Answer:
M = 0.011 mol/L
Explanation:
Molarity = n/V,
n: No. of moles
V: volume in liters
n of KMnO4 (Molar mass = 158 g/mol) = 0.435/158 = 0.00275 moles
Molarity (M) = 0.00275/0.25 = 0.011 mol/L
Describe and explain how the surface of the earth and it's atmosphere have changed to form the surface of the earth and its atmosphere today
Everyone is aware that the first billion years of Earth's existence were marked by intense volcanic activity. Because of the circumstances, there were so many gases in our atmosphere that life could not exist there (Very similar like the atmosphere of Mars & Venus of today).
Carbon dioxide was most prevalent, whereas oxygen was scarce. Next, the modifications that affected the ratio of gases were:
1) To increase oxygen levels. "Photosynthesis by Plants" was the sole and most significant source of increasing oxygen.
2) In order to reduce carbon dioxide. - I Absorbable by plants for the photosynthesis process.
(ii) The majority of the CO2 is dissolved in the oceans, and a large portion of it is trapped in sedimentary rocks like limestone and fossil fuels.
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When 1.8 moles of nitrogen react how many moles of ammonia are formed
1.8 moles of nitrogen react with 3 moles of hydrogen to form 2 moles of ammonia.
The chemical equation for the reaction is:
N2 + 3H2 → 2NH3
Therefore, 2 moles of ammonia are formed.
Ammonia is an odourless gas that has a potent scent.. It is the main component of many industrial and household cleaning products, and is also used widely in agriculture as a fertilizer. Ammonia can be hazardous to human health if inhaled, ingested, or if it comes in contact with the skin or eyes. Inhalation of high concentrations of ammonia can cause irritation of the eyes, nose, throat, and lungs. Ingestion of ammonia can cause severe damage to the digestive system.
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How much energy is produced when 93. 5 grams of oxygen reacts with 13. 2 g hydrogen in
the following reaction?
2 H2 + O --> 2 H2O
H = -572 kJ
The amount of energy produced when 93.5 g of oxygen reacts with 13.2 g of hydrogen is -31,640.8 kJ.T.
When 93.5 g of oxygen reacts with 13.2 g of hydrogen in the reaction 2H2 + O2 → 2H2O, the amount of energy produced is -572 kJ. To calculate this, we can use the following equation:
Energy (in kJ) = -572 x (moles of oxygen) x (moles of hydrogen)
First, we need to find the moles of oxygen and hydrogen. To do this, we need to use the molar mass of each element, which can be found in the periodic table. The molar mass of oxygen is 16 g/mol, and the molar mass of hydrogen is 2 g/mol. Therefore, we can calculate the moles of oxygen as follows:
93.5 g of oxygen / 16 g/mol = 5.84 mol of oxygen
And the moles of hydrogen can be calculated as follows:
13.2 g of hydrogen / 2 g/mol = 6.6 mol of hydrogen
Now, we can plug these values into the equation:
Energy (in kJ) = -572 x (5.84 mol of oxygen) x (6.6 mol of hydrogen) = -31,640.8 kJ
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his is a reddish-brown irritating gas that gives photochemical smog its brownish color; in the atmosphere it can also be converted in the atmosphere into an acid that is one of the major component of acid deposition, what is this substance?
This reddish-brown irritating gas that gives photochemical smog its brownish color and is also a major component of acid deposition is Nitrogen dioxide (NO2).
Nitrogen dioxide (NO2) is a reddish-brown gas that is a photochemical smog component. It's also a component of acid deposition when it's converted to an acid in the atmosphere. Nitrogen dioxide (NO2) is one of the major air pollutants that contribute to the formation of smog. It's generated from the burning of fossil fuels, particularly in high-temperature combustion processes that produce smog.
Nitrogen dioxide is formed when nitrogen in the atmosphere reacts with oxygen in the atmosphere.Nitrogen dioxide is one of the primary pollutants produced by motor vehicle exhausts. When nitrogen oxide (NO) and volatile organic compounds (VOCs) are released into the atmosphere by burning fossil fuels, they react with sunlight to create photochemical smog. Nitrogen dioxide, a secondary air pollutant, is produced as a result of this reaction. Nitrogen dioxide (NO2) is a reddish-brown gas that absorbs light at wavelengths below 400 nanometers, giving photochemical smog its brownish color.
Nitrogen dioxide (NO2) is a major component of acid deposition when it is converted in the atmosphere into an acid. Acid deposition is a type of precipitation that contains acidic substances, such as sulfuric acid and nitric acid. When acid deposition falls to the ground, it can cause damage to plant and animal life, as well as buildings and other structures.
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Calcium hydroxide and hydrochloric acid react to form calcium chloride and water as show in the chemical reaction. If the chemicals are present in exactly the correct ratios to fully use all of the ingredients, how many moles of water would be formed from 5 moles of HCI
Answer:
5 moles H2O
Explanation:
We need a balanced equation for the reaction.
Ca(OH)2 + 2HCl = CaCl2 + 2H20
Everything should be balanced. This tells us we should expect 2 moles of H2O from 2 moles of HCl. That is a 1:1 molar ratio, or
(1 mole H2O/1 mole HCl)
If we start with 5 moles of HCl, we can use the molar ratio:
(5 moles HCl)*((1 mole H2O/1 mole HCl) = 5 moles H2O (the unit "moles HCl" cancels out, leaving just moles H2O)
solve the system of inequalities by graphing
y_<-5x+4
y_>6x+4
The graphical solution to the above system of inequalities is attached accordingly.
What is a system of inequalities?A system of inequalities is a set of two or more inequalities that are considered together. The solution to a system of inequalities is the set of all values that satisfy all the inequalities simultaneously.
To graph the system of inequalities y < 6x + 4 and y > 5x + 4, we first graph the boundary lines y = 6x + 4 and y = 5x + 4.
To graph the line y = 6x + 4:
Plot the y-intercept (0, 4).
Use the slope, rise over run, to find additional points. For example, if we move up 6 units and right 1 unit from the y-intercept, we get the point (1, 10).
Draw a straight line through the points.
To graph the line y = 5x + 4:
Plot the y-intercept (0, 4).
Use the slope, rise over run, to find additional points. For example, if we move up 5 units and right 1 unit from the y-intercept, we get the point (1, 9).
Draw a straight line through the points.
Now we need to shade the area that satisfies the system of inequalities.
To do this, we can choose a test point, such as (0, 0), and plug it into both inequalities:
y < 6x + 4:
0 < 6(0) + 4
0 < 4 (true)
y > 5x + 4:
0 > 5(0) + 4
0 > 4 (false)
Since (0, 0) satisfies the first inequality but not the second, we shade the area below the line y = 6x + 4 but above the line y = 5x + 4.
The shaded area is the region between the two lines, below y = 6x + 4, and above y = 5x + 4.
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In physical labs, when conducting this experiment, sometimes the metal is heated and cooled for several rounds. After each round, the mass is recorded. This continues until the mass measurements remain the same. Explain the purpose of this process and how it might reduce errors.
Answer:
The purpose of heating and cooling the metal for several rounds in the experiment is to ensure that it reaches a stable state or equilibrium. This equilibrium state means that the metal has reached a constant temperature and has stopped losing or gaining weight due to chemical reactions. By recording the mass after each round of heating and cooling, scientists can monitor the weight changes and determine when the metal has reached a stable state.
The repeated rounds of heating and cooling also help to reduce errors in the experiment. By conducting multiple rounds of heating and cooling, any residual impurities or gases on the surface of the metal will be removed. This ensures that the metal is in a pure state before measurements are taken, which increases the accuracy of the final results. Additionally, the repeated rounds of heating and cooling allow for any fluctuations in the ambient temperature to be accounted for, further reducing errors in the experiment. Overall, the process of heating and cooling the metal multiple times helps to ensure accuracy and reliability in the experimental results.
Explanation:
The specific heat of a certain type of cooking oil is 1. 75 J/(g°C). How much heat energy is needed to raise the temperature of
2. 11 kg of this oil from 23 °C to 191 °C?
The heat energy needed to raise the temperature of 2.11 kg of the cooking oil from 23°C to 191°C is 609960 J.
