If you could repeat the lab and make it better, what would you do differently and why?

There are always ways that labs can be improved. Now that you are a veteran of this lab and have experience with the procedure, offer some advice to the next scientist about what you suggest and why. Your answer should be at least two to three sentences in length.

Answer:

protease is an enzyme

Explanation:

It hydrolyse peptide bonds of proteins and also called proteolytic enzymes.

Answer:

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

Explanation:

Answer:

Coulombs equation involves distance and the distance from one radius to the next allows us to predict certain characteristics such as pull and attraction. For example, you would expect, a higher charge on the ion and a higher dipole moment causes a larger force. This is due to the magnitude which is the distance between these two and effectively that is how Columbus law comes into play.

Coulomb's law states that the force of repulsion or attraction among both two charged bodies is directly proportional to the product of their charges as well as inversely proportional to the square of the length between them.

An electric force is created when two charged particles collide. The forces will be greater if you have larger charges.

Coulomb's Law can be understood by combining these two ideas and the fact that charges can attract and repel each other. It is a formula for calculating the electrical forces between two objects.

Coulomb's equation involves distance, and the distance between two radiuses allows us to predict certain characteristics such as pull and attraction.

As you might expect, a higher charge on the ion and a higher dipole moment result in a greater force. This is due to the magnitude of the distance between these two, and this is where Columbus law comes into play.

Thus, this way, Coulomb's law can help you understand why some interparticle forces are stronger than others.

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Solid KMnO₄ needed = 7.9 g

Given

MW KMnO₄ = 158 g/mol

500 mL(0.5 L) of a 0.1M stock solution of KMnO₄

Required

solid KMnO₄

Solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

Input the value :

n = M x V

n = 0.1 M x 0.5 L

n = 0.05 mol

Mass KMnO₄ :

= mol x MW

= 0.05 x 158 g/mol

= 7.9 g

The solid KMnO₄ a person need to add before filling water flask will be:

"7.9 g".

According to the question,

Molecular weight of KMnO₄ = 158 g/mol

Volume of solution = 500 mL or,

                                = 0.5 L

Molarity = 0.1 M

We know the relation,

Molarity, M = [tex]\frac{n}{V}[/tex]

or,

→ n = M × V

By substituting the values,

     = 0.1 × 0.5

     = 0.05 mol

hence,

The mass of KMnO₄ will be:

= mol × Molecular weight

= 0.05 × 158

= 7.9 g

Thus the response above is appropriate.

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Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

[tex]\frac{P}{T} =k[/tex]

When an ideal gas goes from a state 1 to a state 2, it is true:

[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]

In this case:

Replacing:

[tex]\frac{180 kPa}{291 K} =\frac{350 kPa}{T2}[/tex]

Solving:

[tex]T2=350 kPa*\frac{291 K}{180 kPa}[/tex]

T2= 565.83 K

The new temperature will be 565.83 K.

Answer:

The number of passengers that the Embraer E170 could carry if its fuselage was made of steel  is 39 passengers

Explanation:

The given parameters of the cylinder representing the fuselage are;

The length of the cylinder, l = 30.0 meters

The width of the cylinder, w = 2.5 meters

The thickness of the cylinder, t = 2.5 mm = 0.0025 meters

The volume of the metal required to make the fuselage cylinder, V = (π·w²/4 - π·(w - 2·t)²/4) × l

Therefore, by substituting the known values, we have;

V = (π × 2.5²/4 - π×(2.5 - 2×0.0025)²/4) × 30 = 0.58845957392

The volume of the metal required to make the fuselage cylinder, V≈ 0.58846m³

The given density of steel = 7.87 g/cm³ = 7870 kg/m³

The given density of aluminum = 2.70 g/cm³ = 2,700 kg/m³

Mass = Density × Volume

The mass of the fuselage made with steel = The given density of steel × The volume of the metal required to make the fuselage cylinder

