Answer:
B
Explanation:
How many microliters are in 41.0 mL
Answer:
41000 is the answer
The amount of microliters in 41.0 mL is 41,000 microliters
How to find the volume in microlitersTo convert milliliters (mL) to microliters (µL), you need to multiply the value in milliliters by 1000 because there are 1000 microliters in 1 milliliter.
So, to convert 41.0 mL to microliters:
41.0 mL * 1000 = 41,000 µL
Therefore, there are 41,000 microliters in 41.0 mL.
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Which product forms from a reaction between calcium (Ca) and phosphorus
(P)?
A. Ca2P3
B. Cap
C. CazP2
D. CaP2
Among these options, the correct formula for calcium phosphide is D. [tex]CaP_2[/tex]. Option D
The product formed from a reaction between calcium (Ca) and phosphorus (P) is calcium phosphide, which is represented by the chemical formula [tex]Ca_3P_2[/tex].
In the reaction between calcium and phosphorus, the calcium atom (Ca) donates two electrons to each phosphorus atom (P). This results in the formation of calcium ions (Ca2+) and phosphide ions (P3-). The ions combine to form the compound calcium phosphide ([tex]Ca_3P_2[/tex]).
The formula [tex]Ca_3P_2[/tex]indicates that three calcium atoms combine with two phosphorus atoms. The numerical subscripts are determined by the charges of the ions involved. Calcium, being a group 2 element, forms ions with a +2 charge (Ca2+), while phosphorus, being a group 15 element, forms ions with a -3 charge (P3-).
The product options provided are:
A. [tex]Ca_3P_2[/tex]
B. Cap
C. [tex]CazP_2[/tex]
D. [tex]CaP_2[/tex]
Among these options, the correct formula for calcium phosphide is D. [tex]CaP_2[/tex].
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Answer: Ca3P2
This is the answer!
Explanation:
A. Ca3P2
B. CaP2
C. Ca2P3
D. CaP
Which of the following wavelengths penetrate earth's atmosphere?
O Microwaves
O Gamma rays
O Radio waves
O X-rays
Answer:
Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.
Let me know if this helps!
A certain electromagnetic wave a wavelength of 415 nm. What is the frequency of the wave in hz?
Answer:
The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz
Explanation:
The wavelength of the electromagnetic wave, λ = 415 nm
The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s
Given that an electromagnetic wave is a periodic wave, we have;
The speed of the electromagnetic wave, c = f×λ
Where;
f = The frequency of the electromagnetic wave
Therefore, we have;
f = c/λ
From which we have;
f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz
The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz
What can wind energy be transformed or converted into?
Answer:
Electrical energy
Explanation:
The wind Mill is an example of a device that converts wind energy into electrical energy
star_____ has the greatest absolute brightness
Answer:
Star A would have the greater absolute brightness. This is because absolute brightness finds out the actual brightness of a star at a standard distance from Earth. If Star A is twice as far from Earth as Star B but they still both appear to have the same amount of brightness.
Consider these compounds:
a. CuCO3
b. ZnS
c. Ni(CN)2
d. Ag2CrO4
Complete the following statements by entering the letter corresponding to the correct compound. Without doing any calculations it is possible to determine that silver carbonate is more soluble than _________ , and silver carbonate is less soluble than ____________. It is not possible to determine whether silver carbonate is more or less soluble than _______________ by simply comparing Ksp values.
Explanation:
If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.
- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B
WS 3.5 more Lewis structures
How many grams of Al2O3 can form from 34.6 grams of Al
Answer: 65.28 g of [tex]Al_2O_3[/tex] will be produced from 34.6 g of Al.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} Al=\frac{34.6g}{27g/mol}=1.28moles[/tex]
The balanced chemical reaction is
[tex]4Al+3O_2\rightarrow 2Al_2O_3[/tex]
According to stoichiometry :
4 moles of [tex]Al[/tex] produce = 2 moles of [tex]Al_2O_3[/tex]
Thus 1.28 moles of [tex]Al[/tex] produce=[tex]\frac{2}{4}\times 1.28=0.64moles[/tex] of [tex]Al_2O_3[/tex]
Mass of [tex][tex]Al_2O_3[/tex]= [tex]moles\times {\text {Molar mass}}=0.64moles\times 102g/mol=65.28g[/tex]
Thus 65.28 g of [tex]Al_2O_3[/tex] will be produced from 34.6 g of Al.
