A serving of crackers has 1.5 grams of fat.
How many grams of fat are in 3.75 servings?
O A. 3.90
B. 5.25
C. 5.305
D. 5.625

Answers

Answer 1
D. You multiply 3.75x1.5 :)

Related Questions

Plz help me well mark brainliest if correct

Answers

all of the above which is e

all of the above is the correct answer i believe

. In this exercise, you will conduct regression analysis with binary and categorical variables. (a) Use the command tabulate to show the categories of the variable occupation and their frequencies. What is the relative frequency of the category Sales

Answers

The answer is 85.q jjdhggehjejen

A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then they did in the 1990s. In 1990s, the average amount of time spent playing computer games was 10.2 hours per week. Is the amount of time greater than that for this year

Answers

Answer:

mu = the population true mean time spent by teenagers playing computer game this year

Step-by-step explanation:

Dear student, there is no much information given to answer this question but we will try as much as possible to explain  (what is the parameter) of the true mean.

In 1990s;

μ = 10.2 hours/week

From the information given,we understand that the parameter is linked to the population, and we're looking for the population average time spent playing computer games by teens in the current situation.

In this situation, the population parameter is the population true mean mu = the population true mean.

What is the growth factor for 233% growth

Answers

Answer:

Here is what you do. Make it into vertex form and then whatever the x factor is is the growth factor

2) Use the law of sines to find the length of SR
sin⁡(A)/a=sin⁡(B)/b=sin⁡(C)/c

Answers

Answer:

take 28 degree as reference angle

using sine angle

sin28=p/h

0.46=10/h

0.46h=10

h=10/0.46

h=21.73

therefore hypotenuse =21.73

again using sine rule

take 25 degree as reference angle

sin 25=p/h

0.42=SR/21.73

0.42*21.73=SR

9.12=SR

9.1=SR

Step-by-step explanation:

ellus
Find the surface area of the composite figure.
2 cm
7 cm
2 cm
12 cm
12 cm
7 cm
7 cm
SA = [?] cm2

Answers

Answer:

SA = 484 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)

✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 7 cm

H = 12 cm

S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²

✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 2 cm

H = 2 cm

S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²

✔️Base area of the smaller rectangular prism = L*W

L = 7 cm

W = 2 cm

Area = 7*2 = 14 cm²

✅Surface area of the composite figure = 434 + (64 - 14)

= 434 + 50

= 484 cm²

A teacher is comparing the quarter grades between two of her classes. She takes a random sample of 8 students from each class and lists the grades as shown. Find the mean for Class A.
Class A: 80, 83, 74, 91, 76, 87, 93, 72
Class B: 90, 75, 82, 86, 73, 85, 79, 94

Answers

The mean for class A is 82

An experimenter is studying the effects of temperature, pressure, and type of catalyst on yield from a certain chemical reaction. She considers 6 different temperatures, 5 different pressures, and 4 different catalysts are under consideration.

a. If any particular experimental run involves the use of a single temperature, pressure, and catalyst, how many experimental runs are possible?
b. How many experimental runs are there that involve use of the lowest temperature and two lowest pressures?
c. Suppose that five different experimental runs are to be made on the first day of experimentation. If the five are randomly selected from among all the possibilities, so that any group of five has the same probability of selection, what is the probability that a different catalyst is used on each run?

Answers

Answer:

a) 120 possible experimental runs

b) 8 possible experimental runs

c) 0

Step-by-step explanation:

a. For the experiment, there are 6 different temperatures (T), 5 different pressures (P), and 4 different catalysts (C). We can find the total number of combinations using the product rule.

N = T × P × C

N = 6 × 5 × 4 = 120

b) If we use only the lowest temperature, we have T = 1, and if we use the two lowest pressures, we have P = 2. We can find the total number of combinations using the product rule.

N = T × P × C

N = 1 × 2 × 4 = 8

c) If we perform 5 experimental runs with 4 possible catalysts, it is not possible to use a different catalyst each time. At least, 1 catalyst must be repeated twice. Then, the event "a different catalyst is used on each run" has a probability of 0.