∴ The mass of the fuselage made with steel = 7870 × 0.58846 ≈ 4631.18

The mass of the fuselage made with steel ≈ 4631.18 kg

Similarly, the mass of the fuselage made with aluminum = 2,700 × 0.58846 ≈ 1588.84

The mass of the fuselage made with aluminum ≈ 1588.84 kg

The total mass the Embraer E170 could carry = The mass of the fuselage made with aluminum + The mass of the 78 passengers

The average mass of each passenger = 79 kg

∴ The total mass the Embraer E170 could carry ≈ 1588.84 + 78 × 79 = 7750.84

The total mass the Embraer E170 could carry ≈ 7750.84 kg

The extra mass the Embraer E170 could carry when made of steel = (The total mass the Embraer E170 can carry) - (The mass of the fuselage made with steel)

∴ The extra mass the Embraer E170 could carry when made of steel = 7750.84 - 4631.18 = 3119.36

The extra mass the Embraer E170 could carry when made of steel ≈ 3119.36 kg

The number of passengers the Embraer E170 could carry when made of steel  = (The extra mass the Embraer E170 could carry when made of steel)/(The average mass of one passenger)

∴ The number of passengers the Embraer E170 could carry if its fuselage was made of steel  = 3119.36 kg/(79 kg/passenger) ≈ 39.489 passengers

The number of passengers that the Embraer E170 could carry if its fuselage was made of steel  ≈ 39 passengers (we round down when counting people which are whole quantities)

mass of pentane : = 30.303 g

moles of Al₂(CO₃)₃ : = 0.147

Given

1. Reaction

C₅H₁₂+8O₂→6H₂O+5CO₂.

45.3 g water

2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂

37.2 MgCO₃

Required

mass of pentane

moles of Al₂(CO₃)₃

Solution

1. mol water = 45.3 : 18 g/mol = 2.52

From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :

= 1/6 x mol H₂O

= 1/6 x 2.52

= 0.42

Mass pentane :

= mol x MW

= 0.42 x 72.15 g/mol

= 30.303 g

2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44

mol Al₂(CO₃)₃ :

= 1/3 x mol MgCO₃

= 1/3 x 0.44

= 0.147

Answer:

The Alkali metals

Explanation:

The alkali metals react with the nonmetals in Group VIIA (F2, Cl2, Br2, I2, and At2) to form ionic compounds or salts. Example: Chlorine reacts with sodium metal to produce sodium chloride, table salt. Because they form salts with so many metals, the elements in Group VIIA are known as the halogens.

Alkali metals are the type of metal that can react with metals to form salts. They form ionic compounds or salts when reacting with non-metals.

Alkali metals are the six elements of group 1 of the periodic table. thee metals are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

The main characteristics of alkali metals are:

Alkali metals interact to generate ionic compounds or salts. As an illustration, sodium metal and chlorine react to form sodium chloride or table salt.

Thus, alkali metals form salt when reacting with metals.

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The speed of the car = 22.25 m/s

Given

A distance of 22.75 km

Time = 17.04 minutes

Required

The speed (in m/s)

Solution

Speed is the ratio of distance per time

Can be formulated :

v = d/t  

v= speed, m/s

d=distance=m

t=time,s

Input the value :

[tex]\tt v=\dfrac{22.75~km}{17.04~minutes}\times \dfrac{1000~m}{1~km}\times \dfrac{1~minute}{60~second}\\\\v=\boxed{\bold{22.25~m/s}}[/tex]

Answer:

sediments

Explanation:

Answer:

Explanation:

is guiZ

The study of chemicals is called chemistry.

When two elements react together to form a new compound is called a reaction.

[tex]C + O_2 --> Co_2[/tex]

[tex]H_20 ----> H_2 + O_2[/tex]

[tex]Fe + H_2So_4---> FeSo_4+ H_2[/tex]

[tex]BaCl + H_2So_4 + ---> BaSo_4 + HCl[/tex]

[tex]C + O_2 ---> CO_2[/tex]

Hence, the answer is mentioned above.