Calculate the molar mass of Ba(C2H3O2)2
Answer:
1. Barium Acetate.
2. Formula: Ba(C2H3O2)2.
3. Molar Mass: 255.415.
Explanation:
Convert to moles 12.06 x 10^22 molecules
Answer:
0.2 mole
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 12.06×10²²
Number of mole =?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
12.06×10²² molecules = 12.06×10²² / 6.02×10²³
12.06×10²² molecules = 0.2 mole
Thus, 12.06×10²² molecules is equivalent to 0.2 mole
what is the equation between aqueous sodium carbonate and dilute hydrochloric acid
Answer:
When solutions of sodium carbonate and hydrochloric acid are mixed, the equation for the hypothetical double displacement reaction is: Na2CO3 + 2 HCl → 2 NaCl + H2CO3 Bubbles of a colorless gas are evolved when these solutions are mixed.
Do all living things depend on nonliving things to survive? Support your answer with an example.
Answer:
Living things need nonliving things to survive. Without food, water, and air, living things die. Sunlight, shelter, and soil are also important for living things. ... Plants use water from the soil, carbon dioxide from the air, and energy from sunlight to make their own food.
Explanation:
Answer: yes they do here are is an example a tree depends on water to keep it hydrated.
Explanation:
What mass of carbon dioxide (CO2) is produced when 62.8g of methane (CH4) reacts with oxygen (O2)? Thank you!
Answer:
172.48gExplanation:
CH4 + 2O2 ---> CO2 + 2H2O
moles of methane = 62.8/16 = 3.92
by stotiometry,
3.92 = n
thus mass of co2 = moles× molar mass = 3.92 × ( 12 + 32)
3.92× 44 = 172.48 gramsQUICK PLZZZ why do people run away from the hot weather into the cool ocean on a sunny day? Explain your answer using one of the properties of water?
You are presented with a white solid and told that, because of careless labeling, it is not clear whether the substance is mercury(I) nitrate, calcium carbonate, or aluminum nitrate. When you transfer the solid to a beaker and add water, the solid dissolves to give a clear solution. Next, a Na2SO4(aq) solution is added and a white precipitate forms.
Required:
a. What is the identity of the unknown white solid?
b. How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 2.5 M CH3OH?
Answer:
aluminum nitrate
Explanation:
We already know that calcium carbonate is insoluble in water hence it will not even dissolve in the water.
Mercury(I) nitrate is soluble in water, when sodium sulfate (Na2SO4) is added to mercury(I) nitrate (Hg2(NO3)2), a pale yellow precipitate is formed.
Aluminum nitrate is soluble in water and reacts with Na2SO4(aq) solution according to the reaction, 2Al(NO3)3(aq)+3Na2SO4(aq) ---> Al2(SO4)3(s)+6NaNO3(aq). The precipitate, Al2(SO4)3(s) is a white crystalline hygroscopic solid.
Consider the reaction of nitrogen dioxide with molecular hydrogen: 2 NO2(g) + 7 H2(g) + 4H2O(l) + 2 NH3(g) Calculate AH°rxn for this reaction given by manipulation of reactions (i) and (ii): 2 NH3(g) → N2(g) + 3 H2(g) AH°rxn = +92.0 kJ (i) N2(g) +4 H2O(l) ---> 2 NO2(g) + 4 H2(g) AHºrxn = +3.40E2 kJ (ii)
The reaction enthalpy is the heat energy absorbed or evolved from a reaction. The enthalpy of reaction for the given reaction is -432 KJ.
What is enthalpy?Enthalpy is the heat energy evolved or absorbed by a reaction system. The reaction enthalpy can be negative or positive. A positive enthalpy means the heat is absorbed and a negative enthalpy means that the heat is evolved by the system.
