Answer:
34.2%
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Cr₂O₃ + 2Al —> Al₂O₃ + 2Cr
Next, we shall determine the mass of Cr₂O₃ that reacted and the mass of Al₂O₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of Cr₂O₃ = (52×2) + (3×16)
= 104 + 48
= 152 g/mol
Mass of Cr₂O₃ from the balanced equation = 152 × 1 = 152 g
Molar mass of Al₂O₃ = (27×2) + (16×3)
= 54 + 48
= 102 g/mol
Mass of Al₂O₃ from the balanced equation = 1 × 102 = 102 g
SUMMARY:
From the balanced equation above,
152 g of Cr₂O₃ reacted to produce 102 g of Al₂O₃.
Next, we shall determine the theoretical yield of Al₂O₃. This can be obtained as follow:
From the balanced equation above,
152 g of Cr₂O₃ reacted to produce 102 g of Al₂O₃.
Therefore, 23.3 g of Cr₂O₃ will react to produce = (23.3 × 102)/152 = 15.64 g of Al₂O₃.
Thus, the theoretical yield of Al₂O₃ is 15.64 g.
Finally, we shall determine the percentage yield of Al₂O₃. This can be obtained as follow:
Actual yield of Al₂O₃ = 5.35 g
Theoretical yield of Al₂O₃ = 15.64 g.
Percentage yield of Al₂O₃ =?
Percentage yield = Actual yield /Theoretical yield × 100
Percentage yield = 5.35 / 15.64 × 100
Percentage yield of Al₂O₃ = 34.2%
express 0.0005L as an integer
Answer:
I had this question on a test a long time ago and i believe it is
16- or 32-
Explanation:
How many grams of oxygen are required to combine with 0.750 grams of nitrogen in the compound: N2O5?
Answer:
2.14 g.
Explanation:
Hello!
In this case, since the mole ratio between nitrogen and oxygen is 2:5 respectively, we realize we first need the moles of nitrogen given it's atomic mass (14.01 g/mol):
[tex]n_N=0.750g*\frac{1mol}{14.01g}=0.0535molN[/tex]
Now, we calculate the moles of oxygen:
[tex]n_O=0.0535molO*\frac{5molO}{2molN}=0.134molO[/tex]
Then, we compute the moles of oxygen given its atomic mass (16.00 g/mol):
[tex]m_O=0.134molO*\frac{16.00gO}{1molO_2} \\\\m_O=2.14gO[/tex]
Best regards!
When light waves from a light source enter the eye, the light is refracted by two structures
before entering the retina to create impulses sent to the optic nerve. Those two structures
are....
A. Iris & comea
B. pupil & lens
C. ciliary muscles & choroid
D. comea & lens
write the subshell electron configuration (i.s. 1s2 2s2, ect.) for S16 atom
Answer:
1s22s22p63s23p4.As ice cream melts, the particles in it will ____
which causes it to _____ thermal energy.
a. Speed up, lose
b. Speed up, gain
c. Slow down, lose
d. Slow down, gain
Answer:
a. Speed up, lose
Explanation:
#CARRYONLEARNING
Answer:
b. speed up, gain
Explanation:
pls help !!!! ^^^^^^^^^
Answer: 1000 kg
Explanation:
I’m a god
Molecules have ?
: A) both potential and kinetic energy. B) only kinetic energy. C) only potential energy. D) neither kinetic nor potential energy.
Answer:
C) only potential energy.
How many mL of a 0.50 M solution can you obtain from the dilution of 147.1 mL of a 1.61 Molar solution?
Report your answer in mL (without the unit).
Answer:
[tex]V_2=45.7mL[/tex]
Explanation:
Hello there!
In this case, since the equation to deal with dilution process involves the initial and final concentration and volume:
[tex]C_1V_1=C_2V_2[/tex]
Thus, given the initial and final concentrations and the initial volume, we can write:
[tex]V_2=\frac{C_1V_1}{C_2} =\frac{0.50M*147.1mL}{1.61M}\\\\V_2=45.7mL[/tex]
Best regards.
Help help help help help
Answer:
neon gas
Explanation:
neon is a noble gas, meaning it has a full outer shell of elections. this means it is stable and is very unlikely to have a reaction with another substance.
A 5.41 g sample of carbon reacts with hydrogen to form 6.32 g of an organic compound. What is the empirical formula of the organic compound?
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Empirical formula =?
Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Mass of Hydrogen (H) =?
