Identify which type of study the following example describes.

Severing the connections between visual regions and the rest of the brain in animals, and observing the animals failure to recognize objects,

Answers

Answer 1

Answer:

They are training animals in a maze and recording physiological changes in their brains, Stimulating a brain structure and recording subsequent changes in movement, Introducing two adults that are potentially attracted to each other, and then measuring their sex hormone levels, Measuring the brain volumes and intelligences of people in a group, Observing enlarged cerebral ventricles in the brains of many people with schizophrenia, Severing the connections between visual regions and the rest of the brain in animals, and observing the animals’ failure to recognize an object, and Studying the relationship between a sex hormone treatment and strength of an animal’s mating behavior.

Explanation:


Related Questions

Which group of algae is the most closely related to vascular plant, what scientific evidence can be used to support your answer

Answers

Answer:

Explanation:

The green algae lineages hypothesized to be most closely related to land plants include: Coleochaetophyceae (coleochaetes). Charophyceae (stoneworts).well  lack  of vascular tissue—specialized groups of cells that conduct of  water or dissolved nutrients throughout the plants body.(i guess this the scientific evidenxe if not comment ill provide more information)

hope it helps

The women has had two miscarriages. What is the chance that she could have a normal child? a. The chance of a normal child is approximately one in four; however, all of the normal children will be translocation carriers.b. The chance of a normal child is approximately one in two; however, all of the normal children will be translocation carriers.c. The chance of a normal child is approximately one in four; however, half of the normal children will be translocation carriers.d. The chance of a normal child is approximately one in two; however, half of the normal children will be translocation carriers

Answers

Dududjdudbdudjdbbrud

Each of two parents has the genotype brown divided by red​, which consists of the pair of alleles that determine hair color​, and each parent contributes one of those alleles to a child. Assume that if the child has at least one brown ​allele, that color will dominate and the​ child's hair color will be brown. a. List the different possible outcomes. Assume that these outcomes are equally likely. b. What is the probability that a child of these parents will have the red divided by red ​genotype? c. What is the probability that the child will have brown hair color​?

Answers

Answer:

Explanation:

From the given information:

Each of two parents has the genotype brown divided by red​

So ;

The man's genotype is : [tex]\mathbf {\dfrac{Brown}{Red}}[/tex]

The woman's genotype is : [tex]\mathbf {\dfrac{Brown}{Red}}[/tex]

This [tex]\mathbf {\dfrac{Brown}{Red}}[/tex] genotype consist of the pair of alleles that determine hair color​

Now; we are given an assumption that:

if the child has at least one brown ​allele, that color will dominate and the​ child's hair color will be brown.

i.e Brown allele is dominant to Red allele

(a) List the different possible outcomes.

The cross between :

[tex]\mathbf {\dfrac{Brown}{Red}* \mathbf {\dfrac{Brown}{Red}}}[/tex] will produce the following offsprings which is the different possible outcomes.

[tex]= \mathbf {\dfrac{Brown}{Brown} \ \ : \ \ \mathbf {\dfrac{Brown}{Red}} \ \ : \ \ \mathbf {\dfrac{Red}{Brown}} \ \ : \ \ \mathbf {\dfrac{Red}{Red} }}[/tex]

(b) . What is the probability that a child of these parents will have the red divided by red ​genotype?

The probability that the child of  these parents will have [tex]\mathbf {\dfrac{Red}{Red} }}[/tex] is one out of four

i.e

= 1/4

= 0.25

(c) What is the probability that the child will have brown hair color​.

We are being told that;  if the child has at least one brown ​allele, that color will dominate and the​ child's hair color will be brown.

i.e Brown allele is dominant to Red allele

Thus; from above we will see that three of the offsprings have at least one brown allele;

Thus; the probability  that the child will have brown hair color​ is = 3/4

= 0.75

What is the shape of an Acid-fast bacteria?

Answers

Like a rod shaped for Acid fast bacteria

Consider a gene with three alleles controlling coloration of a flowering plant. There are 3 possible phenotypes, corresponding to the following dominance hierarchy among the alleles: A1 is dominant to A2 and A3, and A2 is dominant to A3. Which of the following genotype pairs express the same phenotype?

A.
A2A2, A3A3

B.
A1A1, A3A3

C.
A1A2, A1A3

D.
A2A3, A1A3

Answers

Answer:

C. A1A2, A1A3

Explanation:

This question depicts a gene coding for coloration in a flowering plant. The gene is controlled by multiple alleles, three specifically. The alleles are labelled A1, A2, and A3, with each coding for it's own respective trait.

According to the question, A1 is dominant over A2 and A3 i.e. A1 will always mask the phenotypic expression of A2 and A3 and express itself. Also, A2 is dominant over A3 i.e. A2 will always mask the phenotypic expression of A3. This overall means that the trait encoded by allele A3 will only be expressed when the same alleles are present.

To the question; since A1 is dominant over the other two alleles (A2 and A3), it will be phenotypically expressed ahead of them in a heterozygous state with both alleles. That is, A1A2 genotype will give rise to a phenotype encoded by A1. Also, A1A3 will produce a phenotype encoded by A1. Hence, genotypes A1A2 and A1A3 will express the same phenotypes.

A2A2 and A3A3 will express different phenotypes since they are both in a same alleles condition. Likewise for A1A1 and A3A3. A2A3 and A1A3 genotypes will express different phenotypes encoded by A2 and A1 respectively since they are both dominant over A3.

In an accident with farm machinery, Mr. Roque had his left arm severed just below the elbow. Mrs. Roque stopped the bleeding, called for an ambulance, and packed the severed arm in ice for the EMTs to take to the hospital. Will Mr. Roque ever be able to move the fingers of his left hand again? What structures must be reattached, and what has to happen?

Answers

Answer:

The mentioned case of arm severing is considered as major surgery, and the restructuring of the severed arm is only possible when Mr. Roque will reach the hospital within four to five hours of the incident, also known as the window period.  

After performing the surgery, Mr. Roque may regain movement in the arm to some extent after performing certain kinds of exercises, however, he may not feel the sensations in the fingers of his left hand again. The entire process of healing of the severity may take about two to three years, and in certain cases, the body fails to heal completely, and the affected limb may lose its function entirely.  

In the given case, the structures that are required to get reattached are the muscles of the forearm and the blood vessels and the nerve supply to the affected region. The systematic arrangement of these structures is done with the help of surgery. However, after the surgery, the patient is recommended to perform certain kinds of hand and finger muscle exercises so that the functioning of the arm get regain slowly and gradually.  

45-year-old was admitted with sarcoidosis of both lungs. An extracorporeal perfusion of donor lungs, from an unrelated donor, and successful bilateral lung transplantation were completed without any complications. What is the second code you should assign

Answers

Answer:

The second code in this case is the procedure for perfusion

Explanation:

Extracorporeal perfusion is the process of diverting the patient's blood via an artificial circulatory device to enable the gas exchange (oxygen absorbed, carbon dioxide removed) to take place. Only medical experts should handle this procedure so as to avoid any and all undesired scenarios or negligence towards patient care.  

In garden peas, the allele for tall plants (T) is dominant over the allele for dwarf plants (t). A true-breeding tall plant is bred with a true-breeding dwarf plant to produce heterozygous tall plants. The F1 heterozygotes then self-fertilize to yield F2 offspring. Complete the Punnett square for this monohybrid cross using the F1 gametes with the appropriate genotype and placing the correct F2 genotype/phenotype combination in the Punnett square.Male gamete TT Tall Tt Tall Female gamete Tt Tall tt Dwarf For each of the following. determine the probability that a child will be affected with the given condition.Consider the following genotypes and phenotypes:BB, Bb, yellow(normal) urinebb, beeturia(red urine after eating beets)HH, Hh, colored eyelidshh, normal eyelidsEE, Ee, brachydactyla(short fingers)ee, normal fingers1. If a man and woman both have a genotype Ee, then what is the probability that their child wii have normal fingers?2, If a man has a normal urine and genotype Bb and woman has beeturia and genotype bb what is the probability that the child will have beeturia fingers?3. What is the probability that their child will have colored eyelids?4. What is the probability that their child will have colored and beeturia eyelids?

Answers

Answer:

Explanation:

TT ×tt

I

Tt Tt Tt Tt

Where Tt Tt Tt TT are the genotype for the first filial generation.