The given two reactions 1 and 2 have to be reversed to get the net reaction as follows. Thus the positive enthalpy of these reactions becomes negative when reversed.
[tex]2NO_{2} + 4 H_{2} \rightarrow N_{2} +4H_{2}O\\ -92 KJ\\ \\N_{2} + 3 H_{2} \rightarrow 2NH_{3} - -340 J[/tex]
Now, add these two reactions so that we get the reaction of nitrogen dioxide and hydrogen to give water and ammonia and the enthalpies of the above reactions are also added.
Sum of enthalpies of above two reactions is the enthalpy of the required reaction written as follows:
[tex]2NO_{2} + 4 H_{2} \rightarrow N_{2} +4H_{2}O\\ -92 KJ\\ \\+\\ \\\\N_{2} + 3 H_{2} \rightarrow 2NH_{3} - -340 J\\\\\rightarrow NO_{2} + 7H_{2} \rightarrow 4H_{2}O + 2NH_{3}[/tex]
Enthalpy of net reaction = -92 + -340 = -432 KJ
Therefore, enthalpy of reaction for the given reaction is -432 KJ.
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can someone please help!!
Answer:
1:aerobic
2:anaerobic
3:aerobic
La
Nd
Pm
Sm
Tb
Но
Er
Tm
Yb
Lu
Ac
Np Pu Am Cm Bk
CH
Es
Fm Md No
100 g of acetic acid (CH, COOH) is dissolved in a 500.0 ml solution. What is the molarity? Report your answer with the
correct number of significant figures
Answer:
3.34 M
Explanation:
Step 1: Given data
Mass of acetic acid: 100 gVolume of solution (V): 500.0 mL (0.5000 L)Step 2: Calculate the moles of acetic acid
The molar mass of acetic acid is 60.05 g/mol.
100 g × 1 mol/60.05 g = 1.67 mol
Step 3: Calculate the molarity of acetic acid
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
M = 1.67 mol/0.5000 L = 3.34 M
9.
Calculate the mass of a liquid with a density of 3.2 g/mL and a volume of 24 mL.
Question: A first order reaction : B===>C has a half life of 20mins. What percentage shall have reacted after 47minutes
Answer:19.6%
Explanation:
From K=0.693/t
0.693/20 =0.03465min^-1
But rate law is K =2.303/t log a/(a-x)
Substitute the value of k
0.03465=2.303/47 log a / (a-x)
Log a/ (a-x) = 0.7071
a/ (a-x) = 5.094
(a-x)/ a = 1/5.094 = 0.196
Percentage of reactants remaining after 47 minutes= 0.196× 100% = 19.6%
What is the mass of oxygen gas in a 12.2 L
container at 16.0°C and 8.15 atm?
Answer in units of g.
Answer:
grams O₂ = 134 grams
Explanation:
PV = nRT => n = PV/RT
P = 8.15atm
V = 12.2 Liters
R = 0.08206L·atm/mol·K
T = 16.0°C + 273 = 289K
n = (8.15atm)(12.2L)/(0.08206L·atm/mol·K)(289K) = 4.2 moles O₂
grams O₂ = 4.2 moles O₂ x 32g/mol = 134 grams O₂
how partition of Bengal mobilize
please help me
A 0.5242-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.9740 g of CO2 and 0.1994 g of H2O. What is the empirical formula of the compound?
Answer:
C₃H₃O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 0.5242 g
Mass of CO₂ = 0.9740 g
Mass of H₂O = 0.1994 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For carbon, C:
Mass of CO₂ = 0.9740 g
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32 = 44 g/mol
Mass of C = 12/44 × 0.9740
Mass of C = 0.2656 g
For hydrogen, H:
Mass of H₂O = 0.1994 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16 = 18 g/mol
Mass of H = 2/18 × 0.1994
Mass of H = 0.0222 g
For oxygen, O:
Mass of compound = 0.5242 g
Mass of C = 0.2656 g
Mass of H = 0.0222 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 0.5242 – (0.2656 + 0.0222)
Mass of O = 0.5242 – 0.2878
Mass of O = 0.2364 g
Finally, we shall determine the empirical formula. This can be obtained as follow:
Mass of C = 0.2656 g
Mass of H = 0.0222 g
Mass of O = 0.2364 g
Divide by their molar mass
C = 0.2656 /12 = 0.0221
H = 0.0222 /1 = 0.0222
O = 0.2364 /16 = 0.0148
Divide by the smallest
C = 0.0221 / 0.0148 = 1.5
H = 0.0222 / 0.0148 = 1.5
O = 0.0148 / 0.0148 = 1
Multiply through by 2 to express in whole number.
C = 1.5 × 2 = 3
H = 1.5 × 2 = 3
O = 1 × 2 = 2
Empirical formula => C₃H₃O₂
what is the oxidation state of nitrogen in a nh4f molecule
Answer:
+3
Explanation:
NH₄F
=> N + 4H + F = 0
=> N + 4(+1) + 1(-7) = 0
=> N = 7 - 4 = +3
Kayla is creating a model to show her understanding of the water cycle. She wants to show that water is constantly cycling between the atmosphere and Earth’s surface.
What would be the BEST type of model for Kayla to create.
A 3-D model of H2O created with gumdrops and toothpicks.
A. A diagram of molecules gaining energy as they being to evaporate and enter the atmosphere.
B. A poster with pictures of lakes, oceans, rivers and ponds.
C. A circular diagram with arrows showing the movement of water between Earth’s surface and atmosphere.
Answer:C
Explanation:
It would be the most visually understandable.It would be easyer to understand what you are modeling.
Which of the following is TRUE if Esys = 260 J?
Answer:
Both the system and the surroundings are losing 260 J. The system is gaining 260 J, while the surroundings are losing 260 J. Both the system and the surroundings are gaining 260 J. The system is losing 260 J, while the surroundings are gaining 260 J. None of the above is true.
If 10 grams of NaHCO3 react with an excess of HCl, what would be the theoretical mass of NaCl produced?
Worth 15 points. I will give brainliest for best answer. Thank you.
Answer:
Explanation:Reaction NaHCO3 + HCl ⇒ NaCl + H2O + CO2
Molar mass M = (22.99+1.008+ 12.01+3·16 ) g/mol. Calculate
Amount of substance n =m/M, n(NaCl) is equal.
M(NaCl) = 58.44 g/mol and mass m= n·M
EASY CHEM, WILL GIVE BRAINLIEST!!
Hi there!
[tex]\large\boxed{4.04g}[/tex]
To solve, we can use dimensional analysis to convert from molecules to grams.
We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.
After converting, multiply by the atomic mass, or grams per mole.
[tex]1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g[/tex]
EXPERIMENT 1: Identify the oxidation and reduction half-reactions that occur in
Cell 5: Mn(s) | Mn(NO3)2 (aq) || Zn(NO3)2(aq) | Zn(s)
Remember to use proper formatting and notation.
Answer:
Cathode: Mn → Mn²⁺ + 2e⁻ (Oxidation)
Anode: Zn²⁺ + 2e⁻ → Zn (Reduction)
Mn | Mn²⁺ || Zn²⁺ | Zn
Explanation:
To identify the half reaction we need to see the oxidation states.
Mn(s) → Ground state → Oxidation state = 0
Mn(NO₃)₂ → Mn²⁺ → The oxidation state has increased.
This is the oxidation reaction. It has released two electrons:
Mn → Mn²⁺ + 2e⁻
Zn(NO₃)₂ → Zn²⁺
Zn → Ground state → The oxidation state was decreased.
This is the reduction reaction. It has gained two electrons:
Zn²⁺ + 2e⁻ → Zn
Cathode: Mn → Mn²⁺ + 2e⁻
Anode: Zn²⁺ + 2e⁻ → Zn
Mn | Mn²⁺ || Zn²⁺ | Zn