If the compound below is oxidized, the resulting product is ___. Select one: a. methane and propane b. butanal c. butanoic acid d. butane

Answer: it’s B!! :)

Answer:

its only 25

Explanation:

Answer:

It's important for scientists to know the properties of matter because all things are made up of matter. Each type of matter has different physical characteristics and scientists need to know and understand these characteristics to make calculations. ... The main phases of matter are solid, liquid, and gas

Explanation:

^^

Answer:

Noble gases

Explanation:

Noble gases

Answer:

An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion.

Answer:

when an atom gains an electron, it gains a negative charge . it's volume increases as well due to the increase in repulsion between the electrons

Answer:

True

Explanation:

Physical properties are based on all of our five senses, so yeah

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, there are ways to save the forest of third world countries - this includes

1) Creating of forest reserves: Wide areas of land that are still forested can still be preserved and converted to forest reserves which can prevent these areas from being deforested as a result of human activities or industrialization.

2) Government policies: Government can put policies in place to prevent people from embarking on deforestation of certain lands. This is because some parts of the third world countries still rely on wood for cooking and other sources of daily activities.

3) Replanting of deforested areas: Replanting of trees can also help third world countries in saving the forest.

Answer:

lol, I just did this assignment, cold water

0:30: slowly expand

1:00: still expanding

1:30: expanding is continued

2:00: still expanding slowly

2:30: expanding slowly

3:00: expanded twice the size from the first time

hot water

0:30: expanding quickly

1:00: still expanding

1:30: starts to reach the surface and still expanding

2:00: almost all the of the dye reached the top

2:30: the dye reached the top and is starting to split

3:00: the dye split appart and is moving down again

radiation

white paper

0:30: at a low temp. at around 3.3 C

1:00: still at a low temp. around 4.4 C

1:30: slowly rising temp. around 5.5 C

2:00: still slowly rising temp. around 7.2 C

2:30: still at a low temp. around 8.3 C

3:00: ends at a low temp. around 10 C

black paper

0:30: at a resonable temp. at around 6.6 C

1:00: temp. rises quicker at around 13.3 C

1:30: temp. stil rising quickly at around 17.7 C

2:00: temp. is getting hotter at around 21.6 C

2:30: temp. is still getting hotter at around 26.1 C

3:00: temp. ends at a hot temp. at around 30 C

Explanation:

Answer:

28%

Explanation:

Basically, all o did was write the equations, balance it and solve for them. Also, at the place I stared, I used simultaneous equation to solve it. Multiplying by 8 and also 3.

It's a pretty straightforward question.

At the final step that's missing, I Did

(y)C3H8 = 2.8 / ( 2.8 + 7.1)

(y)C3H8 = 0.28

Answer:

[tex]pH=1.67[/tex]

Explanation:

Hello.

In this case, since the reaction between the sulfuric acid and the potassium hydroxide is:

[tex]2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O[/tex]

We can see a 2:1 mole ratio between them, thus, we compute the moles of acid and base that are present in the solution by using the employed volume and its concentration:

[tex]n_{H_2SO_4}=0.155mol/L*0.0350L=0.005425molH_2SO_4\\\\n_{KOH}=0.225mol/L*0.0350L=0.007875molKOH\\[/tex]

Next, we use the 2:1 mole ratio to compute the consumed moles of acid:

[tex]n_{H_2SO_4}^{consumed}=0.007875molKOH*\frac{1molH_2SO_4}{2molKOH}=0.0039375molH_2SO_4[/tex]

It means that the leftover of sulfuric acid is:

[tex]n_{H_2SO_4}^{leftover}=0.005425-0.0039375=0.001488molH_2SO_4[/tex]

Therefore, since sulfuric acid is a strong acid, the pH is defined in terms of its concentration which is actually equal to the concentration of hydrogen ions in solution, which is computed considering the total additive volume:

[tex][H^+]=[H_2SO_4]=\frac{0.001488mol}{0.070L}=0.02125M[/tex]

So the pH turns out:

[tex]pH=-log(0.02125)\\\\pH=1.67[/tex]

Best regards.

answer:  

i believe the answer is inverse.

if i'm wrong sorry :(

if i'm right your welcome :)

Answer:blacks screen. No answers to choose from. Thanks for the points:))

Explanation: