Answer:
286.60
Please tell me if I'm wrong.
The length of a rectangle is 3 yd longer than its width. If the perimeter of the rectangle is 62 yd, find its width and length
Answer:
Length=17 yds, Width=14 yds
Step-by-step explanation:
62=x+x+(x+3)+(x+3)
4x+6=62
4x=56
x=14
x+3=17
What is 6 1/2 subtracted by 2 2/3
Answer:
The answer to this equation is 3 5/6
Step-by-step explanation:
in order to solve this problem, we must first turn these fractions into improper fractions. We can do this by multiplying the base number with the denominator and adding the numerator to that number.
6 1/2 = 13/2
2 2/3 = 8/3
Now, set up your equation.
13/2 - 8/3
Change the denominators to the same number so it will be easier to subtract.
39/6 - 16/6
Now subtract.
23/6 = 3 5/6
Answer:
3 5/6
Step-by-step explanation:
6 1/2 - 2 2/3 = 13/2 - 8/3
(39 - 16)/6 = 23/6 = 3 5/6
I NEED HELP PLEASE, THANKS! Use Cramer's Rule to find the solution of the system of linear equations, if a unique solution exists. –5x + 2y – 2z = 26 3x + 5y + z = –22 –3x – 5y – 2z = 21 A. (–1, –7, 2) B. (–6, –1, 1) C. (–1, 3, 1) D. no unique solution
Answer:
Option B
Step-by-step explanation:
We are given the following system of equations -
[tex]\begin{bmatrix}-5x+2y-2z=26\\ 3x+5y+z=-22\\ -3x-5y-2z=21\end{bmatrix}[/tex]
Now by Cramer's Rule, we would first write down the matrix of the coefficients , replacing each column with the answer column -
[tex]\begin{bmatrix}-5&2&-2\\ 3&5&1\\ -3&-5&-2\end{bmatrix}[/tex] ,
[tex]\begin{bmatrix}26\\ -22\\ 21\end{bmatrix}[/tex]
Replace each column of the coefficients shown at the top, with the answer column at the bottom respectively -
[tex]\begin{bmatrix}-5&2&26\\ 3&5&-22\\ -3&-5&21\end{bmatrix}[/tex]
Now solve through Cramer's Rule -
x = Dx / D = - 6,
y = Dy / D = - 1,
z = Dz / D = 1
Solution = ( - 6, - 1, 1 ) = Option B
-5 x + 2 y - 2 z = 263 x + 5 y + z = -22 - 3 x - 5 y - 2 z = 21
Answer is x=-6,\:z=1,\:y=-1
Solve 3v2 – 84 = 0, where v is a real number.
Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.
If there is no solution, click on "No solution".
Answer:
The given equation has two solutions
[tex]v = (-5.29, \: 5.29)[/tex]
Step-by-step explanation:
The given equation is
[tex]3v^2 - 84 = 0[/tex]
Let’s solve the equation
[tex]3v^2 - 84 = 0 \\\\3v^2 = 84 \\\\v^2 = \frac{84}{3} \\\\v^2 = 28 \\\\[/tex]
Take the square root on both sides
[tex]\sqrt{v^2} = \sqrt{28} \\\\v = \sqrt{28} \\\\v = \pm 5.29 \\\\[/tex]
So the equation has two solutions
[tex]v = (-5.29, \: 5.29)[/tex]
Also refer to the attached graph of the equation where you can verify that the equation has two solutions.
Note:
It is a very common mistake to consider only the positive value and not the negative value.
Consider the square root of 25
[tex]\sqrt{25} = \pm 5 \\\\Since \\\\5 \times 5 = 25 \\\\-5 \times -5 = 25 \\\\[/tex]
That is why we have two solutions for the given equation.
