If _______________ is disregarded all objects dropped near surface of planet fall with same acceleration.

Answer:1342

Explanation:

Answer:

answer is 1/2 as much force required

Answer:

Metabolism

Explanation:

metabolism is the sum of all chemical reactions that take place within an organism

Answer:

Metabolism

Explanation:

Answer:

zero displacement

its returnin to the starting point.

5 north 5 south

Answer:

31.21 m/s

Explanation:

radius=41m

time = 8 sec

circumference=2πr

from formula

circumference=2×22/7×41

=257.71m

now

velocity=total distance( circumference)/total time

=257.71/8

= 32.21m/s

The velocity of race car makes one lap around a track with a radius of 41 meters in 8 seconds is 32.19 m/s

Velocity is "rate of change of displacement with respect to time".

i.e. v= dx/dt

it is also defined as displacement over time. i.e. v=Displacement/Time.

Velocity shows how much distance can be covered in unit time. It's SI unit is m/s. It is vector quantity ( having both direction as well as momentum). where displacement is distance from mean position.

Given,

Radius of the track r= 41m

time taken by car to complete one lap T = 8s

velocity v = ?

we know that ω = 2π÷T

ω = 2×3.14 ÷ 8

ω = 0.785 rad/s

v=rω

v= 41×0.785

v= 32.185 ≅32.19 m/s

Hence velocity of the car is 32.19 m/s

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Answer:

Space Weather Data

They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.

Explanation:

Answer:

It is either A or D I think it is A.

Answer:

thxs for the points

Explanation:

because just started

Answer:

[tex]x =\frac{-R}{2}[/tex]

Explanation:

From the question we are told that mass

Thin layer radius [tex]= 2R[/tex]

Generally the expression for ths solution is given as

Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2

the center of mass will not move at initial state  

Considering the center of mass of both bodies

[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]

[tex]x =\frac{-R}{2}[/tex]

Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]                          

The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

Given-

Radius of the ball is [tex]R[/tex].

the mass of the ball is [tex]m[/tex].

The mass of the thin shell is [tex]m[/tex].

The radius of the thin shell is [tex]2 R[/tex].

For the two bodies with mass [tex]m[/tex], the center of mass can be given as,

[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]

In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,

[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]

[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]

[tex]x_{cm} =x[/tex]

Distance for center of mass can also be given as,

[tex]x_{cm} =m\times o[/tex]

[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]

[tex]x_{cm} =\dfrac{-R}{2}[/tex]

Comparing both the values of the distance of center of mass we get,

[tex]x =\dfrac{-R}{2}[/tex]

Hence, The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

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Answer:

Explanation:

It is still using F = m*a -- just in a disguised form.

Givens

F = 900 N

vf = 360 m/s

vi = 0

t = 40 second

Formulas

a = (vf - vi)//t

F = m * a

Solution

a = (360 - 0)/ 40

a = 9

F = m * a

900 = m * 9

m = 900/9

m - 100 kg.          Doesn't seem high enough.

Answer:

a= V- u/t

a= 360 - 0 /40 = 9 m/sec2

F = MA

900 = M * 9

M = 900/9

M= 100 kg

Answer:

As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.

Answer:

The value is  [tex]M = 42.3 \ kg[/tex]

Explanation:

From the question we are told that

    The first  position of the fulcrum  is  x = 49.7 cm

    The mass  attached is [tex]m = 41.5 \ g[/tex]

    The position of the attachment is  [tex]x_1 = 28.5 \ cm[/tex]  

    The second position of the fulcrum is  [tex]x_2 = 39.2 \ cm[/tex]

Generally the sum of clockwise torque =  sum of anti - clockwise torque

So  

       [tex]CWT = m (x_2 - x_1)[/tex]

Here CWT  stands for clockwise torque

       [tex]ACWT = M ( x - x_2)[/tex]

So

      [tex]m (x_2 - x_1) = M ( x - x_2)[/tex]

=>   [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]

=>    [tex]M = 42.3 \ kg[/tex]

Answer:

The force due to air resistance is 256 N.

