If a wave has a wavelength of 10 m and a speed of 2.5×108 m/s (this is 250000000 m/s) what is the frequency of the wave?

Answer:

The answer is A ) High pressure

I hope this helps you :)

please let me know if I am wrong

Answer:

the answer is a C a newton

Explanation:

sinces : Momentum = velocity × mass

then : 30 = 10 × m and m = 30 ÷ 10 = 3 kg

Answer: A device records the time it takes sound waves to travel from the surface to the ocean floor and back again. Sound waves travel through water at a known speed. Once scientists know the travel time of the wave, they can calculate the distance to the ocean floor.

Explanation:

Answer:

a) F = 5.14 10⁻⁸ Hz,  f = 4.76 10-8 Hz,  b)   v = 2.29 m / s,   f = 42.5 Hz

Explanation:

a)This problem has two parts.

For the calculations relative to the planet Venus, we use that the period and the frequency are related

            f = 1 / T

frequency of the orbit around the Sun

Let's reduce the period to the SI system

           T = 225 days (24h / 1days) (3600 s / 1h) = 1.94 10⁷ s

           F = 1 / 1.94 10⁷

           F = 5.14 10⁻⁸ Hz

rotation frequency

            T = 243 d = 2.1 107 s

             f = 1 / T

             f = 1 / 2.1 107

            f = 4.76 10-8 Hz

b) give the data of some marine waves

the speed of the wave can be found with kinematics

            v = x / t

            v = 50.0 / 21.8

            v = 2.29 m / s

If the wavelength is L = 9.28m

this distance is the distance between two consecutive ridges or valleys

             λ / 2 = L

             λ = 2L

             λ = 2 9.28

             λ = 18.56 m

the speed of the wave is

             v = λ f

             f = v /λ

             f = 2.29 / 18.56

             f = 42.5 Hz

I think the answer for the following question is A.

okay this is kinda easy

What is the gravitational field strength on the moon?

The Moon has a gravitational field strength of 1.6 N/kg.

Answer: It is trusted that the sum of all forces acting on the student, adds up to zero the student is not moving.

Explanation: the plane they give you that the plane is moving at a constant velocity of 250 m/s this means that the acceleration is zero, we substituted in the formula F=ma which will give us the Force. And knowing that its constant speed, forward force is then equal to the Air resistance. Hence we find the Air resistance force

Answer:

1. conduction

2. convection

3. radiation

4. conduction

5. convection

6. radiation

7. conduction

8. conduction

9. radiation

10. convection

11. radiation

12. conduction

13. convection

Answer:

Density = 3 kg/m³

Explanation:

Given the following data;

Volume = 3m³

Mass = 9 kg

To find the density;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

[tex]Density = \frac{mass}{volume}[/tex]

Substituting into the formula, we have;

[tex]Density = \frac{9}{3}[/tex]

Density = 3 kg/m³

Answer:

A and C are correct.

Answer:

θ = 17.67°

Explanation:

The grating equation can be used here to find the angle. The grating equation is given as follows:

[tex]m\lambda = dSin\ \theta[/tex]

where,

m = order = 2

d = 3.88 x 10⁻⁶ m

λ = wavelength of light = 589 nm = 5.89 x 10⁻⁷ m

θ = angle = ?

Therefore, using these values in the equation, we get:

[tex](2)(5.89\ x\ 10^{-7}\ m) = (3.88\ x\ 10^{-6}\ m)Sin\theta \\Sin\theta = \frac{(2)(5.89\ x\ 10^{-7}\ m)}{(3.88\ x\ 10^{-6}\ m)}\\\\\theta = Sin^{-1}(0.3036)[/tex]

θ = 17.67°

Answer:17.67

Explanation:

Answer:1.) 2 seconds

2.) 4.5 hertz

3.) it will become one third is original value

4.)5.9 seconds

5.)0.87 meters

Explanation:

1. The time period of wave is 0.125 second

2. The frequency of a wave in the second rope is 1.5 hertz.

3. The frequency will become one third of its original value.

4. the time taken by sound of a clap of thunder to travel 2 kilometers is 5.9 seconds.

5. The wavelength of note is 0.87 meter

1. Time period [tex]=\frac{1}{frequency} =\frac{1}{8} =0.125second[/tex]

2. Since both rope are identical. Therefore, both rope have same frequency.

Thus,  The frequency of a wave in the second rope is 1.5 hertz.

3. In relation between wavelength and frequency, wavelength is inversely proportional to frequency.

If the wavelength of a wave in a particular medium is tripled , then the frequency of the wave will become one third of its original value.

4. The time taken by sound of a clap of thunder,

                                    [tex]=\frac{2000}{340}=5.9seconds[/tex]

5. Wavelength is the ratio of speed to the frequency.

                      [tex]Wavelength=\frac{340}{392}=0.87meters[/tex]

Learn more:

https://brainly.com/question/17264163

Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

To learn more about momentum from here, refer to the link;

brainly.com/question/17662202

#SPJ2

Gravitational force increases as the mass increases and decreases as the distance between the bodies is increased.

Reasons:

The given parameters are;

The moons of the planet = Moon A and Moon B

Mass of Moon A = 2·M

Mass of moon B = M

The distance between Moon B and the planet = 2 × The distance between Moon A and the planet

Required:

Comparison (compare) of the force exerted from the planet on Moon A and Moon B.

Solution:

The force, F, exerted from the planet is the gravitational force which is given by Newton's Law of Gravitation as follows;

Where;

G = Universal gravitational constant

[tex]M_{planet}[/tex] = Mass of the planet

M = Mass of the Moon

R = The distance from the planet to the Moon

For Moon A, we have;

Mass = 2·M

Distance = R

Which gives;

[tex]\displaystyle F_A = G \cdot \frac{M_{planet} \times 2\cdot M}{R^2} = 2\cdotG \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{2 \cdot F}[/tex]

With Moon B, we have;

Mass = M

Distance = 2·R

Therefore;

[tex]\displaystyle F_B = G \cdot \frac{M_{planet} \times M}{(2 \cdot R)^2} = G \cdot \frac{M_{planet} \times M}{4 \cdot R^2} = \frac{1}{4} \cdot G \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{\frac{1}{4} \cdot F}[/tex]

Which gives;

[tex]\displaystyle \frac{F_A}{F_B} = \frac{2 \cdot F}{\frac{1}{4} \cdot F } =2 \times \frac{4}{1} = \mathbf{8}[/tex]

[tex]\displaystyle \frac{F_A}{F_B} = 8[/tex]

[tex]F_A = \mathbf{8 \times F_B}[/tex]

The force from the planet on Moon A, [tex]F_A[/tex], is 8 times the force from the planet on Moon B.

Therefore, whereby option B is;

The correct option is option B

Learn more about Newton's Law of gravitation here:

https://brainly.com/question/18670622

Answer:

dont have the answer but you cute

Explanation:

Answer:

In an year about 6 major hurricanes and 3 minor storms occurs.

Explanation:

Answer:

A: Place the ball in the plastic bag, and twist the top so the ball is secure in the bag. Wrap the twisted portion with tape so it stays tight. Use the hole punch or scissors to poke a hole in the part of the bag that’s above the ball. Slip an end of the string through the hole, and tie a knot. This is your pendulum. Hold the loose end of the string still with one hand. With the other hand, raise the ball in an arc so that it’s almost level with the hand holding the string. With the string taut, let the ball go. What do you observe?

Mine was swaying perfectly fine. after a little bit it gradually started swinging slower until stopped.

B: Why did the pendulum stop swinging? Where did the energy go?

gravity was pulling it towards the ground, however the weight and momentum of the ball helped it keep swinging for a good while.

C: Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic [THE ENERGY OF MOTION IN A BODY] energy is the energy of motion, and potential energy [THE STORED ENERGY IN AN OBJECT] is stored energy. At the top of its swing, does the pendulum have kinetic or potential energy?

when its at the very top of the swing it does have a very small amount of time until it starts going back down again but during that time it is potential energy

D: At the bottom of its swing, does the pendulum have kinetic or potential energy?

the pendulum still has kinetic energy when it is the closest to the ground since it is still swinging

E: Think about the process of raising the pendulum to one side and letting it go. For this event, create a list of each form of energy associated with the pendulum as it cycles.

when its in my hand: potential energy

when it starts swinging: kinetic energy

when its going upwards: kinetic energy

when it stops swinging: potential energy

F: How could you give the pendulum more energy?

one way you could possibly make it have more energy is if you make the string longer

G: Now raise the pendulum and let it hit a metal lid or pan. When the ball strikes the lid, what forms of energy can you identify?

I could hear sound energy when the two made contact but for the most part it was kinetic energy

Answer:

I could hear sound energy when the two made contact but for the most part it was kinetic energy

Explanation:

Answer:

Hope this helps if not so sorry ;-;

Explanation:

Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F *

Note:

Have a nice day :)

The linear velocity is changing and the angular velocity is Constant best describes the passenger’s linear and angular velocity while passing a point.

The rate of change of angular displacement is defined as angular speed, and it is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular velocity

The linear velocity is given as the product of angular velocity and radius.

v=ωr

In the circular motion, the linear velocity is changing. Because the radius is changing.While the angular velocity is constant.Because it is an independent quantity.

Hence the Linear velocity is changing and the angular velocity is Constant best describing the passenger’s linear and angular velocity while passing a point.

To learn more about the angular velocity refer to the link;

https://brainly.com/question/13649539

Explanation:

the pressure is given by P=hpg

where h is height,p is density, g is 10m/s²

thus P= 0.05m•13.6x10³•10

P=6.8x10³ Hgmm

Answer:

Chemical energy is energy stored in the bonds of atoms and molecules. ...

Mechanical energy is energy stored in objects by tension. ...

Nuclear energy is energy stored in the nucleus of an atom—the energy that holds the nucleus together. ...

Gravitational energy is energy stored in an object's height.

Answer:

Nuclear power

Electricity

Mechanic

Gravity

Explanation:

Oxygen has an atomic number 8, because it has 8 protons and 8 electrons.

The first shell of an atom can hold up to 2 electrons but oxygen has 8 electrons, in that eight electrons 2 are in the first shell, so it has 6 more electrons left. The second shell can hold up to 8 electrons, oxygen has only 6 more electrons after the first shell is full, so it will have 6 electrons in the second shell

From this we know that oxygen has 2 shells so it is in period 2, and by counting from left to right, the sixth box in period 2 lies on group 16

Therefore Oxygen lies on group 16 and period 2

Happy to help :)

If you need my help for any other question, feel free to ask

Answer:

Blood circulation

Explanation:

The process being described is the circulation of blood.

Oxygen-rich blood leaves the heart through arteries and is transported to various cells and tissues where the exchange of oxygen for carbon dioxide takes place. Thereafter, the oxygen-deficient/carbon dioxide-rich blood moves into the veins and returns to the right side of the heart before traveling to the lung. In the lung, the carbon dioxide in the blood is exchanged for oxygen before the blood enters the left side of the heart and circulated all over again.

Answer:

An electric current into a magnetic field

Explanation:

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