Hey there!
Molar mass NaCl = 58.44 g/mol
58.44 g ----------------- 22.4 ( at STP )
3.2 g -------------------- Volume ??
Volume = ( 3.2 x 22.4 ) / 58.44
Volume = 71.68 / 58.44
Volume = 1.226 L
Hope this helps!
Answer:
V = 0.56 L
Explanation:
Given data:
Mass of NaCl = 3.2 g
Volume of chlorine gas = ?
Pressure and temperature = standard
Solution:
Chemical equation:
2NaCl → 2Na + Cl₂
Number of moles of NaCl:
Number of moles = mass/molar mass
Number of moles = 3.2 g/ 58.44 g/mol
Number of moles = 0.05 mol
Now we will compare the moles of NaCl with chlorine;
NaCl : Cl₂
2 : 1
0.05 : 1/2×0.05 = 0.025 mol
Volume of chlorine:
PV = nRT
V = nRT/P
V = 0.025 mol × 0.0821 atm.L/mol.K × 273 K / 1 atm
V = 0.56 L
What was a key discovery in the advancement me up early information transfer
Answer:
The transfer was essential to understand the mutation and the possibility of new, more resistant strains in microorganisms.
Explanation:
the transfer of microorganisms is based on the transfer of genetic data through conductive pathways that penetrate the membranes, called pili or genetic bridges.
These mutated genes with higher resistance are transmitted and resistance is generated in entire populations and even species.
During the process of condensation, water vapor:____________.
(1) releases 334 J/g of heat energy
(2) releases 2260 J/g of heat energy
(3) gains 334 J/g of heat energy
(4) gains 2260 J/g of heat energy
Answer: (2) releases 2260 J/g of heat energy
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Latent heat of condensation is energy released when 1 mole of vapor condenses to form liquid droplets.
The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.
Phase transition refers to the changes in the states of matter between gas, liquids, and solids.
The correct answer is:
Option 2. releases 2260 J/g of heat energy
The process can be explained as:
1. Condensation is the process of conversion of water vapor into the liquid state.
2. Latent heat of vaporization is defined as the amount of heat required for 1 mole of liquid to convert into a gaseous phase at atmospheric pressure.
3. The change in the temperature does not occur during the condensation, and the heat required for the phase transition is latent heat. The heat of condensation of water vapor is 2,260 J/g.
Thus, the correct answer is Option 2.
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What is the velocity of a plane to travel 3000 miles from New York to California in 4.5 hours
Answer:
[tex]velocity = \frac{displacement}{time} \\ v = \frac{3000}{4.5} \\ v = 666.67 \: miles \: per \: hour \\ or \\ v = 666 \frac{2}{3} \: miles \: per \: hour[/tex]
Calculate the molar mass of adrenaline (C9H13NO3C9H13NO3), a hormone responsible for regulating heart rate and other functions of the sympathetic nervous system. Express your answer to five significant figures.
Answer:
[tex]M_{C_9H_{13}NO_3}=183.23g/mol[/tex]
Explanation:
Hello!
In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:
[tex]M_{C_9H_{13}NO_3}=m_C*9+m_H*13+m_N+m_O*3[/tex]
Now, we plug in the atomic masses to obtain:
[tex]M_{C_9H_{13}NO_3}=12.01*9+1.01*13+14.01+16.00*3\\\\M_{C_9H_{13}NO_3}=183.23g/mol[/tex]
Best regards!
Which gas is most abundant in Earth’s atmosphere?
Answer:
nitrogen
Explanation:
The atmosphere contains many gases, most in small amounts, including some pollutants and greenhouse gases. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere. Why do I care?
nitrogen is the most abundant gas in the atmosphere
when aqueous solutions of sodium hypochlorite and nitric acid are mixed, an aqueous solution of sodium nitrate and hypochlorous acid results. Write the net ionic equation for the reaction.
Answer:
H+ (aq) + ClO- (aq) ---> HClO(aq)
Explanation:
The net ionic reaction equation is a chemical equation that explicitly shows only the particular ions that undergo a chemical change in the course of a given reaction.