To generate the 2nd filial generation, we self the 1st generation.

Tt × Tt

I

TT Tt Tt tt

We have TT Tt Tt tt as the second filial generation.

If a man and a woman both have Ee the probability that the child will have normal finger is 1/4

Ee × Ee

I

EE Ee Ee ee

Where EE, Ee is brachydactly and ee is normal finger.

When a man with normal eye is crossed with a man with beeturia the probability of having a child with beeturia 2/4

Bb × bb

I

Bb bb Bb bb

Where BB Bb is normal eye and bb is beeturia

When a man with colored eye lid HH is crossed with normal eyes lid hh the probability of having a child with color eyes lid is 1

HH × hh

I

Hh Hh Hh Hh

Where Hh represent normal eyes lid

In a songbird species, defending a territory saved the bird 584 calories a day in reduced foraging activity, but cost the bird 656 calories in defense of the territory. Is defending the territory consistent with the prediction from optimal foraging theory, and what can explain this

Answers

Answer:

The correct answer is "No, this is not consistent with the predictions on optimality".

Explanation:

The optimal foraging theory (OFT) establishes that an organism looks for the best foraging strategy, which involves maximizing the amount of energy that is available in its daily activities. In this case, the songbird species is not consistent with the predictions on optimality since it needs more calories than it intakes in order to defend its territory. In this scenario, the songbird will lose 72 calories per day.

Many types of cancer are known to overexpress the receptor protein tyrosine kinase. Which molecular technique can be used to reduce expression of tyrosine kinase in cell culture?

Answers

Answer:

By phosphorylation or by activating cyclin-dependent kinase-mediated signaling pathways

Explanation:

The Cyclin-Dependent Kinases (Cdks) are a family of critical regulatory proteins capable of modulating the progression through the cell cycle. Cdks are in turn regulated by binding to cyclin proteins or by phosphorylation at specific amino acid residues (generally tyrosine and threonine).

Phosphorylation is the most widely studied posttranslational modification and it is known to inhibit (and also activate) protein function, while cyclin-dependent kinases are proteins known to inhibit the activity of Cdks and thereby acting as tumor suppressors by inducing cell death-apoptosis.

many people try to eliminate fat from their diet

Answers

Answer:

yes they do

Explanation:

they do because they don't want to be big chungus anymore, they want to be a skinny queen

BEFORE equilibrium has been reached in this container: (Circle a letter for each) 1. Movement of glucose across the membrane in this container can best be described as A. Solution A to Solution B B. Solution B to Solution A C. both directions D. neither direction

Answers

Hello. You forgot to put the image so that this question can be answered, but I will describe what the image shows.

The image shows two types of "cups" that have a type of connection between the two. In cup A there is 1 mole of glucose and 1 mole of fructose. In cup B there is 0.1 mol of glucose and 1.5 mol of fructose.

Answer:

A. Solution A to Solution B

Explanation:

Balance is achieved when the "cup" with the lowest concentration of glucose receives glucose from the "cup" with the highest concentration, to the point that the two glasses establish equal concentrations of glucose between them.

We know that cup B has a lower concentration of glucose, which indicates that the movement of this solute was from cup A towards cup B. With this we can conclude that the letter A is the correct answer.

Macromolecules in the cell can often interact transiently as a result of noncovalent interactions. These weak interactions also produce stable, highly specific interactions between molecules. Which of the factors below is the most significant in determining whether the interaction will be transient or stable?
a) the size of each molecule
b) the number of chemical bonds between the molecules
c) the concentration of each molecule
d) rate of synthesis

Answers

Answer:

The correct answer is option b) "the number of chemical bonds between the molecules".

Explanation:

Chemical bonds are the forces that enable the formation of compounds. The number of chemical bonds is a determining factor to know if an interaction will be transient of stable. The more chemical bonds the more stable an interaction will be. Few chemical bonds between molecules makes an interaction unstable and easy to break, enabling transient interactions that are key to certain biological pathways.

