If you are doing stoichiometry and it asks you to go from grams of one substance to grams of a new substance, how many steps (how many boxes) would you draw in your setup?

a.1

b.2

c.3

d.4

You do not have to explain if you want to.

Answer:

relation (but not a function)

Explanation:

c on edge

Answer:

[tex]V=3.50x10^{-22}L[/tex]

Explanation:

Hello there!

In this case, given the dimensions of the box, we first compute the volume by multiplying each side:

[tex]V=4nm*8.75nm*10nm=350nm^3[/tex]

Next, we apply the following conversion factor in order to obtain the corresponding liters:

[tex]V=350nm^3*(\frac{1m}{10^9nm} )^3*\frac{1000L}{1m^3} \\\\V=350nm^3*\frac{1m^3}{10^{27}nm^3} *\frac{1000L}{1m^3}\\\\V=3.50x10^{-22}L[/tex]

Best regards!

Answer:

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Answer:

2.0 × 10⁴ mg

Explanation:

Step 1: Given data

Mass (m): 0.020 kg

Step 2: Convert the mass from kilograms to grams

We will use the conversion factor 1 kg = 1,000 g.

0.020 kg × (1,000 g/1 kg) = 20 g

0.020 kg is equal to 20 g.

Step 3: Convert the mass from grams to milligrams

We will use the conversion factor 1 g = 1,000 mg.

20 g × (1,000 mg/1 g) = 2.0 × 10⁴ mg

20 g is equal to 2.0 × 10⁴ mg. Then, 0.020 kg is equal to 2.0 × 10⁴ mg.

Answer:

When a liquid releases enough energy, the liquid will freeze and turn into a solid. Phase changes are what causes one state of matter to turn into another. All phase changes are physical changes.

Explanation:

if ur really saying liquid a person accomplished in languages

especially : one who speaks several languages ?

please mark as brainliest

Answer:

22 g

Explanation:

Step 1: Write the balanced equation

N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)

Step 2: Calculate the moles of NH₃ produced from 2.0 moles of H₂

The molar ratio of H₂ to NH₃ is 3:2.

2.0 mol H₂ × 2 mol NH₃/3 mol H₂ = 1.3 mol NH₃

Step 3: Calculate the mass corresponding to 1.3 moles of NH₃

The molar mass of NH₃ is 17.03 g/mol.

1.3 mol × 17.03 g/mol = 22 g

Answer: The mass in grams is 514.8.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadros number}}[/tex]

given molecules = [tex]7.03\times 10^{24}[/tex]  

Putting in the values we get:

[tex]\text{Number of moles}=\frac{7.03\times 10^{24}}{6.023\times 10^{23}}=11.7moles[/tex]

mass of [tex]CO_2=moles\times {\text {Molar mass}}=11.7mol\times 44g/mol=514.8g[/tex]

The mass in grams is 514.8.

Answer:one mole of stuff (atoms, molecules, eggses), there are NA individual items of that stuff. So, there are 4.5 × NA BCl3 molecules; i.e. 4.5 × 6.022×1023 ≅ 27×1023 individual molecules of BCl3

Explanation:

Answer:

[tex]\boxed {\boxed {\sf About \ 2.7 *10^{24}\ atoms\ N }}[/tex]

Explanation:

To convert from moles to atoms, Avogadro's Number: 6.022*10²³ must be used. This number tells us the amount of particles (atoms, molecules, etc) in 1 mole of a substance. In this case, the particles are atoms of nitrogen.

[tex]\frac {6.022 *10^{23} \ atoms \ N}{1 \ mol \ N}[/tex]

Multiply by the given number of moles: 4.5

[tex]4.5 \ mol \ N *\frac {6.022 *10^{23} \ atoms \ N}{1 \ mol \ N}[/tex]

The moles of nitrogen will cancel.

[tex]4.5 \ *\frac {6.022 *10^{23} \ atoms \ N}{1 }[/tex]

The denominator of 1 can be ignored.