In this particular reaction, the molecular reaction equation is shown as follows;
HNO3(aq) + NaOCl(aq) -----------> NaNO3(aq) + HOCl(aq)
Ionically;
H+ (aq) + ClO- (aq) ---> HClO(aq)
What is the molecular geometry for SF2H2?
Trigonal pyramidal
Bent
Linear
Tetrahedral
Trigonal planar
Answer:
Tetrahedral
Explanation:
SF2H2 is a derivative of the sulfuranes (SL4) compounds. The quantum mechanics of these sulfuranes is quite complicated.
Simply, they consist of ten electrons around the sulphur central atom one of which is a lone pair. The electronegativity of fluorine plays a key role in the structure and molecular geometry of SF2H2.
The molecule is found to be tetrahedral in shape by quantum mechanical calculations.
answer choices
a. 13
b. 15
c. 28
d. 30
:))
Answer:
15 neutrons
Explanation:
Number of neutrons = atomic mass - number of protons.
So Neutrons = 28 - 13 protons
(Since atom is neutral, number of electrons = number of protons, which is how I get the 13 protons)
Neutrons = 15
Please help me thanks so much....I’ll mark you?!?!:))))
Answer:
Extreme heat
Explanation:
Because when matter is heated up The molecules move faster.
Answer:
I think it's extreme heat
can u pls help me with this question
Answer:
C
Explanation:
Condensation
Answer:
C....... ...................
Element X has two naturally occurring isotopes, 65X (isotopic mass 65.0457 amu, abundance 20.53%) and 67X (isotopic mass 66.9704 amu, abundance 79.47%). Calculate the atomic mass of element X.
Answer:
66.5753 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A (⁶⁵X):
Mass of A = 65.0457 amu
Abundance of A = 20.53%
Isotope B (⁶⁷X):
Mass of B = 66.9704 amu
Abundance of B = 79.47%
Atomic mass of X =?
The atomic mass of X can be obtained as follow:
Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]
= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]
= 13.3539 + 53.2214
= 66.5753 amu
Therefore, the atomic mass of X is 66.5753 amu.
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
What is the average atomic mass?The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.
Element X has 2 isotopes:
⁶⁵X with an isotopic mass of 65.0457 amu and an abundance of 20.53% (0.2053).⁶⁷X with an isotopic mass of 66.9704 amu and an abundance of 79.47% (0.7947).We can calculate the average atomic mass of X using the following expression.
mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X
mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947
mX = 66.58 amu
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
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2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the solution?
12
Ans: pH = 11
Answer:
11
Explanation:
Moles of KOH = [tex]10^{-2}[/tex]
Volume of water = 10 liters
Concentration of KOH is given by
[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]
[tex][KOH][/tex] is strong base so we have the following relation
[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]
[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]
[tex]\Rightarrow pH=14-3=11[/tex]
So, pH of the solution is 11
Question 1 of 10
Where is a tomado most likely to form?
O A. Where warm, moist air masses traveling north collide with cool,
dry air masses traveling south
O B. On the northwestern side of a low-pressure system
C. Where a high-pressure system is lingering over an area
OD Over warm, tropical ocean water
SUBMIT
Answer:
A Where warm, moist air masses traveling north collide with cool,
dry air masses traveling south
At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same conditions 285.8 KJ is released when one mole of H2O is formed from its elements. Find Delta h of the vaporization of water at these conditions
Answer:
44Kj
Explanation:
These are the equations for the reaction described in the question,
Vaporization which can be defined as transition of substance from liquid phase to vapor
H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H
-241.8kj -------eqn(1)
H2(g)+ 1/2 O2(g) ------>H2O(l).
