if the moon rises around 3 a.m., its phase must be Waning crescent .
What is meant by Waning crescent?The moon will look as a half moon, or third quarter moon, when the light level drops. The shadow cast by a third quarter moon will increase until it resembles a crescent form, which is known as a fading crescent.
A fading crescent moon has an illuminated area of less than 50% but is still growing.
You'll notice that the energy is waning as the moon begins to move back into the new phase, allowing you to calm down and devote more attention to your inner thoughts.
When the moon is transitioning from a full moon to a new moon, it is said to be in its declining phase. The declining moon, keep in mind sympathetic magick, is wonderful for banishing work, or cutting ,
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calculate the rms speed of carbon atoms near the surface of the sun at a temperature of about 6000 k .
Root mean square speed of the carbon atom near the surface of sun is 32233.52 m/sec.
Root mean square speed is defined as the the square root of the average of the square of the velocity and given as [tex]\sqrt{3}[/tex]RT/M
Where R =8.3145J/mol.k
M molar mass of the molecule in kg/mol
Carbon atom has the element number as 6 and has a molecular mass of 12 au. molar mass of the molecule can be given as:
Carbon = C = 12g/mol = 0.012kg/mol
T= Temperature = 6000K
Vrms = [tex]\sqrt{3}[/tex]RT/M
Vrms = ( [tex]\sqrt{3 * 8.315 * 6000}[/tex] ) / 0.012
Vrms = 32233.52 m/sec
The rms speed of carbon atoms near the surface of the sun at a temperature of about 6000 k is 32233.52 m/sec.
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you have been hired to design a spring-launched roller coaster that will carry two passengers per car. the car goes up a 13-m-high hill, then descends 20 m to the track's lowest point. you've determined that the spring can be compressed a maximum of 2.5 m and that a loaded car will have a maximum mass of 420 kg. for safety reasons, the spring constant should be 14 % larger than the minimum needed for the car to just make it over the top.
a) what spring constant (k) should you specify ?
b) What is the maximum speed of a 350 kg car if the spring iscompressed the full amount.
Based on safety considerations, the spring constant to be provided is computed to be k = 1661.4N/m. The speed of a 370 kg car when the spring is fully compressed is computed to be v = 14.6 m/s.
Where F = applied force and x = spring displacement, the formula for the spring constant is provided. The absence of a positive sign indicates that the restorative force opposes the speed.
In common use and kinematics, an object's speed (often abbreviated as v) is defined as the size of the change in position per unit of time or over time for an object.
These calculations are used to determine the car's weight:
W = mg W = 420* 9.8 = 4116 N
F = k(spring constant)
K = f=F/x = 4116/2.5 = 1646.4N/m is the formula for the spring constant.
Given the need for safety, the spring constant to be used is determined as follows: k = 1646.4N/m + 15 = 1661.4N/m.
When the spring is fully compressed, the 370 kg automobile will move at a speed of 14.6 m/s because 1/2 mv^2 = 1/2kx^2
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Why does the skateboarder continue to move forward when he hits the trash? what is the unbalanced force?.
According to Newton's first law: An item at relaxation will continue to be at relaxation until acted on with the aid of using an unbalanced force.
What are newton's laws of motion?
Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.
According to Newton's first law: An object at rest will remain at rest unless acted on by an unbalanced force. An object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
There is a force that moves the skater and his skate forward, after the hit, his speed is reduced, but this force is not completely counteracted, and that's why he continues moving forward.
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What is the formula for the compound that forms between magnesium and phosphorous?
Answer:
Magnesium phosphate | Mg3(PO4)2
Explanation:
The formula for the compound that forms between magnesium and phosphorous is Mg3(PO4)2
at the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration?
The instantaneous acceleration is maximum.
What is instantaneous acceleration?The main definition of instantaneous acceleration is. The ratio of velocity change during a given time interval such that the time interval equals zero.The velocity of an object at a specific point in time or along its path is referred to as instantaneous velocity. Acceleration that occurs instantly. It is defined as the limiting value of the average acceleration when the time interval t becomes very small.The result is the instantaneous acceleration expressed mathematically as a(t)=ddtv, which is the derivative of the velocity function v(t) (t). Thus, instantaneous acceleration is the derivative of the velocity function, just as velocity is the derivative of the position function.
