Explanation:
13+x=43>2x
13+x=43>2x+43>2x
13+x=86>4x
x-4x=86-13
3x=73
x=73/3
x=24.333
x=24.4
The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?
Which law applies to the picture?
Newtons 1st Law of Motion
Newtons 2nd Law of Motion
Newtons 3rd Law of Motion
Answer:
Newton's first law
Explanation:
Newton's first law of motion says, that an object will stay in its current motion, unless if a force acts upon it.
So an object already at rest, will stay at rest. And the ball rolling will keep rolling, if no other force such as friction slows it down.
When a wave goes through a substance, _______________ has occurred.
When a wave gets trapped or stuck in a substance, ______________ has occurred.
When a wave bounces off of a surface, ______________ has occurred.
The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.
Answer:
A) When a wave goes through a substance, _______________ has occurred.
This is refraction or transmission.
Refraction refers to the changes in the wave that occur when it enters a new medium, in this case, the substance.
Transmission refers to the transfer of energy that is now in the medium.
Usually, we have both of those together.
B) When a wave gets trapped or stuck in a substance, ______________ has occurred.
This is total internal reflection. This happens when, by the Snel Law, the angle of the transmited wave is 90° (or larger) which is traduced in no transmitted wave, this is why the wave is "trapped" in the substance.
C) When a wave bounces off of a surface, ______________ has occurred.
This is reflection.
D) The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.
This is the Law of Reflection, that says "when light is reflected from a surface, the angle of reflection is the same as the angle of incidence"
Personal behavior is the only factor that determines if a person becomes ill.
Please select the best answer from the choices provided.
ОТ
OF
Answer:
FALSE
Explanation:
Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temperature), and measured terminal speed of 2.64X10^-5 m/s and weight-neutralizing voltage of 35.0 V. How many electrons have been attached to, or detached from the initially neutral plastic sphere
Following are the calculation to the given question:
Given:
Please find the given question.
To find:
value=?
Solution:
With terminal voltage, no force equals zero.
So,
[tex]\to mg = 6\times \pi \times \eta \times r\times \vartheta \\\\[/tex]
As [tex]35\ V[/tex] is weight neutralizing voltage
[tex]\to mg= q\times v \times r\\\\[/tex]
So,
[tex]\to q\times v \times r= 6 \times \pi \times \eta \times r \times \vartheta \\\\\to q\times v = 6 \times \pi \times \eta \times \vartheta \\\\\to q =\frac{6 \times \pi \times \eta \times \vartheta}{v} \\\\[/tex]
[tex]=\frac{6 \times 3.14 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 18.84 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\ =3.2 \times 10^{-10}\ coulombs[/tex]
Therefore
[tex]\to q= n \times e\\\\[/tex]
Hence n comes to be [tex]2\times 10^9\[/tex] electrons.
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which is an example of a vector quantity
A.time
B.speed
C. acceleration
D. distance
Answer:
The answer to your question is C
Explanation:
acceleration is a vector quantity because it has both magnitude and direction
Explain How can you
use a distance-time graph
to calculate average
speed?
Explanation:
Average speed = change in distance / change in time
In other words, the average speed is the slope of the line connecting two points on the graph.
a barge is pulled down the canal by a horse walking beside it, if the rope angle is 60.0 degrees, the force exterted is 400N and the barge being pulled is 100N how much work did the horse do
Answer:
The horse does 20,000 Nm of work.
Explanation:
Using = ∶ (400 ∗ 60°)(100) → The horse does 20,000 Nm of work.
The horse does 20,000 Nm of work.
What is work?Work is the energy transferred to or from an object via the application of force along a displacement.
In its simplest form, it is often represented as the product of force and displacement.
The work W is equal to the force f times the distance d, or W = fd.
If the force is being exerted at an angle θ to the displacement, the work done is W = f d cos θ.
From the given values,
W = f d cos θ.
W = 400*100 cos60°
W= 20,000 Nm
The horse does 20,000 Nm of work.
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#SPJ2
Newtons Second Law of motion states that for acceleration to stay the same...
Answer:
newton force is the state of gravity force they abstract when they came closer
what would happen to life on earth if all the plants died? plz help
Answer:
we would all die
Explanation:
If all the plants on earth died, so would the people. ... When green plants make food, they give off oxygen. This is a gas that all animals must breathe in order to stay alive. Without plants, animals would have no oxygen to breathe and would die.
A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
What is the time interval of marble?
Answer:
t = 6.09 seconds
Explanation:
Given that,
Speed, v = 44.1 cm/s
Distance, d = 269 cm
We need to find the time interval of the marble. Speed is distance per unit time.
[tex]v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s[/tex]
Hence, the time interval of the marble is 6.09 seconds.
does potential thermal energy affect the temperature of an object?
