If gold is selling presently for $1000.00/oz how much would 1 cubic inch of gold be worth?
Note: 1 inch= 2.54 cm; 1 oz. =28.3 g Density of gold: 19.3 g/cm^3

Answer:

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. ... Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.

Answer: when an electromagnetic field interacts with a magnet

Explanation:

Answer:

Polarity.

Explanation:

The most important intermolecular force to allow a solvent to dissolve in water is polarity. This is because water is a polar substance and there is a chemical law that states that there is only solubility between substances of equal polarity. Thus, water is only able to dissolve a polar substance, just like it. In this case, we can say that the equal polarity between the two solvents is the most important for one to be able to dissolve the other.

Answer:

Explanation:

the average rate of change of the concentration =

( initial concentration - final concentration ) / time

Initial concentration = 2.000 M

the average rate of change of the concentration = .0540 M/s

time = 2 s

Putting the values

.0540 =  (2.000 - X ) / 2

0.108 = 2.000 - X

X = 1.892 M .

Final concentration = 1.892 M .

Answer:

When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.

The empirical and  molecular formula : C₂₁H₂₂N₂O₂

Given

The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen, 8.38 % Nitrogen, and 9.57 % Oxygen

Required

The empirical and  molecular formula

Solution

C : 75.42 : 12 = 6.285

H : 6.63 : 1 = 6.63

N : 8.38 : 14 = 0.599

O : 9.57 : 16 = 0.598

Divide by 0.598

C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2

The empirical formula : C₂₁H₂₂N₂O₂

(C₂₁H₂₂N₂O₂)n = 334

(334)n=334

n = 1

Answer:

bulb or pump, meniscus, outside

Explanation:

In order to use a pipet, place a BULB OR PUMP at the top of the pipet. Use this object to fill the pipet such that the MENISCUS of the liquid is even with the volume line. Release the liquid, touching the tip of the pipet to the side of the container if necessary to release the last drop OUTSIDE the pipet tip.

Answer:

(CH3)3C^+ + OH^-  --------> (CH3)3COH

Explanation:

This reaction has to do with SN1 reaction of alkyl halides. Here tert-butanol is formed from tert-butyl bromide.

The first step in the reaction is the formation of a carbocation. This is a unimolecular reaction. The rate of reaction depends on the concentration of the alkyl halide. This is a slow step and thus the rate determining step in the mechanism.

(CH3)3CBr -------> (CH3)3C^+ + Br^-

The second step is a fast step and it completes the reaction mechanism. It is a bimolecular reaction as follows;

(CH3)3C^+ + OH^-  --------> (CH3)3COH

Answer:

28.9452

Explanation:

Answer:

28.9452%

Explanation:

Rb-44.1781

Cr-26.8767

O-28.9452

Explanation:

a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.

b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.

c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.

d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.

The type of interactions in the following solutions are:

In a solution, the dissolution of solute molecules is driven by the interactions between the solute and solvent molecules.

The solute solvent interaction is based on the nature of the molecules. The interactions in the following solutions are:

The water is polar solvent and LiCl is an ionic molecule. The interaction between the molecules will be Ion-dipole force.

The acetronitrile and [tex]\rm NF_3[/tex] both are polar molecules. The force present in the interactions is Dipole-dipole force.

The benzene and [tex]\rm CCl_4[/tex] both are nonpolar molecules. The type of interaction present in the solution is London Dispersion force.

The water is a polar solvent, and Methylamine is an organic compound. The interaction in the solution is hydrogen bonding.

Learn more about solute-solvent interactions, here:

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Answer: [tex]LiF[/tex] , [tex]AlCl_3[/tex] and [tex]BeCl_2[/tex]

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

[tex]LiF[/tex] , [tex]AlCl_3[/tex] and [tex]BeCl_2[/tex] contain ionic bonds as they aremade up of metals and non metals.

Mass  of ammonium sulfate = 660.7 g

Given

3.01 x 10²⁴ molecules of ammonium sulfate

Required

mass

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

mol ammonium sulfate (NH₄)₂SO₄ :

n = N : No

n = 3.01 x 10²⁴ : 6.02 x 10²³

n = 5

mass ammonium sulfate :

= mol x MW

= 5 x 132,14 g/mol

= 660.7 g

Answer:

[a]. - 445.45J,

[b]. - 367.92 J

Explanation:

The following parameters are given in the question above. These information are used in solving this problem.

The mass of Xenon = 65.0 g of xenon, pressure = 2.00 atm, temperature = 298 K.

The number of moles of xenon = mass/ molar mass = 65g/ 131.293= 0.495.

The cp= 3/2 R, cp =3/2R + R = 5/2 R.

j = cp/cv = 3/2.

[a]. The final temperature,T2 = (2)^-2/3 × (298)^5/3 = T2^5/3.

Final temperature,T2 = 225.84K.

Expansion work = nCv [ T₂ - T₁] = 0.495 × 3/2 × 8.314 × [ 225.84 - 298] = - 445.45J.

(b). The final temperature can be Determine as;

3/2( T2 - 298k) = - 1 (T2 /1 - 298/2).

3/2(T2 - 298) = - T2 + 149K.

3T2 - 894 = - 2T2 +298K.

T2 = 238.4 K.

Workdone= nCv (T2 - T1) = 0.495 × 3/2 × 8.314 (238.4 - 298) = - 367.92 J.

