Answer:
less than 25°
Explanation:
I did this question for school and when I put this answer it was correct.
Different satellites orbit the earth with a vast range of altitudes, from just a couple hundred km, all the way to tens of thousands of km above the surface. The international space station (ISS) is in a low earth orbit, just 400km above the surface (you can see it with the naked eye at sunset and sunrise as a bright, moving dot). At this altitude, the acceleration due to gravity has a value of 8.69m/s Assuming that the radius of the earth is 6400km).
1. What is the speed of the ISS? Express your answer to three significant figures and include the appropriate units.
2. What is the orbital period (T) of the ISS in minutes?
Answer:
a) v = 7.69 10³ m / s, b) T = 92.6 min
Explanation:
a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity
a = v² / r
v = [tex]\sqrt{a r}[/tex]
the distance to the ISS is
r = R_earth + d
r = 6400 10³ + 400 10³
r = 6800 10³ m
we calculate
v = [tex]\sqrt{8.69 \ 6800 \ 10^3}[/tex]Ra (8.69 6800 103)
v = [tex]\sqrt{59.09 \ 10^6}[/tex]
v = 7.687 10³ m / s
the result with the correct significant figures
v = 7.69 10³ m / s
b) The speed of the ISS is constant, so we can use the uniform motion relationships
v = d / t
if distance is the orbit distance
d = 2π r
time is called period
v = 2π r / T
T = 2π r / v
let's calculate
T = 2π 6800 10³ /7,687 10³
T = 5.558 10³ s
let's reduce the period to minutes
T = 5.558 10³ s (1 min / 60s)
T = 9.26 10¹ min
T = 92.6 min
At what rate is thermal energy being generated in the 2R-resistor when = 12 V and R = 3.0 ?
a. 12 W
b. 24 W
c. 6.0 W
d. 3.0 W
e. 1.5 W
If there's nothing else connected to the battery except the 3-ohm resistor, then the question is defective and the correct answer is not on the list.
With 12v connected across the resistor, the current through the resistor is
I = (E/R) = (12/3) = 4 Amperes.
The power generated inside a resistor is
P = (E x I) = (12v) x (4 A) = 48 watts
Which refers to the sum of all the forces that act upon an object?
O absolute force
O net force
O positive force
Answer:
Net force refers to the sum of all the forces that act upon an object.
Explanation:
Determine the maximum volume in gallons [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of feet [ft] so the total pressure at the bottom of the container will not exceed pound-force per square inch [psi]. Assume the height of the tank is sufficient to store the amount of olive oil required, and the surface pressure is 1 atmosphere [atm]. The specific gravity of olive oil is 0.86.
This question is incomplete, the complete question is;
Determine the maximum volume in gallons [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of 3feet [ft] so the total pressure at the bottom of the container will not exceed 26 pound-force per square inch [psi]. Assume the height of the tank is sufficient to store the amount of olive oil required, and the surface pressure is 1 atmosphere [atm]. The specific gravity of olive oil is 0.86.
Answer:
A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo
Explanation:
Given the data in the question;
Using SI units
Diameter = 3 ft = 3 × 0.3048 = 0.9144 m
pressure at bottom Pb = 26 psi = 26 × 6.89476 × 1000 = 179263.76 pascal
surface pressure Ps = 1 atm = 1 × 101325 = 101325 pascal
specific gravity = 0.86
we know that; density of water = 1000 kg/m³
so, density of oil P = density of water × specific gravity
= 1000 × 0.86 = 860 kg/m³
pressure at depth can be related to pressure at surface;
Pb = Ps + Pgh
acc. due gravity g = 9.81 m/s²
we substitute
179263.76 = 101325 + ( 860 × 9.81 × h)
8436.6h = 179263.76 - 101325
8436.6h = 77938.76
h = 77938.76 / 8436.6
h = 9.238 m
Now;
Volume of the cylinder = π/4 × D² × h
we substitute
Volume of the cylinder = π/4 × ( 0.9144 )² × 9.238
Volume of the cylinder = 6.0665 m³
we know that; 1 m³ = 264.172 gal
so; Volume of the cylinder = 6.0665 × 264.172 gal
Volume of the cylinder = 1602.6 gallons
Therefore, A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo
A cable raises a mass of 120.0 kg with a constant speed. What
force of tension is in the cable
NEW
1
The mass is rising with a constant speed.