Given the set of data below, which measure(s) will change if the outlier is removed? (Check all that apply.) 1,6,8,8,8
mean
range
median
mode​

Answers

The diameter of a circle measures 12 yd what is the Circumference some of the circle? Use 3.14 for n

The mean, range, and median will vary if the outlier is eliminated. Options A, B, and C are correct.

What is mean?

The arithmetic mean is a term used to describe the average. It's the ratio of the total number of observations to the sum of the observations.

The data set is;

1,6,8,8,8

Outliers in a dataset or graph are extreme values that stand out significantly from the main pattern of values.

There is an aberration in the graph below, on the far left. The value in January is much lower than the value in the other months.

If the outlier is removed mean, range, and median will changes.

Hence options A, B and C are correct.

To learn more about mean refer:

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Order the following units of a capacity families to greatest gallon paint cup quart

Answers

Answer:

7 yards

Step-by-step explanation:

The vertices of a rectangle in the coordinate plane are located at (4, -3), (4,5), (-5,5), and (-5, -3).

Answers

I’m pretty sure the correct answer is 30 because that’s what you get after counting all units on the outside of the rectangle

A distance of 400 km is represented in the map by 3 cm. What is the distance between two towns if they are 7.5 cm apart in the map?​

Answers

Answer:

The distance between the two towns is of 1000 km.

Step-by-step explanation:

This question is solved by proportions, using a rule of three.

We have that:

3 cm represents a distance of 400 km.

What is the distance represented by 7.5 cm?

3 cm - 400 km

7.5 cm - x km

Applying cross multiplication:

[tex]3x = 400*7.5[/tex]

[tex]x = \frac{400*7.5}{3}[/tex]

[tex]x = 1000[/tex]

The distance between the two towns is of 1000 km.

Quadrilateral ABCD is inscribed. The measure of ∠A=67°. What is the measure of ∠C?

Answers

Answer:

angle C =113 degree

Step-by-step explanation:

angle A + angle C =180 degree

angle C = 180 degree - angle A  

angle C = 180 degree - 67 degree

=113 degree

brainliest for answer

Answers

Answer:

what is the question?

Step-by-step explanation:

Answer:

i answered

Step-by-step explanation:

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Answers

Answer:

1/18

Step-by-step explanation:

[tex]\frac{1}{9}[/tex]÷2

make 2 a fraction

[tex]\frac{1}{9}[/tex]÷[tex]\frac{2}{1}[/tex]

cross multiply

1*1

9*2

[tex]\frac{1*1}{9*2}[/tex]

[tex]\frac{1}{18}[/tex]

Answer:

Step-by-step explanation:

You always invert the second number in a division question and then multiply. This one is a little different. It has three levels. What do you do about that?

[tex]\frac{\frac{1}{9} }{\frac{2}{1} }[/tex]

Now you have a four level question which is handled the same way as all four level question.

Invert the bottom and multiply. Invert means turn upside down. So you turn the 2/1 upside down and you get 1/2

[tex]\frac{1}{9}*\frac{1}{2}[/tex]

What you get is 1/18 The green box with the question mark is a 1.

Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following. Probabilitygiven the number of trials and the probability of obtaining a success. Round your answer to four decimal places. P(x>10), n=14, p= .8

Answers

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

In this question:

[tex]n = 14, p = 0.8[/tex]

P(x>10)

[tex]P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501[/tex]

[tex]P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501[/tex]

[tex]P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539[/tex]

[tex]P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440[/tex]

[tex]P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981[/tex]

So P(x > 10) = 0.6981.

In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association and independence should be performed. What is the expected frequency of West Campus and failed

Answers

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

Answer:

57.5

Step-by-step explanation:

Got it right on the test.

If you know how to solve this, Please answer it. Thank You

The first one to answer the question right, will get Brainlist!