Set up and evaluate the optimization problem. You are constructing a cardboard box from a piece of cardboard with the dimensions 4 m by 8 m. You then cut equal-size squares from each corner so you may fold the edges. What are the dimensions (in m) of the box with the largest volume
Answer:
[tex]Shorter\ side=4-2\times 0.845=2.31\ m\\Longest\ side=8-2\times 0.845=6.31\ m\\Height=0.845\ m[/tex]
Step-by-step explanation:
Given that , dimension of the cardboard is 4 m by 8 m.
Lets the dimensions of the square is x m by x m.
The volume after cutting the equal size of square from all the four corners is given as
[tex]V=x\times (4-2x)\times (8-2x)\\V=x\times (32-16x-8x+4x^2)\\V=x\times (4x^2-24x+32)\\V=4x^3-24x^2+32x\\[/tex]
For the maximum volume
[tex]\dfrac{dV}{dx}=12x^2-48x+32=0\\3x^2-12x+8=0\\[/tex]
For maximum value of volume , the value of x will be 0.845
x= 0.845
Therefore the dimensions will be
[tex]Shorter\ side=4-2\times 0.845=2.31\ m\\Longest\ side=8-2\times 0.845=6.31\ m\\Height=0.845\ m[/tex]
The volume of a shape is the amount of space in the shape.
The dimensions that produce the largest volume are: 2.31 m by 6.31 m by 0.845 m
The dimensions of the cardboard is given as:
[tex]\mathbf{Length = 4m}[/tex]
[tex]\mathbf{Width = 8m}[/tex]
Assume the cut-out is x.
So, the dimension of the box is:
[tex]\mathbf{Length = 4 - 2x}[/tex]
[tex]\mathbf{Width = 8 - 2x}[/tex]
[tex]\mathbf{Height = x}[/tex]
So, the volume of the box is:
[tex]\mathbf{V = (4 - 2x)(8 - 2x)x}[/tex]
Expand
[tex]\mathbf{V = 32x -24x^2 + 4x^3}[/tex]
Differentiate
[tex]\mathbf{V' = 32 -48x + 12x^2}[/tex]
Set to 0
[tex]\mathbf{32 -48x + 12x^2 = 0}[/tex]
Divide through by 4
[tex]\mathbf{8 -12x + 3x^2 = 0}[/tex]
Rewrite as:
[tex]\mathbf{3x^2-12x +8 = 0}[/tex]
Using a calculator, we have:
[tex]\mathbf{x = 0.845,\ 3.155}[/tex]
3.155 is greater than the dimension of the box.
So, we have:
[tex]\mathbf{x = 0.845}[/tex]
Recall that:
[tex]\mathbf{Length = 4 - 2x}[/tex]
[tex]\mathbf{Width = 8 - 2x}[/tex]
[tex]\mathbf{Height = x}[/tex]
So, we have:
[tex]\mathbf{Length = 4 - 2 \times 0.845 = 2.31}[/tex]
[tex]\mathbf{Width = 8 - 2 \times 0.845 = 6.31}[/tex]
[tex]\mathbf{Height = 0.845}[/tex]
Hence, the dimensions that produce the largest volume are: 2.31 m by 6.31 m by 0.845 m
Read more about volumes at:
https://brainly.com/question/15918399
Please answer this correctly
Answer:
1/5
Step-by-step explanation:
The number 5 or greater than 4 is 5.
1 number out of 5 total parts.
= 1/5
P(5 or greater than 4) = 1/5
A hiker starting at point P on a straight road wants to reach a forest cabin that is 2 km from a point Q, 3 km down the road from P . She can walk 8 km/hr along the road but only 3 km/hr through the forest. She wants to minimize the time required to reach the cabin. How far down the road should she walk before setting off through the forest straight for the cabin?
Answer:
2.19 km
Step-by-step explanation:
If x is the distance she walks down the road before turning, then the total time is:
t = x/8 + √((3 − x)² + 2²) / 3
t = x/8 + √(9 − 6x + x² + 4) / 3
24t = 3x + 8√(13 − 6x + x²)
24t = 3x + 8(13 − 6x + x²)^½
Take derivative of both sides with respect to x.
