if you want to know the identity of an unknown substance, what type of formula would you most likely want to know?

Answer:h

Explanation:

Answer:

Acids and alkalis both contain ions. Acids contain lots of hydrogen ions, which have the symbol H+. Alkalis contain lots of hydroxide ions, symbol OH-. Water is neutral because the number of hydrogen ions is equal to the number of hydroxide ions.

Answer:

Mg donates two electrons to O

Explanation:

Lewis dot notation uses dots and crosses to represent valence electrons on atoms.

Magnesium is a metal and would donate or lose electrons during bonding.

Oxygen is a non metal and would gain electrons during bonding.

The correct option is;

Mg donates two electrons to O

Answer:

When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.

Explanation: Sodium is a metal with a low electronegativity it will form an ionic bond with a non metal with a high electronegativity.

Both Florine and Sulfur are non metals with high electronegativity.

Neon is a noble gas family VIII A and normally doesn't form any bonds at all.

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Answer:

True

It is true that he size of coupling constants (J values) depend on three factors:

a. Through bond distance between the protons.

b. Angle between the two C-H bonds.

c. Electronegative substituents.

Explanation:

With the increase in the valence angle the coupling constant reduces. The distance between the carbon atoms also influence coupling constant. With increase in bond length, the coupling constant decreases. Also the more an atom is electronegative, the lesser is the coupling constant

Thus, it is true that he size of coupling constants (J values) depend on three factors:

a. Through bond distance between the protons.

b. Angle between the two C-H bonds.

c. Electronegative substituents.

Answer:

13.3 h

Explanation:

Step 1: Given data

Time (t): 48,000 seconds

Step 2: Convert "t" from seconds to minutes

We will use the conversion factor 1 min = 60 s.

48,000 s × 1 min/60 s = 800 min

Step 3: Convert "t" from minutes to hours

We will use the conversion factor 1 h = 60 min.

800 min × 1 h/60 min = 13.3 h

To sum up, 48,000 seconds is equal to 13.3 hours.

Answer:

D) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and no double bonds

Explanation:

We can tell that the compound " (5R)-5-[(1S)-1,2-dihydroxyethyl]-3,4-dihydroxy-furan-2,3,4(5H)-trione " has 3 carbonyl groups due to it having "trione" in the name (and it lacking other carbonyl group names, like amide or carboxylic acid).

As there is no "-ene" part of the name referencing a double bond, the only option left is option D).

Answer:

The growth of any plant is controlled by many factor and it depends on them.

Explanation:

The words are sorted according to their genetic factors and the environment factors by the category on which they effect and impact the growth of a plant.

Genetic factor :

Waxy leaves, bad tasting leaves, disease, leaf structure, types of stem, plant structure, reproduction, types of roots.

Environment factor : sunlight, drought, fire, flood, heat wave, insects, wind, space, pH of soil, temperature, pollution, terrain, soil conditions, lack of air.

[H⁺]=6.696 x 10⁻⁵

pH = 4.174

Given

The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution

Required

the [H+]  and pH

Solution

Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids

For weak acid :

[tex]\tt [H^+]=\sqrt{Ka.M}[/tex]

Input the value :

[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴

[H⁺]=6.696 x 10⁻⁵

pH = - log [H⁺]

pH = - log 6.696 x 10⁻⁵

pH = 5 - log 6.696

pH = 4.174

Answer:

See explanation

Explanation:

Big Bang: During the big bang, elements were formed by the squeezing together of light nuclei. Hydrogen atoms were fused together to make helium,  lithium  and other light weight elements.

Stellar Nucleosynthesis: Stellar nucleosynthesis is the process by which elements are created within stars by combining the protons and neutrons together from the nuclei of lighter elements(Thoughtco). In the stars, hydrogen may be fused to give helium, lithium and other elements lighter than iron.

Supernova Nucleosynthesis: A supernova is a process in which a star releases a large amount of energy together with neutrons, hence elements that are heavier than iron, like uranium and gold, can be produced in the process.