Draw a carbon monoxide molecular

Answers

Answer:

               C==O

Explanation:

Which factors affect the rate of photosynthesis select all that apply

Answers

Answer:

Limiting factors such as

Effect of temperature

Effect of light intensity

Concentration of carbon dioxide

These all factors can affect the rate of photosynthesis

Explanation:

I hope it will help you

Answer:

light intestity

rate of oxygen

carbon4oxide concentration

temperature

25
The basic unit of life is a(n)

Answers

Answer:

Air, water life without these is nothing

Answer:

A cell is the smallest unit of a living thing. A living thing, whether made of one cell (like bacteria) or many cells (like a human), is called an organism. Thus, cells are the basic building blocks of all organisms

Explanation:

Biochemical changes in the body, that affect the rate of metabolism and elimination of a substance from the body and produce increased amounts to achieve the desired effects, may lead to development of

Answers

Answer:

Tolerance

Explanation:

Tolerance is the capacity of an organism to survive changes in certain environmental and biochemical conditions. It has to with changes an organism is able to withstand when is subjected to certain factors which can biotic or abiotic.

For example, in the consumption of alcohol, tolerance can occur when there is a fast elimination of alcohol from the body system. This is usually as a result of the activation of a group of enzymes that is responsible for the metabolism of alcohol in excessive alcohol drinkers. The activation of this enzymes increases the catabolism of alcohol and hence reduces the active time within the body, hence reducing the time by which alcohol intoxicates.

What do eukaryotic cells have that prokaryotic cells do not?

Answers

There are several differences between the two, but the biggest distinction between them is that eukaryotic cells have a distinct nucleus containing the cell's genetic material, while prokaryotic cells don't have a nucleus and have free-floating genetic material instead.

If the Hemoccult test result is negative, no further testing is done. If the Hemoccult test result is positive, the individual will have a second stool sample tested with the Hemoccult II test. If this second sample also tests positive for blood, the individual will be referred for more extensive evaluation. What is the effect on net sensitivity and net specificity of this method of screening

Answers

Answer:

Hemoccult test sensitivity is 89.3% and specificity is 92.7%

Explanation:

Hemoccult test is a test that is carried out in order to find out the presence of occult blood in your stool. This method is used to detect colorectal cancer in your body. Blue color of the blood indicate that the test is positive while the green color represents that the test is negative. Test sensitivity is the ability of a test which identify the person who is affected with the disease i. e. true positive, whereas test specificity is the ability of the test to correctly identify the patient without the disease. The value of sensitivity of the Hemoccult test is 89.3% the specificity is 92.7%, and the positive predictive value is 2.5%.

there are more hydrogen atoms in living organisms than any other atoms are asking is more abundant in the terms Mass why is this statement true​

Answers

Answer:

The statement is true because most organisms are made of water, and water consists of mostly hydrogen (atoms) since its chemical formula is H2O.

Which type of mutation results in a frame shift mutation? Check all that apply? Substitute Insertion Deletion Point mutation

Answers

Answer: Insertion, Deletion

Explanation:

The frameshift mutation can be defined as a genetic mutation that is caused by the deletion or insertion of the DNA sequence or base pairs that shifts the sequence to be read. As a result of this the abnormal proteins are produced along with incorrect amino acid sequence that either shorter or longer than the normal protein.

smear samples from patient admitted at the kole-teaching hospital with boils and abscesses were brought to the laboratory for staining and microscopic examination. As an upcoming microbiologist state the keeping steps you would to stain the smear using Gram stain.upon examination, you've found blue coloured graped-cluster berry round the cell
1.what could be the outcome of the Gram staining reaction
2.what could be this bacterium and why

Answers

Answer:

It could be a Staphylococcus or also called Staphylococcus, due to the disposition it presents.

Explanation:

Staphylococci are coconuts (rounded shape) that unite in the form of a bunch of grapes, this is characteristic of them.

It could become a Staphylococ Aureus, since these are usually associated with the most frequent infections in humans, but the possibility that it is another type of the same bacterial family is not ruled out.

