If 20.0 mLmL of a 0.100 NN acid solution is needed to reach the end point in titration of 32.5 mLmL of a base solution, what is the normality of the base solution

This Should Be Your Answer:

Step 1: Formation of ions

Step 2: Formation of ionic bonds

Step 3: Formation of cubes

Step 4: Formation of crystals

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Answer:

Black Cats?

Explanation:

Answer:

32.7 g of Zn

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl₂ + H₂

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂

Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂.

Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.

Thus, 0.5 mole of Zn is required.

Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:

Mole of Zn = 0.5 mole

Molar mass of Zn = 65.4 g/mol

Mass of Zn =?

Mass = mole × molar mass

Mass of Zn = 0.5 × 65.4

Mass of Zn = 32.7 g

Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.

Answer: Two compounds below that can be used to make a buffer solution are acetic acid and acetate ion.

Explanation:

A solution that helps in resisting change in pH when a small amount of acid or base is added to it is called a buffer solution.

A buffer solution consists of a mixture of weak acid and its conjugate base.

Acetic acid has a chemical formula [tex]CH_{3}COOH[/tex] and its conjugate base is [tex]CH_{3}COO^{-}[/tex].

This base is also called acetate ion.

Acetic acid is a weak acid because it dissociates weakly when added to a solvent like water.

Therefore, acetic acid and acetate ion will form a buffer solution.

Thus, we can conclude that two compounds below that can be used to make a buffer solution are acetic acid and acetate ion.

Answer:

sulphuric acid

nitric acid

carbolic acid

The ionic compounds contribute to climate change that is sulphuric acid, nitric acid and carbolic acid.

Ionic compounds were made up of ions kept together by the attraction of positive and negative ions. One of the most well-known ionic compounds is common salt (sodium chloride). Molecular compounds were made up of distinct molecules that also are kept together through electron sharing (covalent bonding).

Long-term variations in temperature but also weather systems are referred to as climate change.

Therefore, the ionic compounds contribute to climate change that is sulphuric acid, nitric acid and carbolic acid.

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Answer:

Potassium dicyanoargentate(I) | C2AgKN2 - PubChem.

Synonyms: Potassium dicyanoargentate(I)pota...

Molecular Formula: C2AgKN2

Explanation:

Answer:

Explanation:

Isomers are compounds with the same molecular formula but chemically distinctive structures. Compounds that vary in connectivity, or how the component atoms are related to one another, are known as constitutional isomers. They have distinct functional groups and bonding patterns according to the sequence in which the atoms are linked together.

From the information given:

The compound given is C₃H₆Br₂ and the constitutional isomer of the compound can be seen in the image attached below.

The formal charges are calculated as follows:

Formal charge = valence electron - 1/2(bonding electron) - lone electron

For Br:

Formal charge = 7 - 1/2(2) - 6

Formal charge = 7 - 1 - 6 = 0

For C:

Formal charge = 4 - 1/2(8) - 0

Formal charge = 4 - 4 = 0

For H:

Formal charge = 1 - 1/2(2)

Formal charge = 1 - 1 = 0

Answer: There are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.

Explanation:

Given: Molarity = 3.0 M

Mass of NaCl = 97.9 g

Molar mass of NaCl = 58.44 g/mol

As number of moles is the mass of substance divided by its molar mass.

So, moles of NaCl are calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{97.9 g}{58.44 g/mol}\\= 1.675 mol[/tex]

Molarity is the number of moles of a substance present in liter of a solution.

Therefore, volume of given solution is calculated as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\3.0 M = \frac{1.675 mol}{Volume}\\Volume = 0.558 L[/tex]

Thus, we can conclude that there are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.

Answer:

Hydrogen Bonds

Explanation:

Opposite charges attract one another. The slight positive charges on the hydrogen atoms in a water molecule attract the slight negative charges on the oxygen atoms of other water molecules. This tiny force of attraction is called a hydrogen bond.

Answer:

mass = moles x molar mass

m= 3.7 x (23x2+16)

m= 3.7x62

m= 229.4g

198.4 grams are there is 3.7 moles of Na₂O.

The number of moles is defined as the ratio between given mass and molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\[/tex]

Given:

Number of moles= 3.7 moles

To find:

Mass=?

Molar mass of Na₂O= 62 g/mol

Thus substituting the values in the given formula

[tex]\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}= 3.2 \text{moles}*62 \text{g/mol}\\\\\text{Given mass}=198.4 \text{g}[/tex]

Thus, 198.4 grams are there is 3.7 moles of Na₂O.

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Answer:

98

Explanation:

I dont even know

Which reactions are you referring to?

Can you add an image please?

or the reactions you are asking about?

Answer:

did not mean to type that sorry i'm pretty sure the answers are c and b.

Explanation:

Answer:

Question 9

Explanation:

An everyday chemical reaction is rusting and iron reacts with oxygen to form rust

Question 8

Chemical reactions do not include fusion and fission only nuclear reactions like radioactivity

Answer:

Number of mole of H₃PO₄ = 0.306 mole

Explanation:

From the question given above, the following data were obtained:

Mass of H₃PO₄ = 30 g

Number of mole of H₃PO₄ =?