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hree children are riding on the edge of a merry-go-round that is 115 kg, has a 1.7-m radius, and is spinning at 24 rpm. the children have masses of 32, 34, and 40 kg. (a) if the children with masses of 34 and 40 kg move to the center of the merry-go-round, what is the new angular velocity in rpm?
The new angular velocity in rpm is
27.7 rpm
M = 115 kg be the mass of the merry-go-round,
r = 1.7 m be its radius,
m1 = 32 kg,
m2 = 34 kg,
m3 = 40 kg be the masses of the three children,
ω = 22 rpm be the angular velocity with all children at the edge,
ω' (to be calculated) be the angular velocity after m2 is moved to the center.
The conservation of angular momentum can be used to resolve this.
The angular momentum before and after the move must be equal.
But there are two presumptions we must make.
1) The merry-go-round has a consistent disc shape. Although it is improbable, if the merry-go-round has a more widespread. The issue gets more complex due of its convoluted shape.
2) The kids are on the merry-go-outer round's edge. Regardless of where the kids are, the issue is easily fixable.
but, since I have no information, I'll guess it's on the edge.
In general, a mass m at the edge contributes mr²ω to the angular momentum.
The rotating uniform disk contributes Mr²ω/2 to the angular momentum.
Now we can equate the total angular momentum after the move to the total
angular momentum before the move.
Mr²ω'/2 + m1r²ω' + m3r²ω' = Mr²ω/2 + m1r²ω + m2r²ω + m3r²ω
From that express
ω' = ω(M/2 + m1 + m2 + m3)/(M/2 + m1 + m3)
Substituting actual numbers
ω' = 22×(115/2 + 32 + 34 + 40)/(115/2 + 32 + 40) = 27.7 rpm
Hence, new angular velocity in rpm is 27.7 rpm
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a planet with a radius of 6.00 x 107 m has a gravitational field of magnitude 30.0 m/s? at the surface. what is the escape speed from the planet?
The escape speed of the planet is 756.60 m/s
How to calculate escape speed from the planet ?The earth's surface escape speed is roughly 11.2 km/s. This means that an object must have a minimum beginning velocity of 11.2 km/s in order to escape the gravity of the earth and journey into limitless space.
The minimum speed required for a free, unpropelled object to be able to escape the gravitational pull of a primary body and travel an infinite distance from it is known as the escape velocity or escape speed in celestial mechanics. Typically, it is expressed as an ideal speed that disregards atmospheric friction.
Given ,
Gravitational magnitude = 30.00m/s
Escape speed from planet = √[2×30/6*107][
√[2×30.00] /6 ×107
= 756.60 m/s
Therefore Escape speed from planet is 42.4264
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a circular coil of wire has a radius of 7 cm and contains 40 turns. a field of 0.900 t passing through the coil collapses at a uniform rate to zero in 0.200 seconds. what emf is generated in the wire?
The EMF generated by the coil is 2.772 V.
Radius of the coil = R = 7 cm = 0.07 m
Number of turns = N = 40
Initial Magnetic Field = B₁ = 0.900 T
Final Magnetic Field = B₂ = 0
Time = 0.2 s
Change in the Magnetic field of the coil =
= dB/dt = (0.9 - 0) / 0.2
= dB/dt = 9/2 T/s
Area of the coil = A = πR²
The total flux related to the circular coil = ∅
= ∅ = NBA
EMF induced by the coil =
= E = d∅/dt
= E = NA dB/dt
= E =40 X π X (0.07)² X (9/2)
= E =2.772 V
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at what speed does the rock strike the water if it is thrown with the same initial speed but at an angle 24 degrees below the horizontal?
The offered statement states that the rock hits the water at various times and with equal velocity.
What is a speed set of questions?The number of kilometers reached to the time needed to travel that distance is known as speed. Since speed simply has a part and no magnitude, it is a proportionality constant.
Briefing:
If we ignore air resistance due to the energy conservation, then the velocity of both stones would have to be equal because energy is a finite resource. They will each have the same sum of kinetic and potential energies at the beginning, hence the potential and the kinetic energies must be identical at the end, this happens when they reach the ground. Potential energy will change into kinetic energy.