To calculate the heat energy needed to raise the temperature of the cooking oil, we can use the formula:
Q = m × c × ΔT
where:
Q = heat energy (in joules)
m = mass of oil (in grams)
c = specific heat of the oil (in J/(g°C))
ΔT = change in temperature (in °C)
First, we need to convert the mass of the oil from 2.11 kg to grams:
2.11 kg = 2.11 x 1000 g/kg = 2110 g
Substituting the given values into the formula, we have:
Q = 2110 g × 1.75 J/(g°C) × (191°C - 23°C)
Q = 2110 g × 1.75 J/(g°C) × 168°C
Q = 609960 J
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Which mixture can be separated by filtration?
-mayonnaise
-muddy water
-shaving cream
-gelatin
The four mixtures listed above can be separated by filtration. Filtration is a technique commonly used to separate a suspended solid from a liquid, or from another solid, in order to purify or clarify the product or solution. In this respect, mayonnaise, muddy water, shaving cream and gelatin can be separated by filtration.
First, mayonnaise can be separated by filtration. Mayonnaise is a combination of oil and egg yolks, and it is a mixture that can be separated using a cheesecloth or a paper filter. This process works because the large particles of egg yolks and oil can be caught in the filter, while the smaller liquid components can be left behind.
Muddy water can also be separated by filtration. Muddy water typically contains suspended solids such as dirt and clay, which can be removed by passing the water through a filter. These solids are collected on the filter while the remaining water is clarified and clean.
Shaving cream can be separated by filtration as well. By using a filter paper, the oils contained in the shaving cream will stick to the filter, while the rest of the ingredients in the cream will be trapped behind the filter.
Finally, gelatin mixtures can also be separated by filtration. Gelatin is a mixture that contains proteins, fats, sugars and minerals. Separating these components can be achieved by passing the mixture through a filter. The proteins and fats will be collected on the filter, while the minerals and sugars will remain behind.
In conclusion, filtration is a process used to separate different components from a mixture. This process can be used to separate mayonnaise, muddy water, shaving cream and gelatin mixtures. By using filtration, the suspended solids in these mixtures can be removed, while the remaining components can be considered purified or clarified.
If anyone takes Chemistry from BJU, can you please tell me the answers for the chapter 15 test about thermochemistry? I really don't feel confident going into this test, and I know I will fail without the answers.
The study of heat and energy in relation to various physical transformations and chemical processes is known as thermochemistry. Energy might be released or absorbed throughout the reaction ( exothermic).
How challenging is thermochemistry?Thermochemistry is difficult. Several fictitious terms, like enthalpy, entropy, and the dreaded Gibbs free energy, must be understood. These ideas are difficult to understand and full of traps. Unless you have a fantastic tutor for Cambridge Coaching who can make everything crystal obvious for you.
What are the two thermochemical laws?The law of conservation of energy, the law of conservation of mass, and Hess's law are the three fundamental principles of thermochemistry.
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A sample contains 5.5 x 1024 atoms of calcium. What is the mass of the sample? (round to the nearest whole number)
After calculating the mass by using the molar mass of calcium (Ca) and Avogadro's number (Nₐ), Rounding to the nearest whole number, the mass of the sample is approximately 365 g.
How to determine the mass of the sample?
To determine the mass of the sample, we need to use the molar mass of calcium (Ca) and Avogadro's number (Nₐ) to convert the number of atoms to mass.
The molar mass of calcium is approximately 40.08 g/mol, which means that one mole of calcium contains 6.022 x 10²³ atoms.
So, first we need to find out how many moles of calcium are in the sample:
moles of calcium = number of atoms / Avogadro's number
moles of calcium = 5.5 x 10²⁴ / 6.022 x 10²³
moles of calcium = 9.13
Now we can use the molar mass of calcium to convert moles to grams:
mass of sample = moles of calcium x molar mass of calcium
mass of sample = 9.13 x 40.08
mass of sample = 365.4 g
Rounding to the nearest whole number, the mass of the sample is approximately 365 g.
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Una estudiante de secundaria ha escuchado que añadir unas gotas de limon a la zona expuesta del alimento demora el proceso de oscurecimiento ; pero ¿ como podemos indagar cientificamente si esto es cierto ? ayudenme plis
To find out if the proposed hypothesis or scientific assumption is true, we must submit it to experimentation or hypothesis testing.
