through a Palladium sheet,
M = -∝[tex]AT(dc/dx)[/tex]
where time t is 1 hour (3600 sec)
We substitute,
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per hour.
Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.
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This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.
What are Renewable Resoures?
Answer:
resources that you can use more than 1 time like rechargeable battery or solar energy
Explanation:
Which contributes to the polarity of a water molecule?
Oa linear shape along with strong covalent bonds
O deflection of hydrogen atoms by lone pairs of electrons
O no difference in the electronegativity of oxygen and hydrogen
Ohydrogen bond formation between water molecules
Answer:
B
Explanation:
Answer:
B
Explanation:
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