Mass of H = mass of compound – mass of C
Mass of H = 6.32 – 5.41
Mass of H = 0.91 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of C = 5.41 g
Mass of H = 0.91 g
Divide by their molar mass
C = 5.41 / 12 = 0.451
H = 0.91 / 1 = 0.91
Divide by the smallest
C = 0.451 / 0.451 = 1
H = 0.91 / 0.451 = 2
Thus, the empirical formula for the compound is CH₂
What volume in milliters would give 12.0 grams of NaOH from a 2.0 M NaOH solution?
Answer:
V = 150 mL
Explanation:
Hello!
In this case, since the molarity of a solution is computed via:
[tex]M=\frac{n}{V}[/tex]
Whereas we are asked to compute the volume:
[tex]V=\frac{n}{M}[/tex]
Thus, we first compute the moles in 12.0 g of NaOH as its molar mass is about 40.0 g/mol:
[tex]n=\frac{12.0g}{40.0g/mol}=0.3mol[/tex]
Thus, at first instance, the volume liters is:
[tex]V=\frac{0.3mol}{2.0mol/L} \\\\V=0.15L[/tex]
Which in milliliters is:
[tex]V=0.15L*\frac{1000mL}{1L}\\\\V=150mL[/tex]
Best regards!
polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles of ethylene glycol (a diol). A.Calculate the critical extents of reaction for gelation using (i) the statistical theory of Flory and (ii) the Carothers theory.B.Comment on the observation that the measured value of the critical extent of reaction is 0.866.
Answer:
(a). (I). 0.816; 0.816
(ii). 0.917.
(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.
Explanation:
So, without mincing words let's get straight into the solution to the question above.
(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;
P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).
P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).
The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.
The value of b = (1.2 + 1.2)/ 1.2 = 0.5.
Thus, putting the values into the equation (1) and (2) above gives;
NB: n = 3.
P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.
P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.
Using the (ii) carother's theory to Determine the critical extent of reaction gelation.
We have the following values for glycerol: k = 0.4, n = 3.
For ethylene glycol; k = 0.6, n = 2.
Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917
(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.
Which shows a monosaccharide?
Cuz D is cyclo-thingy molecule and its a sugar
(i think A is fatty acid or other molecules and C is hydrocarbon. B dont have oxygen)
Monosaccharides are the group of carbohydrates that are the simplest form of sugar. Option D. galactose is a monosaccharide sugar.
What are monosachharides?Monosaccharides are simple sugars and are the fundamental unit of carbohydrates. The general structural formula for the monosaccharides is [tex]\rm (CH_{2}O)_{n}.[/tex]
The structure of the monosaccharide sugar contains carbon, oxygen, and hydrogen molecules in their structure. Option A. is a fatty acid molecule, and option B. lacks an oxygen molecule, and hence they are not monosaccharides.
Option C. is a hydrocarbon chain that lacks oxygen molecules and option D. is a galactose that is a simple sugar with six carbon atom rings.
Therefore, option D. galactose is the monosaccharide.
Learn more about monosaccharides here:
https://brainly.com/question/5282729
A.It is used to generate electricity
B.It produces more energy than fusion
C.It produces waste material that can be radioactive
D.It is the splitting of an atomic nuclues into two or more
fragments
Which of the following is NOT a true statement
about nuclear fission?
Answer:
Pretty sure the answer is B
Refer to the map of "The Major North American Land Biomes" to answer the question.
Animals of the Deciduous Forest Biome may be found:
in Canada
in Texas
in Mexico
east of the Mississippi River
Answer:
all i can help you with is one of them is Canada. If im
wrong i am sorry.
Explanation:Refer to the map of "The Major North American Land Biomes" to answer the question.
Answer:
is Canada and Texas
good luck and hope it helps
A gas has a volume a 3L at 200kPa. What will it's new volume be if the pressure is changed at 500Kpa
Answer:
300/
Explanation:
jdjdjdhddhehhrjejejehe
Which statement correctly describes a difference between aesexual and sexual reproduction?
Answer:
(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.
Explanation:
This is variation is caused as a result of both gamete production and fertilisation.
What determines the average kinetic energy of the particles in a gas?
Answer: The average kinetic energy of the particles in a gas is proportional to the temperature of the gas. Because the mass of these particles is constant, the particles must move faster as the gas becomes warmer. The volume of the gas therefore becomes larger as the temperature of the gas increases.
atomic mass of an element is mass of an atom of the element but this quantity is an average mass only.why?
Answer:
atoms are the smallest building blocks of elements, the reason why its an average mass is because its so so light to have an 'accurate' and straight forward mass.
The name of the ionic compound LiCl is
hurry
Answer:
The name of the ionic compound LiCl is Lithium Chloride
Please help!
Calculate the percent by mass of water in FeCl2 · 4H20.