=> So it has no vertical acceleration.
=> So there is no net vertical force acting on it.
=> So the sum of the vertical forces on it is zero.
There are two vertical forces acting on the mass.
=> the force of gravity, pulling it down
=> the tension in the cable, pulling it up.
The force of gravity acting on the mass (its weight) is (mass) x (gravity).
=> That's (120 kg) x (9.8 m/s²) downward.
=> That's 1,176 newtons downward.
If the vertical forces add up to zero, the other force ... the tension in the cable ... must be the same magnitude in the opposite direction.
=> The force of tension in the cable is 1,176 newtons upward.
An electrically charged point particle with a mass of 1.41 x 10-6 kg is launched horizontally into a uniform electric field with a magnitude of 686 N/C. The particle's initial velocity is 5.39 m/s, directed eastward, and the external electric field is also directed eastward. A short time after being launched, the particle is 9.89 x 10-3 m below and 0.151 m east of its initial position. Determine the net charge carried by the particle, including the algebraic sign ( or -).
Answer:
the net charge carried by the particle is -2.35 × 10⁻⁷ C
Explanation:
Given that;
mass m = 1.41 × 10⁻⁶ kg
Magnitude E = 686 N/C
v = 5.93 m/s
A short time after being launched, the particle is 9.89 x 10-3 m below and 0.151 m east of its initial position
consider vertical;
u =0, y = 9.89 × 10⁻³ m, g = a = 9.8 m/s²
Now, from the second equation of motion;
s = ut + 1/2 × at²
so, y = ut + 1/2 × at²
we substitute
9.89 × 10⁻³ = 0×t + (1/2 × 9.8 × t²)
9.89 × 10⁻³ = 4.9t²
t² = 9.89 × 10⁻³ / 4.9
t² = 0.0201836
t = √0.00201836
t = 0.0449 s
Consider horizontal;
u = 5.93 m/s, a = (qE/m) m/s, t = 0.0449 s, x = 0.151 m
also, from the second equation of motion;
s = ut + 1/2 × at²
so
x = ut + 1/2 × (qE/m) × t²
we substitute
0.151 = (5.93 × 0.0449) + (1/2 × ((q×686)/1.41 × 10⁻⁶) × (0.0449 )²
0.151 = 0.266257 + 0.69149143q / 1.41 × 10⁻⁶
0.151 - 0.266257 = 0.69149143q / 1.41 × 10⁻⁶
-0.115257 = 0.69149143q / 1.41 × 10⁻⁶
-0.115257 × 1.41 × 10⁻⁶ = 0.69149143q
0.69149143q = -1.6251237 × 10⁻⁷
q = -1.6251237 × 10⁻⁷ / 0.69149143
q = -2.35 × 10⁻⁷ C
Therefore, the net charge carried by the particle is -2.35 × 10⁻⁷ C
A 800-w iron is left on the ironing board with the base exposed to the air. About 85 percent of the heat generated by iron dissipate through its base with surface area of 0.15 ft2 . Calculate the amount of heat the iron dissipates in 2 hours, the heat flux on the surface of iron and total cost of electricity wasted in 2 hours if unit cost of electricity to be $0.11kwh.
Answer:
ΔQ = 4896 KJ
Heat Flux = 57407.55 W/m²
Cost = $ 0.176
Explanation:
The amount of heat dissipated in two hours can be given as:
[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]
where,
P = Power of Iron = 800 W
t = time taken = 2 hrs
η = Conversion efficiency = 85% = 0.85
[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]
ΔQ = 4896 KJ
Now, for heat flux:
[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]
Heat Flux = 57407.55 W/m²
Now, for total heat energy in KWhr in two hours:
[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]
Now, for the cost:
[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]
Cost = $ 0.176
A 0.85 N force exists between a 7.1 * 10 ^ - 6 * C charge 5.4 m away. What is the magnitude of the second charge ? Please show work
Answer:
Explanation:
Force between charge is given by the following expression
F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .
Putting the given values ,
.85 = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²
Q₂ = .85 x 5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )
= .38788 x 10⁻³ C .