An experience is proposed in which the materials are needed:
1 apple
2 lemon
Cold water in container1. Cut and peel half of the apple and immerse it in cold water to which the juice of 2 lemons is added
2. The other half is left unpeeled exposed to the air
Results:
A. In the dough submerged in water it is observed that it does not darken while it is submerged in the water with lemon
B. In the apple exposed to the oxidation of the air, a noticeable darkening is observed .
Oxygen oxidizes the enzyme phenol oxidase present in the fruit, through complex reactions proteins are formed that darken the surface of the apple.
Lemon delays and prevents darkening
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Translated question : A high school student has heard that adding a few drops of lemon to the exposed area of food slows the browning process, but how can we scientifically find out if this is true?
Which prefix indicates a molecule with 4 carbon atoms 
Answer: But
Explanation:
1 carbon atom - meth
2 carbon atoms - eth
3 carbon atoms - prop
4 carbon atoms - but
this needs to be memorised
The illustration depicts possible routes of collisions in the
reaction CH₂ = CH₂ + HCl → CH3CH₂Cl.
Which statement is true?
O The molecules do not change speed.
O The chlorine atom is a spectator ion in the reaction.
O The bonds are not broken in the reaction.
O The positioning of all reactants is crucial.
The correct statement is "The positioning of all reactants is crucial".
What are the reactants?
The given illustration shows the possible routes of collisions in the reaction CH₂ = CH₂ + HCl → [tex]CH_{3}CH_{2}Cl[/tex].
Regarding the given options, the correct statement is "The positioning of all reactants is crucial".
This is because, in this reaction, the reactants must collide with a specific orientation or positioning in order for the reaction to occur. Specifically, the chlorine atom from HCl must collide with one of the carbon atoms in ethylene (CH₂=CH₂) in a way that allows the bond between the carbon and hydrogen to break and a bond to form between the chlorine and the carbon atom. This type of reaction is known as an addition reaction, and it requires the proper orientation of the reactant molecules for it to occur.
Therefore, the positioning of all reactants is crucial for this reaction to take place.
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i need help please i don’t understand
Tertiary or intermediate colors can be created from color mixing.
What Are Tertiary Colors?In a particular color system like RGB, CMYK (more modern), or RYB[2], a tertiary color or intermediate color is created by combining complete intensity of one primary color with half saturation of another primary color and none of a third primary color (traditional).
For the RGB color wheel and the RYB color wheel, tertiary hues have generic names that vary slightly. The following titles are displayed. Another meaning of tertiary color is offered by color theorists like Moses Harris and Josef Albers , who propose that tertiary colors are produced by combining complimentary colors or sets of secondary colors, such as orange-green, green-purple, and purple-orange.
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In a survey of 3941 adults, 730 oppose allowing transgender students to use the bathrooms of the opposite biological sex.
3 Construct a 99% confidence interval for the population proportion. Interpret the results.
)
A 99% confidence interval for the population proportion is (1
(Round to three decimal places as needed. )
a
The 99% confidence that the true proportion of adults who oppose allowing transgender students to use the bathrooms of the opposite biological population sex is between 0.1626 and 0.2084.
This means that we are 99% confident that the true population proportion of adults who oppose allowing transgender students to use the bathrooms of the opposite biological gender lies between 18.3% and 22.3%.
To construct a 99% confidence interval for the population proportion, we can use the following formula:
confidence interval = sample proportion ± z* (standard error)
Where, sample proportion = proportion of people in the sample who oppose allowing transgender students to use the bathrooms of the opposite biological sex = 730/3941 = 0.1855
z* = the z-score corresponding to a 99% confidence level, which can be found using a standard normal distribution table or calculator. For a two-tailed test at the 99% confidence level, the z-score is 2.576.
standard error = the standard deviation of the sampling distribution of the proportion, which can be calculated using the formula sqrt(p * (1-p) / n), where p is the sample proportion and n is the sample size.
Substituting the values we have:
confidence interval = 0.1855 ± 2.576 * sqrt(0.1855 * (1-0.1855) / 3941)
This simplifies to:
confidence interval = (0.1626, 0.2084)
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What is the total number of moles present in a
52.0-gram sample of NaN(s) (gram-formula mass
= 65.0 gram/mole)?
So the total number of moles present in the 52.0-gram sample of Na(s) is 0.8 moles.
How to calculate mole ?
Divide the sample's mass by its molar mass to determine the total number of moles in a 52.0-gram sample of sodium (Na).
As Na has an atomic mass of 23.0 atomic mass units (amu) and each element has an average of 6.02 x 1023 atoms per mole, Na has a molar mass of 23.0 grams/mole.
The gram-formula mass of Na
which is reported as 65.0 grams/mole, must be used since the inquiry pertains to a sample of Na in its solid state (Na(s)).
moles = mass molar mass moles
= 52.0 g 65.0 g/mol moles
= 0.8 mol
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To conduct electricity, a solution must contain.
-nonpolar molecules.
-polar molecules.
-ions
-free electrons
How many nitrogen atoms are there in one molecule of N2H4?
From the chemical formula of hydrazine, each patch has two Nitrogen tittles.
N2H4 is a tintless and ignitable liquid with a pungent odor. It's generally used as a reducing agent in chemical responses and as a rocket fuel. Each N2H4 patch contains two nitrogen tittles and four hydrogen tittles, with a molecular weight of32.04 g/ spook.
The patch has a direct shape with a bond angle of about 111 degrees between the two nitrogen tittles. The nitrogen tittles in N2H4 have a covalent bond between them, with each nitrogen snippet participating three electrons to form a triadic bond. The two hydrogen tittles are attached to each nitrogen snippet through single covalent bonds. Overall, N2H4 is an important and protean chemical with numerous artificial and exploration operations.
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Predict what will happen to the volume of a gas, if it's pressure is raised three times, keeping the temperature constant?
a. Will remain constant
b. will become one third
c. will become three times
d. will become two third
Answer: Volume will become one third .
Explanation:
For volume of gas the equation is given as
P V = n R T
V = [tex]\frac{n R T}{P}[/tex]
now increasing P by three times we have new volume V' as
→ V' = [tex]\frac{n R T}{3P}[/tex]
→ V' = [tex]\frac{1}{3} \frac{n R T}{P}[/tex]
→ V' = [tex]\frac{1}{3} V[/tex]
Therefore the volume will become one third of the previous volume.
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Chromium has four naturally occuring isotopes. Cr-50 (mass of 49. 946 amu and 4. 35% abundance); Cr-52 (mass of 51. 941 amu and 83. 79% abundance); Cr-53 (mass of 52. 941 amu and 9. 50% abundance); and Cr-54 (mass of 53. 939 amu and 2. 36% adundance). Calculate the average atomic mass of chromium.
51. 996 amu
Eliminate
B) 52. 000 amu
C) 52. 191 amu
D) 52. 25 amu
B) 52.000 amu is the right response because it comes nearest to the calculated average atomic mass.
To calculate the average atomic mass of chromium, we need to take into account the mass and abundance of each of its isotopes. We can use the following formula to calculate the average atomic mass:
Average atomic mass = (mass of isotope 1 x abundance of isotope 1) + (mass of isotope 2 x abundance of isotope 2) + (mass of isotope 3 x abundance of isotope 3) + (mass of isotope 4 x abundance of isotope 4)
Substituting the values given in the problem, we get:
Average atomic mass = (49.946 amu x 0.0435) + (51.941 amu x 0.8379) + (52.941 amu x 0.0950) + (53.939 amu x 0.0236)
Average atomic mass = 2.173027 + 43.592439 + 5.02999 + 1.272404
Average atomic mass = 52.06786 amu
Therefore, the correct answer is B) 52.000 amu, which is the closest value to the calculated average atomic mass.
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to calculate the specific heat capacity of a material, the mass of the material need to be measured
Temperature of the material needs to be measured. Then the equation Q=mcΔT needs to be used, where Q is the heat energy, m is the mass, c is the specific heat capacity and ΔT is the change intemperature.
What is material?Material is something that can be seen, felt, and/or interacted with. It is the physical substance of which a thing is composed. Materials can be made up of elements, compounds, and/or mixtures of these. Examples of materials include metals, plastics, rubber, wood, paper, cloth, glass, and water. Each material has unique properties such as strength, weight, color, texture, and durability. The choice of material used in a design or product is important as it affects the cost, performance, and overall success of the item.