Next, we shall determine the molar mass of H₃PO₄. This can be obtained as follow:

Molar mass of H₃PO₄ = (3×1) + 31 + (4×16)

= 3 + 31 + 64

= 98 g/mol

Finally, we shall determine the number of mole in 30 g of H₃PO₄ as follow:

Mass of H₃PO₄ = 30 g

Molar mass of H₃PO₄ = 98

Number of mole of H₃PO₄ =?

Mole = mass / molar mass

Number of mole of H₃PO₄ = 30 / 98

Number of mole of H₃PO₄ = 0.306 mole

Answer: A volume of 500 mL water is required to prepare 0.1 M [tex]H_{3}PO_{4}[/tex] from 100 ml of 0.5 M solution.

Explanation:

Given: [tex]M_{1}[/tex] = 0.1 M,    [tex]V_{1}[/tex] = ?

[tex]M_{2}[/tex] = 0.5 M,       [tex]V_{2}[/tex] = 100 mL

Formula used to calculate the volume of water is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL[/tex]

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M [tex]H_{3}PO_{4}[/tex] from 100 ml of 0.5 M solution.

Answer:

C₂O₂

Explanation:

Step 1: Given data

Step 2: Calculate the molar mass of the empirical formula

M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12 g/mol + 1 × 16 g/mol = 28 g/mol

Step 3: Calculate "n"

We will use the following expression.

n = molar mass of molecular formula / molar mass of empirical formula

n = (56 g/mol) / (28 g/mol) = 2

The molecular formula is:

CO × n = CO × 2 = C₂O₂

Answer:

The needed heat is 47,65 Joules.

The number of Joules of heat is required to change the 21.1g of liquid water into steam at 100°C is 47686 Joules.

The latent heat of vaporization is defined as the amount of heat needed at a constant temperature for the conversion of a liquid at its boiling point to gas. The latent heat of vaporization is different for different liquids.

The particles of water vapor at 100°C  have more energy than that of liquid water. Because the extra energy is in the form of latent heat of vaporization. The word “latent” from the Latin word “latere" means to cover up or hide.

Given, the amount of water, m= 21.1 g

We know that, the heat of vapourization of water = [tex]2260 J/g[/tex]

The latent heat of vaporization (q) is calculated as:

q = mH

q = (21.1 g) × (2260J/g)

q = 47686 J

Therefore, the 47686 Joules are required to boil 21.1 g of water at a temperature of 100°C.

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Answer: The volume of the new solution​ is 83.33 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 200 mL,    [tex]M_{1}[/tex] = 0.5 M

[tex]V_{2}[/tex] = ?,             [tex]M_{2}[/tex] = 1.2 M

Formula used to calculate the volume of new solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 200 mL = 1.2 M \times V_{2}\\V_{2} = 83.33 mL[/tex]

Thus, we can conclude that volume of the new solution​ is 83.33 mL.

Answer: The final concentration of aluminum cation is 0.335 M.

Explanation:

Given: [tex]V_{1}[/tex] = 47.8 mL (1 mL = 0.001 L) = 0.0478 L

[tex]M_{1}[/tex] = 0.321 M,       [tex]V_{2}[/tex] = 21.8 mL = 0.0218 L,      [tex]M_{2}[/tex] = 0.366 M

As concentration of a substance is the moles of solute divided by volume of solution.

Hence, concentration of aluminum cation is calculated as follows.

[tex][Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}[/tex]

Substitute the values into above formula as follows.

[tex][Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}\\= \frac{0.321 M \times 0.0478 L + 0.366 M \times 0.0218 L}{0.0478 L + 0.0218 L}\\= \frac{0.0153438 + 0.0079788}{0.0696}\\= 0.335 M[/tex]

Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.

Answer:

at age 15 the BMR begin to gradually decrease

Answer:

tungstun

Explanation:

Answer:

tungsten

Explanation:

strongest out of any natural metal (142,000 psi).

Explanation:

pls the question is not clear to me

Answer:

[tex]P_2=795mmHg[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the final pressure by using the Boyle's law as an inversely proportional relationship in pressure to volume at constant temperature:

[tex]\frac{P_2}{V_2} =\frac{P_1}{V_1}[/tex]

Thus, we solve for our target, P2, to obtain:

[tex]P_2=\frac{P_1V_2}{V_1} =\frac{770mmHg*603mL}{584mL}\\\\P_2=795mmHg[/tex]

Regards!

Answer:

2.7×10⁻³ mole

Explanation:

Applying

Q = it.............. Equation 1

Where Q = amount of charge, i = current, t = time

From the question,

Given: i = 0.860 A, t = 5 minutes = (5×60) seconds = 300 seconds

Subsitute these values into equation 1

Q = (0.860×300)

Q = 258 C

If one mole of electron has a charge of 96500 C

Then, x mole of electron will have a charge of 258 C

1 mole ⇒ 96500 C

X moles ⇒ 258 C

Solve for X

X = (258×1)/96500

X = 2.7×10⁻³ mole