24 dt/dx = 3 + 4(13 − 6x + x²)^-½ (-6 + 2x)
When t is a minimum, dt/dx = 0.
0 = 3 + 4(13 − 6x + x²)^-½ (-6 + 2x)
-3 = 4(13 − 6x + x²)^-½ (-6 + 2x)
3 / (6 − 2x) = 4(13 − 6x + x²)^-½
3 / (24 − 8x) = (13 − 6x + x²)^-½
(24 − 8x) / 3 = (13 − 6x + x²)^½
(24 − 8x)² / 9 = 13 − 6x + x²
576 − 384x + 64x² = 117 − 54x + 9x²
459 − 330x + 55x² = 0
Solve with quadratic formula.
x = [ 330 ± √((-330)² − 4(55)(459)) ] / 2(55)
x = (330 ± √7920) / 110
x = 2.19 or 3.81
Since 0 < x < 3, x = 2.19.
Which equation is a function of x?
Answer:
x" means that the value of y depends upon the value of x, so: y can be written in terms of x (e.g. y = 3x ). If f(x) = 3x, and y is a function of x (i.e. y = f(x) ), then the value of y when x is 4 is f(4), which is found by replacing x"s by 4"s . this should help I asked my brother for the answer and he told me to put this happy to help :0
Help me with this problem, thank you<3
Answer:
1,050 workers
Step-by-step explanation:
25% = 0.25
0.25 × 1400 = 350
1400 - 350 = 1050
Hope this helps.
what is the solution of
[tex] \sqrt{ {x}^{2} + 49 = x + 5[/tex]
Answer:
x = 2.4
Step-by-step explanation:
We assume you intend ...
[tex]\sqrt{x^2+49}=x+5\\\\x^2+49=x^2+10x+25\qquad\text{square both sides}\\\\24=10x\qquad\text{subtract $x^2+25$}\\\\\boxed{2.4=x}\qquad\text{divide by 10}[/tex]
I paid twice as much by not waiting for a sale and not ordering on line. Which ofthe following statements is also true?
(a) I paid 200% more than I could have online and on sale.
(b) I paid 100% of what I could have online and on sale.
(c) I paid 200% of what I could have online and on sale.
(d) I paid 3 times what I could have online and on sale.
Answer:
Option (c).
Step-by-step explanation:
It is given that, I paid twice as much by not waiting for a sale and not ordering online.
Let the cost of items ordering online be x.
So, now i am paying twice of x = 2x
Now, we have find 2x is what percent of x.
[tex]Percent =\dfrac{2x}{x}\times 100=200\%[/tex]
It means, I paid 200% of what I could have online and on sale.
Therefore, the correct option is (c).
Find the Prime factors of 1729. Arrange the factors in ascending order. Find a relation between
consecutive prime factors
Answer:
prime factors in ascending order of 1729 is 7 , 13 , 19
relation between consecutive prime factors is 6
Step-by-step explanation:
given data
number = 1729
solution
we get here factors of 1729
1729 = 7 × 13 × 19
so that required prime factors in ascending order of 1729 is 7 , 13 , 19
and
now we get relation between these prime factors is the difference between consecutive prime factors is
13 - 7 = 6
19 - 13 = 6
so relation between consecutive prime factors is 6
Step-by-step explanation:
Prime factors of the number 1729 are 7,13,19
i.e. 1729 =7×13×19
The factors in ascending order are 7,13,19.
Clearly we can see that each consecutive prime factors have difference of 6.
13-7=6
19-13=6
The population of the city of Peachwood is currently 12,000 and increases every year at a rate of 5%. The function that describes the model is ƒ(x) = 12000 • 1.05x. Which of the following choices would be the number of people in the city after one year?