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Why are there different ways to describe an atom?
Answer:
Atoms are complex structures, and scientists use different models or descriptions to explain their behavior and properties. These models have evolved over time as our understanding of the atom has increased.
One reason for the different ways to describe an atom is that atoms have both particle-like and wave-like properties. Early models, such as the Thomson model, viewed atoms as a positively charged sphere with negatively charged electrons scattered throughout. Later models, such as the Rutherford model and Bohr model, introduced the concept of the nucleus and orbiting electrons.
As our understanding of quantum mechanics improved, new models, such as the quantum mechanical model, were developed to better explain the wave-like nature of electrons and their behavior within atoms. This model uses a mathematical approach to describe the probability of finding an electron in a specific location within an atom.
Additionally, different models may be better suited for different purposes. For example, the Bohr model is often used in introductory chemistry courses to explain the concept of energy levels, while the quantum mechanical model is more advanced and can be used to calculate more precise properties of atoms.
In summary, the different ways to describe an atom reflect the evolving nature of scientific understanding, as well as the need for different models to explain different aspects of the atom.
Explanation:
Your body utilizes this reaction with sucrose. A regular bag of
Skittles has about 84 g of sucrose, if you eat the entire bag and
burn all the sugar, what mass of CO₂ will you breath out?
The combustion reaction of sucrose (C12H22O11) with oxygen (O2) can be represented by the following equation:
C12H22O11 + 12 O2 → 12 CO2 + 11 H2O
From the balanced equation, we can see that 1 mole of sucrose reacts with 12 moles of oxygen to produce 12 moles of carbon dioxide.
The molar mass of sucrose is approximately 342.3 g/mol (12 x 12.01 g/mol + 22 x 1.01 g/mol + 11 x 16.00 g/mol), which means that 84 g of sucrose is equivalent to:
84 g / 342.3 g/mol = 0.2456 moles of sucrose
According to the balanced equation, the combustion of 1 mole of sucrose produces 12 moles of carbon dioxide. Therefore, the combustion of 0.2456 moles of sucrose will produce:
0.2456 moles x 12 moles CO2 / 1 mole sucrose = 2.9472 moles of carbon dioxide
Finally, we can convert moles of carbon dioxide to mass using the molar mass of carbon dioxide, which is approximately 44.01 g/mol. Therefore, the mass of carbon dioxide produced from burning 84 g of sucrose in Skittles would be:
2.9472 moles x 44.01 g/mol = 129.5 g of CO2
So, if you ate an entire bag of Skittles (84 g of sucrose), you would breathe out approximately 129.5 g of carbon dioxide.
If we have three different solutions, A, B, and C, each containing 100. grams of water, plus respectively 34.2 g of sucrose, 4.6 g of ethanol, and 4.0 g of sodium hydroxide, which statement is true? Molar Masses surcose, C12H22O11 342.0 g/mol ethanol, C2HsOH 46.0 g/mol sodium hydroxide, NaOH 40.0 g/mol A, B, and C all have different freezing points. A, B, and C will all have the same freezing points. C has the lowest freezing point in the group. The boiling point of C is lower than that of A or B A and C have the same boiling point, but B has a lower one
The correct statement is that A, B, and C all have different freezing points. This is because the freezing point of a substance depends on the number of solute particles per unit volume of solution. Since A, B, and C each contain different amounts of sucrose, ethanol, and sodium hydroxide, they each have different amounts of solute particles, and therefore different freezing points.
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in this problem, you will calculate the molarity of acetic acid in vinegar and the pka of acetic acid. a. convert 5% (by mass) acetic acid into molarity. you may assume the density of vinegar is 1 g/ml. b. use the measured ph of vinegar to calculate the pka of acetic acid. c. calculate the percent error between the experimental and the theoretical pka (4.75).
