If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°C in an insulated beaker, what is the final temperature of the mixture, assuming that no heat is lost? (CetOH =2.42 J/G C)

If 45.0 ML Of Ethanol (density =0.789g/mol) Initially At 6.0C Mix With 45.0 ML Of Water (density =1.0

Answers

Answer 1

The final temperature of the mixture : 21.1° C  

Further explanation  

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Q in(gained) = Q out(lost)  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q ethanol=Q water

mass ethanol=

[tex]\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g[/tex]

mass water =

[tex]\tt mass=1~g/ml\times 45~ml=45~g[/tex]

then the heat transfer :

[tex]\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC[/tex]


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Answer:

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Some street lights use incandescent bulbs, and others use LEDS. Which would you recommend and why?​

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In a chemical reaction, [_____] are the substances present after the reaction.

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Answer:

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Explanation:

What must be known for the rate constant to be calculated from the rate law?

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C. The reaction rate at known reaction concentrations

Explanation:

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Explanation:

From the question given above, the following data were obtained:

Mass = 236.376 g

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Density can be defined as the mass of a substance per unit volume of the substance. It can be expressed mathematically as:

Density = mass /volume

With the above formula, we can obtain the density of the object as shown below:

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Volume = 81.5 cm³

Density =?

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Thus, the density of the object is 2.9 g/cm³

How can you increase the gravitational potential energy (GPE) of an empty shoe box on the middle shelf of a bookcase?

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Answer:

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Explanation:

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According to the theory of plate tectonics, where do activities such as earthquakes and volcanic eruptions occur?
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C
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Answer:

The correct answer is 70.41 kJ ≅ 70.4 kJ

Explanation:

The heat required to sublimate the solid at its sublimation temperature is calculated by using the following formula:

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Answer:

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Answer:

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Answer:

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General Formulas and Concepts:

Chemistry - Atomic Structure

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Explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

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This question is incomplete, the complete question is;

A 1.00 g sample of NH4NO3 is decomposedin a bomb calorimeter. The temperature increases by 6.12°C. What is the molar heat of decomposition for ammonium nitrate?

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the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol

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Answer:

69.09 g

Explanation:

First we calculate the mass of the sample of concentrated H₂SO₄, using the given volume and density:

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There are 70.288 grams of solution, of which 98.3% is H₂SO₄. Thus the H₂SO₄ mass is:

70.288 g * 98.3/100 = 69.09 g

Taking into account the definition of density and percentage by mass, the mass of H₂SO₄ in a 38.2 cm³ sample of concentrated sulfuric acid is 69.09 grams.

Definition of density

But first you must know the definition of density. Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

Mass of solution

In this case, you know that:

Density= 1.84 [tex]\frac{g}{cm^{3} }[/tex]

Volume= 38.2 cm³

Replacing in the definition of density:

[tex]1.84 \frac{g}{cm^{3} }=\frac{mass}{38.2 cm^{3} }[/tex]

Solving:

mass= 1.84 [tex]\frac{g}{cm^{3} }[/tex]×38.2 cm³

mass= 70.288 g

So, the mass of the solution is 70.288 grams.

Definition of percentage by mass

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

[tex]percentage by mass=\frac{mass of solute}{mass of solution}x100[/tex]

Mass of H₂SO₄

In this case, you know:

percentage by mass=98.3%

mass of solute= ?

mass of solution= 70.288 grams

Replacing in the definition of percentage by mass:

[tex]98.3=\frac{mass of solute}{70.288 grams}x100[/tex]

Solving:

[tex]\frac{98.3}{100} =\frac{mass of solute}{70.288 grams}[/tex]

[tex]0.983=\frac{mass of solute}{70.288 grams}[/tex]

0.983× 70.288 grams= mass of solute

69.09 grams= mass of solute

The mass of H₂SO₄ in a 38.2 cm³ sample of concentrated sulfuric acid is 69.09 grams.

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my brain hurts. halp​

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Answer:

the answer is C ( i hope your teacher explains

How do we write a formula for those combinations of atoms?

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Answer:

please follow me

Explanation:

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What is stoochiometry?

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Answer:

Stoochiometry is the quantitative relation between the number of moles ( and therefore mass ) of various products and reactants in a chemical reaction.

Explanation:

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A sample of gas occupies a volume of 571.5 mL at 0.944 atm and 10 oC. Determine the pressure of this sample at 1.183 L and 32 oC.

Answers

Answer:

0.491 atm

Explanation:

Initial volume V1 = 571.5 mL = 0.5715 L

Initial Pressure P1 = 0.944 atm

Initial Temperature T1 = 10 oC + 273 = 283 K (Converting to kelvin units)

Final Temperature T2 = 32 oC + 273 = 305K (Converting to kelvin units)

Final volume V2 = 1.183 L

Final Pressure P2 = ?

These parameters related by the combined gas law;

P1V1 / T1   = P2V2 / T2

Mke P2 subject of formular;

P2 = P1 V1 T2 / V2 T1

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What nuclide undergoes fission to form molybdenum-103, atomic number 42, tin-131, atomic number 50, and two neutrons?
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Answers

Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

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Answer:

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