Answer: 12600
Step-by-step explanation:
We are given the function that f(x) = 12000 * 1.05x
the x in f(x) is the amount of years that passed in the city of Peachwood, and the f(x) is the total population of Peachwood
These are two key elements in this function,
Therefore after 1 year the equation would be f(1) = 12000*1.05(1)
or f(1) = 12600
Explain the importance of factoring.
Answer:
Factoring is a useful skill in real life. Common applications include: dividing something into equal pieces, exchanging money, comparing prices, understanding time, and making calculations during travel.
Sorry if this is a little wordy, I can get carried away with this sort of thing
anyway, hope this helped and answered your question :)
Line segment ON is perpendicular to line segment ML. What is the length of segment NP?
Answer:
2 units.
Step-by-step explanation:
In this question we use the Pythagorean theorem which is shown below:
Given that
The right triangle OMP
The hypotenuse i.e OM is the circle radius =5 units.
The segment MP = 4 units length
Therefore
[tex]OP^2 + MP^2 = OM^2[/tex]
[tex]OP^2 + 4^2 = 5^2[/tex]
[tex]OP^2 + 16 = 25[/tex]
So OP is 3
Now as we can see that ON is also circle radius so it would be 5 units
And,
ON = OP + PN
So,
PN is
= ON - OP
= 5 units - 3 units
= 2 units
Answer:
2
Step-by-step explanation:
A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some children take 5 pieces, and 1 child takes 7 pieces of candy. How many children take 3 pieces of candy?
Answer:
6
Step-by-step explanation:
12*5=60
6*3=18
1*7=7
hope this help
Three girls of a group of eight are to be chosen. In how many ways can this be done?
Answer:
Step-by-step explanation:
8P3=8*7*6=336
Suppose you toss a coin 100 times and get 65 heads and 35 tails. Based on these results, what is the probability that the next flip results in a tail?
Answer:
[tex] P(Head) = \frac{65}{100}=0.65[/tex]
[tex] P(Tail) = \frac{35}{100}=0.35[/tex]
And for this case the probability that in the next flip we will get a tail would be:
[tex] P(Tail) = \frac{35}{100}=0.35[/tex]
Step-by-step explanation:
For this case we know that a coin is toss 100 times and we got 65 heads and 35 tails.
We can calculate the empirical probabilities for each outcome and we got:
[tex] P(Head) = \frac{65}{100}=0.65[/tex]
[tex] P(Tail) = \frac{35}{100}=0.35[/tex]
And for this case the probability that in the next flip we will get a tail would be:
[tex] P(Tail) = \frac{35}{100}=0.35[/tex]
S=4LW+2WH;S+=136,L6,W=4 WHAT IS H
Answer:
H=5
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
S=4lw+2wh
Put S as 136, l as 6, w as 4, and solve for h.
136 = 4(6)(4)+2(4)H
136 = 8h + 96
-8h = 96 - 136
-8h = -40
h = -40/-8
h = 5
Consider the function g(x) = x^12. Describe the range of the function.
Answer:
0 ≤ g(x) < ∞
Step-by-step explanation:
The range is all non-negative numbers.
___
g(x) is an even-degree polynomial with a positive leading coefficient, so it opens upward. There is no added constant, so its minimum value is zero. The function can take on all values zero or greater.
range: [0, ∞)
b. Parallelogram PQRS has base RS=14 m and an area of 70 m². What is the height of
the parallelogram?
Rs=14m and an area of 70m2
Answer
h = 5m
Step-by-step explanation:
area of a parallelogram is b * h
base = 14 m
h = ?
Area = 70 m²
Area = b * h
70 = 14 * h
h = 70 / 14
h = 5 m
Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?
Answer:
x^2-2x+1
Step-by-step explanation:
We can solve this by using FOIL
First, Outside, Inside, Last
Multiply the x with the x to get x^2
Then x times -1 for the outside numbers to get -x
Then -1 times x for the inside numbers to get -x
And finally -1 and -1 for the last numbers to get 1
Add the two -x to get -2x.