Δ H =285.8kj ---------eqn(2)
But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as
H2O(l) ------>>H2O(g)---------------eqn(3)
But the equation from eqn(2) the eqn does go with vaporization so we can re- write as
H2O ------> H2(g)+ 1/2 O2(g)
Δ H= 285.8kj ---------------eqn(4)
To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)
Δ H=285.8kj +(-241.8kj)= 44kj
can u pls help me with this question
Answer:
B
Explanation:
Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and characteristic colors by which we can identify them. Therefore, in the analysis of mixtures of metal ions, it is very common to precipitate the metal ions by using dihydrogen sulfate (commonly called hydrogen sulfide), H2S. Suppose you had a mixture of Fe2+, Cr3+, and Ni2+. Complete the net ionic equations for the precipitation of these metal ions by the use of H2S. (Type your answers using the format Fe2+ for Fe2+.)
Answer:
See explanation
Explanation:
For Fe;
Fe2+(aq) + 2H+(aq) + S2-(aq) ----> FeS(s) + H2(g)
For Ni
Ni2+(aq) + 2H+(aq) + S2-(aq) ----> NiS(s) + H2(g)
For Cr
2Cr3+(aq) + 6H+(aq) + 3S2-(aq) ----->Cr2S3(s) + 3H2(g)
We must remember that in writing these equations, the number of electrons lost or gained must be balanced. The number of electrons lost by the metal must equal the number of electrons gained by hydrogen. This rule was followed in writing all the equations above.
what kind of structure do the cations and anions in table salt form
Answer:
ionic solids
Explanation:
Ionic solids are a regular pattern of cations and anions that arrange themselves into a continuous solid network.
NaCl is composed of sodium ions and chloride ions that are held together by Coulumbic attractive forces to form a large crystal structure.
Such ionic solids have a very high melting point and do not conduct electricity in the sold state. However, the molten substance or a solution of the substance conducts electricity.
What is the mass of 8.50 × 1022 molecules of NH3?
Answer:
The mass of 8.50 × 10²² NH₃ molecules is ≈ 1.84 g.
One mole of a molecule contains 6.02 × 10²³ molecules. The mass of 8.50 × 10²² molecules of NH₃ is 2.39 g.
What is ammonia (NH3)?Ammonia is an inorganic compound formed by hydrogen and nitrogen. Ammonia exists in gaseous state.
One mole of every element or compound contains 6.02 × 10²³ molecules. This number is called Avogadro number. The molar mass of ammonia is 17 g/l
It is given that the number of molecules of ammonia here, is 8.50 × 10²².
The no.of moles of ammonia = 8.50 × 10²²/ 6.02 × 10²³
= 0.141 moles.
If one mole ammonia is 17 g/l, the mass of 0.141 moles of NH₃ is calculated as follows: 0.141 × 17 = 2.39 g. Hence the mass of NH3 which contains 8.50 × 10²² molecules is 2.39 g.
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Question 3 of 10
Often, personal data are transmitted using digital signals. What might go
wrong with these transmissions?
A. The signal might become too weak to detect because it slows
down
B. The data might be altered, or changed, during the transmission
C. The data might be misinterpreted because of noise,
D. The data might be stolen or accessed by hackers.
Answer: D
Explanation:
The personal data are transmitted using digital signals. The data might be stolen or accessed by hackers to go wrong with these transmissions. Therefore, option D is correct.
What is digital signal ?A digital signal is one that can only ever take on one of a few discrete values at any given time. It represents data as a sequence of discrete values.
A continuous signal that represents physical measurements is an analog signal. Digital modulation is used to create time-separated signals known as digital signals. Sine waves serve as its signal. The square waves serve as a marker.
It makes use of a continuous range of values to aid in the representation of data. Digital technologies are any techniques, systems, equipment, or resources that produce, store, or process data electronically.
Thus, option D is correct.
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Calculate the number of grams of solid aluminium chloride that will form when a mixture containing 0.150 g of aluminum powder and 1.00 g of chlorine gas is allowed to react.
2Al (s) + 3Cl2 (g) ---> 2AlCl3 (s)
a. 741 g AlCl3
b. 471 g AlCl3
c. 0.741 g AlCl3
d. 246 g AlCl3
Answer:
the answer is B:) have a good day
Do you think the amount of the liquid changes how acidic or basic it is? Explain your thinking.