Answer:
Yes, it does
Explanation:
There are not many explanations, but when thermal energy is shined on an object it usually starts to heat up.
Derrick crawls 4 feet south, and then turns east and crawls 6 feet.
What distance did he cover?
What was his displacement?
Displacement is a vector quantity. The distance and displacement of the given object are 10 ft and 7.07 ft respectively.
Distance:
It can be defined as the change in position of the object. It is a scalar quantity.
Displacement = 4+6
Displacement = 10 ft
Displacement:It can be defined as the vector change in position overall change in position.It is a vector quantityVector quantity is the quantities that have both magnitude and direction.[tex]\rm Dislacement =\sqrt { 4^2 +6^2}\\\\ \rm Dislacement = 7.07 ft[/tex]
Therefore, the distance and displacement of the given object are 10 ft and 7.07 ft respectively.
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what is alpha decay?
Answer:Alpha decay, type of radioactive disintegration in which some unstable atomic nuclei dissipate excess energy by spontaneously ejecting an alpha particle.
Explanation:
sort the properties of metalloids into the correct categories
Boron
Sillicon
Germanium
Arsenic
Antimony
Tellurium
Pelorium
Metallic characteristics: lustrous, solid at room temperature
In-between characteristics: semiconducting, amphoteric
Nonmetallic: brittle
A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
Answer:
what's the question ,so I can answer it right ?
a torch battery produces electricity from – energy
Answer:
First, the batteries contain chemical energy, which is energy that is released during a chemical change. When chemical bonds are formed or broken, electrons are rearranged, and this movement of electrons produces chemical energy. Batteries can convert stored chemical energy into electrical energy.
chemical energy
A trumpet player on a moving railroad flatcar moves toward a second trumpet player standing alongside the track both play a 490 Hz note. The sound waves heard by a stationary observer between the two players have a beat frequency of 2.0 beats/s. What is the flatcar's speed? Take the speed of sound to be 343 m/s.
Answer:
The value is [tex]v_s = 1.394 \ m/s[/tex]
Explanation:
From the question we are told that
The frequency of the second player is [tex]f_2 = 490 \ Hz[/tex]
The beat frequency is [tex]f_b = 2.0 \ Hz[/tex]
The speed of sound is [tex]v_s = 343 \ m/s [/tex]
Generally the frequency of the note played by the first player is mathematically represented as
[tex]f_1 = f_2 + f_b[/tex]
=> [tex]f_1 = 490 + 2.0 [/tex]
=> [tex]f_1 = 492 Hz[/tex]
From the relation of Doppler Shift we have that
[tex]f_1 = \frac{ f_2 (v+ v_o )}{v-v_s }[/tex]
Here [tex] v_o\ is\ the\ velocity\ of\ the\ observer\ with\ value\ 0 \ m/s [/tex]
So
[tex]492 = \frac{ 490 (343+0 )}{343 -v_s }[/tex]
=> [tex]v_s = 1.394 \ m/s[/tex]
A 3.7-mm-diameter wire carries a 20 A current when the electric field is 8.2×10−2 V/m .
What is the wire's resistivity? (in Ωm)
Answer:
ρ = 4.4 10⁻⁸ Ω m
Explanation:
For this exercise let's start by finding the value of the resistance using Ohm's law
V = I R
R = V / I
The voltage is related to the electric field
V = E L
let's substitute
R = E L / I
R = 8.2 10⁻² / 20
R = 4.1 10⁻³ L
now we can use the resistance relation
R = ρ L / A
the area of a circular wire is
A = π r² = π d² / 4
ρ = R π d² / (4 L)
let's calculate
ρ = (4.1 10⁻³ L) π 0.0037² / (4 L) = (4.1 10⁻³) π 0.0037² / (4)
ρ = 4.4 10⁻⁸ Ω m
The resistivity of the wire is 4.4 10⁻⁸ Ω m.
We know that;
V = I R
R = V / I
The voltage the electric field can be connected using the formula;
V = E L
Hence;
R = E L /I
R = 8.2 10⁻² / 20
R = 4.1 10⁻³ L
For resistivity;
R = ρ L / A
the area can be obtained from;
A = π r² = π d² / 4
ρ = R π d² / (4 L)
ρ = (4.1 10⁻³ L) π 0.0037² / (4 L) = (4.1 10⁻³) π 0.0037² / (4)
ρ = 4.4 10⁻⁸ Ω m
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express forty meters with four significant figures
40.00 meters
add a decimal place so that trailing zeroes are counted as significant figures.
if AN OBJECT HAS ZERO NET FORCE ON IT THEN THE OBJECT MUST BE AT REST true or false
Answer:
False
Explanation:
constant velocity is also 0 net force
Answer:
FALSE
Explanation:
The object can be at rest or also could be in uniform motion (moving with constant velocity)
What do the elements in group 17 of the periodic table have in common
A simple model of a hydrogen atom is a positive point charge +e (representing the proton) at the center of a ring of radius a with negative charge −e distributed uniformly around the ring (representing the electron in orbit around the proton). Find the magnitude of the total electric field due to this charge distribution at a point a distance a from the proton and perpendicular to the plane of the ring.
