(I really need this to boost my grade)

Label the permeable and impermeable rock layers

Answers

Answer 1

Answer: HI your question is incomplete but i will provide a general answer that can help you

answer : Permeable Rock layers allow the flow of fluid like substances through them, While Impermeable rock layers do not allow the flow of fluid like substance through them.

Explanation:

Permeable rocks are rocks containing pores through Fluid like substances can penetrate through in the rocks. examples of Permeable rocks are ; Sandstones and Chalk

While an Impermeable rock is a rock that does not allow the flow of fluid like substance through it due to the absence of pores in its rock layers . examples of such rock are ; Clay and marble  

Although some permeable rocks might exhibit low level of permeability as well but generally Rock sample with pores are classified as permeable rock layers.


Related Questions


HELP PLSSS, IM SO CONFUSED

Answers

4. DNA is something you’re born with and cannot change. it is designed specifically to you. it’s your “blueprint”

5. 94,696.9696- miles

Which statement is true? (1 point)
O Fossils cannot provide information about relatedness of life forms.
O Fossils can provide information about when life forms existed.
O Fossils cannot provide information about life cycles and behaviors.
O Fossils can provide information about the entire evolutionary process of life forms.

Please help! I will give you Brainly !

Answers

Answer:

1. fossils can provide information about when life forms existed

2.3

3.they can show false relationships between organisms that are not reflected in the DNA

4.Living things have adapted and changed over time for specific, discoverable reasons

5.This suggests that all of these species share a common ancestor

Explanation:

Fossils give us information about how animals and plants lived in the past.

Fossils can provide information about when life forms existed.

Fossils can provide information about the entire evolutionary process of life forms.

What are Fossils?Fossil of an animal or plant has been preserved in Earth’s crust. It is the primary source of information about the history of life on Earth.Fossils are the undecayed remains of the living organisms. These remain preserved inside the lining of sediments.

Thus, we can conclude that the correct options are A and D.

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How is editing the genetic code different from artificial selection?



A It enables humans to influence the inheritance of DNA

B It enables humans to directly change DNA

C It can only be used on animal DNA

D It is not yet possible to edit the genetic code

Answers

Answer:

Option B

Explanation:

Artificial selection is influencing of inheritance of any trait . in this limited options are given to allow a species to mate and produce offspring

In genetic code editing directly genes are edited.

Hence, option B is correct

Describe the environment you live in

Answers

Answer:

El entorno de donde vives es que tienes que salir afuera mirar que naturaleza hay por ejemplo afuera de mi casa hay un árbol eso es ya una naturaleza afuera hay una calle fuera de mi casa hay animales domesticados afuera de mi casa hay vecinos pero no te confundas estas hablando de la naturaleza así que solo pon sobre las plantas arboles frutos v de lo que es las plantas o naturalezas espero que te sira

Explanation:

corona plis

Our hair and nail contain
Α. Protein
B Calcium
C Chlorine
D Phosphorus.​

Answers

Answer:

protein

Explanation:

our hair and nail contain option ( D) protein.nails and hairs of one body's made up of follicles and matris.

Dr. Nachman and his colleagues collected rock pocket mice across 35 kilometers of the Arizona Sonoran Desert, which included both dark, rocky lava outcrops and light, rocky, granite areas. They recorded substrate color, and coat-color frequencies for each location. Each site was separated from any of the others by at least eight kilometers. The researchers trapped a total of 275 mice. Their data are summarized below:

Collecting Site Substrate Color Number of Mice Phenotype
Light Dark
1 Dark 22 3 19
2 Light 80 74 6
3 Light 22 19 3
4 Dark 28 3 25
5 Light 58 25 33
6 Dark 65 9 56


Required:
a. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on light-colored substrates.
b. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on dark-colored substrates.
c. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the light, rocky, granite substrate. For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.

Answers

Complete question

Dr. Nachman and his colleagues collected rock pocket mice across 35 kilometers of the Arizona Sonoran Desert, which included both dark, rocky lava outcrops and light, rocky, granite areas. They recorded substrate color, and coat-color frequencies for each location. Each site was separated from any of the others by at least eight kilometers. The researchers trapped a total of 275 mice. Their data are summarized below (numbers have been slightly modified for the purposes of this worksheet).

Field Data Summary

Collecting Site Substrate Color Number of Mice Phenotype Light Dark

1 Dark 22 3 19

2 Light 80 74 6

3 Light 22 19 3

4 Dark 28 3 25

5 Light 58 25 33

6 Dark 65 9 56

1. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on light-colored substrates. [to 3 decimal places]

2. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on dark-colored substrates. (to 3 decimal places)

3. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the light, rocky, granite substrate. For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.

4. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the dark, rocky lava substrate. (to 3 decimals). For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.

5. Which fur color seems to have the greatest overall selective advantage? Use data collected from both dark-colored and light- colored substrates to support your answer.

6.What environmental change gave a selective advantage for one coat color over another?

7. In a separate study, 76 rock pocket mice were collected from four different, widely separated areas of dark lava rock. One collecting site was in Arizona. The other three were in New Mexico. Dr. Nachman and colleagues observed no significant differences in the color of the rocks in the four locations sampled. However, the dark-colored mice from the three New Mexico locations were slightly darker than the dark-colored mice from the Arizona population. The entire Mc1r gene was sequenced in all 76 of the mice collected. The mutations responsible for the dark fur color in the Arizona mice were absent from the three different populations of New Mexico mice. No Mc1r mutations were associated with dark fur color in the New Mexico populations. These findings suggest that adaptive dark coloration has occurred at least twice in the rock pocket mouse and that these similar phenotypic changes have different genetic bases. How does this study support the concept that natural selection is not random?

8. To determine if the rock pocket mouse population is evolving, explain why it is necessary to collect fur color frequency data over a period of many years.

Answer:

1)

frequencies of light-colored mice  ≅ 0.74 frequencies of dark-colored mice  ≅ 0.26

2)

frequencies of light-colored mice ≅ 0.13 frequencies of dark-colored mice ≅ 0.87

3)

p² ≅ 0.02 q² ≅ 0.74 2pq ≅ 0.24

4)

q² = 0.13 p² = 0.4 2pq = 0.46

5) The dark-colored fur seems to have the greatest overall selective advantage

6) Dark lava changed the color of the substrate, from light to dark.

7) Because to produce dark color, animals from the different regions suffered different mutations that drove them to have almost the same dark fur color.

8) To see if the mice population is evolving. If it is, there will be a change in the allelic and genotypic frequencies over the years. If it is not evolving, the frequencies will keep equal through the years.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files                  

The probability of a white chicken and a black chicken having a checkered chicken is ________
and is an example of ________

A- 50% incomplete dominance
B- 100% co-dominance
C- 100% incomplete dominance
D- 50% co- dominance

Answers

The answer is b trust me

Receptor binding motifs such as RGD have highly selective recognition for cell adhesion. Outline a strategy for incorporating a cell adhesive recognition domain to a biomaterial. Address the problems surrounding domain quantity, type, and affinity in your discussion.

Answers

Answer:

Explanation:

RGD stands for Arginine Glycine Aspartate and is a three-amino-acid peptide. It is the most extensively utilized adhesive peptide for adhering diverse cell types to a variety of biomaterials. Integrins, fibrinogen,  osteopontin, fibronectin, and bone sialoprotein, as well as collagens and laminins, all include an RGD primary binding domain. As a result, the synthetic (artificial) peptide RGD may bind to a wide range of integrin types. The artificial RGD retains its functioning through the sterilizing and processing processes of biomaterial creation because of its recognition advantage. This feature denotes the immune reactivity and pathogen transmission during xenograft.

Affinity can be modulated by the conformation of artificial RGD. The efficacy of RGD is also determined by the in vitro deposition of cells on the surface of the material sample.

The molecular processes unravel its effectiveness throughout its use as a scaffold foundation in in-vivo models. The fact that artificial RGD cannot work well in isolation is now a major aspect that defines its activity.

It has been discovered that cells release a variety of integrin-binding proteins that are more effective in activating integrin signalling than pure RGD. As a result, most biomaterials will bind and adsorb these proteins rather than RGD. As a result, a serum-free medium is employed in the majority of in vitro research.

As a result, biomaterials are supplied with RGD as well as quasi polymers such as polyethylene glycol to reduce the variance produced by native proteins. The addition of additional amino acids to RGD based on natural sequences can increase its biological activity, which can aid in the development of new tissues and the stimulation of cellular responses and signalling.

The amino terminal endpoint of the peptide, as well as the carboxyl group of the material surface, establish a covalent connection, which binds the peptide to just the surface of its biomaterial. Cell adhesion biomaterials are made from a variety of cell adhesion materials, including poly-L-lysine, mussels adhesive protein (MAP), and outer membrane (extracellular matrix) proteins.

Because MAPS are high in Dihydroxyphenylalanine and lysine, RGD is coupled with either of these to boost its cell adhesion capability. As a result, they can also aid in the attachment to damp or moist surfaces. It may also firmly adhere to glass, metals, and plastics. The addition of thiol groups to a peptide can also aid in its orientation and boost its stability.

The gap and density of this peptide sequence and structure on the biomaterial surface may be adjusted using a micro and nanotechnology (nanoscale patterning) method, which also improves ligand binding accuracy. Cellular reactions and cell activity are also under its control. Integrin receptors have been shown to be between 9 - 12 nm in size, therefore nanoscale surface patterning is crucial.

As a result, the above methods serve as a strategy for incorporating a cell adhesion recognition domain into a biomaterial while taking into account all of the technical intervention affecting its quantity, type, and affinity to the top layer for cell adhesion as a functioning tissue rather than a monolayer.

In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and e indicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit fly produced the following offspring.

Wild Type Male Wild Type Female White-eyed Male White-eyed Female Brown-eyed Female
F1 Generation 0 45 55 0 1

The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the following offspring.

Wild Type Male Wild Type Female White-eyed Male White-eyed Female Brown-eyed Female
F2 Generation 23 31 22 24 0

Required:
a. Determine the genotypes of the original parents (P generation) and explain your reasoning.
b. Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes.

Answers

Answer:

The genotypes of the original parents are

Male: X⁺Y   Female: X⁻X⁻

The Chi-square analysis leads us to accept the prediction of the parental genotypes.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files.

(a) The genotypes for the original parents (P generation) are

Male: X⁺Y  

Female: X⁻X⁻

(b) The prediction of the parental genotype is accepted by the Chi-squared test analysis.  

What is the eye color pattern in fruit flies?

Drosophila Melanogaster is a fruit fly with abnormally big, brightly colored eyes.

The range in color from red to sepia to white reveals a lot about the genetic makeup of the fly.

(a)  E = + ⇒ Dominant allele coding for wild-type eyes

     e = - ⇒ Recessive allele coding for white eyes

Now, Crossing the : male wild-type with a female white-eyed

(Parental)   =  X⁺Y x X⁻X⁻

(Phenotype) =   wild   white

(Gametes)  =    X⁺ Y X⁻ X⁻

(Punnett square)  =  X⁺ Y

X⁻   =  X⁺X⁻  X⁻Y

X⁻   =  X⁺X⁻   X⁻Y

In (F1)generation = 2/4 = 1/2 = 50% of the progeny are expected to be wild-type females.

And 2/4 = 1/2 = 50% of the progeny are expected to be white-eyed males.

Thus, the percentages are almost 50:50, as the expected ones.

So, the genotypes of the original parents are

Male:      X⁺Y

Female:  X⁻X⁻

(b) Using Chi-squared test :

Observed fruit fly type:

Wild Type Male - 25

Wild Type Female - 31

White-eyed Male - 22

White-eyed Female - 24

Expected fruit fly type:

Wild Type Male - 25

Wild Type Female - 25

White-eyed Male - 25

White-eyed Female - 25

Now, chi square [tex]= \sum\dfrac{(O- E)^2 }{E}[/tex]

By putting numbers in the formula, we are getting

Wild Type Male - 0.16

Wild Type Female - 1.44

White-eyed Male - 0.36

White-eyed Female - 0.04

Now, X² = 0.16 + 1.44 + 0.36 + 0.04 = 2

Critical value = 7.82

X² (2) < critical value (7.82)

Thus, this is the evidence to accept the given hypothesis.

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In mutualism, both organisms participating benefit from the relationship.
True or False?

Answers

Answer:

true

Explanation:

PLS HELP FAST NO LINKS!

If you live in a region that has hot, dry summers, and cool, wet winters, what climate might you live in?

A. arid

B.temperate

C.tropical

D.Mediterranean

Answers

Answer:

Mediterranean climate

the answer would be d

What are two things we need to consider to make living off Earth possible?​

Answers

Oxygen and Food? Tell me if that ain’t it :)

its also nice to keep a _______ in my purse

Answers

Answer:

its also nice to keep a __phone_____ in my purse

Explanation:

Brendan made a diagram to compare and contrast the benefits of two types of social behavior.

The diagram shows 2 overlapping circles labeled Flocking and Herding. There is a z in Herding.

Which description belongs in the area marked "Z"?

reproduction
protection
foraging
hydrodynamic efficiency
please help this is an exam and its timeddddd

Answers

Answer:

Which description belongs in the area marked Z? Protection.

Explanation:

Have a great summer.

Herding is refer to as the act of bringing individual animals together into a group, maintaining the group, and moving the group from place to place or any combination of those.  The description belongs in the area marked "Z" is foraging. Thus, the correct option is C.

What is flocking?

A flocking is refer to as the large number of birds, especially those gathered together for the purpose of migration.  For example, a large number of animals, especially sheep or goats kept together and migrate.

Foraging behavior includes all the methods by which an animal acquires and utilizes sources of energy and nutrients. This also includes the location and resources consumption, as well as their recapture and storage, within the context of the larger community.

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Define Vascular tissue?

Answers

Answer:

Vascular tissue is a complex conducting tissue found in vascular plants that is made up of several cell types. The xylem and phloem are the two main components of vascular tissue. Internally, these two tissues carry fluid and nutrients.

OAmalOHopeO

definition of human rights​

Answers

A human rights violation is the disallowance of the freedom of thought and movement to which all humans legally have a right. While individuals can violate these rights, the leadership or government of civilization most often belittles marginalized person

The diagram shows the human alimentary canal. In which parts does peristalsis take place?​ plss be sure abt it

Answers

Answer:

i think answer is 3 and 4

Explanation:

peristalsis is located at esophagus and in our digestive system

The parts where peristalsis will take place are ; ( C )  parts 3 and 4

Peristalsis is a series of muscle contraction occurring in the digestive system of Humans also these series of muscle contraction can be seen in tubes connecting the human kidney and bladder as well.  

From the diagram parts 3 ( esophagus )and 4 ( intestines ) are part of the human digestive system and peristalsis is very evident in these regions in the human body.

Hence we can conclude that The parts where peristalsis will take place are  3 and 4

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How does pH paper indicate the pH of a solution?
A. By turning a certain color
B. By changing the color of the solution
C. By causing a certain number of bubbles to form
D. By forming a number in the pH scale on the paper

Answers

By turning a certain color

Write a note based on the types of energy sources and carbon sources of a specific soil

Answers

Answer:

The primary sources of energy in the environment include fuels like coal, oil, natural gas, uranium, and biomass. All primary source fuels except biomass are non- renewable. Primary sources also include renewable sources such as sunlight, wind, moving water, and geothermal energy. Energy is the capacity of a physical system to perform work. Energy exists in several forms such as heat , kinetic or mechanical energy, light, potential energy , electrical, or other forms. Energy is the ability to do work. Energy sources could be classified as Renewable and Non-renewable. There are five major renewable energy sources

Solar energy from the sun.

Geothermal energy from heat inside the earth.

Wind energy.

Biomass from plants.

Hydropower from flowing water.

Different Sources of Energy

Soar Energy. The primary source of energy is the sun.  

Wind Energy. Wind power is becoming more and more common

Geothermal Energy. Source: Canva

Hydrogen Energy

Tidal Energy

Wave Energy  

Hydroelectric Energy  

Biomass Energy

Hope this helps Have a good day

How is waste (and the accumulation of it) not only harming wildlife, but ourselves?

Answers

Not many people knew about this, but many of our waste go back into the rivers and water companies collect that water and sell it back to us!
And it has recently been on the news that a pregnant woman had micro plastics found inside the umbilical cord! Everything we drink and eat, has an 100% chance of having mini micro plastics.