Explanation:

Given;

mass of the plane, m = 5 kg

applied force on the plane, Fa = 706 N

the net force on the plane, ∑F= 450 N

Let the force due to air resistance = Fr

The net force on the plane is given as;

Net force = applied force - force due to air resistance

∑F = Fa - Fr

Fr = Fa - ∑F

Fr = 706 - 450

Fr = 256 N.

Therefore, the force due to air resistance is 256 N.

Answer:

2

Explanation:

A huge enormous gigantic number ... two in every molecule of the stuff !

Answer:

acceleration = v-u /t

30- 20/5

= 10/5 = 2m/sec²

Force = mass * acceleration

Force = 0.1 * 2

Force = 0.2 Newton

Answer:

I hope the above pic will help you

I will always help you understanding your assingments

have a great day #Captainpower:)

Answer:

You need to put the diagrams. repost and include the diagrams

Answer:

10 grams

Explanation:

I took a test with this question earlier.

Answer: True

Answer:

Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that can be perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nm, or 4.00 × 10⁻⁷ to 7.00 × 10⁻⁷ m, between the infrared and the ultraviolet.

Explanation:

This is one type of light.

Answer:

A screw

Explanation:

Answer:

1) 4000Joules

2) 25%

3) 320N

Explanation:

A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.

Calculate;

1)The work done by the effort

2)The efficiency of the system

3)The effort applied

1) Workdone by the effort is the work input = Load * distance moved by the Load

Workdone by the effort = 400 * 10

Workdone by the effort = 4000Joules

2) Efficiency = Work output/Work input * 100

Work output = work done against friction = 100 Joules

Efficiency = 100/4000 * 100

Efficiency = 10000/4000

Efficiency  = 25%

Hence the Efficiency of the system is 25%

3) Using the efficiency formula:

efficiency = MA/VR * 100

Velocity ratio = 5

MA = Load/Effort

efficiency = (L/E)/5 * 100

25 = 400/E/5 * 100

25/100 = 400/5E

0.25 = 400/5E

0.25 * 5E = 400

1.25E = 400

E = 400/1.25

E = 320N

hence the effort applies is 320N

Reflection is when waves bounce off a surface this because I did it in 7th grade was my favorite unit to learn in school.

When two different media come together at an  a wavefront might change direction so that it returns to the first medium, which is known as reflection.

The reflection of light, sound, and water waves are typical examples. According to the law of reflection, the angle at which the wave incident on the surface equals the angle at which it is reflected for specular reflection (such as at a mirror).

Reflection produces echoes in acoustics and is used in sonar. It is crucial to the study of seismic waves in geology. Surface waves in bodies of water are used to observe reflection.

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Answer:

to transfer the voltage

Explanation:

The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.

Answer:

For this we applicate 2nd law of Newton:

F = ma

Replacing:

400 N = 100 kg * a

a = 400 N / 100 kg

a = 4 m/s²

The aceleration is 4 meters per second squared.

Answer:

....................

Explanation:

---------------------

The free-body diagram of the forces acting on a book resting on a table is shown in the figure.

When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.

So, the forces acting on a book resting on a tabletop are:

1. Weight of the book, W(downward)

2. Normal force (N) perpendicular to the surface in contact.

Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.

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Answer:

The volume of the gas becomes three times the initial volume.

Explanation:

Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.

So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.

The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.

As the pressure is constant, so [tex]P_1=P_2[/tex].

Let V_1 and V_2 be the initial and final volume respectively.

Assuming that the given gas is ideal gas.

So, applying the ideal gas equation

PV=nRT

where n is the number of moles of the gas and R is the universal gas constant.

For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]

and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]

Dividing the equation (i) by (ii), we have

[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]

As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then

[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]

As the pressure is not changing, so [tex]P_1=P_2[/tex], then

[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]

[tex]V_2=3V_1[/tex]

So, the volume of the gas becomes three times the initial volume.

Answer:

I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.

Answer:

A

Explanation:

where the hole is because it's a rigid object with uniform density.