A single point mutation in a gene results in a nonfunctional protein. Individuals heterozygous for this mutation were identified using a Southern blot. Which pair of wild-type (WT) and mutant alleles most likely contains the mutation?
A. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCGATGCTTAGGCATCT-3
B. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCGAAGCTTAGGCATAT-3
C. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTTGAAGCTTAGGCATCT-3
D. WT 5-TAGTCGAAGCTTAGGCATCT-3
Mutant 5-TAGTCCAAGCTTAGGCATCT-3

Answers

Answer:

C. WT 5-TAGTCGAAGCTTAGGCATCT-3

Mutant 5-TAGTTGAAGCTTAGGCATCT-3

Explanation:

In the wild type, the DNA sequence encodes the following aminoacidic segment: SRSLGI; while the mutant form has a stop codon in the second codon (TGA). A stop codon is a trinucleotide sequence in the messenger RNA (mRNA) that indicates a stop signal in protein synthesis. There are three types of stop codons: UGA, UAG and UAA, where U represents Uracile in the mRNA instead of Thymine in the DNA sequence.

Representation:  

C. WT 5-T AGT CGA AGC TTA GGC ATC T-3 >> 5'3' Frame 1 = SRSLGI

Mutant 5-T AGT TGA AGC TTA GGC ATC T-3 >> 5'3' Frame 1 = S-, where - represents a stop codon (TGA) and therefore it is the end of the protein.

dependent and independent variable hi guys please help me i want an example of indepent and depent variable for ech variable example Note : please in science not in math in science Gratefully , Brainly Sthay home and keep safe

Answers

Answer:

The quantities between which a graph is plotted are called variables.The independent variables are those which do not depend on other quanitity for example time.The dependents variables are those which depend on other quantity for example velocity,acceleration,speed,momentum etc.

Answer:

It is B,D,E

(✿◠‿◠)

Which of these is an organism?

Answers

Answer:

A wolf...........

.......................

Answer:

I believe the answer is heart

As global warming continues the oceans absorb more of the earths heat. What term describes the ocean as a storage location for this heat

Answers

Answer:

do you have any options for this question?

Suppose a plant breeder wants to isolate mutants in tomatoes that are defective in DNA repair. However, this breeder does not have the expertise or equipment to study enzymes in DNA repair systems.
Which methods would best allow the breeder to identify tomato plants that are deficient in DNA repair?
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants. Measure the somatic mutation rates for the putative DNA repair mutant plants.
C) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
D) Measure the germ line spontaneous and induced mutation rates for the putative DNA repair mutant plants.

Answers

The provided question has marked options incorrectely the correct order as follows:

A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.

B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants.

C) Measure the somatic mutation rates for the putative DNA repair mutant plants.

D) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.

E) Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.

Answer:

The correct answer is: A), C) and E)

Explanation:

The breeder wants to isolate the mutants in tomatoes that are defective in DNA repair, to identify such plants breeder should follow these methods as they will allow best to identifying the defective tomatoes-

Measure the somatic mutation rates for the putative DNA repair mutant plants.

Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.

Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.  This will allow the breeder to see and analyze the ability of DNA repair in tomatoes

Why are enzymes important to cells? Why does an egg change color and texture when heated?

Answers

When you boil an egg, it goes from liquid to solid because the heat breaks and reconfigures the hydrogen bonds between amino-acids in the egg proteins. You permanently change the shape of the proteins, and so permanently change their qualities (in this case, texture).

Each trait of a plant is determined by _____.
A) an allele
B) one gene
C) a pair of genes
D) one dominant gene

Answers

Answer:

c. a pair of genes

Explanation:

Answer:

C) a pair of genes

Explanation:

C should be correct because each trait is controlled my multiple genes. It is very rare to see one thing being controlled strictly by one gene, rather multiple things work together to produce the traits. Living things are very amazing if you dive deep into their DNA level,

infIdentify flexor digitorum profundus in the right upper limb and the ulnar vein that is immediately superficial to it on its medial surface. What is the correct order of veins that blood flows through to reach the heart from the right flexor digitorum profundus and the right ulnar vein

Answers

Answer:

The upper region of the body veins carries blood that has no oxygen to the heart through superior vena cava and the lower part of the blood with no oxygen will transfer to the heart with the help of superior vena cava.

In Right hand:

At first, blood in the palmar region or distal end of the arm deoxygenated blood from this side will go to the following manner -

right ulnar vein - to the right Axillary vein - to the right subclavian vein - Right internal jugular vein - right brachiocephalic vein and finally it reaches the superior vena cava of the heart.

The same pathway will take place on the left side of the upper region of the body.

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