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Answer:

Hi there, The correct answer is, OPT A

Explanation:

Please mark as the brainliest

Answer:

A. Bromine (Br)

Explanation:

Answer:

its called vapor. It can hold so much than colder eater based on the weather. For example if its cold it can heat up faster but if its hot it will maybe stay the same

Answer:

a

Explanation:

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The balanced equation :

LiI(aq) + AgNO₃(aq) --> AgI(s) + LiNO₃(aq)

Given

Word equation

Required

Balanced equation

Solution

There are 3 ways to express a chemical equation:

Skeleton equation for reaction above :

LiI(aq) + AgNO₃(aq) ⇒ AgI(s) + LiNO₃(aq)

If we look at this reaction, all the cations and anions have a charge of 1 (+1 or -1) so the balanced reaction between the skeleton equation and the balanced equation is the same

Answer:

Pseudoscience

Explanation:

Predicting the future based solely on the position of the planets is an example of pseudoscience.

Pseudoscience is a body of knowledge that is not based on the scientific method but on some unverifiable/unprovable claims.

Predictions about the future can only be valid if it is based on the scientific method, not just about the position of the planet. The scientific method involves observation, hypothesis formulation, testing of the hypothesis through repeatable experiments, and arriving at conclusion.

Any other statement or belief that is not based on these procedures is said to be pseudoscientific.

Answer:

The answer to your question is pseudoscience.

Explanation:

I took the module 1 exam and got it right, yesterday.

Answer:

1.725e+18

Explanation:

Answer:

The orest one is possible D

Explanation:

1. Double-Replacement reactions

2. Decomposition  

3. Combustion

4. Syntesis

5. Single replacement

Given

Chemical equations

Required

Type of reaction

Solution

1. 2AgNO₃ + MgCl₂ ⇒ 2AgCl + Mg(NO₃)₂

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant

2. 2KBr⇒2K +Br₂

Decomposition  

Single compound breaks down in to 2 or more products

3. C₃H₈ + 5O₂ ⇒ 4H₂O + 3CO₂

Combustion

Hydrocarbon and Oxygen reaction and form water and carbon dioxide

4. NaO + H₂O ⇒ NaOH

Syntesis

2 or more reactants combine to form a single product

5. Zn + CuCl₂ ⇒ZnCl₂ + Cu

Single replacement

One element replaces another element from a compound

Answer:

Rusting is an oxidation reaction. The iron reacts with water and oxygen to form hydrated iron(III) oxide, which we see as rust. Unlike rust, which can flake off the surface of iron and steel objects, the layer of aluminium oxide does not flake off.

Explanation:

I feel like it's C. or D. but I guess it's C.

Answer: B

Explanation: Cuz .

Answer: The answer to your question is A

Explanation: Hey I miss you

Answer:

Converting Between Moles and Liters of a Gas at STP. To convert between moles and the volume of a gas at STP, we will use the factor label method discussed in the first unit. This conversions relies on the fact that a mole of gas at STP has a volume of 22.4 L.

Explanation:

One molecule of carbon dioxide at STP has a volume of 22.4 liters . Thus number of molecules of carbon dioxide in 12.2 L is 3.27 × 10²³ molecules.

A molecule is formed by the combination of same or different kinds of atoms. A number molecules together form a compound. Water, carbon dioxide etc. are compounds.

One mole of a molecule contains 6.022 × 10²³ number of atoms. Similarly, one mole of a compound contains, 6.022 × 10²³ number of molecules.This number is called Avogadro number.

At standard temperature and pressure (STP) that is at 298 K and 1 atm pressure, one mole of any substance carry 22.4 L. Thus number moles of 12.2 L of carbon dioxide is 12.2 / 22.4 = 0.54 moles.

Number of molecules = 0.54 moles × 6.022 × 10²³

                                     =  3.27 × 10²³

Hence, number of molecules of carbon dioxide in 12.2 L is 3.27 × 10²³ molecules.

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