If a drop of red dye is placed in the middle of a shallow dish of water, the dye will diffuse slowly and a red cloud of dye will grow larger with time.

a. True
b. False

Answer:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

Explanation:

This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.

When the equation is balanced, and the coefficient of H₂O is 3.

To balance the chemical equation:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + H₂O

The number of atoms of each element is the same on both sides of the equation.

Balance the hydrogen atoms. There are three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance the hydrogen atoms, multiply H₂O by a coefficient of 3:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + 3H₂O

If the oxygen (O) atoms are balanced. There are four oxygen atoms on the right side, but only two oxygen atoms on the left side. To balance the oxygen atoms, we need to multiply NaOH by a coefficient of 2.

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Answer:

3.84 J/g°C

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance

c = specific heat of copper

∆T = change in temperature (°C).

Based on the provided information;

Q = 43783J

m = 24g

∆T = 500°C - 25°C = 475°C

c = ?

Using Q = m × c × ∆T

43783 = 24 × c × 475

43783 = 11400c

c = 43783 ÷ 11400

c = 3.84 J/g°C

Answer:

josephmelichar

Explanation:

In the first step, 2 protons combine. In doing so one of the protons will convert into a neutron by losing a positron (positive electron) and a neutrino; this is also known as beta decay. This changes one of the protons (positive charge) into a neutron (neutral charge) and allows the two particles to combine.

Answer:

The answer is "Option 2".

Explanation:

Answer:

A

Explanation:

Hydrogen isn't an alkali metal

Answer:

hydrogen

Explanation:

hydrogen is a gas not a metal

Answer:

A budget is an estimation of revenue and expenses over a specified future period of time and is usually compiled and re-evaluated on a periodic basis. Budgets can be made for a person, a group of people, a business, a government, or just about anything else that makes and spends money.

Answer:

Explanation:

The boiling point will increase due to dissolution of sugar in water . Increase in boiling point ΔT

ΔT = Kb x m , where Kb is molal elevation constant water , m is molality of solution

Kb for water = .51°C /m

moles of sugar = 16.90 / 342.3

= .04937 moles

m = moles of sugar /  kg of water

= .04937 / .04090

= 1.207

ΔT = Kb x m

= .51 x 1.207

= .62°C .

So , boiling point of water = 100.62°C .

Answer:

200.0lg

Explanation:

please give a brainliest

Answer:

1) 1.5 kg

2) 0.6 kg

Explanation:

[tex](3)(30) = 60m, m = 90/60 = 1.5[/tex] kg

[tex](0.8)(15) = 20m, m = 12/20 = 0.6[/tex] kg

Answer:

C

Explanation:

1atm=760torr

X=250torr

Cross multiply

760torrX=250torr*atm

Divide both sides by 760torr

X=250torr*atm/760torr

X=0.32895atm

X=0.329atm

Option C is collect

Answer:

Explanation:

The density is  

1.1 g c m 3 .

Answer:

1.9 L

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

Monounsaturated Fat 1g

Answer:

20 moles of Iron are needed

Explanation:

In 1 mole of Iron (III) oxide, Fe₂O₃, there are 2 moles of Iron, Fe. The equation that we can write is:

2 moles Fe = 1 mole Fe₂O₃

To find the moles of iron that are needed to produce 10 moles of Fe₂O₃ we must use this equation as follows:

10 moles of Fe₂O₃ * (2 moles Fe / 1mole Fe₂O₃) =

Answer:

0.60 moles of atoms of carbon

Explanation:

Step 1: Given data

Step 2: Calculate the number of carbon atoms in the given sample

According to the chemical formula of the compound, the molar ratio of C to O is 2:6, that is, there are 2 moles of atoms of C every 6 moles of atoms of O. The number of moles of atoms of C is:

1.8 mol O × 2 mol C / 6 mol O = 0.60 mol C

When Magnesium comes in contact with Oxygen, it reacts with Oxygen causing a layer of Magnesium Oxide on the metal. If Magnesium is burnt, it will cause a bright white light creating Magnesium Oxide.

The initial appearance of Magnesium is a ribbon with a layer of Magnesium Oxide.

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Answer:

See Explanation

Explanation:

We can write the molecular orbital configuration of molecules in the same way as we write the orbital electron configuration of atoms. The valence electrons in the molecule are filled into molecular orbitals of appropriate energy in accordance to the Aufbau principle.

For CO;

σ2s2, σ*2s2, Π2py2, Π2pz2, σ2px2

For NO;

σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2, Π*2px1

For CN-;

σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2

These are the ground state electron configurations of these molecules.

Answer:

Have 2 filled orbitals and 3 partially filled orbitals.

Explanation:

Hello there!

In this case, according to the given information of the electron configuration for that particle; it is possible for us to infer it has 5 valence electrons, as the electrons on its outermost shell (2). Moreover, we undertand this particle needs three bonds, does not have neither the electron configuration of a noble gas which ends by p⁶ nor that of an alkali earth metal as it ends by s².

Therefore, we infer the correct answer is Have 2 filled orbitals and 3 partially filled orbitals because according to the Hund's rule, the s orbital is fulfilled and the p orbital has 1 electron orbital fulfilled and two partially filled orbitals.

Regards!

Unnillium (101)

Unnilbium (102)

Unniltrium (103)

Unnilquadium (104)

Unnilpentium (105)

Unnilhexium (106)

Unnilseptium (107)

Unniloctium (108)

Unnilennium (109)

Ununnillium (110)

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

Answer:

Sample A

Explanation:

Molarity of a solution can be calculated using the formula:

Molarity = number of moles (mol) ÷ volume (vol)

For Sample A:

V = 300ml = 300/1000 = 0.3 L

Molarity = 1M

n = number of moles (mol)

1 = n/0.3

n = 0.3moles

For Sample B:

V = 145 mL = 145/1000 = 0.145L

Molarity = 1.5 M

n = number of moles

1.5 = n/0.145

n = 1.5 × 0.145

n = 0.22 moles

Based on the above results (moles), sample A with 0.3 moles contains the larger concentration of sodium chloride.

Answer:

B.Anything that takes up space and has mass

Answer: When exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

Explanation:

A degree of randomness in the molecules of a substance is called entropy.

When exhaust from car engines spreads throughout our atmosphere then it means the molecules are moving at a faster speed due to which they spread into the atmosphere rapidly.

This means that the entropy of exhaust is increasing.

Thus, we can conclude that when exhaust from car engines spreads throughout our atmosphere and adds to pollution then it is an example of increase in entropy.

An increase in entropy

Answer: The event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.

Explanation:

A process in which heat is evolved is called an exothermic process.

When hot metal plate at [tex]150^{o}C[/tex] is placed in air at room temperature then heat is given off by the metal plate due to which there will occur a decrease in kinetic energy of its molecules.

As a result, molecules in the metal will slow down.

Whereas heat is absorbed by the air molecules from the metal due to which kinetic energy of air molecules will increase.

Thus, we can conclude that the event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.

Answer:

its e

Explanation: