If you have 500 mL of a 0.10 M solution of the acid, what mass of the corresponding sodium salt of the conjugate base do you need to make the buffer with a pH of 7.74 (assuming no change in volume)

Answers

Answer 1

Answer:

5.90g of NaClO are needed

Explanation:

Assuming the weak acid is HClO pKa = 7.54

To solve this question we must use the H-H equation for acids:

pH = pKa + log [A-] / [HA]

Where pH is the pH we want = 7.74

pKa is pKa of the weak acid = 7.54

[A-] could be taken as the moles of the conjugate base (Moles NaClO) and [HA] moles weak acid = 0.500L * (0.10mol/L) = 0.0500 moles HClO

Replacing:

7.74 = 7.54 + log [NaClO] / [0.0500 moles]

0.20 = log [NaClO] / [0.0500 moles]

1.5849 = [NaClO] / [0.0500 moles]

Moles NaClO = 0.0792 moles

The mass is: -Molar mass NaClO = 74.44g/mol-

0.0792 moles * (74.44g / 1mol) =

5.90g of NaClO are needed
Answer 2

5.90g of NaClO mass of the sodium salt of the conjugate base are need to make the buffer with a pH of 7.74.

What is pH?

pH tells the solution is acidic or basic. pH means potential hydrogen.

Given,

Assuming the weak acid is (hypochlorous acid) HClO

pKa = 7.54

[tex]pH = pKa + \dfrac{ log[A-] }{ [HA]}[/tex]

(Moles NaClO) and [HA] moles weak acid = 0.500L * (0.10mol/L) = 0.0500 moles HClO

Putting the value

[tex]7.74 = 7.54 + \dfrac{ log[NaClO] }{ [0.0500 moles]}\\0.20 =\dfrac{ log}{[0.0500 moles]} \\1.5849 =\dfrac{ [NaClO]}{Moles\;of\; NaClO } = 0.0792 moles[/tex]

The mass is

Molar mass NaClO

= 74.44g/mol - 0.0792 moles * (74.44g / 1mol)

=5.90g of NaClO are needed

Thus, 5.90g of NaClO are needed.

Learn more about pH, here:

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Related Questions

answer questions 3 and 4 for a brainly!

Answers

Answer:

The correct answer is -

3. Butyne

4. Pentene

Explanation:

The names of such organic compounds are classified on the number of the carbon atoms and based on a number these prefixes are attached -

Meth - one carbon

Eth - two carbons

Prop - three carbons

But - four carbons

Pent - five carbons, and so on

The bonds can be identified by names of an organic compound by their suffixes -

- ane = single bond

- ene = double bond

-yne = triple bond

Thus, for question 3, carbon numbers are 4 and triple bond so Butyne, and similarly for question 4, 5 carbon atoms and double bond so Pentene.

A gas is contained in a horizontal cylinder with a moveable piston of cross-sectional area 0.33\text{ m}^20.33 m 2 . The region outside the cylinder is at standard ambient temperature and pressure, 298\text{ K}298 K and 1\text{ bar}1 bar. When 2040\text{ J}2040 J of heat flow into the gas, the internal energy of the gas increases by 1380\text{ J}1380 J. Calculate the distance through which the piston moves. You may assume friction is negligible.

Answers

Answer:

0.02 m

Explanation:

∆U = q + w

w = ∆U - q = (1380 - 2040) J = -660 J

w = -p∆V = -pA∆h

∆h = -w/(pA)

p = 1 bar × (100000 Pa/1 bar) = 100000 Pa

∆h = -(-660 J)/(100000 Pa×0.33 m²) = 0.02 m

A gas is contained in a horizontal cylinder with a moveable piston of cross-sectional area 0.33\text{ m}^20.33 m 2. The distance through which the piston moves is 0.02 m.

What is piston ?

Among other related systems, pistons are found in reciprocating engines, reciprocating pumps, gas compressors, hydraulic cylinders, and pneumatic cylinders. It is the moving part that is enclosed in a cylinder and sealed off from the gas by piston rings.

The piston, which is a part of combustion engines, transforms the energy released during combustion into a mechanical action and sends it, via the piston pin and connecting rod, to the crankshaft as a torsional force. The piston in the cylinder goes up and down when the engine is running.