Put it all together
x^2-2x+1
Answer:
[tex]x^2-2x+1[/tex]
Step-by-step explanation:
=> (x-1)(x-1)
USING FOIL
=> [tex]x^2-x-x+1[/tex]
=> [tex]x^2-2x+1[/tex]
The manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less. A member of the hotel's accounting staff noticed that the total charges for guest bills have been increasing in recent months. The accountant will use a sample of weekend guest bills to test the manager's claim.
a. Which form of the hypotheses should be used to test the manager's claim?
H0:
greater than or equal to 600
greater than 600
less than or equal to 600
less than 600
equal to 600
not equal to 600
Ha: Select
greater than or equal to 600
greater than 600
less than or equal to 600
less than 600
equal to 600
not equal to 600
b. When H0 cannot be rejected, can we conclude that the manager's claim is wrong?
Yes
No
c. When H0 can be rejected, can we conclude that the manager's claim is wrong?
Yes
No
Answer:
(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $600
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $600
(b) When H0 cannot be rejected, we conclude that the manager's claim is correct.
(c) When H0 can be rejected, we conclude that the manager's claim is wrong.
Step-by-step explanation:
We are given that the manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less.
The accountant will use a sample of weekend guest bills to test the manager's claim.
Let [tex]\mu[/tex] = population mean guest bill for a weekend
(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $600
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $600
Here null hypothesis states that the mean guest bill for a weekend is $600 or less.
On the other hand, alternate hypothesis states that the mean guest bill for a weekend is more than $600.
(b) When the null hypothesis ([tex]H_0[/tex]) cannot be rejected, then the correct conclusion would be: We conclude that the mean guest bill for a weekend is $600 or less which means that the manager's claim is correct.
(c) When the null hypothesis ([tex]H_0[/tex]) can be rejected, then the correct conclusion would be: We conclude that the mean guest bill for a weekend is more than $600 which means that the manager's claim is wrong.
The kitchen is 15 feet wide and wight 18ft long. How many 12 inch Square tiles will it take to tile the kitchen floor?
Answer:
270 tiles.
Step-by-step explanation:
The kitchen is 15 x 18 feet. If we multiply we find the area is 270 square feet. one square foot is a 12 x 12 inch square, so we can fit one tile per square foot, giving us 270 tiles.
A local doctor’s office logged the number of patients seen in one day by the doctor for ten days. Find the means, median, range, and midrange of the patients seem in 10 days. 27 31 27 35 35 25 28 35 33 24
Answer:
Mean = 30, Median = 29.5, Range = 9 and Mid-range = 29.5.
Step-by-step explanation:
We are given that a local doctor’s office logged the number of patients seen in one day by the doctor for ten days.
Arranging the given data in ascending order we get;
24, 25, 27, 27, 28, 31, 33, 35, 35, 35.
(a) Mean is calculated by using the following formula;
Mean, [tex]\bar X[/tex] = [tex]\frac{\text{Sum of all values}}{\text{Total number of observations}}[/tex]
= [tex]\frac{27+ 31+ 27+ 35+ 35+ 25+ 28+ 35+ 33+ 24}{10}[/tex]
= [tex]\frac{300}{10}[/tex] = 30
So, the mean of the given data is 30.
(b) For calculating the median, we have to first have to observe that the number of observations (n) in the data is even or odd.
If n is odd, then the formula for calculating median is given by;Median = [tex](\frac{n+1}{2})^{th} \text{ obs.}[/tex]
If n is even, then the formula for calculating median is given by;Median = [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+ (\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]
Here, the number of observations is even, i.e. n = 10.
So, Median = [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+ (\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]
= [tex]\frac{(\frac{10}{2})^{th} \text{ obs.}+ (\frac{10}{2}+1)^{th} \text{ obs.} }{2}[/tex]
= [tex]\frac{(5)^{th} \text{ obs.}+ (6)^{th} \text{ obs.} }{2}[/tex]
= [tex]\frac{28+31}{2}[/tex]
= [tex]\frac{59}{2}[/tex] = 29.5
So, the median of the data is 29.5.