Answer:
Now e is due to the ring at a
So
We say
1/4πEo(ea/ a²+a²)^3/2
= 1/4πEo ea/2√2a³
So here E is faced towards the ring
Next is E due to a point at the centre
So
E² = 1/4πEo ( e/a²)
Finally we get the total
Et= E²-E
= e/4πEo(2√2-1/2√2)
So the direction here is away from the ring
When a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 N .m2 /C. When the paper is turned 25° with respect to the field the flux through it is:_____.1. 02. 12 N .m2 /C3. 21 N .m2 /C4. 23 N .m2 /C5. 25 N .m2 /CB. A charged point particle is placed at the center of a spherical Gaussian surface. The electric flux is changed if:______.1. the sphere is replaced by a cube of the same volume2. the sphere is replaced by a cube of one-tenth the volume3. the point charge is moved off center (but still inside the original sphere)4. the point charge is moved to just outside the sphere5. a second point charge is placed just outside the sphereC. A charge of 0.8 × 10−9 C is placed at the center of a cube that measures 5 m along each edge. What is the electric flux through any 2 faces of the cube?
Answer:
1) 23 N.m²/C
2) The point charge is moved just outside the sphere
3) 30 N.m²/C
Explanation:
1) The flux through the field can be gotten by finding the dot product of the angle the later is turned, and the given uniform electric field.
25 * cos 25 =
25 * 0.9063 =
22.66 or approximately, 23 N.m²/C
2) The point charge is moved just outside the sphere
3) Using Gauss' Law, the electric flux through one face of the cube is given as Φ = Q / 6ε₀, thus,
Φ = 0.8*10^-9 / 6 * 8.85*10^-12
Φ = 0.8*10^-9 / 5.311*10^-11
Φ = 15 N.m²/C
And therefore, the flux through any 2 faces of the cube is 2 * 15 = 30 N.m²/C
The bonds between molecules store ____ Energy?
Answer:
chemical energy
Explanation:
Answer:
chemical energy
Explanation:
Energy is also stored in the covalent bonds holding atoms together in molecules. ... the difference in the amount of free energy given off as the original, reacting molecules fly apart, and the amount of free energy absorbed as the new covalent bonds form is left in the environment, often as light and/or heat.
(1.736+9.6435)÷3.22=
The answer is 3.53400621
Reduce the expression, if possible, by cancelling common factors.
Answer: 3.53400621
Explanation: Hope this helped! :)
Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.30 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.600 m/s2 to the right. Find the magnitudes of the two forces P and Q in newtons.
Answer:
P = 2.45 N
Q = 6.65 N
Explanation:
According to Newton's 2nd Law:
Unbalanced Force = ma
where,
m = mass = 7 kg
a = acceleration
In the first case when both forces P and Q act on left side:
Unbalanced Force = P + Q
a = 1.3 m/s²
Therefore,
P + Q = (7 kg)(1.3 m/s²)
P + Q = 9.1 N ------------------------- equation 1
Now, in second case when both forces have different directions:
Unbalanced Force = Greater Force - Smaller Force
Unbalanced Force = Q - P
a = 0.6 m/s²
Therefore,
Q - P = (7 kg)(0.6 m/s²)
Q - P = 4.2 N ------------------- equation 2
Adding equation 1 and equation 2, we get:
(Q + P) + (Q - P) = 9.1 N + 4.2 N
2 Q = 13.3 N
Q = 6.65 N
Using this value in equation 2, we get:
6.65 N - P = 4.2 N
P = 2.45 N
Which phenomenon related to light allows scientists to measure the distance between a star and Earth? A. Dark patches appear in the electromagnetic spectrum emitted by stars. B. Light waves spread out as they move farther from their source. C. Stars have different colors based on their temperature. D. Stars have unique elements that make up their atmospheres.
Answer:
The Answer Is B not C
Explanation:
Answer:b
Explanation:
HELP ASAP CORRECT ANSWER ONLY 10 PTS Collaboration, listening, and negotiating are considered __________ skills. interpersonal mathematical personal verbal
Answer:
Explanation:
verbal as they are all linked to communication and speaking
a cart travels 3.00 meters east and then 4.00 meters north. the magnitude
Answer: 5 m
Explanation:
X^2= 9+16
X = 5
According to pythagoras law