If 238 J of heat is absorbed by a sample of metal with a mass of 40.7 g, and it raises the temperature from 20.0°C to
32.4°C, what is the specific heat capacity of the metal? (show your work)

Answer:

Empirical formula is CH

Explanation:

A hydrocarbon, CₐHₓ reacts with oxygen in the combustion reaction as follows:

CₐHₓ + O₂ → a CO₂ + x/2 H₂O

That means we can find the moles of C and H from the moles of CO2 and H2O. As empirical formula is defined as the simplest whole-number ratio of atoms in a molecule, we can determine it as follows:

Moles CO2 = Moles C -Molar mass: 44.01g/mol:

0.4225g * (1mol / 44.01g) = 0.0096 moles C

Moles H2O -Molar mass: 18.01g/mol:

0.0865g H2O * (1mol / 18.01g) = 0.0048moles H2O * (2mol H / 1mol H2O) =

0.0096 moles H

The ratio of atoms of C:H is:

0.0096moles C / 0.0096moles H = 1

That means empirical formula is CH

Answer:

ed

Explanation:

ed

Answer:

702000

Explanation:

(2 x 10^3) + (7 x 10^5)

=> 2 x 1000 + 7 x 100000

=> 2000 + 700000

=> 702000

Answer:

H3PO4 + 5 HCl → PCl5 + 4 H2O

Explanation:

The given equation is

H3PO4 + HCl = PCl5 + H2O

The above chemical equation has one P atom on both the sides, hence phosphorus is balanced

There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -

H3PO4 + 5HCl = PCl5 + H2O

Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become

H3PO4 + 5HCl = PCl5 + 4H2O

Let us check for oxygen

Oxygen on LHS = 4 and oxygen on RHS = 4

Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O

Answer:

the answer is c

Explanation:

i did the test

The enthalpy of the formation of water is -285.8 kJ/mol. The information that can be made by the statement is heat is released during the process. The correct option is C.

Enthalpy is the volume times the pressure times the internal energy of the system. It is an entity of thermodynamics. It is the measurement of the energy in a thermodynamic system. The enthalpy totals the internal energy plus pressure and volume.

The statement that is given here is given that enthalpy is -285.8 kJ/mol. The value is negative, so the energy is released here. When energy is gained the energy will be positive and when the energy is released it is negative.

Thus, the correct option is C, heat is released during the process regarding the given statement of enthalpy.

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Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.

Explanation:

The combustion equation of acetylene is as follows.

[tex]C_{2}H_{2} + \frac{5}{2}O_{2} \rightarrow 2CO_{2} + H_{2}O[/tex]

Formula to calculate enthalpy of formation for a reaction is as follows.

[tex]\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol[/tex]

Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.

Answer:

Explanation:

A) the NaI solution will have a higher boiling point than the KI solution

Answer:

false

Explanation:

cozz you'll need it inorder to find the correct mole ratio

Answer:

not B

Explanation:

my friend got it wrong

Answer:

Mole of the H2O = 4.5

Number of molecules =4.5 multipled by avogadro's number.

Answer:

Lower the temperature of the solution

Answer:

One movement that i can't do is float in mid air

Explanation:

Answer:

[tex]C_{alloy}=0.497\frac{J}{g\°C}[/tex]

Explanation:

Hello there!

In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:

[tex]Q_{allow}=-(Q_{water}+Q_{Al})[/tex]

Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:

[tex]m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})[/tex]

Then, we solve for specific heat of the metallic alloy to obtain:

[tex]C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}[/tex]

Thereby, we plug in the given data to obtain:

[tex]C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}[/tex]

Regards!

Answer:

The molar mass is 40.1+2×(14+3(16))=40.1+2×(62)=164.1g/mol.

Answer:

lol ok 1+1=2 2 x 2=4

have a good day :)

Explanation:

Answer:  oke

Explanation: have a goood day!

Answer:

Option B

Explanation:

The rate law is represented as

Rate of the reaction = [tex]k [A^x][B^y][/tex]

Here K is the rate constant

A is the concentration of substance A

B is the concentration of substance B

Hence, If  reactant A is in the rate law equation, then if its concentration varies then it will impact the rate of the reaction

Hence, option B is correct

Answer:

c I do believe good luck with the answer

Explanation:

He used just the right amount of matter in water to get it to evaporate at a normal temperature and to condense into clouds for rain.

To cause water evaporate at a regular temperature and condense in clouds for rain, God has employed precisely the proper amount of substance in the water.

Water is constantly circulated throughout the Earth-atmosphere system throughout the water cycle, also known as the hydrologic cycle. The five key stages of the water cycle—evaporation, transpiration, condensate, precipitation, and runoff—are the most crucial. Water is used by all of the processes in the cycle, but its distribution changes over time even while the overall amount of water is largely constant.

Water is converted from its liquid state to its gaseous, or smoke, state through evaporation. This transfer happens when some water molecules have accumulated enough kinetic energy to launch themselves off the water's surface. To cause water evaporate at a regular temperature and condense in clouds for rain, God has employed precisely the proper amount of substance in the water.

Therefore, to cause water evaporate at a regular temperature and condense in clouds for rain, God has employed precisely the proper amount of substance in the water.

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Answer:

Option D

Explanation:

The complete question is

Which statement is true concerning colloids?

A. It carries a net electric charge

B. It consists of one phase only

C. It can be made out of two gases

D. It is electrically neutral as a whole

Solution

The particles with in the colloids are either positively or negatively charged due to presence of molecular electrolyte. The charged particles do not cluster together due to repulsion force. However, these charged particles align along two different layers - one positive layer and the other negative layer.

The net charge reduces to zero because of two forces in equal amount due to presence of equal number of positive and negative charges

Hence, option D is correct

Answer: 0.45

Explanation:

Answer:

The hypothetical van't Hoff factor of magnesium nitrate,[tex]Mg(NO_3)_2[/tex] is 3 .

Explanation:

Lets calculate -

[tex]Mg(NO_3)_2\rightarrow Mg^2^+ +2NO_3^-[/tex]

We know that ,

[tex]i=\alpha n+(1-\alpha )[/tex]

Dissociation should be 100% for the hypothetical vant hoff factor , that is

[tex]\alpha =1[/tex] and [tex]n=3[/tex] for  [tex]Mg(NO_3)_2[/tex]

Therefore , putting the given values ,

[tex]i=1\times3+(1-1 )[/tex]

[tex]i=3+0[/tex]

[tex]i=3[/tex]

Hence , the answer is 3.

The hypothetical van't Hoff factor of magnesium nitrate is 3.

Van't Hoff factor is a measure of the deviation of a solution from ideal behavior. It depends on the number of particles in the solution. The more the particles in solution, the greater the Van't Hoff factor and the greater the deviation from ideal behavior.

For Mg(NO3)2, the hypothetical van't Hoff factor is 3 since there are three particles in solution when magnesium nitrate is dissolved in water.

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Answer:

0.01 M

Explanation:

As this problem deals with a dilution process, we can solve it by using the following formula:

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.

That means that in this case:

We input the given data:

Answer:

A precipitate is a solid that forms in a liquid when a chemical reaction takes place.

MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2

Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2

Explanation: