If my candle has a brightness of 15 candela from a distance of 2 meter. What would the brightness be at a distance of 6 meters?

Answer:

what's the question? I don't understand

Answer:

Limestone can from form shell fragments of sea creatures

Explanation:

Answer:

Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.

Explanation:

Answer:

B

Explanation:

F= m×a

450N = 1.5kg × a

450/1.5 = a

a=300m/s²

IM NOT SURE THO

Answer:

a) the magnitude is 6.37 m/s

b) the direction relative to due west, as seen by Barbara is 46.37° north of west

Explanation:

Given the data in the question;

Barbara is skating due south at a speed of 4.6 m/s

Neil is skating due west at a speed of 4.4 m/s

so

[tex]u_{B}[/tex]→ = 4.6 (-j^)

[tex]u_{N}[/tex]→ = 4.4 (-i^)

[tex]u_{NB}[/tex]→ = [tex]u_{N}[/tex]→ - [tex]u_{B}[/tex]→  = 4.4 (-i^) - 4.6 (-j^)

= -4.4i^ + 4.6j^

a) magnitude

magnitude |([tex]u_{NB}[/tex]→ )| = √( (-4.4)² + (4.6)²)

= √( 19.36 + 21.16)

= √40.52

= 6.37 m/s

Therefore, the magnitude is 6.37 m/s

b) direction relative to due west, as seen by Barbara.

using SOH CAH TOA

tan = opp / adj

so direction will be;

∅ = tan⁻¹( 4.6 / -4.4)

∅ = tan⁻¹( - 1.0454545 )

∅ = - 46.37°

Therefore, the direction relative to due west, as seen by Barbara is 46.37° north of west

Answer:

Mechanical advantage = 4

Explanation:

Given the following data;

Distance of effort, de = 8m

Distance of ramp, dr = 2m

To find the mechanical advantage;

Mechanical advantage = de/dr

Substituting into the equation, we have;

Mechanical advantage = 8/2

Mechanical advantage = 4

Explanation:

option A is the correct answer of this question .

plz mark my answer as brainlist if you find it useful.☺️

Answer:

180 turns

Explanation:

Given data

Vi= 240 volts

Vo= 960volts

Ns= 720 turns

Required

The amount of Primary turns Np

The expression relating voltage and turns in a transformer is given as

Np/Ns= Vi/Vo

substitute

Np/720= 240/960

cross multiply

720*240= Np*960

172800= Np*960

Np= 172800/960

Np= 180

Hence the primary turns is 180 turns

Answer:

B. 2.5

not 2.5m because IMA is unitless.

The identical mechanical advantage of the inclined plane is 2.5.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Length of the inclined plane; d = 5 m.

Height of the inclined plane; h = 2 m.

So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane

= 5 m/2 m

= 2.5.

Hence, the  identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.

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Answer:

The entire conductor is at the same potential.

The electric field inside is zero.

Explanation:

For a conductor in electrostatic equilibrium, the properties are:

A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors.

It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads).

Instead, all that is required of the charged particle is a small amount of nudging from its neighbor, who in turn will nudging its neighbor, and so on, until a particle gets nudged into the consumer, so supplying it with power.

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Answer:

the charge carriers have an energy 2.8 10⁻¹⁹ J

Explanation:

The energy in a diode is conserved so the energy supplied must be equal to the energy emitted in the form of photons.

The energy of a photon is given by the Planck expression

             E = h f

the speed of light, wavelength and frequency are related

             c = λ f

we substitute

             E = [tex]\frac{h \ c}{\lambda}[/tex]

a red photon has a wavelength of lam = 700 nm = 700 10⁻⁹ m

we calculate the energy

              E = 6.626 10⁻³⁴  3 10⁸/700 10⁻⁹

              E = 2.8397 10⁻¹⁹J

therefore the charge carriers have an energy 2.8 10⁻¹⁹ J,

Answer:

a)  v = 7.69 10³ m / s,  b)    T = 92.6 min

Explanation:

a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity

          a = v² / r

          v = [tex]\sqrt{a r}[/tex]

the distance to the ISS is

           r = R_earth + d

           r = 6400 10³ + 400 10³

           r = 6800 10³ m

we calculate

           v = [tex]\sqrt{8.69 \ 6800 \ 10^3}[/tex]Ra (8.69 6800 103)

           v = [tex]\sqrt{59.09 \ 10^6}[/tex]

           v = 7.687 10³ m / s

the result with the correct significant figures

            v = 7.69 10³ m / s

b) The speed of the ISS is constant, so we can use the uniform motion relationships

            v = d / t

if distance is the orbit distance

            d = 2π r

time is called period

            v = 2π r / T

            T = 2π r / v

let's calculate

            T = 2π 6800 10³ /7,687 10³

            T = 5.558 10³ s

let's reduce the period to minutes

            T = 5.558 10³ s (1 min / 60s)

            T = 9.26 10¹ min

            T = 92.6 min

Answer:

composition :))

Explanation:

Answer:

Both C and D are true, but it mainly depends on answer C, the composition of the star.

Explanation:

Hope This Helps!

Answer:

266 m

Explanation:

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Answer:

Net force refers to the sum of all the forces that act upon an object.

Explanation:

Answer:

The answer is below

Explanation:

Centripetal acceleration is the acceleration due to the movement of an object in a uniform circular motion. The acceleration is directed towards the center of the circle.

Centripetal acceleration is given by the formula:

a = v² / r; where v is the speed of the object and r is the radius of curvature (distance from object ot the center of circle).

Let us assume the car has a velocity of v m/s. For the curve with radius of curvature r:

a₁ = v² / r

For the curve with radius of curvature r = 2r:

a₂ = v² / 2r = (1/2)a₁

Therefore the centripetal acceleration is greater in the curve with radius pf curvature r and smaller in the curve with twice the radius of curvature of the other.

Answer:

ΔQ = 4896 KJ

Heat Flux = 57407.55 W/m²

Cost = $ 0.176

Explanation:

The amount of heat dissipated in two hours can be given as:

[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]

where,

P = Power of Iron = 800 W

t = time taken = 2 hrs

η = Conversion efficiency = 85% = 0.85

[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]

ΔQ = 4896 KJ

Now, for heat flux:

[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]

Heat Flux = 57407.55 W/m²

Now, for total heat energy in KWhr in two hours:

[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]

Now, for the cost:

[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]

Cost = $ 0.176

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]

So, the magnitude of the electrostatic force is 36 N.

Answer:

go to settings and find what your looking for

Explanation:

Answer:

mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Explanation:

The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz

let's use the relationship between wave speed, wavelength and frequency

           v = λ f

           λ= v / f

           λ = 343/10000

           λ = 3.43 10⁻² m

the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range

          f = (100 10³ + 25 10³) / 2

          f = 62.5 10³ Hz

          λ = 343 / 62.5 10³

          λ = 5.5 10⁻³ m

Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.

The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Answer:

uh finish the question please lol.

Answer:

false this is correct answer of this question

Answer:

It's A.

Explanation:

DNA is a double helix.

Model which accurately displays structure of DNA is model A as DNA is a double helical structure.

DNA  is a hereditary material which is present in human beings as well as all other living organisms.  Every cell which is present in an organism's body has DNA  which is the same. Most of the DNA is situated in the cell's nucleus  and small amount of it can be found in the cell's mitochondria as well.

Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.

DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule  and a phosphate group. A base, phosphate  sugar are together called as nucleotides.

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Answer:

  [tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)

Explanation:

The general equation of a traveling wave on the x-axis is

        [tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)

the amplitude of the wave is E₀ = 10 V / m

the wave number is

         k = 2π /λ

indicate the value of   λ = 550 nm = 550 10⁻⁹ m

we substitute

         k = 2π / 550 10⁻⁹

         k = 1.15 10⁻¹¹ m⁻¹

angular velocity is related to frequency

          w = 2πf

the speed of light is related to the wavelength and frequency

           c = λ f

           f = c /λ

we substitute

           w = [tex]2\pi \frac{c}\lambda }[/tex]

           w = 2π  3 10⁸/550 10⁻⁹

           w = 3.427 10¹⁵ rad / s

we substitute in the electric field equation

           [tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)

Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth

           Ey (0,0) = 10

which corresponds to its maximum positive value, therefore this is the expression of the traveling wave

Answer: 1.5 N/C

Explanation:

The equation is derived from Coulomb's Law, but is not exactly Coulomb's Law:

F = qE

q is the test charge

E is the electrical field produced by the source charge

F is the force in Newtons

In this problem, we were given the value of the test charge q, and the force acting on it due to the electric field from the source charge.

E = F/q

E = 6.5N/4.3C

E = 1.5 N/C

Answer:

Explanation:

Force between charge is given by the following expression

F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .

Putting the given values ,

.85  = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²

Q₂ = .85 x  5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )

= .38788  x 10⁻³ C .

= 387.88 x 10⁻⁶ C .

Answer:

F_total = -65.5 N

Explanation:

Coulomb's law is

           F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2

In this exercise the force on the charge q3 is asked, for this we use that the force is a vector

          F_total = F₁₃ + F₂₃

let's look for every force

          F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]

it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m

the distance is

          r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]

          r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]

          r₁₃ = 1.175 10⁻³ m

we calculate

          F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]

          F₁₃ = 3.598 N

as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right

we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0

             F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]

            r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]

            r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103

            r₂₃ = 0.5 10⁻³ m

             F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]

             F₂₃ = 6.912 10¹ N

             F₂₃ = 69.12 N

as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left

the total force is

            F = total = 3.598 - 69.12

            F_total = -65.5 N

the negative sign indicates that the force is to the left

Answer:

agree with above answer

Answer:

The energy of the light would increase from visible light into the ultraviolet range.

Explanation:

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