Answer:
36.23 %
Explanation:
Let's assume we have 1 mol of FeCl₂ · 4H₂O. In that case we would have:
1 mol of FeCl₂, weighing 126.75 g (that's the molar mass of FeCl₂), and4 moles of H₂O, weighing (4 * 18 g/mol) 72 g.Now we can calculate the percent by mass of water:
% mass = mass of water / total mass * 100% % mass = [tex]\frac{72}{72+126.75}[/tex] * 100% = 36.23 %Why is solubility critical when fighting a hydrocarbon fire?
Answer:
Unlike other extinguishing agents - water, dry chemical, CO2, etc., a stable aqueous foam can extinguish a flammable or combustible liquid fire by the combined mechanisms of cooling, separating the flame/ignition source from the product surface, suppressing vapors and smothering. It can also secure for extended periods of time against reflash or reignition. Water, if used on a standard hydrocarbon fuel, is heavier than most of those liquids and if applied directly to the fuel surface, will sink to the bottom having little or no effect on extinguishment or vapor suppression. If the liquid fuel heats above 212ºF, the water may boil below the fuel surface throwing the fuel out of the contained area and spreading the fire. For this reason, foam is the primary fire-extinguishing agent for all potential hazards or areas where flammable liquids are transported, processed, stored or used as an energy source.
this is what I found, hope it helps
In contrast to other extinguishing agents such as water, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling, separating the flame source from the product surface, suppressing vapors, and smothering.
What is solubility ?The term solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.
It can also protect against ref lash or reignition for extended periods of time. Water is heavier than most liquids when used on a standard hydrocarbon fuel and will sink to the bottom if applied directly to the fuel surface, having little or no effect on extinguishment or vapor suppression.
If the liquid fuel heats above 212°F, water may boil beneath the fuel surface, releasing the fuel and spreading the fire.
Thus, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling.
To learn more about the solubility, follow the link;
https://brainly.com/question/22185953
#SPJ2
What is the name of the polyatomic in MgSO4?
Answer:
Magnesium Sulfate
Explanation:
Answer:
magnesium sulfate
Explanation:
mg stands for magnesium and SO is sulfate
Help me with this one please!
Answer:
sorry i dont know
Explanation:
please help appreciate it!!
Explanation:
Ionization reactions are reactions that involve an electrically neutral atom or molecule be converted into electrically charged atom or molecule (ions).
Ions are recognized by the (⁺) and (⁻) signs.
First Reaction: Ions are formed so this option is correct.
Second Reaction: Ions are formed so this option is correct.
Third Reaction: This option is wrong. No ions are formed.
Fourth Reaction: Ions are formed so this option is correct.
Fifth Reaction: Ions are formed so this option is correct.
Which statement below best describes the weather.
---
a
Weather is the average temperature of an area over several years.
b
Weather is recorded yearly.
c
Weather changes and is recorded daily.
d
Weather cannot be predicted.
(SCIENCE)
Answer:
C
Explanation:
I believe it would be weather because climate is the average temperature of a area. This leads me to believe it is c.
I am sorry if this is incorrect, but that is what I would've went with if I was taking the test. :)
How many mol of C3H8 are consumed when 3 mol of CO2 are produced ?
Answer:
1 mol C₃H₈
Explanation:
Step 1: Write the balanced equation for the combustion of C₃H₈
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₃H₈ to CO₂ is 1:3.
Step 3: Calculate the moles of C₃H₈ consumed when 3 moles of CO₂ are produced
We will use the established molar ratio.
3 mol CO₂ × 1 mol C₃H₈/3 mol CO₂ = 1 mol C₃H₈
Please help find out code?
Which of the following best describe gas particles?
SELECT ALL THAT APPLY
A.) moving randomly
B.) collide with each other
C.) move slow
D.) High kinetic energy
E.) moving orderly
Answer:
A, B and D
Explanation:
Gas particles move randmly at high speed, colliding with each other
Select the correct image.
Which structure is a valid representation of a hydrocarbon molecule?
Н
1
Н-С-Н.
Н
Н
Н
Н
Н
1
н-с-н
Н Н
Н Н
1 1
1 1
Н-С—С—С—С—С-Н
1 1 1 1
Н Н H Н Н
H— С—С=С—С—С-Н
1
1 І
1
Н Н Н Н Н
Н
1
H-C-H
Н Н
Н Н
1 1
Н-С—С—С С— С
1
1
1
Н Н Н Н Н
Н
1
H-C-H
Н
Н
1
1
H-C— C-CEC— C-H
Н н н н Н
Answer:
H-C-H
Explanation:
hydrogen plus carbon hdrocloide