Molarity of acetic acid = 0.00083 mol/L. Therefore, the percent error between the experimental and theoretical pKa of acetic acid is: Percent error = (experimental pKa - 4.75)/4.75 x 100%
a. To calculate the molarity of acetic acid in vinegar, you need to convert 5% (by mass) acetic acid into moles. To do this, you will use the equation:
Moles of acetic acid = (mass of acetic acid/molar mass of acetic acid) x (density of vinegar)
We can assume that the density of vinegar is 1 g/ml. The molar mass of acetic acid is 60.05 g/mol. So, we can calculate the moles of acetic acid as follows:
Moles of acetic acid = (0.05 g/60.05 g/mol) x (1 g/ml) = 0.00083 mol
To calculate the molarity of acetic acid, we need to divide the number of moles of acetic acid by the volume of vinegar (in liters):
Molarity of acetic acid = 0.00083 mol/L
b. To calculate the pKa of acetic acid, you need to use the measured pH of vinegar. The pH of a solution can be related to the pKa of an acid using the equation:
pKa = pH + log ([A-]/[HA])
where [A-] is the concentration of the acid’s conjugate base and [HA] is the concentration of the acid itself. The pKa of acetic acid is 4.75. So, the equation above can be rearranged to calculate the concentration of the conjugate base, [A-]:
[A-] = 10^(pKa - pH) x [HA]
Therefore, we can calculate the pKa of acetic acid given the measured pH of vinegar and the molarity of acetic acid:
pKa = pH + log ([A-]/[HA]) = measured pH + log (10^(pKa - pH) x [HA]/[HA]) = measured pH + log (10^(4.75 - measured pH))
c. To calculate the percent error between the experimental and theoretical pKa of acetic acid, we can use the following equation:
Percent error = (experimental - theoretical)/theoretical x 100%
Therefore, the percent error between the experimental and theoretical pKa of acetic acid is:
Percent error = (experimental pKa - 4.75)/4.75 x 100%
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at a certain temperature and pressure, chlorine molecules have an averages speed of .0380 m/s what is the average speed of so2 molecules under the same conditions?
The average speed of SO2 molecules at a certain temperature and pressure will be the same as the average speed of chlorine molecules, which is: 0.0380 m/s
At a certain temperature and pressure, chlorine molecules have an average speed of .0380 m/s. Under the same conditions, the average speed of SO2 molecules will be the same. This is because temperature and pressure are constant parameters and do not change the speed of molecules. Therefore, the average speed of SO2 molecules at the same temperature and pressure is .0380 m/s.
To further explain, the temperature is related to the kinetic energy of molecules and the average speed of a molecule is proportional to the square root of its absolute temperature. Therefore, when the temperature is constant, the average speed of the molecules is constant too.
Similarly, pressure is related to the number of collisions between molecules, but it does not have an effect on the average speed of the molecules. Therefore, when the temperature and pressure are constant, the average speed of the molecules is also constant.
In conclusion, the average speed of SO2 molecules at a certain temperature and pressure will be the same as the average speed of chlorine molecules, which is .0380 m/s.
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What bonding pattern do you observe that you could use to predict whether a compound will be a gas at stp?
Answer:
Covalent compounds are typically liquids or gases at room temperature, although the more complex and the larger the molecule, the greater the chance that it could exist as a solid.
Explanation:
From desch.org
In the balanced chemical reaction for the combustion of propane, what is the molar ratio of O2 to CO2?
C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)
A. 3 to 5
B. 5 to 3
C. 1 to 1
D. 5 to 1
Answer:
B. 5 to 3
Explanation:
There's 5 O2 and 3 CO2
5:3 or 5 to 3
(It isn't A because of the order it was asked in. it always matters what you put first, so generally speaking,
"A to B" or "B to A" ratio wouldn't be the same.)
how many moles of (H20) are produced when 25.0 grams of C2H2 burns completely
Answer:
To answer this question, we need to first write the balanced chemical equation for the combustion of C2H2:
C2H2 + 2.5 O2 → 2 CO2 + H2O
From the equation, we can see that for every mole of C2H2 burned, we produce one mole of water (H2O).
To find the number of moles of C2H2 in 25.0 grams, we need to divide the mass by the molar mass:
molar mass of C2H2 = 2(12.01 g/mol) + 2(1.01 g/mol) = 26.04 g/mol
moles of C2H2 = 25.0 g / 26.04 g/mol = 0.961 mol
Therefore, the number of moles of H2O produced is also 0.961 mol.