= 387.88 x 10⁻⁶ C .
g Light is a traveling wave! The oscillations are oscillations of electric fields. The electric fields oscillate in the y-direction while the light travels in the x direction, so we can create a wave equation Ey(x,t); Ey is the y-component of the electric field, x is position in meters, and t is time in seconds. Consider light with a wave length of 550 nanometers, a wave speed of 3.00 x 108 m/s , and an amplitude of 10 V/m (volts/meters). Construct the traveling wave equation for this light if at t = 0 seconds, the light is at its maximum positive value and is traveling in the negative x-direction. Your equation, Ey(x,t) , should only have the variables x and t (i.e. calculate the values of the relevant traveling wave quantities to three sig figures and use those in the equation you are constructing, do not use the symbols in your final answer).
Answer:
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Explanation:
The general equation of a traveling wave on the x-axis is
[tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)
the amplitude of the wave is E₀ = 10 V / m
the wave number is
k = 2π /λ
indicate the value of λ = 550 nm = 550 10⁻⁹ m
we substitute
k = 2π / 550 10⁻⁹
k = 1.15 10⁻¹¹ m⁻¹
angular velocity is related to frequency
w = 2πf
the speed of light is related to the wavelength and frequency
c = λ f
f = c /λ
we substitute
w = [tex]2\pi \frac{c}\lambda }[/tex]
w = 2π 3 10⁸/550 10⁻⁹
w = 3.427 10¹⁵ rad / s
we substitute in the electric field equation
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth
Ey (0,0) = 10
which corresponds to its maximum positive value, therefore this is the expression of the traveling wave
pls help i’ll give brainliest
Explanation:
option A is the correct answer of this question .
plz mark my answer as brainlist if you find it useful.☺️
Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance ddd is
|F|=K|QQ′|d2|F|=K|QQ′|d2,
where K=14πϵ0K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q1q1q_1 = -11.5 nCnC , is located at x1x1x_1 = -1.675 mm ; the second charge, q2q2q_2 = 40.0 nCnC , is at the origin (x=0.0000)(x=0.0000).
What is the force exerted by these two charges on a third charge q3q3q_3 = 48.0 nCnC placed between q1q1q_1 and q2q2q_2 at x3x3x_3 = -1.215 mm ?
Your answer may be positive or negative, depending on the direction of the force.
Express your answer numerically in newtons to three significant figures.
Answer:
F_total = -65.5 N
Explanation:
Coulomb's law is
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2
In this exercise the force on the charge q3 is asked, for this we use that the force is a vector
F_total = F₁₃ + F₂₃
let's look for every force
F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]
it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m
the distance is
r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]
r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]
r₁₃ = 1.175 10⁻³ m
we calculate
F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]
F₁₃ = 3.598 N
as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right
we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0
F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]
r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]
r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103
r₂₃ = 0.5 10⁻³ m
F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]
F₂₃ = 6.912 10¹ N
F₂₃ = 69.12 N
as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left
the total force is
F = total = 3.598 - 69.12
F_total = -65.5 N
the negative sign indicates that the force is to the left
HELP URGENT WILL GIVE BRAINLIEST
Bearing in mind that a sound reflects off an object if the object is larger than the wavelength of the sound, calculate the wavelength of a sound in the air for a sound in the middle of the human hearing range. Then calculate the wavelength for a sound in the middle of the bat hearing range. If you had to use echolocation to detect an insect, which sound has an advantage
Answer:
mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters
Explanation:
The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz
let's use the relationship between wave speed, wavelength and frequency
v = λ f
λ= v / f
λ = 343/10000
λ = 3.43 10⁻² m
the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range
f = (100 10³ + 25 10³) / 2
f = 62.5 10³ Hz
λ = 343 / 62.5 10³
λ = 5.5 10⁻³ m
Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.
The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters
Compounds Boiling point °C Elemental composition Type of compound H20 100.0 all nonmetals covalent CS2 46.3 all nonmetals covalent CH4 -161.5 all nonmetals covalent HCI -85.1 all nonmetals covalent NaCl 1413.0 a metal and a nonmetal ionic KCI 1420.0 a metal and a nonmetal ionic If the teacher asks about a different covalent compound, what can the student predict about its properties? Select all that apply. A. It consists of all metals. B. It has a high boiling point. C. It has a low boiling point. D. It consists of all nonmetals.