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328-kg car moving at 19.1 m/s in the x direction hits from behind a second car moving at in the same direction. if the second car has a mass of and a speed of right after the collision, what is the velocity of the first car after this sudden collision?
The velocity of the first car after this sudden collision is +14 m/s.
What is velocity?
Velocity can be defined as the rate of change of position of object with respect to time or a specific frame of reference. it can also be defined as the speed of an object in a specific direction, this means that the value of velocity changes as the direction of the the movement of the object changes. this makes velocity a vector quantity.
Its SI unit is [tex]m/s^{-1}[/tex].
What are vector quantities?
Vector quantities are those quantities that have both the direction and the magnitude, eg: velocity, displacement, force etc.
According to the given information:
we know, mV + Mv = mU + Mu
where m = 320kg, M = 720 kg, v = 13m/s, V = 19 m/s, u = 15.1 m/s
U = (mV + Mv - Mu)/m
= (328 x 19.1 + 790 x 13 - 790 x 15.1)/328
= +14 m/s
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I understood the question to be:
A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13.0 m/s in the same direction. If the second car has a mass of 790 kg and a speed of 15.1 m/s right after the collision, what is the velocity of the first car after this sudden collision?
a ball of mass 1.50 kg is hung from a spring which stretches a distance of 0.6875 m. the spring constant of the spring (a scalar quantity) is n/m
The spring constant of the spring (a scalar quantity) is 21.38 N/m.
What is spring constant ?The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the larger the spring constant.
How do you calculate the spring constant?x represents the spring's displacement from its equilibrium position, and k is the spring constant in N/m.
The constant of proportionality k is called Coulomb's constant.
According to given information spring's displacement(x)= 0.6875 m and mass(m)=1.50kg
F=-K × x
K=f/x=mg/x=1.50×(9.8)/0.6875=21.38N/m
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a mass m on a frictionless table is attached to a hanging mass m by a cord through a hole in the table. find the speed with which m must move for m to stay at rest.
The speed with which m must move from M to stay at rest is √Mgr/m m/sec .Centripetal Force is responsible for the speed of mass m.
We are given that final state of mass M is rest. It means its velocity is zero. If velocity is zero it means that force acts on the mass M is balanced. When forces are balanced ,body will remain at rest as component of force and gravity cancel each other.
So, if mass M is at rest we need to identify what force are acting on the mass M.
Since mass M is directly perpendicular to acceleration due to gravity, therefore gravity will act some force on it.
Since mass M is moving in circle, due to its movement mass M feels centripetal force.
Therefore, centripetal force due to mass m=Force due to gravity
=>m×(v²)/r=Mg
=>v² = (Mg×r)/m
=>v=√Mgr/m
Hence, speed of mass m is √Mgr/m,
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(Complete question) is:
a mass m on a frictionless table is attached to a hanging mass M by a cord through a hole in the table. find the speed with which m must move for M to stay at rest.
A ball is initially moving at 12 m/s up a ramp. The acceleration of the ball is -2 m/s/s down the ramp. What is the balls velocity after 8 seconds? (frame of reference + is up the ramp)
The ball is moving with a velocity of 28 m/s after 8 seconds.
What is the equation of motion?The equations of motion can be used to set up the relationship between the initial velocity and final velocity, acceleration, time, and displacement of a moving object.
The three equations of motion for a moving object can be represented:
[tex]v = u +at\\S = ut +\frac{1}{2} at^2\\v^2 - u^2 = 2aS[/tex]
Give, the initial velocity of the ball moving up, u = 12 m/s
The acceleration of the ball up the ramp, a = + 2m/s²
The final velocity can be calculated from the first equation of motion:
v = u + at
v = 12 + (2) (8)
v = 12 + 16
v = 28 m/s
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g capacity, the ability of the material/structure to safely resist load without breaking or damage, depends on?
Ductility determines whether a material or structure can safely withstand a load without breaking or suffering damage.
Ductility: What is it?A material's ductility is a mechanical property that refers to how easily it can be drawn from. In the field of materials science, ductility refers to how much plastic deformation under tensile stress a material can withstand before breaking. Ductility is a top priority in both engineering and manufacturing.