In guinea pigs, the color of the fur is determined by a single gene with two alleles control. The brown allele (B) is dominant over the white allele (b). Two heterozygous guinea pigs are crossed. Draw a genetic diagram with the genotypic, phenotypic and ratio information of the P₁ and F ₁ generations of this cross.​

Answers

Answer:

       B          b

B      BB       Bb

b       Bb      bb

Genotype:

ratio - 1:2:1

1 BB = 25%

2 Bb = 50%

1 bb = 25%

Phenotype:

ratio - 3:1

3 Brown: 75%

1 White:25%

HOpe this helps

in the fermentation experiment using yeast with the different sugars what was the dependent variable

Answers

Answer:

The dependent variable is fermentation rate.

Explanation:

When finding dependent variable phrase it like this:

______ depends on _____.

Where the first blank is the dependent variable and the second blank is the independent variable. For example, if I were to test the effects of pH on an enzyme, I would say the function of the enzyme depends on the pH level. This makes the function of the enzyme the dependent variable. In this case, fermentation rate depends on the different sugars. Hope this helps!

16. Which process has most likely occurred when new traits appear in a species?

Answers

Mutations in these genes can produce new or altered traits, resulting in heritable differences (genetic variation) between organisms. ... Evolution occurs when these heritable differences become more common or rare in a population, either non-randomly through natural selection or randomly through genetic drift.

Mutations in genes produce new or altered traits, that leads to heritable differences (genetic variation) between organisms.

What is heredity?

Heredity is defined as the sum of all biological processes through which particular characteristics are transmitted from parents to their offspring.

Evolution occurs when these heritable differences become more common in a population, either non randomly through natural selection or randomly through genetic drift.

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What is happening in these images?

Answers

there aren't any images lol

146. The ATP/CP Pathway is best for which of the following activities? A. Running a marathon B. 100m sprint C. 30 minutes steady state cardio D. - Tabata workout​

Answers

Answer:

100m sprint

Explanation:

The ATP/CP Pathway is best for in 100m sprint activity.

what is ATP ?

Adenosine Triphosphate (ATP) is the energy carrier in every living organisms on earth which capture and store energy metabolized from food and light sources in the form of ATP.

ATP is broken down through hydrolysis during energy required by a cell, The high energy bond is broken and removal of a phosphoryl group occurred.

The energy released from this process is used to drive various cellular processes.

ATP is constantly  participates in biological reactions and central to the health and growth of all life, transfer energy from one location to another,.

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Energy is transferred from the Sun to Earth many by

Answers

Energy is transferred from the Sun to Earth mainly by [tex]\sf\purple{electromagnetic\:waves\:or\:radiation}[/tex].

D. electromagnetic waves.

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Please answer only if you know this is a final 

Answers

Answer:

ecosystem

Explanation:

atmosphere is a present around the surface of the earth but it is not present around the surface of the Moon why​

Answers

Answer:

tmosphere is a present around the surface of the earth but it is not present around the surface of the Moon because

This reduces the amount of gravity on the moon. Strong gravity is needed to hold an atmosphere into place. With weak gravity, gases that are emitted from the surface quickly are lost to outer space. Another reason is because the moon does not currently experience plate tectonics and geologic upwelling. Plate tectonics allows for a recycling of crust and convergence and divergence of plates occurs and this leads to volcanoes and gases escaping at the boundaries. The moon is said to be geologically dead.

which of the following occurs during the process of asexual reproduction
Mitosis only
meiosis only
Mitosis and meiosis
none of the these​

Answers

Answer:

Explanation:

Reproduction may be asexual when one individual produces genetically identical offspring, or sexual when the genetic material from two individuals is combined to produce genetically diverse offspring. Asexual reproduction occurs through fission, budding, and fragmentation.

What term is used to describe the number of chromosomes in a gamete, such as
an egg cell or a sperm cell?

Answers

Answer:

The biology term, haploid can also refer to the number of chromosomes in egg or sperm cells, which are also called gametes

The term used to describe the number of chromosomes in a gamete would be haploid.

Gametes are usually formed by meiosis and meiosis is referred to as reductional division. When a normal diploid (2n) cell divides by meiosis, the daughter cells would have half the number of chromosomes of the parent cell. In other words, the daughter cells will have n number of chromosomes as opposed to 2n.

Cells with n chromosome numbers are generally referred to as haploid while those with normal 2n chromosome numbers are said to be diploid. Egg and sperm cells are haploid cells.

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