I'll give brailiest.
Answer:
yes, the cells in the liguid is all congrating together.
Explanation:
For this experiment you will need to perform a serial dilution of CO(NO3)2 solutions, meaning that you will begin with a stock solution, dilute it to make a new solution, and then use that new solution as the stock solution for the next dilution. You will start with a 0.25 M CO(NO3)2 solution. Using the values below, calculate the volume of solution and water needed at each step of the dilution.
Concentration of original solution mL of original solution required mL of water required Concentration of new solution
0.25M 0.1M
0.1M 0.05M
0.05M 0.01M
Answer:
See answer below
Explanation:
In this case, I will put the original photo of this exercise, because we are missing one data. The first picture is the original exercise.
Now, according to this, we need to make a serial dilution of CO(NO₃)₂. We don't know the volume of this solution, but we do know the total volume of the preparing solution (In the picture states that the total volume will be 10 mL).
So, we know the final volume of the solutions to be prepared, so, le'ts use the expression that will help us to solve this:
C₁V₁ = C₂V₂
Where:
C₁: Concentration of the given solution (stock)
V₁: volume required to prepare the dilluted solution
C₂; Concentration of the dilluted solution
V₂: Total volume of the dilluted solution.
Now that we know the expression to use and the meaning of each value, let's prepare the solutions:
To prepare 10 mL of 0.1 M using a 0.25 M, we will replace these values in the above expression; from there, we will solve for V₁, that value will tell us the required volume to prepare solution 2, and then, by difference we can calculate the volume of water:
Volume of water (Vw) =V₂ - V₁
Now replacing the values:
0.25V₁ = 0.1 * 10
V₁ = 1/0.25 = 4 mL
V₁ = 4 mLThis means that we need 4 mL of the stock to prepare the 0.1 M of dilluted solution, therefore, the volume of water required is:
Vw = 10 - 4
Vw = 6 mLUsing these same steps for the other two solutions we will get V1 and V2 for both of them. In this case, I will go straight to the procedure without further explanation because it's the same of this one.
For solution 2:
0.1V₁ = 0.05 * 10
V₁ = 0.5/0.1
V₁ = 5 mLVw = 10 - 5
Vw = 5 mLFinally for solution 3:
V₁ = 0.01 * 10 / 0.05
V₁ = 2 mLVw = 10 - 2 mL
Vw = 8 mLHope this helps
In a lab, you produce a quantity of the radioactive isotope thorium-234. Over the course of several weeks, the unstable isotope decays, and you measure the amount of thorium-234 remaining in the sample. You obtain the following data. What is the half life of Thorium-234? How much Thorium 234 will there be after two half lives?
Days Elapsed Grams of Thorium 234 Remaining
0 16
12 11
24 8
36 6
a. 36 days
b. 12 days
c. 24 days / 4 grams
Answer:
Option C. 24 days / 4 grams
Explanation:
From the question given above, the following data were obtained:
Days Elapsed >>>> Mass Remaining
0 >>>>>>>>>>>>>>> 16
12 >>>>>>>>>>>>>>> 11
24 >>>>>>>>>>>>>>> 8
36 >>>>>>>>>>>>>>> 6
A. Determination of the half-life of Thorium-234.
To determine the half-life, it is important to know the definition of half life.
Half-life is defined as the time taken for a substance to reduce to half its original mass.
From the table given above, we can see that the original mass of the isotope is 16 g (i.e at 0 day). By day 24, the mass of the isotope is 8 g (i.e half the original mass). Thus, the half-life of the isotope is 24 days.
B. Determination of the mass of the isotope remaining after 2 half lives.
Original amount (N₀) = 16 g
Number of half-lives (n) = 2
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2² × 16
N = 1/4 × 16
N = 4 g
Thus, 4 g of the isotope is remaining after 2 half lives.