It describes a material's suitability for specific manufacturing processes (like cold working) and its capacity to withstand mechanical overload. Among the metals that are frequently referred to as ductile are copper and gold. Not all metals, like cast iron, can fail brittlely; some can instead fail ductilely. Polymers can be thought of as ductile materials because they typically allow for plastic deformation.
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write an expression for the gravitational potential energy of the falling mass in terms of the angular displacement
The potential energy of a falling mass is [tex]PE=-m g R \theta[/tex] and [tex]g=9.8 \mathrm{~m} / \mathrm{s}^2.[/tex]
As we know,
The expression that relates linear displacement and angular displacement is given below:
[tex]s=r \theta[/tex]
Now we will replace s with h and r with R in the above expression.
[tex]h=R\theta[/tex]
Here, the height is h and the radius is R.
The initial potential energy is as follows:
[tex]P E_{\mathrm{i}}=m g h[/tex]
Now, replace h with R[tex]\theta[/tex].
We will get it as: [tex]P E_{\mathrm{i}}=m g R \theta[/tex]
Now, substituting [tex]$0^{\circ}$[/tex] for [tex]\theta[/tex]
[tex]P E_{\mathrm{i}} & =m g R\left(0^{\circ}\right) \\=0 \mathrm{~J}[/tex]
The expression for the final potential energy will become:
[tex]P E_{\mathrm{f}}=m g R \theta[/tex]
The potential energy of the falling mass will become:
[tex]P E=P E_{\mathrm{i}}-P E_{\mathrm{f}}[/tex]
From Expressions (1) and (2), the following expression can be obtained:
[tex]P E =0 \mathrm{~J}-m g R \theta \\=-m g R \theta[/tex]
The value of g is as follows: g=9.8 [tex]\mathrm{~m} / \mathrm{s}^2[/tex]
The potential energy of a falling mass is [tex]PE=-m g R \theta[/tex] and [tex]g=9.8 \mathrm{~m} / \mathrm{s}^2.[/tex]
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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8 m from the takeoff point. part a if the kangaroo leaves the ground at a 19 ∘ angle, what is its takeoff speed
The take-off speed of the gray kangaroo is 11.28 m/s.
How to calculate the takeoff speed?The kangaroo's final speed is zero when it is at its highest point above the ground, and the time it spends there is halved from the time it will take it to hit the earth again.
To calculate the horizontal distance (S) travelled by the kangaroo we need the equation,
[tex]S=v_{0} cos\theta t[/tex]
Here,
v₀ = takeoff speed
[tex]\theta[/tex] = the angle of projection
t = total time taken by the kangaroo.
Given,
The take-off distance for each jump attained by the kangaroo = 8 m
The angle of projection = 19°
Substituting the above values in the above equation,
[tex]8 = v_{0} cos19t[/tex]
[tex]t=\frac{8}{v_{0}cos19 }[/tex]
[tex]t=\frac{8}{0.9455v_{0} }[/tex]
The following equation can be used to determine the kangaroo's final speed when it reaches its highest point above the ground:
[tex]v=v_{0} sin\theta-\frac{gt}{2}[/tex]
Now, Substitute 0 for the value of v we get,
[tex]0=v_{0} sin\theta \frac{g}{2} ( \frac{8}{0.9455v_{0} })\\v_{0} = \sqrt{\frac{8g}{2*0.9455*sin\theta} } \\[/tex]
[tex]v_{0} = \sqrt{\frac{8g}{2*0.9455*sin\theta} } \\\\v_{0} = \sqrt{\frac{8*9.80}{2*0.9455*sin19} }\\v_{0}= 11.28 m/s[/tex]
Hence, the take-off speed of the gray kangaroo is 11.28 m/s.
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combining the two values calculated above tells us the total momentum before the collision. the total momentum of cart 1 and cart 2 before the collision is 0.01 . if you were to do the same calculations to determine the momenta of each cart after the collision and then combine them, you would find that the total momentum of cart 1 and cart 2 after the collision is -0.022 . therefore, the change in momentum (change = final -initial) pf the whole sistem from before the coallision is -0.03. this is one trial. Which of the following statements is most true?
