Answer:
326 kg
Explanation:
m=f/a
3000/9.2=326 kg
Caroline uses 20 N of force to move a box of books 10 m. How much work
did she do?
Work = (force) x (distance)
Work = (20 N) x (10 m)
Work = 200 Joules
PLEASE HELP—ITS PHYSICS AND I NEED ANSWERS ASAP
If a motor is rated at 5.6KW, work done in 20minutes is equal to:
Answer:
given Power= 5.6×1000=5600watt
t=20min=20×60=1200sec. work done=?
P=w/t
w=pt=5600×1200=672×10^4Joule
The amount of work done by the motor is equal to 6.72 Megajoules.
Given the following data:
Time = 20 minutesPower = 5.6 Kilowatt = 5600 Watts.Conversion:
1 minute = 60 seconds20 minutes = [tex]20 \times 60 = 1200[/tex] seconds.To determine the amount of work done by the motor:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = power \times time[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = 5600 \times 1200[/tex]
Work done = 6,720,000 Joules
Note: 1,000,000 Joules = 1 Megajoules.
Work done = 6.72 Megajoules.
Read more on work done here: https://brainly.com/question/13818347
Convection currents will transfer heat throughout a gas until what condition arises?
A.
The gas condenses and forms a liquid.
B.
The gas particles stop moving entirely.
C.
The gas has the same temperature throughout.
D.
The gas has no thermal energy in it.
Answer:
C
Explanation:
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The gas has the same temperature throughout. (C)
PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?
Answer:
acceleration due to gravity: -9.8 m/s^2
Fg=mass of object*(-9.8)
Explanation:
This is a pretty vague question, but I'll answer as best I can.
All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as
Force of gravity=(Gravitational constant*mass of object 1*mass of object 2)/distance between objects squared
Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)
How many joules of heat energy are needed to raise the temperature of 10.0 g (0.0100 kg) of aluminum from 22 K to 55 K, if the specific heat of aluminum is 897 J/kg * K. Explain your answer
Answer:
296.01 J
Explanation:
From the question,
Q = cm(t₂-t₁)....................... Equation 1
Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature
Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k
Substitute these values into equation 1
Q = 897×0.01×(55-22)
Q = 897×0.01×33
Q = 296.01 J
Hence 296.01 Joules of heat is required.
A player prefers to make high passes that lift the puck above the ice. Which stick should the
player choose?
Answer:
i dont know
Explanation:
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