[tex]4.5 \ *{6.022 *10^{23} \ atoms \ N}[/tex]

[tex]2.7099*10^{24} \ atoms \ N[/tex]

The original measurement of moles had 2 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 0 in the hundredth place tells us to leave the 7.

[tex]2.7 *10^{24}\ atoms\ N[/tex]

There are about 2.7*10²⁴ atoms of nitrogen in 4.5 moles.

Answer:

3.32 L

Explanation:

Step 1: Write the balanced equation

TiCl₄(l) + 2 H₂O(g) → TiO₂(s) + 4 HCl(g)

Step 2: Calculate the moles corresponding to 14.0 g of TiCl₄

The molar mass of TiCl₄ is 189.68 g/mol.

14.0 g × 1 mol/189.68 g = 0.0738 mol

Step 3: Calculate the moles of H₂O needed to react with 0.0738 moles of TiCl₄

The molar ratio of TiCl₄ to H₂O is 1:2. The moles of H₂O needed are 2/1 × 0.0738 mol = 0.148 mol

Step 4: Calculate the volume corresponding to 0.148 moles of H₂O(g)

At standard temperature and pressure, 1 mole of H₂O(g) has a volume of 22.4 L.

0.148 mol × 22.4 L/1 mol = 3.32 L

Answer:

[tex]m_{Hg}=829.4gHg[/tex]

Explanation:

Hello there!

In this case, considering the Avogadro's number, which helps us to realize that 1 mole of mercury atoms contains 6.022x10²³ atoms and at the same time 1 mole of mercury weights 200.59 g, we obtain:

[tex]m_{Hg}=2.49x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{200.59g}{1molHg}\\\\m_{Hg}=829.4gHg[/tex]

Best regards!

Answer:

64.7

Explanation:

Answer:

64.7 is the answer

hope this helps

have a good day :)

Explanation:

B

the sun!

yay

!!!!!!!!!!!

Answer:

EARTH

Explanation:

Earth‘s gravity, as already noted, is equivalent to 9.80665 m/s² (or 32.174 ft/s²). This means that an object, if held above the ground and let go, will accelerate towards the surface at a speed of about 9.8 meters for every second of free fall.

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

Answer:

Explanation:

4.125 g of copper oxide contains 3.294 g of Cu . Rest is oxygen

oxygen is 4.125 - 3.294 = .831 g

Ratio of oxygen and copper = .831 : 3.294

.831 / .831 : 3.294 / .831

= 1 : 3.96

1 : 4 ( Approx )

percentage of oxygen in copper oxide = 20 % approx

in the second experiment ,

1.476 g of copper oxide is formed from 1.179 g of Cu

oxygen in this copper oxide = 1.476 - 1.179 = .297 g

Ratio of oxygen and copper

.297 : 1.179

.297/.297 : 1.179/ .297

1 : 3.96

1 : 4 ( approx )

percentage of oxygen in copper oxide = 20 % approx

So it follows the law of definite proportions .

Answer:

O + O ---Δ----> O2

Explanation:

plz follow me friend

Answer:

hello my ne is yash follow me please

Answer:

112 of O2

Explanation:

Now if simply oxygen is given so we'll consider O2

3.5 moles O2 means,

3.5 x 32 = 112 grams of O2

Considering the definition of molar mass, the mass of 3.5 moles of O₂ is 112 grams.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

In this case, you know the molar mass of the oxygen O is 16 g/mole.

So, the molar mass of the compound O₂ is calculated as:

O₂= 2× 16 g/mole

Solving:

O₂= 32 g/mole

Next, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 32 grams, 3.5 moles of the compound contains how much mass?

[tex]mass= \frac{3.5 molesx32 grams}{1 mole}[/tex]

mass= 112 grams

Finally, the mass of 3.5 moles of O₂ is 112 grams.