Answer:

the volume of a object will go down but the density stays the same

The one that does not describe a chemical property is bleach is poisonous when swallowed. The correct options are C.

Chemical properties are those properties that show the reactivity of an element. These chemical properties are pH, chemical stability, reactivity, radioactive decay, flammability, toxicity, etc.

Gasoline is a chemical compound, its burning will be a chemical property because it shows how it reacts when it comes in contact with another chemical.

Gold is a pure element, its reactivity tendency is a chemical property, and it is not reactive with oxygen. Density is also a property of an element. And lead is denser than gold, which will show a chemical property.

Thus, the correct options are C. Bleach is poisonous when swallowed.

To learn more about chemical properties, refer to the link:

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Answer:

Petrified wood contains minerals that are only found in fossils.

Explanation:

learned it in school (promise)

Answer:

13g of CO₂ is the maximum amount that could be produced

Explanation:

The reaction of hexane with oxygen is:  

C₆H₁₄ + 19/2O₂ → 6CO₂ + 7H₂O  

Where 19/2 moles of oxygen react per mole of C₆H₁₄

To solve this question we need to find theoretical yield finding limiting reactant :

Moles C₆H₁₄:  

4.3g C₆H₁₄ * (1mol / 86.18g) = 0.0499 moles  

Moles O₂:  

25.8g * (1mol / 32g) = 0.806 moles  

For a complete reaction of 0.0499 moles of C₆H₁₄ are needed:

0.0499 moles of C₆H₁₄ * (19/2 mol O₂ / 1mol C₆H₁₄) = 0.474 moles of O₂.

As there are 0.806 moles, O₂ is in excess and C₆H₁₄ is limiting reactant

In theoretical yield, the moles of hexane added = 6Moles of CO₂ produced. Moles of CO₂ are:

0.0499 moles C₆H₁₄ * (6mol CO₂ / 1mol C₆H₁₄) = 0.299 moles CO₂

In grams:

0.299 moles CO₂ * (44.01g / mol) = 13g CO₂

This question is incomplete, the complete question is;

Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels selectively permeable only to chloride ions. The left compartment (also called inside) contains 1 mM Cl- and the right compartment (also called outside) contains 100 mM Cl-. What will the electrical potential be when the system attains equilibrium? [ assume body temperature; log 100 = 2, log 10 = 1, log 1 = 0, log 0.1 = -1, log 0.01 = -2]

Options;

a) -62 mV

b) -124 mV

c) +62 mV

d) 0 mV

e) +124 mV

Answer:

the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

Explanation:

Given the data in the question;

Two compartments are divided by lipid bilayer;

In inside compartment Cl- ion concentration- 1mM and out side of the cell concentration is 100mM

now we apply the Nernst equilibrium potential equation;

Chlorine ion valency is z = –1

So

[tex]E_{eq}[/tex] = 62/z × log(ion outside/ ion inside) [for Cl‐ ions]

[tex]E_{eq}[/tex] = (62 / –1) x log(  100 / 1 )

 [tex]E_{eq}[/tex] = -62 x 2 =

[tex]E_{eq}[/tex]  = –124mV

Therefore, the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

Answer: Theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]

[tex]\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles[/tex]

The balanced chemical equation is:  

[tex]2S+3O_2\rightarrow 2SO_3[/tex]  

According to stoichiometry :

2 moles of [tex]S[/tex] produce =  3 moles of [tex]SO_3[/tex]

Thus 0.28 moles of [tex]S[/tex] will produce=[tex]\frac{3}{2}\times 0.28=0.42moles[/tex]  of [tex]SO_3[/tex]  

Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g[/tex]

Thus theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

Answer:

See explanation

Explanation:

When sodamide reacts with methanol, the following equilibrium is set up;

CH3OH(aq) + NH2-(aq) ⇄ CH3O-(aq) + NH3(aq)

In the reaction, the sodamide acts as a base that abstracts a proton from methanol to yield the conjugate base of methanol which is the methoxide ion.

The forward reaction is favoured at equilibrium.