The equation given by

∆ U = q + w

w = ∆ U - q

= ( 1380 - 2040 )

J = -660 J

w = -p∆V

= -pA∆h

∆h = -w / (pA)

p = 1 bar × ( 100000 Pa / 1 bar )

= 100000 Pa

∆h = - ( -660 J) / ( 100000 Pa × 0.33 m² )

= 0.02 m

Thus, The distance through which the piston moves is 0.02 m.

To learn more about piston, follow the link;

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#SPJ2

Which of the following pH numbers are acidic? (Choose 2)
9
11
7
5
3

Answers

the pH numbers that are acidic above is 3 and 5

All of the following elements are metals EXCEPT?
A. Br B. Co C. Cu D. Zn

Answers

Answer:

Br

Explanation:

What is the molecular weight (rmm) of NaOH?
40
20
50
60

Answers

Answer: A/40 it is actually 39.997 but since that is not an answer they rounded up

Explanation:

How many miles are in 27.4 g of NO2

Answers

Answer:

0.59 moles

Explanation:

Given mass = 27.4 g

Molar mass of NO₂ = 46 g/mol

We need to find the number of moles. We know that,

No of moles = given mass/molar mass

Put all the values,

[tex]n=\dfrac{27.4}{46}\\\\n=0.59[/tex]

Hence, there are 0.59 moles of NO₂ .

container has 3 moles of gas with a volume of 60 liters and at a temperature of 250 K, Calculate the pressure inside the container in kPa

Answers

Answer:

103.9 KPa

Explanation:

From the ideal gas equation;

PV=nRT

From the parameters given;

P= ?

T=250 K

V= 60L

n=3

R=0.082 atmLK-1mol-1

P= nRT/V

P= 3 × 0.082 × 250/60

P= 1.025 atm

1 atm=101325 pascals

1.025 atm = 1.025 atm × 101325 pascals/1atm

= 103.9 KPa

Answer:

103.9kPa

Explanation:

To solve this question we must use the equation:

PV = nRT

P = nRT / V

Where P is pressure in atm

n are moles of the gas = 3mol

R is gas constant = 0.082atmL/molK

T is absolute temperature = 250K

V = 60L

P = 3mol*0.082atmL/molK*250K / 60L

P = 1.025atm

As 1atm = 101.325kPa

1.025atm * (101.325kPa / 1atm) = 103.9kPa

Can someone help me with this?

Answers

yeah so you have to start of with converting your first two values into moles (forget the third one)

97.5 g NO * 1 mol/30.01 g NO = 3.25 moles NO

88.0 g O2 * 1 mol/16.00 g O2 = 5.5 moles O2

now we can find the limiting reactant by checking for the amount of product each reactant should give us by using molar ratios

3.25 mol NO * 2 mol NO2/2 mol NO = 3.25 mol NO2

5.5 mol O2 * 2 mol NO2/ 1 mol O2 = 11

so NO is the limiting reactant since it produces less product/gets used up quicker

3.25 mol NO * 2 mol NO2/2molNO = 3.25 mol NO2

so this is our theoretical yield and the question provides us with the actual yield (2.68 moles). since the actual yield is given in moles, we don't have to convert to grams. our percent yield formula goes like: actual yield/theoretical yield * 100

2.68 mol/3.25 mol * 100 = 82.46%

a gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the container if the temperature remains constant?

1. 2.54 kPa

2. 157 kPa

3. 481 kPa

pls help ;(

Answers

Answer:

[tex]\boxed {\boxed {\sf 2. \ 157 \ kPa}}[/tex]

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:

[tex]P_1V_1=P_2V_2[/tex]

We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.

[tex]275 \ kPa *20.0 \ L=P_2V_2[/tex]

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

[tex]275 \ kPa *20.0 \ L=P_2* 35.0 \ L[/tex]

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}[/tex]

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2[/tex]

The units of liters cancel.

[tex]\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2[/tex]

[tex]\frac {5500}{35.0} \ kPa= P_2[/tex]

[tex]157.142857 \ kPa=P_2[/tex]

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

[tex]157 \ kPa= P_2[/tex]

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.

Can I please get help with chemistry.
I got these three questions wrong and I’m wondering which answers would be right for the questions.

Answers

Answer: The 3rd one

Explanation: Electronegativity is a measure of how strongly atoms attract bonding electrons to themselves.

