Identify the amplitude in the wave image below.*
F. G H J

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is [tex]12.5\ km[/tex]

Speed of car is [tex]100\ km/h[/tex]

Car drives for [tex]30\ \text{minute}\ or\ 0.5\ hr[/tex]

(a)Distance traveled is

[tex]\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km[/tex]

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by [tex]\frac{5}{18}[/tex]

[tex]\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s[/tex]

Answer:

The magnitude of the free-fall acceleration at the orbit of the Moon is [tex]2.728\times 10^{-3}\,\frac{m}{s^{2}}[/tex] ([tex]\frac{2.784}{10000}\cdot g[/tex], where [tex]g = 9.8\,\frac{m}{s^{2}}[/tex]).

Explanation:

According to the Newton's Law of Gravitation, free fall acceleration ([tex]g[/tex]), in meters per square second, is directly proportional to the mass of the Earth ([tex]M[/tex]), in kilograms, and inversely proportional to the distance from the center of the Earth ([tex]r[/tex]), in meters:

[tex]g = \frac{G\cdot M}{r^{2}}[/tex] (1)

Where:

[tex]G[/tex] - Gravitational constant, in cubic meters per kilogram-square second.

[tex]M[/tex] - Mass of the Earth, in kilograms.

[tex]r[/tex] - Distance from the center of the Earth, in meters.

If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 5.972\times 10^{24}\,kg[/tex] and [tex]r = 382.26\times 10^{6}\,m[/tex], then the free-fall acceleration at the orbit of the Moon is:

[tex]g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(382.26\times 10^{6}\,m)^{2}}[/tex]

[tex]g = 2.728\times 10^{-3}\,\frac{m}{s^{2}}[/tex]

Answer:

d = 1.51 x 10⁻⁵ m = 15.1 μm

Explanation:

We will use young's Double Slit formula here:

[tex]Y = \frac{\lambda L}{d}\\\\d = \frac{\lambda L}{Y}[/tex]

where,

d = width of strand = ?

λ = wavelength = 631.8 nm = 6.318 x 10⁻⁷ m

L = Screen to hair distance = 1.2 m

Y = fringe spacing = 5.02 cm = 0.0502 m

Therefore,

[tex]d = \frac{(6.318\ x\ 10^{-7}\ m)(1.2\ m)}{0.0502\ m}[/tex]

d = 1.51 x 10⁻⁵ m = 15.1 μm

AnWind power or wind energy is the use of wind to provide mechanical power through wind turbines to turn electric generators for electrical power. Wind power is a popular sustainable, renewable source of power that has a much smaller impact on the environment compared to burning fossil fuels. Wind farms consist of many individual wind turbines, which are connected to the electric power transmission network. Onshore wind is an inexpensive source of electric power, competitive with or in many places cheaper than coal or gas plants. Onshore wind farms have a greater visual impact on the landscape than other power stations, as they need to be spread over more land and need to be built away from dense population. Offshore wind is steadier and stronger than on land and offshore farms have less visual impact, but construction and maintenance costs are significantly higher. Small onshore wind farms can feed some energy into the grid or provide power to isolated off-grid locations. The wind is an intermittent energy source, which cannot be dispatched on demand. Locally, it gives variable power, which is consistent from year to year but varies greatly over shorter time scales. Therefore, it must be used together with other power sources to give a reliable supply. Power-management techniques such as having dispatchable power sources (often gas-fired power plant or hydroelectric power), excess capacity, geographically distributed turbines, exporting and importing power to neighboring areas, grid storage, reducing demand when wind production is low, and curtailing occasional excess wind power, are used to overcome these problems. As the proportion of wind power in a region increases the grid may need to be upgraded. Weather forecasting permits the electric-power network to be readied for the predictable variations in production that occur. In 2019, wind supplied 1430 TWh of electricity, which was 5.3% of worldwide electrical generation, with the global installed wind power capacity reaching more than 651 G…swer:

Explanation:

Answer:

Explanation:

The most likely thing that would happen is that the galaxies continue becoming more and more massive, eventually becoming part of a galaxy cluster. These are massive but cluttered parts of the universe that hold many galaxies extremely close to one another. This also leads to galaxies colliding with one another, although when this happens they usually seem to pass right through each other as if they were ghosts. This is simply due to their sheer size and distance between their bodies of mass.

Answer:

It will merge with other galaxies

Explanation:

Pearson Connexus 2023

Answer:

The unknown substance is Aluminum.

Explanation:

We'll begin by calculating the change in the temperature of substance. This can be obtained as follow:

Initial temperature (T₁) = 25 ⁰C

Final temperature (T₂) = 100 ⁰C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 25

ΔT = 75 ⁰C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Change in temperature (ΔT) = 75 ⁰C

Mass of the substance (M) = 135 g

Heat (Q) gained = 9133 J

Specific heat capacity (C) of substance =?

Q = MCΔT

9133 = 135 × C × 75

9133 = 10125 × C

Divide both side by 10125

C = 9133 / 10125

C = 0.902 J/gºC

Thus, the specific heat capacity of substance is 0.902 J/gºC

Comparing the specific heat capacity (i.e 0.902 J/gºC) of substance to those given in the table above, we can see clearly that the unknown substance is aluminum.

Answer:

Explanation:

Given that:

the initial angular velocity [tex]\omega_o = 0[/tex]

angular acceleration [tex]\alpha[/tex] = 4.44 rad/s²

Using the formula:

[tex]\omega = \omega_o+ \alpha t[/tex]

Making t the subject of the formula:

[tex]t= \dfrac{\omega- \omega_o}{ \alpha }[/tex]

where;

[tex]\omega = 1.53 \ rad/s^2[/tex]

∴

[tex]t= \dfrac{1.53-0}{4.44 }[/tex]

t = 0.345 s

b)

Using the formula:

[tex]\omega ^2 = \omega _o^2 + 2 \alpha \theta[/tex]

here;

[tex]\theta[/tex] = angular displacement

∴

[tex]\theta = \dfrac{\omega^2 - \omega_o^2}{2 \alpha }[/tex]

[tex]\theta = \dfrac{(1.53)^2 -0^2}{2 (4.44) }[/tex]

[tex]\theta =0.264 \ rad[/tex]

Recall that:

2π rad = 1 revolution

Then;

0.264 rad = (x) revolution

[tex]x = \dfrac{0.264 \times 1}{2 \pi}[/tex]

x = 0.042 revolutions

c)

Here; force = 270 N

radius = 1.20 m

The torque = F * r

[tex]\tau = 270 \times 1.20 \\ \\ \tau = 324 \ Nm[/tex]

However;

From the moment of inertia;

[tex]Torque( \tau) = I \alpha \\ \\ Since( I \alpha) = 324 \ Nm. \\ \\ Then; \\ \\ \alpha= \dfrac{324}{I}[/tex]

given that;

I = 84.4 kg.m²

[tex]\alpha= \dfrac{324}{84.4} \\ \\ \alpha=3.84 \ rad/s^2[/tex]

For re-tardation; [tex]\alpha=-3.84 \ rad/s^2[/tex]

Using the equation

[tex]t= \dfrac{\omega- \omega_o}{ \alpha }[/tex]

[tex]t= \dfrac{0-1.53}{ -3.84 }[/tex]

[tex]t= \dfrac{1.53}{ 3.84 }[/tex]

t = 0.398s

The required time it takes= 0.398s

Answer:

Movement of Electrons in opposite direction of the rotation of the pickup coil leads to the direction of Electrical energy ( Alternating current ).

Explanation:

For a Generator to generate electricity, Electrons that is found in the rotating coil of the Generator will experience some sort of force that makes them to start moving in a direction that is perpendicular to the direction of the rotating/pickup coil found in the Generator.

The conversion of mechanical energy (Rotation of the pickup coil ) to electrical energy takes place in the Generator

The generator makes an alternating current because electrons move in opposite direction of the rotating coil

In other to generate a Direct current using a generator we have to replace the slip rings with commutator.

Answer:

In the morning the molecules were moving away from each other with a smaller speed than when the truck was carrying the substance.

Explanation:

Answer:

0.50 A

Explanation:

We can find the current from this through Ohm's Law:

V = IR

Now, in it's original form, we're only looking for Voltage. However, we can switch this formula around to find each part of it:

I = V / R (current)

R = V / I (resistance)

In this case, we'll use the formula for current:

V = 120 V

R = 240 Ω

I = ?

I = 120 / 240

I = 0.5 A

Answer:

Answer:

Distance = 6 m

Time = 5.2 sec

speed = x

formula to find speed is distance upon time

Now,

speed = 6/5.2

speed = 1.15

Answer:

a) the period of vibration of the bird’s wings is 0.0667s

b) the frequency of the wings’ vibration is 15 Hz

c) the angular frequency of the bird’s wingbeats is 94.2 rad/s

Explanation:

Given the data in the question;

beat at a rate of up to 900 times per minute.

The number of vibrations per unit time can be be determined as follows;

frequency f = number of vibration / time ---------- let this be equation 1

Also Time period T is;

T = 1/f { time period and frequency are reciprocal to each other }

T = 1/f ---------- Let this be equation 2

Then, the angular frequency ω can be determined using the formular;

ω = 2π × f -------------- Let this be equation 3.

Now, given that; The wings of the blue-throated hummingbird beat at a rate of up to 900 times per minute; Hence,

from equation 1, frequency f = number of vibration / time

f = 900 / 1 min

f = 900 / 60 sec

f = 15 Hz

Therefore, the frequency of the wings’ vibration is 15 Hz

a) the period of vibration of the bird’s wings

from equation 2, T = 1/f ,

we substitute in the value of f

T = 1 / 15 Hz

T = 0.0667s

Therefore, the period of vibration of the bird’s wings is 0.0667s

c) the angular frequency of the bird’s wingbeats;

from equation 3, ω = 2π × f

we substitute

ω = 2π × 15 Hz

ω = 94.2 rad/s

Therefore, the angular frequency of the bird’s wingbeats is 94.2 rad/s

Answer:

49.5 m/s

Explanation:

Let's use the energy approach to solve this problem.

We are given the mass and displacement of the boulder.

The formula for potential energy is PE = mgh.

The formula for kinetic energy is KE = 1/2mv².

If we ignore air resistance, we can use the conservation of energy to solve this problem by setting PE and KE equal to each other. By doing so, we realize that the mass of the boulder does not affect the speed that it hits the ground (final velocity).

Divide both sides of the equation by m.

Let's take the downwards direction as positive. The displacement of the boulder is 125 m and g = 9.8 m/s².

Now we can solve for v.

Multiply both sides by 2.

Take the square root of both sides.

Rounded to the nearest 0.1 m/s, the final velocity of the boulder is 49.5 m/s.

Solution :

Given data:

Area of the solar sail, A = 16 [tex]$m^2$[/tex]

Mass (array + sail), m = [tex]$3 \times 10^{-3}$[/tex] kg

Power, P = 100 GW

               = [tex]$10^{11}$[/tex] W

Time, t = 10 min

           = 10 x  60 s

Distance, D = [tex]$4.3 \times 4 \times 10^{16}$[/tex] m

Kinetic energy, [tex]$KE=\frac{1}{2}mv^2=P\times t$[/tex]

[tex]$v=\sqrt{\frac{2Pt}{m}}$[/tex]

[tex]$v=\sqrt{\frac{2\times 10^{11}\times 600}{3 \times 10^{-3}}}$[/tex]

  [tex]$=2 \times 10^8$[/tex] m/s

So, the acceleration is [tex]$a=\frac{v}{t}$[/tex]

[tex]$a=\frac{2 \times 10^8}{6 \times 10^2} \ m/s^2$[/tex]

 [tex]$=333333.33 \ m/s^2$[/tex]

Therefore, force,

[tex]$F = ma$[/tex]

   [tex]$=3 \times 10^{-3}\times 333333.33$[/tex]

   = 1000 N

Pressure, [tex]$P=\frac{F}{A}$[/tex]

                   [tex]$=\frac{1000}{16}$[/tex]

                   [tex]$=62.5 \ N/m^2$[/tex]

Therefore, time taken is t

Now the distance is

[tex]$d_1=\frac{1}{2}at_1^2$[/tex]

[tex]$d_1=0.5 \times 333333.33 \times (600)^2$[/tex]

    [tex]$=6 \times 10^{10} \ m$[/tex]

Now, the distance, [tex]$d_2 = D-d_1=v.t_2$[/tex]

Now, [tex]$t_2=\frac{(17.2 \times 10^{16})-(6 \times 10^{10})}{2 \times 10^8}$[/tex]

            = 859999700 s

Therefore, total time is

[tex]$T=t_1+t_2$[/tex]

  = 86000300 s

  = 27.27 years

Answer:

6 W

Explanation:

From the given information:

The resistance in Parallel for 2R is:

[tex]R_p = \dfrac{2R\times 2R}{2R+2R} \\ \\ R_p= R[/tex]

The equivalent resistance:

[tex]R_{eq} = R_p + R = 2R[/tex]

[tex]R_{eq} = 2(3)[/tex]

[tex]R_{eq} = 6 \ \ ohms[/tex]

The current through the circuit in R is:

[tex]= \dfrac{12}{R+R} \\ \\ = \dfrac{12}{2\times 3} \\ \\ = 2 A[/tex]

The current through the circuit in 2R is:

[tex]I_2R = (2A) \times \dfrac{2R}{2R+2R}[/tex]

[tex]I_2R = 2A \times \dfrac{1}{2} \\ \\ I_2R = 1A[/tex]

Finally, the thermal energy:

[tex]P_{2R} = (1)^2 (2R)[/tex]