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Which of the models most accurately represents the structure of DNA?
A
B.
G
Answer:
It's A.
Explanation:
DNA is a double helix.
Model which accurately displays structure of DNA is model A as DNA is a double helical structure.
What is DNA?
DNA is a hereditary material which is present in human beings as well as all other living organisms. Every cell which is present in an organism's body has DNA which is the same. Most of the DNA is situated in the cell's nucleus and small amount of it can be found in the cell's mitochondria as well.
Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.
DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule and a phosphate group. A base, phosphate sugar are together called as nucleotides.
Learn more about DNA,here:
https://brainly.com/question/13552018
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what did classical physics predict would happen to the light given of by an object as its tempurtare increased
Answer:
The energy of the light would increase from visible light into the ultraviolet range.
Explanation:
blah blah blah, blah blah BLAH
Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of 4.6 m/s. Neil is in front of her. With respect to the ground, Neil is skating due west at a speed of 4.4 m/s. Find Neil's velocity (a) magnitude and (b) direction relative to due west, as seen by Barbara.
Answer:
a) the magnitude is 6.37 m/s
b) the direction relative to due west, as seen by Barbara is 46.37° north of west
Explanation:
Given the data in the question;
Barbara is skating due south at a speed of 4.6 m/s
Neil is skating due west at a speed of 4.4 m/s
so
[tex]u_{B}[/tex]→ = 4.6 (-j^)
[tex]u_{N}[/tex]→ = 4.4 (-i^)
[tex]u_{NB}[/tex]→ = [tex]u_{N}[/tex]→ - [tex]u_{B}[/tex]→ = 4.4 (-i^) - 4.6 (-j^)
= -4.4i^ + 4.6j^
a) magnitude
magnitude |([tex]u_{NB}[/tex]→ )| = √( (-4.4)² + (4.6)²)
= √( 19.36 + 21.16)
= √40.52
= 6.37 m/s
Therefore, the magnitude is 6.37 m/s
b) direction relative to due west, as seen by Barbara.
using SOH CAH TOA
tan = opp / adj
so direction will be;
∅ = tan⁻¹( 4.6 / -4.4)
∅ = tan⁻¹( - 1.0454545 )
∅ = - 46.37°
Therefore, the direction relative to due west, as seen by Barbara is 46.37° north of west
What is the period of a wave with a wavelength of 8 cm and a frequency of 0.5 hertz?
A. 2 seconds
B. 0.125 seconds
C.0.0625 seconds
D. 4 seconds . (I think it's D).
{ cmmt if you want to be added to a Physics B connections acay ig gc}
Answer:
It is 2 seconds.
The period of a wave will bed 2 second. Frequency is the inverse of the time period;Option A is correct.
What is frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
Frequency is given by the formula as,
[tex]\rm f = \frac{1}{t} \\\\ t= \frac{1}{f} \\\\ t= \frac{1}{0.5} \\\\ t= 2\ second[/tex]
The period of a wave will be 2 second.
Hence, option A is correct.
To learn more about the frequency, refer to the link;
https://brainly.com/question/14926605
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The voltage across the diode indicates the energy given to charge carriers (electrons and holes, but more about that later in the course.) If the diode turns on at X volts, then the charge carriers are getting X electron-volts of energy. The charge carriers can give up this energy by emitting a photon. How does the energy the charge carriers get at the turn-on voltage compare to the energy of a red photon
Answer:
the charge carriers have an energy 2.8 10⁻¹⁹ J
Explanation:
The energy in a diode is conserved so the energy supplied must be equal to the energy emitted in the form of photons.
The energy of a photon is given by the Planck expression
E = h f
the speed of light, wavelength and frequency are related
c = λ f
we substitute
E = [tex]\frac{h \ c}{\lambda}[/tex]
a red photon has a wavelength of lam = 700 nm = 700 10⁻⁹ m
we calculate the energy
E = 6.626 10⁻³⁴ 3 10⁸/700 10⁻⁹
E = 2.8397 10⁻¹⁹J
therefore the charge carriers have an energy 2.8 10⁻¹⁹ J,
An objects motion changes
Answer:
uh finish the question please lol.