Learn more about molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

#SPJ2

Answer:

[tex]Y=34.3\%[/tex]

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

[tex]2Al + Cr_2O_3 \rightarrow Al_2O_3 + 2Cr[/tex]

We notice there is a 1:1 mole ratio between Al2O3 and Cr2O3; thus, the following stoichiometric setup is used to compute the theoretical yield first:

[tex]m_{Al_2O_3 }=23.3gCr_2O_3*\frac{1molCr_2O_3}{151.99gCr_2O_3} *\frac{1molAl_2O_3}{1molCr_2O_3} *\frac{101.96gAl_2O_3}{1molAl_2O_3} \\\\m_{Al_2O_3}=15.6gAl_2O_3[/tex]

Thus, the percent yield turns out:

[tex]Y=\frac{5.35g}{15.6g} *100\%\\\\Y=34.3\%[/tex]

Best regards!

Answer:

Germanium monoxide

hope this helps :)

Answer:

320 g.

Explanation:

Hello!

In this case, according to the balanced chemical reaction, we can compute the grams of copper I chloride produced by each reactant, as shown below:

[tex]m_{CuCl}^{by\ Cu}=3.23molCu*\frac{2molCuCl}{2molCu}*\frac{99.0gCuCl}{1molCuCl} =320gCuCl\\\\m_{CuCl}^{by\ Cl_2}=1.64molCl_2*\frac{2molCuCl}{1molCl_2}*\frac{99.0gCuCl}{1molCuCl} =325gCuCl[/tex]

Thus, since copper produces the fewest grams of CuCl, we infer it is the limiting reactant, therefore the correct mass of copper I chloride is 320 g.

Best regards!

Answer:

1.99×10¯¹⁴ M

Explanation:

We'll begin by writing the balanced dissociation equation of pyridine. This is illustrated below:

C₅H₅N + H₂O <=> C₅H₆N⁺ + OH¯

From the balanced equation above,

1 mole of C₅H₅N produced 1 mole of OH¯.

Therefore, 0.502 M C₅H₅N will also produce 0.502 M OH¯.

Finally, we shall determine the concentration of hydronium ion, H₃O⁺ in the solution. This can be obtained as follow:

Concentration of Hydroxide ion [OH¯] = 0.502 M

Concentration of hydronium ion [H₃O⁺] =?

[H₃O⁺] [OH¯] = 1×10¯¹⁴

[H₃O⁺] × 0.502 = 1×10¯¹⁴

Divide both side by 0.502

[H₃O⁺] = 1×10¯¹⁴ / 0.502

[H₃O⁺] = 1.99×10¯¹⁴ M

Thus, the concentration of hydronium ion, H₃O⁺ in the solution 1.99×10¯¹⁴ M

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

Answer:

See explanation below

Explanation:

In this case, we are having a reaction between an anion and alkyl halide. The carbon 1 of the anion will act as nucleophile and will attack the electrophile, which is 5 carbon chain with the bromine in the third carbon.

Now, the nucleophyle is an alkyne of 3 carbon. According to the description, it should be:

CH₃ - C ≡ C⁻

And the alkyl halide is:

CH₃ - CH₂ CH(Br) - CH₂ - CH₃

And the final product after the reaction would be the following:

CH₃ - C ≡ C - CH - (CH₂CH₃)₂

However, in the attached picture you can see this better and the mechanism of reaction.

Hope this helps

Answer:

I believe the answer is Newton's Second Law

Explanation:

Newton's Second Law states that the acceleration of an object will count on how much mass and the amount of force that is applied.

The bowling ball was dropped from the 10th story window and had more force than when the ball was dropped from the 5th story window because the 10th story window gave the bowling ball more acceleration.

Answer:

Most manure consists of animal feces; other sources include compost and green manure. Manures contribute to the fertility of soil by adding organic matter and nutrients, such as nitrogen, that are utilised by bacteria, fungi and other organisms in the soil.

Explanation:

Hope it is helpful....

Answer:

Animal manure, such as chicken manure and cow dung, has been used for centuries as a fertilizer for farming. It can improve the soil structure (aggregation) so that the soil holds more nutrients and water, and therefore becomes more fertile. ... Manure is also commercially composted and bagged and sold as a soil amendment.

Explanation:

answer:

a mountain ridge which circles the earth

subduction zones

Answer:

its A and D

Explanation:

i took the quiz

Answer:

a and d

Explanation: