if a given sample of metal has a mass of 2.68 g and a volume of 1.03 cm3, what is its density?

Answers

Answer 1

Answer: If a given sample of metal has a mass of 2.68 g and a volume of 1.03 cm³, the density of the metal will be 2.6019417476 g/cm³.

Explanation:

To find out the density of any object we must have known values of mass of the object and volume of the object.

Mass- Mass is the amount of matter present in any object or particle. The S.I. unit of mass is the kilogram.

Volume- Volume is defined as the amount of space occupied by an object or particle. The measuring unit of volume is cubic meter (m³)- for larger volumes and cubic centimeters (ccm³) and cubic millimeters (cmm³) for smaller volumes.

Density- Density is the measurement that compares the mass of an object with its volume. The S.I. unit of density is kilogram per cubic meter (kg /m³) and the C.G.S unit is gram per cubic centimeter ( g/ ccm³). Density is denoted by rho (ρ).

The density of an object can be calculated by the following formula:

Density (ρ) = mass (m)/ volume (v)

In the given question, the mass of the object is 2.68 g. i.e. m = 2.68 g and the volume of the given sample is 1.03 cm³ i.e. v = 1.03 cm³.

Hence, by using the above formula and putting the values of mass and volume, we can calculate the density of the sample as below-

Density = mass (m)/ volume (v)

= 2.68 / 1.03

= 2.6019417476 g/cm³

Therefore, for the given sample of metal that has a mass of 2.68 g and volume of 1.03 cm³ will have a density of 2.6019417476 g/cm³.

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Related Questions

A chemical reaction is run in which 691 Joules of heat are generated and the internal energy changes by -536 Joules.

Calculate w for the system.
w =
Joules

Answers

The work done for the system, given that the internal energy changes by -536 Joules, is 1227 joules

How do i determine the work done for the system?

From the question given above, the following data were obtained:

Heat generated (q) = 691 JoulesChange in internal energy (ΔU) = -536 JoulesWork done (W) = ?

The work done for the system can be obtained as illustrated below:

ΔU = q - w

Inputting the given parameters, we have:

-536 = 691 - w

Collect like terms

-536 - 691 = -w

-1227 = -w

Multiply through by -1

w = 1227 joules

Thus, we can conclude that the work done for the system is 1227 joules

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What is percent abundance of 18 medium nails 5 cm long?

Answers

From the attached image, the percentage abundance of 18 medium nails 5 cm long is 19%

Understanding Percentage Abundance

The percent abundance refers to the proportion or percentage of a certain type or category within a given sample or population.

In the case of 18 medium nails that are 5 cm long, we have the information presented in the table and we do not need to do any mathematical calculations.

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Which of the following statements is true?
A.
Chemical reactions can either absorb thermal energy or release thermal energy.
B.
Chemical reactions can only release thermal energy.
C.
Chemical reactions can only absorb thermal energy.
D.
Chemical reactions can neither absorb thermal energy nor release thermal energy.

Answers

The answer is A, as all chemicals reactions exchange energy with the surroundings by releasing Or absorbing heat

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