[tex]P_{2R} = (1)^2 (2\times 3)[/tex]

[tex]P_{2R} = 6W[/tex]

Answer:

r = 1.07 m

Explanation:

The maximum radius of the propeller that can be allowed is given by the following formula:

[tex]v = r\omega\\\\r = \frac{v}{\omega}[/tex]

where,

r = maximum possible radius of the propeller = ?

v = maximum possible linear speed of the propeller = 270 m/s

ω = angular speed of the propeller = (2400 rpm)(2π rad/1 rev)(1 min/60 s)

ω = 251.33 rad/s

Therefore,

[tex]r = \frac{270\ m/s}{251.33\ rad/s}[/tex]

r = 1.07 m

Answer:

I believe it’s A

Explanation:

Answer:

A is correct (1 nm to 100 nm)

Explanation:

I just took the exam

Answer: 3.28 s, 14.76 m

Explanation:

Given

Water moves horizontally with a speed of [tex]v=4.5\ m/s[/tex]

It falls from a height of [tex]h=53\ m[/tex]

Time is taken to fall this much height is

[tex]\Rightarrow t=\sqrt{\dfrac{2h}{g}}\quad [\text{As there is no initial vertical velocity}]\\\\\Rightarrow t=\sqrt{\dfrac{2\times 53}{9.8}}\\\\\Rightarrow t=3.28\ s[/tex]

In this time, water moves horizontally by

[tex]\Rightarrow d=4.5\times 3.28\\\Rightarrow d=14.76\ m[/tex]

Answer:

Heat transfer is an engineering discipline that concerns the generation, use, conversion, and exchange of heat (thermal energy) between physical systems.

Explanation:

Answer:

Heat transfer is a discipline of thermal engineering that concerns the generation, use, conversion, and exchange of thermal energy between physical systems. Heat transfer is classified into various mechanisms, such as thermal conduction, thermal convection, thermal radiation, and transfer of energy by phase changes.

Explanation:

hope that helps

Answer:

1. Laod = 500 N

2. Effort = 250 N

Explanation:

From the question given above, the following data were obtained:

Input work = 187.5 J

Output work = 125 J

Load distance = 25 cm

Effort distance = 75 cm

1. Determination of the load.

Output work = 125 J

Load distance = 25 cm = 25/100 = 0.25 m

Load =?

Output work = Load × Load distance

125 = Load × 0.25

Divide both side by 0.25

Load = 125 / 0.25

Laod = 500 N

2. Determination of the effort.

Input work = 187.5 J

Effort distance = 75 cm = 75/100 = 0.75 m

Effort =?

Input work = Effort × Effort distance

187.5 = Effort × 0.75

Divide both side by 0.75

Effort = 187.5 / 0.75

Effort = 250 N

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. [beep] A single lap should be completed each time you hear this sound. [ding] Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over. The test will begin on the word start. On your mark, get ready, start.

Answer:

Power lines

Explanation:

Generators induce that current that runs the turbines

Turbines also induce currents from water waves that is transmitted.

Transformers change A.C to D.C or vice versa.

Answer:

Bubbles paused

Explanation:

the air bubble doesn't rise because it is no lighter than the water around it—there's no buoyancy. The droplet doesn't fall from the leaf because there's no force to pull it off. It's stuck there by molecular adhesion.

for instance, onto the International Space Station, gravity becomes negligible, and the laws of physics act differently than here on Earth

On Earth, the buoyancy of the air bubbles causes them to rise to the top together, creating a segregation between air and water. However, in microgravity, nothing forces the air bubbles to interact and thus rise together, Green said.

Answer:

SEE EXPLANATION

Explanation:

The dimensional formula of gravitational constant is given by,

M^-1 L^3 T^-2  

Where,  

M = Mass

L = Length

T = Time

Dimensional formula of Specific Heat Capacity =[ M^0L^2T^-2K^-1]

Answer:

x = 4 m

Explanation:

For this exercise we must use the rotational equilibrium relationship, where we place zero at the turning point and counterclockwise rotations we will consider positive

as it indicates that the bar is in equilibrium, its center of mass coincides with the turning point, so the distance is zero and does not create torque on the system

        ∑τ  = 0

        W 3 - w x = 0

        x = 3W / w

        x = 3 Mg / mg

        x = 3 M / m

let's calculate

       x = 3 60/45

       x = 4 m

Answer:

No, it does not.

Explanation:

According to the Law of Gravitation, something going down has more kinetic energy than something going up because it attracts pressure from around it when going down. When it goes up, it has less gravitational force and inertia also stops the ball from rolling upward. Therefore, without the amount of kinetic energy, it will not have the same amount of acceleration.