I might be wrong

write the chemical formula of 25 compound​

Answers

C2h40
No cap that’s it

Two water molecules are weakly attracted to each other when a slightly positive hydrogen atom in the first molecule is attracted to the slightly negative oxygen atom on the second molecule. What type of bond is this

Answers

The answer is: Hydrogen bond

How many Fluorine atoms are needed to accept the electrons of one Ca atom?
1
2
3
4

Answers

2 F atoms

Explanation:

A Ca atom has a valence number of +2, which means that when ionized, it will give up two electrons. In turn, a F atom has a valence number of -1, which means it can only accept 1 electron when ionized. So to accommodate the two electrons from Ca atom, we need 2 F atoms.

Why does the rate of the forward reaction increase when the surface area of a reactant is increased
?
When the surface area increases, the concentration of the substance increases, which reduces
the number of effective collisions.
When the surface area increases, the temperature of the system increases, which in turn
increases the number of effective collisions.
When the surface area increases, the density of the substance increases, which increases the
number of collisions.
When the surface area increases, the number of particle collisions increases, which in turn
increases the number of effective collisions.

Answers

Increasing the surface area of a reactant increases the frequency of collisions and increases the reaction rate. Several smaller particles have more surface area than one large particle. The more surface area that is available for particles to collide, the faster the reaction will occur.

Explain in terms of structure and bonding why carbon dioxide has a low boiling point and calcium carbide has a high boiling point

Answers

Answer:

See explanation

Explanation:

Let us consider the two compounds carefully. Carbon dioxide is purely a non-polar molecular compound while the bond between the C2^2- ion and Ca^2+ is ionic thereby making CaC2 an ionic compound.

Recall that ionic compounds have high melting and boiling points due to strong ionic interactions in the structure of the compound.

On the other hand, CO2 is a non-polar substance whose molecules are held together only by weak dispersion forces.

As a result of the reasons outlined above, carbon dioxide has a low boiling point and calcium carbide has a high boiling point.

If I have 4.4 moles of nitrous oxide (laughing gas) that is kept at 32.9 °C in a container under 1.6 atm, what is the volume of the container? (R = 0.0821 (L*atm)/(mol*K))

Round your answer to 1 decimal place.

Answers

Answer:

Explanation:

Using the ideal gas equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information provided in this question;

P = 1.6atm

n = 4.4 moles

R = 0.0821 L*atm/mol*K

T = 32.9°C = 32.9 + 273 = 305.9K

V = ?

An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
working substance and operates from a most compressed stage of 100 Nm and
327 K. It expands isothermally to a pressure of 90 Nm and then adiabatically to a
most expanded stage of 27 K. Calculate the AU, 9, and w for each step. Calculate
the net work done and the efficiency of the cycle [Cv,m for the gas) is 25 J/k/mol.​

Answers

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

[tex]P_i[/tex] = 100 N·m

[tex]T_i[/tex] = 327 K

[tex]P_f[/tex] = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈ -0.52571 kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = -7.5 kJ

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = -5.00574 kJ

Calculate the current in amperes required to produce 18.0g of aluminium in 1.50hrs (al=27.og )

Answers

Answer:

35.7 A

Explanation:

Let's consider the reduction half-reaction of Al³⁺.

Al³⁺ + 3 e⁻ ⇒ Al

We will calculate the charge required to produce 18.0 g of Al using the following conversion factors.

1 mole of Al has a mass of 27.0 g1 mole of Al is formed upon the circulation of 3 moles of electrons1 mole of electrons has a charge of 96486 C (Faraday's constant)

[tex]18.0gAl \times \frac{1molAl}{27.0gAl} \times \frac{3mole^{-} }{1molAl} \times \frac{96486C}{1mole^{-} } = 1.93 \times 10^{5} C[/tex]

1.93 × 10⁵ C circulate in 1.50 hours. The intensity is:

[tex]I = \frac{1.93 \times 10^{5} C}{1.50h} \times \frac{1h}{3600s} = 35.7 A[/tex]

8.
(a) Tick (™) the box next to the correct statement about the mixture.
mixture of four elements
mixture of four compounds
mixture of two elements and two compounds
mixture of one element and three compounds​

Answers

Answer:

mixture of four compounds

mixture of two elements and two compounds

Explanation:

it can be one of thosecan u tell me if its correct pls I'm studying this too

Inicialmente una muestra de neón tiene un volumen de 2,50 L a 15 °C. ¿Cuál es la
temperatura en °C, cuando el volumen de la muestra cambia a cada uno de los
siguientes volúmenes, ¿manteniéndose la presión constante?
a. 5,0 L b. 1250 ml c. 7,50L d. 3550 ml

Answers

naoooooooo seiiiiiiiii !!!!!!!!!!!!!!