A)There must be a calculation error, because momentum should be conserved in this collision.
B)This demonstrates that momentum is not conserved in this collision.
C)This demonstrates that the motion detector is not precise enough to conduct this
experiment.
E)More trials will not improve the sensitivity of the motion detectors, so there is no point in
collecting more data.
F)Averaging the change in momentum for multiple trials can tell us whether momentum is not
conserved here or the motion detector is imprecise.
Answer:
b
Explanation:
a disk of mass 7 kg and radius 0.6m hangs in the xy plane from a horizontal low friction axle. the axle is 0.06m from the center of the disk. what is the frequency of f of small - angle oscillations of the disk ?
The frequency of of small - angle oscillations of the disk is 1.99/sec. Frequency is converse of time period.
We know very well that,
T=2π√I/mgh
where T is the time period,
I is the moment of inertia of body
m is the mass of the body
g is the acceleration due to gravity
and h is the height of the point from center of body
Now, we know very well that moment of inertia of disk is given by=(1/2)mr² where m is the mass of the body and r is the radius of the body
So, putting the values of mass and radius of disk, we get
=>I=(1/2)×7×(0.6)²
=>I=3.5×0.36
=>I= 1.26kg-m²
Now, h is given as 0.06m,value of g is 9.8m/sec² and value of m is 7kg
So, mgh=7×9.8×0.06=4.116kgm²/sec²
Therefore, T=2π√1.26/4.116
=>T=2π√0.306
=>T=2π×0.55sec
=>T=6.28×0.55sec
=>T=3.454sec
=>Frequency(ω)=2π/T
=>Frequency(ω)=2π/3.454
=>ω=6.28/3.454
=>ω=1.99/sec
Hence, frequency is 1.99/sec.
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an object is suspended by a string from the ceiling of an elevator. if the tension in the string is equal to 25 n at an instant when the elevator is accelerating downward at a rate of 2.0 , what is the mass of the suspended object? (your answer should have one decimal place)
The mass of the suspended object is 3.2 kg.
Solution:
25 N - m (9.8 m/s²) = - m (2.0 m/s²)
= m = (25 N) / (9.8 m/s² - 2.0 m/s²) ≈ 3.2 kg
When suspending an object freely from one point and with a stable balance, hang it so that the center of gravity is directly below the mounting point. In this sketch, the object is suspended at point A and its center of gravity G is directly below point A.
Objects can be hung by strings from a fixed point and can be freely hung and balanced. This is either informed in the question statement or previously determined using previous calculations. Mass must be specified in kilograms.
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a 0.160-g puck strikes and embeds itself in a 6.4 kg block. the block moves off at 1.2 m/s. what was the puck's speed?
The puck's speed was 7.2 m/s.
What is speed?
Despite their similarities, speed and velocity have very different meanings, just as distance as well as displacement do. Speed, which is a scalar quantity, is the "speed at which an object is moving." The rate that an object travels a distance can be assumed of as its speed. A fast-moving object travels at a high speed and completes a significant distance in a brief period of time. This is in contrast to an object moving slowly, which travels a relatively short distance within the same amount of time. Zero speed refers to an object that is not moving at all.
The puck's speed can be determined by solving the equation for momentum conservation. Momentum is conserved when the total momentum before an interaction is equal to the total momentum after the interaction. In this case, the equation looks like this:
m_P * v_P + m_B * v_B = (m_P + m_B) * v_F
Where m_P is the mass of the puck, v_P is the initial velocity of the puck, m_B is the mass of the block, v_B is the initial velocity of the block, and v_F is the final velocity of the block.
Plugging in the given values, we get:
0.160 * v_P + 6.4 * 1.2 = (0.160 + 6.4) * 1.2
Solving for v_P, we get:
v_P = 7.2 m/s
Therefore, the puck's speed was 7.2 m/s.
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determine the moment of inertia of a 8.20 kg sphere of radius 0.793 m when the axis of rotation is through its center
The moment of inertia of the sphere when the axis of rotation is through its center be 2.063 kg-m².
What is moment of inertia?The sum of the products generated by multiplying each particle's mass by the square of its distance from the axis results in the moment of inertia (I), which is always expressed with respect to that axis.