Answer:

No, it is not appropriate to mix water and DMSO

Explanation:

We have to realize that DMSO is a highly polar solvent and water is a highly polar solvent. The question explicitly says that our target is to produce a solvent of intermediate polarity.

We can only do this by mixing a polar and a nonpolar solvent. We have been given the example of the mixture of acetone/hexane which is quite a perfect mixture.

Thus, it is inappropriate to mix DMSO and water.

The water-DMSO mixture has a high polarity and is not appropriate for intermediate polarity solution.

The interactions between solute-solvent result in the solubility and the polarity of the solution. The polar and non-polar solvents result in intermediate polarity of the solution.

The water and DMSO both are highly polar in nature. The addition of polar DMSO to polar water results in the dipole-dipole interaction between the molecules.

The interactions result in the solubility of the solute with solvent.  However, the polarity of the solution will be high as both the molecules gave synergistic mixture polarity to the solution.

Thus, to obtain the solution of intermediate polarity, water-DMSO mixture is not appropriate.

Learn more about non-polar, here:

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Answer:

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. ... Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.

Answer: when an electromagnetic field interacts with a magnet

Explanation:

Answer:

Yes we can calculate the solubility

The solubility of the mineral is 120 g/L

Explanation:

We have the information that the sample taken originally from the rock pool is 25.0 mL

So,

25.0 mL of the sample contained 3.000 g of the sample

10000mL of the sample now contains 1000 * 3.000/25 = 120 g

This means that 120 g of the sample dissolves in 1000mL or 1L of solution.

Therefore, the solubility of the mineral is 120 g/L

The original material has decayed 75%

Given

two half-life

Required

The decayed sample

Solution

General formulas used in decay:  

[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time

t = 2 x t 1/2

Input the value :

[tex]\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%[/tex]  

The amount of Nt = 25% No

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

The moles of CH3COO- are its initial moles - the moles of HCl added

And moles of CH3COOH are its initial moles + moles HCl added

Moles CH3COO-:

Initial moles  = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

pH = 3.90

The pH of the buffer after addition of 10.0 mL of 50.0mM HCl is 3.90

The Henderson-Hasselbach equation is given as:

where

The formula for calculating number of moles is:

The equation of the reaction is given below:

CH3COO- + HCl → CH3COOH + Cl-

moles of CH3COO- = initial moles - moles of HCl added

moles of CH3COOH = initial moles + moles HCl added

Moles CH3COO-

Molarity = 0.010 M

volume = 100 mL = 0.100 L

Initial moles  = 0.100 L * 0.010 M = 0.001 moles

Moles HCl = 0.010L * 0.050 M= 0.0005 moles

Moles CH3COO- = 0.001 - 0.0005 moles

Moles of CH3COO- = 0.000500 moles

Moles CH3COOH:

Molarity = 0.040 M

volume = 100 mL = 0.100 L

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.004 - 0.0005 moles

Moles CH3COO- = 0.003500 moles

Substituting the calculated values:

pH = 4.75 + log [0.000500] / [0.00350]

pH = 3.90

Therefore, the pH of the buffer after addition of the 10.0 mL 50.0mmHg HCL is 3.90

Learn more about about buffers and pH at: https://brainly.com/question/11851669

Answer:

this is the required answer look it once

Answer:

Li3PO4 - correct

FePO4 - correct

Cu3PO4 - correct

Mg3(PO4)2 - correct

Explanation:

In order to answer this question we must be conversant with the idea of valency as well as the idea of writing formula of ionic substances.

Lithium has a valency of 1 while PO4^3- has a valency of 3 so the correct formula of lithium phosphate must be Li3PO4 after the exchange of valencies.

Iron III has a valency of 3 while the phosphate ion also has a valency of 3 so the subscripts cancel out and iron III phosphate is FePO4.

Copper I ion has a valency of 1 and the phosphate ion has a valency of 3. When they exchange valencies, the formula of the compound is Cu3PO4.

Magnesium has a valency of 2 while the phosphate ion has a valency of 3. The exchange of valency gives us the formula Mg3(PO4)2.