A mixture of oxygen( O2), dinitrogen monoxide (N2O), and argon (Ar) has a total pressure of 0.98 atm. What is the partial pressure of N2O, if the partial pressure of O2 is 0.48 atm and the partial pressure of Ar is 0.15 atm?

Answers

Answer: The partial pressure of [tex]N_{2}O[/tex] is 0.35 atm.

Explanation:

Given: Total pressure = 0.98 atm

Partial pressure of [tex]O_{2}[/tex] = 0.48 atm

Partial pressure of Ar = 0.15 atm

Partial pressure of [tex]N_{2}O[/tex] = ?

Total pressure is the sum of partial pressure of each component present in a mixture of gases.

Hence, partial pressure of [tex]N_{2}O[/tex] is calculated as follows.

Total pressure = [tex]P_{N_{2}O} + P_{O_{2}} + P_{Ar}[/tex]

Substitute the values into above formula as follows.

[tex]Total pressure = P_{N_{2}O} + P_{O_{2}} + P_{Ar}\\0.98 atm = P_{N_{2}O} + 0.48 atm + 0.15 atm\\P_{N_{2}O} = 0.35 atm[/tex]

Thus, we can conclude that the partial pressure of [tex]N_{2}O[/tex] is 0.35 atm.

(2-2) Looking at the chemical formula CaF2 (calcium fluoride), what do you think this substance is made of? (Choose ALL that apply)
Metal
Metalloid
Non-metal

Answers

Answer:

Metal

Non-metal

Explanation:

CaF2 is an ionic compound. Ionic compounds are mostly composed of a metal and a non metal. Metals donate electrons to non-metals to form ionic compounds.

Calcium is a divalent ion of group two in the periodic table while F is a univalent nonmetal of group 17 in the periodic table. Hence the compound CaF2 is composed of a metal and a nonmetal.

Calculate the Molar Mass of Radon pentaiodide (Rnls)
857
349
1237

Answers

Explanation:

222.01758 g/mol

3.1Computed Properties

N2 + 3H2 → 2NH3 How many moles of hydrogen are needed to react with 5 moles of nitrogen?​

Answers

Answer: 15 mol

Explanation:

From the equation, we know that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

So, the answer is 5(3) = 15 mol

Thermal energy is a measure of the __________ of particles of matter. *
(subject is science I just cant change it right now)

Answers

Thermal energy measures the total kinetic energy of the particles in a substance.

What is the iupac name of CH3-O-CH2-CH2-CH3?

Answers

Answer:

The iupac name of CH3-O-CH2-CH2-CH3 is Methoxybutane.

1. Hay un gas con 700 milímetros de Mercurio de presión en 922 ml de volumen a 20 grados Celsius. Calcula la temperatura final a 500 mm de mercurio con 451 ml.

2. un gas ocupa un gas ocupa 205 mililitros a 20 grados centígrados y 1,05 atm. Calcule el volumen final a 60 grados centígrados y 2,4 Atmósferas de presión.
3. tenemos 22 L de un gas a una temperatura de 220 K y una presión de 5 Atm, si se modifican la presión a 6.5 atm y la temperatura a 200 K, cuál será el volumen que obtenemos.

Answers

Answer:

püvinlbxyfsswgrxzvnnchcyv nkivtcdg

What are mycelium
??????????

Answers

Answer:

Mycelium is a group of hyphae which are fungus.... these are like roots in structure

Answer:

A mycelium is the vegetative part of a fungus, consisting of a network of fine white filaments

Explanation:

You have 11.27 moles of Cl2 gas. How many moles of NaBr do you need to completely undergo this reaction?

Answers

Answer:

22.54 moles of NaBr are needed

Explanation:

The reaction of Cl2 with NaBr occurs as follows:

Cl2 + 2NaBr → 2NaCl + Br2

Where 1 mole of Cl2 requires 2 moles of NaBr for a complete reaction

As in the problem, we have 11.27 moles of Cl2, the moles of NaBr required are:

11.27mol Cl2 * (2mol NaBr / 1mol Br2) =

22.54 moles of NaBr are needed

The balanced equation for the combustion of Hexane,C6H14 , is

Answers

Answer:

[tex]2C _{6}H _{14} + 19O _{2}→12CO _{2} +14H _{2} O[/tex]

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