Given parameters:
Mass of the sphere: m = 8.20 kg.
Radius of the sphere: r = 0.793 m.
Hence, the moment of inertia of the sphere when the axis of rotation is through its center be = 2/5 mr²
= 2/5 × 8.20 × 0.793 × 0.793 kg-m².
= 2.063 kg-m².
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a brass cube, 10 cm on a side, is raised in temperature by 200oc. the coefficient of volume expansion of brass is 57x10-6/oc. by what percentage does its volume increase?
A brass cube with a side measurement of 10 cm increases in volume by 22.5% when the temperature is increased by 200°C. Brass has a volume expansion coefficient of 57x10-6/oc.
A device's ability to enable fluid flow is relative measured by the flow coefficient of volume of the device. In more concrete terms, the flow coefficient Cv is the amount of water (measured in US gallons) that will pass through a valve at 60 °F and a pressure drop of 1 psi per minute. The concept of temperature is used to convey quantitatively how hot and cold something is. Using a thermometer, one can gauge temperature. Thermometers are calibrated using different temperature scales that traditionally relied on different reference points and thermometric materials for definition.
Given:
length of the cube, l = 10cm
change in temperature of the cube, T = 200
coefficient of volume expansion, beta = 57*10^-6
delta L = delta L/L *100
delta L = 0.0225/0.1 *100
delta L = 22.5%
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6. conical surface of constant density find the moment of iner?tia about the z-axis of a thin shell of constant densthe cone 4x 2 4y 2 - z 2
We need to find the rotational inertia of the shell about the axis of rotation.
What is rotational inertia?Inertia of rest the inability of a body to change by itself its state of rest is called inertia of rest. Inertia of direction. The inability of a body to change by itself its direction of motion. Inertia of motion: The inability of the body to change by itself its state of motion is called inertia of motionYou tend to move forward when a sudden break is applied.You feel a backward force when the bus moves quickly from rest.Dusting bed with a broom removes dust due to inertia of rest.when you shake a branch the leaves get detached.According to Newton's first law of motion, an object with a given velocity maintains that velocity unless acted on by an external force. Inertia is the property of matter that makes this law hold true.Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be.When a car makes a sharp turn at a high speed, the driver tends to get thrown to another side due to inertia of direction.The spark coming out of a grinding stone is tangential to the rotating stone due to directional inertia.The mud from the wheels of a moving vehicle flies off tangentially.[tex]I_{y} = (\frac{1}{8}) \pi r^{4}[/tex]
x = r cos θ
y = r sin θ
dA = r dr dθ
Then the moment of inertia about the x-axis will be
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Why does the closed top of a convertible bulge when the car is riding along a highway?.
Inside the automobile, the air pressure is higher than outside.
What is air pressure?Everything you touch is pressed upon by the weighty air that surrounds you. This pressure is referred to as air pressure or atmospheric pressure. It is the force that the air above a surface applies to it while gravity pulls the surface toward Earth. A barometer is frequently used to measure atmospheric pressure.
Now
According to Bernoulli's equation, regions of airflow with greater velocities have lower pressure than regions with lower velocities when considering airflow over and around a surface.
The air inside the convertible is moving more quickly than the air outside. As a result, there is a greater pressure zone immediately inside the roof's surface.
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A car is sitting at a traffic light. When the light turns green, the car begins moving, accelerating at a constant rate. After 14.9 seconds the car has moved 266 meters. What is the acceleration of the car?
Answer:
The acceleration 2.4 m/s²
Explanation:
Given:
V₀ = 0 m/s - Initial vehicle speed
t = 14.9 s - Time
D = 266 m - Distance traveled by car
__________
a - ? - the acceleration
D = V₀·t + a·t² / 2;
V₀ = 0
D = a·t² / 2;
a = 2·D / t² = 2·266 / 14.9² ≈ 2.4 m/s²
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
What is the magnitude of the torque about his shoulder if he holds his arm straight, but 40 ∘ below horizontal?
The magnitude of the torque about his shoulder if he holds his arm straight, but 40 ∘ below horizontal is 40 Nm.