Summay:
Half-life = 24 days
Amount remaining after 2 half-lives = 4 g
Option C gives the correct answer to the question.
Xander is gaining weight. Which best describes what he can do to prevent obesity? exercise every day and also make healthy choices in his diet excercise once a week but make no change in his diet exercise once a week and also make healthy choices in his diet exercise every day but make no change in his diet
Answer:
exercise every day and also make healthy choices in his diet
Explanation:
This is going to prevent Xander from getting more overweight and will help him lose some pounds.
This is also something I need to do lol
<3
Answer:
A
Explanation:
Exercise every day and also make healthy choices in his diet
In the Lewis symbol for a sulfur atom, there are __________ paired and __________ unpaired electrons. A) 2, 2 B) 4, 2 C) 2, 4 D) 0, 6 E) 5, 1 Answer: B
Answer:
C) 2, 4.
Explanation:
Hello!
In this case, since the sulfur atom has six electrons at its outer shell, it suggests it needs to gain two electrons in order to attain a complete octet, that is why it has 2 paired electrons.
Moreover, since two electrons are paired, then 4 electrons will remain unpaired; therefore the answer would be C) 2, 4.
Best regards!
Calculate the following:
1. Mass of 4.3x10-3 mol of lead
2. Mass of 3.8x1022 antimony atoms
3. Number of atoms in 15.5 kg of tungsten
Answer:
1) Mass = 890.96 g
2) Mass = 7.67 g
3) 507.65 ×10²³ atoms
Explanation:
1) Given data:
Number of moles of lead = 4.3×10⁻³ mol
Mass of lead = ?
Solution:
Mass = number of moles × molar mass
Molar mass of lead = 207.2 g/mol
by putting values,
Mass = 4.3×10⁻³ mol × 207.2 g/mol
Mass = 890.96 g
2) Given data:
Number of atoms of antimony = 3.8×10²² atoms
Mass of antimony = ?
Solution:
1 mole contain 6.022 ×10²³ atoms
3.8×10²² atoms × 1 mol / 6.022 ×10²³ atoms
0.63×10⁻¹ mol
0.063 mol
Mass:
Mass = number of moles × molar mass
Molar mass of lead = 121.76 g/mol
Mass = 0.063 mol × 121.76 g/mol
Mass = 7.67 g
3) Given data:
Mass of tungsten = 15.5 Kg (15.5 kg × 1000 g/ 1kg = 15500 g)
Number of atoms = ?
Solution:
Number of moles of tungsten:
Number of moles = mass/molar mass
Number of moles = 15500 g / 183.84 g/mol
Number of moles = 84.3 mol
1 mole contain 6.022 ×10²³ atoms
84.3 mol × 6.022 ×10²³ atoms / 1mol
507.65 ×10²³ atoms
What is the answer to this?
can u pls help me with this question
Answer:
I think the answer is b
Explanation:
the paragraph states, that it is an experiment to see if there is any oxygen in the water
how does mixture relate to life
Answer:
For example, when we bake a cake, it's a result of a mixture of eggs, flour, sugar, and other ingredients. Any time two or more items are combined, a mixture is formed. Sometimes, the different parts of a mixture can be separated into individual entities. Other times, they're married for as long as they exist.
Explanation:
a helium balloon at 28 C has a volume of 1.8 L and a pressure of 102 kPa. what is the volume of the balloon when is rises into the atmosphere where the pressure is 85 kPa and the temperature is 4 C?
Answer:
V₂ =1.99 L
Explanation:
Given data:
Initial volume = 1.8 L
Initial temperature = 28°C (28+273.15 K= 301.15 k)
Initial pressure = 102 KPa
Final volume = ?
Final pressure = 85 KPa
Final temperature = 4°C (4+ 273.15 K = 277.15 K)
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
V₂ = 102 KPa × 1.8 L × 277.15 K / 301.15 K × 85 KPa
V₂ = 50884.74 KPa .L. K / 25597.75 K.KPa
V₂ =1.99 L