Please help ASAP! Will give brainliest! :)
Answer:
composition :))
Explanation:
Answer:
Both C and D are true, but it mainly depends on answer C, the composition of the star.
Explanation:
Hope This Helps!
A car travels the same distance at constant speed around two curves, one with twice the radius of curvature of the other. For which of these curves is the change in velocity of the car greater? Explain.
Answer:
The answer is below
Explanation:
Centripetal acceleration is the acceleration due to the movement of an object in a uniform circular motion. The acceleration is directed towards the center of the circle.
Centripetal acceleration is given by the formula:
a = v² / r; where v is the speed of the object and r is the radius of curvature (distance from object ot the center of circle).
Let us assume the car has a velocity of v m/s. For the curve with radius of curvature r:
a₁ = v² / r
For the curve with radius of curvature r = 2r:
a₂ = v² / 2r = (1/2)a₁
Therefore the centripetal acceleration is greater in the curve with radius pf curvature r and smaller in the curve with twice the radius of curvature of the other.
The above stress can be approximated by a sinusoidal function (ie, sine wave) with an average 2,388 kPa, amplitude 293 kPa, and a frequency of 6 Hz. At a second flight condition, the stress had an additional sinusoidal component (ie, in addition to the first sine wave above) that has three times the above frequency, half of the magnitudes, and 90 degrees out of phase (leading). Determine the amplitude of the second sinusoidal component in kPa. Provide the answer using 2 decir placed.
Answer:
327.58 kPa
Explanation:
Given data; 1st wave
Amplitude ( A1 ) = 293 Kpa
frequency = 6Hz
Average stress = 2388kPa
phase angle = 90° ( leading )
Determine the amplitude of the second sinusoidal component in kPa
Amplitude of additional wave ( A2 ) = 293 / 2 = 146.5 kPa
Amplitude of first wave ( A 1 ) = 293 kPa
hence the amplitude of the second sinusoidal component
A' = [tex]\sqrt{} A^{2} _{1} } + A^2_{2} + 2A_{1} A_{2} *cos 90[/tex]
= [tex]\sqrt293^2 + 146.5^2 + 2(293*146.5) *( -0.45)[/tex]
= [tex]\sqrt{85849+ 21462.25}[/tex]
= 327.58 kPa
Czocharalski process
Answer:
The Czochralski method, also Czochralski technique or Czochralski process, is a method of crystal growth used to obtain single crystals of semiconductors, metals, salts and synthetic gemstones
Explanation:
hope it helps:)
What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?
Answer:
Mechanical advantage = 4
Explanation:
Given the following data;
Distance of effort, de = 8m
Distance of ramp, dr = 2m
To find the mechanical advantage;
Mechanical advantage = de/dr
Substituting into the equation, we have;
Mechanical advantage = 8/2
Mechanical advantage = 4
A team of scientists is researching the best way to use tides to produce energy. One team includes environmental
scientists.
Which other branch of Earth science would these scientists most likely represent?
-geology
-astronomy
-meteorology
-oceanography
Answer:
agree with above answer
Why are rocks made of limestone usually an indication that an area was previously covered by ocean water
Answer:
what's the question? I don't understand
Answer:
Limestone can from form shell fragments of sea creatures
Explanation:
Two forces, one four times as large as the other, pull in the same direction on a 10kg mass and impart to it an acceleration of 2.5 m/s2. If the smaller force is removed, what is the acceleration of the mass?
Answer:
2 m/s²
Explanation:
Given,
Mass of the block = 10 Kg
Acceleration = 2.5 m/s²
Let the smaller force = F
Bigger force = 4 F
Now,
F + 4F = m a
5F = 10 x 2.5
F = 5 N
If smaller mass is removed acceleration = ?
4F = m a
4 x 5 = 10 x a
[tex]a=\frac{20}{10}[/tex]
a = 2 m/s²
Acceleration of the mass is equal to 2 m/s².
1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of the electric force? The constant k = 9 x 109 N-m2/C2
Solution:
Answer:
F = 36 N
Explanation:
Given that,
Charge, q₁ = +8 μC
Charge, q₂ = -5 μC
The distance between the charges, r = 10 cm = 0.1 m
We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]
So, the magnitude of the electrostatic force is 36 N.
True or False
A curved line indicates a constant velocity
Answer:
false this is correct answer of this question