(c) The range of the data is given by = Highest value - Lowest value
= 35 - 24 = 9
So, the range of the data is 9.
(d) Mid-range of the data is given by the following formula;
Mid-range = [tex]\frac{\text{Highest value}+\text{Lowest value}}{2}[/tex]
= [tex]\frac{35+24}{2}[/tex] = 29.5
A farmer is building a fence to enclose a rectangular area consisting of two separate regions. The four walls and one additional vertical segment (to separate the regions) are made up of fencing, as shown below. A rectangular area consisting of two separated regions. If the farmer has 162 feet of fencing, what are the dimensions of the region which enclose the maximal areas?
Answer:
The maximal area will be "1093.5 square feet".
Step-by-step explanation:
Let,
Length = L feet
Breadth = b feet
Given Total fencing = 162 feet
According to the question,
[tex](2\times L)+(3\times b)=162[/tex]
[tex]2L+3B=162[/tex]
[tex]L=\frac{162-3b}{2}[/tex]
[tex]L=81-\frac{3}{2}b[/tex]
As we know,
[tex]Area=Length\times breadth[/tex]
[tex]=(81-\frac{3}{2}b)\times b[/tex]
[tex]=81b-\frac{3}{2}b^2[/tex]
Now, we required to decrease or minimize the are. So for extreme points:
[tex]\frac{dA}{db}=0[/tex]
or,
[tex]\frac{dA}{dB}=\frac{d}{db}(81-\frac{3}{2}b^2 )=0[/tex]
[tex]81-\frac{3}{2}\times 2\times b=0[/tex]
[tex]b=\frac{81}{3}[/tex]
[tex]b=27 \ feet[/tex]
Now on putting the value of b, we get
[tex]l=81-\frac{3}{2}\times 27[/tex]
[tex]=81-40.5[/tex]
[tex]=40.5 \ feet\\[/tex]
So that the dimensions will be:
⇒ 40.5 feet by 27 feet
Therefore when the dimension are above then the area will be:
= [tex]81\times 27-\frac{3}{2}\times 27\times 27[/tex]
= [tex]2187-\frac{3}{2}\times 729[/tex]
= [tex]2187-1093.5[/tex]
= [tex]1093.5 \ square \ feet[/tex]
the cube of a number increased by 4 times the same number
Answer:
x=∛4 x
Step-by-step explanation:
Let the number be x.
According to the question,
x^3=4 x
x=∛4 x
This is the only answer we can conclude from the information given in the question.
The required expression is x³ + 4x.
Given that,
The cube of a number increased by 4 times the same number is to be determined.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,
Let the number be x,
cube of number = x³
4 time of number = 4x
The cube of a number increased by 4 times the same number, which implies,
x³ + 4x
Thus, the required expression is x³ + 4x.
Learn more about arithmetic here:
brainly.com/question/14753192
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Which is NOT supported by this graph?
30
25
20
15
10
Profit
5
(dollars)
0
-10
-15
Cars Washed
Answer:
D -price of car wash keeps getting higher
Answer: The price of a car wash keeps getting higher
Step-by-step explanation:
Suggest changing to “On the graph of an exponential function representing growth, what happens to the slope of the graph as x increases?”
Answer:
If we have a growing exponential relation, we can write it as:
f(x) = A*r^x
Where A is the initial amount, r is the rate of growth, in this case, r > 1 (because is a growing exponential relation)
Now, the "slope" of the graph in x, is equal to the derivate of f(x) in that point, and we have:
f'(x) = A*(r^x)*ln(r)
Now, remember that r > 1, then ln(r) > 0.
then, f'(x) is a growing function as x grows, and f'(x) grows exponentially, this means that the slope of the graph also grows exponentially as x grows.
Please answer question now in two minutes
Answer:
V lies in the exterior of <STU.
Step-by-step explanation:
V lies in the exterior of <STU.