Arm Weight: 4 kilogram
Ball weight: 4 kilogram
arm span: 70 cm
You must first determine the weights of the arm and the ball. Add the gravity factor to them.
Arm weight: 4 kg times 9.8 equals 39.2 Ball weight: 4 kg times 9.8 equals 39.2
In order to find the torque, = r1 F1 sin + r2 F2 sin,
We must determine r1 and r2, where r1 = 70/2 = 35 cm or.35 m. (arm: to find the center of gravity, divide by 2)
r2 = 70 cm, or.70 m (ball)
The angle is 180° since the arms are extended straight out, which equals m1g(L/2) + m2gL.
The system's length is L.
τ =4 * 9.8 *(0.7/2) + 4 * 9.8 * 0.7 \s
= 40 Nm
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an opaque horizontal plate is well insulated on the edges and the lower surface. the irradiation on the plate is 3000 w/m2, of which 500 w/m2 is reflected. the plate has a uniform temperature of 700 k and has an emissive power of 5000 w/m2. determine the total emissivity and absorptivity of the plate. add: repeat assuming material is semitransparent with transmissivity of 0.10, the same reflectivity and the same emissive power.
Total emmisivity is 0.3706
and absorptivity is 0.833
Irradiation, I = 3000W / m2
reflection, Ir = 500W / m2
uniform temperature, T = 700 k
emissive power E = 5045 W / m2
Total emmisivity,
e = E / 5.67 x 10^-8 (T^4)
e= 5045 / 5.67 x 10^-8 x 700^4
e= 0.3706
absorptivity,
∝ = Iabs / I = I -Ir / I
∝ = 3000-500 / 3000
= 1 - 500 / 3000
∝ = 1 - 1/6
∝ = 0.833
Emissivity is described as the ratio of the energy radiated from a material's surface to that radiated from an ideal emitter, referred to as a blackbody, on the identical temperature and wavelength and underneath the equal viewing conditions.
It's miles a dimensionless range among zero (for an excellent reflector) and 1 (for an ideal emitter).
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The abundance of __________________ _________________( H, He, Li) in the universe is almost exactly as what The Big Bang predicts. Elements were first fused within the _______________________ after the Big Bang
The abundance of light elements such as Hydrogen (H), Helium (He), and Lithium (Li) in the universe is almost exactly as what the Big Bang predicts. Elements were first fused within the protons and neutrons after the Big Bang.
What is Big bang theory?Light elements like hydrogen (H), helium (He), and lithium (Li) are abundant throughout the cosmos, almost exactly as predicted by the Big Bang theory. After the Big Bang, protons and neutrons were the first to combine elements. The most popular theory for how the universe came into being is called the Big Bang Theory. Simply put, it asserts that the universe as we currently understand it originated from a single point that was infinitely hot and dense and that it first expanded and contracted at unfathomable speeds before slowing down and expanding over the course of 13.7 billion years to become the universe that we see today.
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a simple harmonic oscillator with an amplitude of 2.0\;\mathrm{cm}2.0cm passes through its equilibrium position once every 0.0300.030 seconds, what is the frequency of the oscillator?
The frequency of the oscillator is 33.33 Hz.
What is the frequency of the oscillator?
Frequency describes the number of waves that pass a fixed place in a given amount of time
The frequency of the oscillator is determined from the number of times or period taken for the wave to make one complete cycle.
Mathematically, the formula for frequency of oscillatory motion is given as;
F = 1/T
where;
F is the frequency of the oscillatorT is the period of the oscillationF = (1) / (0.03 s)
F = 33.33 Hz
Thus, the frequency of the oscillator is a function of the period of the motion.
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what type of conduit, fittings, switches, lighting fixtures, and receptacles are to be used in the flammable storage area?
The combustible storage room must use cable, connectors, switches, lighting, and plugs of the explosion-proof E12 variety.
What purpose serves a switch?Numerous devices can be connected using switches. Switches prevent route between two devices connected to the same network from obstructing the use of other devices. Switches let you manage who will have access to different network areas. Switches let you keep an eye on utilization.
Explain what switches are.A switch is a device used in electrical engineering that has the ability to connect or detach a circuit's carrying line, halting the flow of electricity, or rerouting it to another conductor.
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