Answer:

0.246 moles

Explanation:

Aluminum Sulfate is an ionic equation so we need to write the equation first with proper charges and subscripts:

Now that we know the ionic equation, we need to find the molar mass of Al_2(SO4)_3. There's 2 Aluminum's, each weighing 26.98 g/mol. There are 3 sulfates, each sulfate weighs 96.06 g/mol. We need to multiply the number of elements/compounds by their mass to get the total molar mass and then add them up (remember atomic mass = molar mass in g/mol):

We now know the molar mass of Al_2(SO4)_3 we need to find how many moles of it there are in an 84.2g sample. To do that, we need to do some dimensional analysis:

The grams of Al_2(SO4)_3 cancel so that we're left with moles of Al_2(SO4)_3 on top:

So in an 84.2g sample of Al_2(SO4)_3 (aka aluminum sulfate), there are 0.246 moles. This is correct because in one mole of Al_2(SO4)_3, there are 342.15g and the sample of 84.2 g of Al_2(SO4)_3 is way smaller than that, so our answer should be less than one mole, which it is.

I hope this helped!

Answer:

BrO3

Explanation:

The empirical formula is the smallest whole-number ratio, you find the greatest common factor (which is 2, in this case), then divide the subscripts by it.

So:

Br2 / 2 = Br1

O6 / 2 = O3

Answer:

21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.

Explanation:

Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.

Formula is: ΔT = Kf . m . i

Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:

ΔT = Freezing point of pure solvent - Freezing point of solution.

This data is known → 6.40°C

m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles

m = 0.351 mol / 0.5kg = 0.702 m

As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:

6.40°C = Kf . 0.702 m . 1

6.40°C /0.702m = 9.11 °C/m.

Let's go to the next question.

ΔT is the same → 6.40°C

But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ →  1Fe³⁺  + 3NO₃⁻

For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4

Let's replace data: 6.40°C = 9.11 °C/m . m . 4

6.40°C / (9.11 m/°C . 4) = 0.176 m

This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.

Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol

Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g

Answer:

Kc=[[CO][H2]3[CH4][H2O]

3.90=(0.30)(0.10)3[CH4]×0.02

[CH4]=0.023.90×0.30×(0.10)3=5.85×10−2 M

Thus, the concentration of methane in the mixture is 5.85×10−2 M.

Answer:

Is zygote fungi an option??

Answer:

zygote fungi

Explanation:

i got the answer right

Answer:

Explanation:

Iron Haber process  = (making ammonia)

Vanadium (V) oxide = Contact process (a stage in making sulfuric acid)

Manganese dioxide = Decomposition of hydrogen peroxide (produces water and oxygen)

Answer:

it develops from the womb

Answer:

outer cells of the blastocyst

Explanation:

on edg:)

Answer:

1.83 × 10³ cm²

Explanation:

Step 1: Given data

Surface area of a NBA basketball (A): 283 in²

Step 2: Convert "A" from square inches to square centimeters

In order to convert "A" from in² to cm², we need a conversion factor. In this case, we will use the conversion factor 1 in = 2.54 cm. Since "in" is raised to the power of 2, we will have to raise the conversion factor to the power of 2 as well.

283 in² × (2.54cm/1 in)² = 1.83 × 10³ cm²

Answer:

Yes we can calculate the solubility

The solubility of the mineral is 120 g/L

Explanation:

We have the information that the sample taken originally from the rock pool is 25.0 mL

So,

25.0 mL of the sample contained 3.000 g of the sample

10000mL of the sample now contains 1000 * 3.000/25 = 120 g

This means that 120 g of the sample dissolves in 1000mL or 1L of solution.

Therefore, the solubility of the mineral is 120 g/L

Answer: the line-emission spectrum of an atom is caused by the energies released when electrons. releases energy of only certain values.

The one that does not describe a chemical property is bleach is poisonous when swallowed. The correct options are C.

Chemical properties are those properties that show the reactivity of an element. These chemical properties are pH, chemical stability, reactivity, radioactive decay, flammability, toxicity, etc.

Gasoline is a chemical compound, its burning will be a chemical property because it shows how it reacts when it comes in contact with another chemical.

Gold is a pure element, its reactivity tendency is a chemical property, and it is not reactive with oxygen. Density is also a property of an element. And lead is denser than gold, which will show a chemical property.

Thus, the correct options are C. Bleach is poisonous when swallowed.

To learn more about chemical properties, refer to the link:

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#SPJ2

The original material has decayed 75%

Given

two half-life

Required

The decayed sample

Solution

General formulas used in decay:  

[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time

t = 2 x t 1/2

Input the value :

[tex]\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%[/tex]  

The amount of Nt = 25% No

Answer:

Explanation:

The objective of this experiment is to match the expected result with each of the propositions given after the experiment had been carried out.

1. The top layer was the organic layer. This is because all the organic compounds have lesser density than water except chloroform that will be formed when NaOH is added.

2. 9-fluorenone was most soluble in the organic layer. This is so as a result of its non-polar carbon structure.

3. Deprotonated chloroanilic acid was most soluble in the aqueous layer as a result of the formation of an electrovalent bond with water.

4. The bottom layer was the aqueous layer as a result of the huge amount of water density.

5. The organic layer was a yellow colored solution.

6. The aqueous layer turned into a pink colored solution.