I PROMISE!!!!!​​

Answers

y = ( x + 9 )^2 - 2

................................

................................

In a small metropolitan area, annual losses due to storm, fire, andtheft are assumed to be independent, exponentially distributed random variableswith respective means 1.0, 1.5, 2.4. Determine the probability that the maximumof these losses exceeds 3.

Answers

Answer:

[tex]0.4138[/tex]

Step-by-step explanation:

Given

[tex]x \to storm[/tex]

[tex]\mu_x = 1.0[/tex]

[tex]y \to fire[/tex]

[tex]\mu_y = 1.5[/tex]

[tex]z \to theft[/tex]

[tex]\mu_z = 2.4[/tex]

Let the event that the above three factors is greater than 3 be represented as:

[tex]P(A > 3)[/tex]

Using complement rule, we have:

[tex]P(A > 3) = 1 - P(A \le 3)[/tex]

This gives:

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

-----------------------------------------------------------------------------------------------------------

The exponential distribution formula of each is:

[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]

So, we have:

[tex]k = 3; \mu_x = 1[/tex]

[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]

[tex]k=3; \mu_y = 1.5[/tex]

[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]

[tex]k = 3; \mu_z = 2.4[/tex]

[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]

-----------------------------------------------------------------------------------------------------------

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]

[tex]P(A > 3) = 1 - 0.5862[/tex]

[tex]P(A > 3) = 0.4138[/tex]

Find each quotient.

494 ÷ 95 =


136.8 ÷ 24 =


96.9 ÷ 19 =


43.2 ÷ 8 =

Answers

Answer:

1. 5.2

2. 5.7

3. 5.1

4. 5.425 or 5.4

Step-by-step explanation:

hope this helps :)

Answer:

1. 5.2

2. 5.7

3. 5.1

4. 5.4

Step-by-step explanation:

you can use the app photo math, you just take a picture of the problem and it will give you the answer and explain the steps.

A math recap workshop is provided to the first year students entering a city college. To evaluate the workshop effectiveness, a study is conducted as following: 20 students with similar math backgrounds are randomly selected for the study. Of the 20 students, 10 of them are selected to attend the workshop and the other 10 do not attend the workshop. After the workshop has taken place a test is given to all 20 students. What is the appropriate inference test to use in this situation

Answers

Answer:

Independent sample t test

Step-by-step explanation:

The Independent sample t test could be explained as a statistical test carried out in other to establish or examine if significant difference exists between two independent samples. That is the outcome of the samples do not depend on one another. Using the scenario described above, the difference between the same variable is measured for two different groups which is the ideal set up for an independent sample t test. The difference between test score for two independent samples (those who attended the workshop and those who did not) is being compared.

Divide the following complex numbers:
(4-i)/(3+4i)
A.-8/7 + 19/7i
B. 16/25 - 19/25i
C. 8/25 - 19/25i
D. -16/7 + 19/7i

Answers

Answer:

C. 8/25 - 19/25i

Step-by-step explanation:

Given that:

[tex]\dfrac{4-i}{3+4i}[/tex]

[tex]= \dfrac{(4-i) (3-4i)}{(3+4i)(3-4i)}[/tex]

[tex]= \dfrac{(4-i) (3-4i)}{(3+4i)(3-4i)} \\ \\ =\dfrac{12 -16i -3i+4i^2}{9 - 12i +12i -16i^2} \\ \\ = \dfrac{12-19i+4i^2}{9-16i^2} \\ \\ = \dfrac{8-19i}{25}[/tex]

[tex]=\dfrac{8}{25}- \dfrac{19i}{25}[/tex]

Consider a normal distribution of values with a mean of 32 and a standard
deviation of 1.5. Find the probability that a value is less than 36.8.


Anyone know?

Answers

Answer: The probability that a value is less than 36.8 is 0.9993.

Step-by-step explanation:

Let X be the random variable that normally distributed.

Given: [tex]\mu=32,\sigma=1.5[/tex]

The probability that a value is less than 36.8 = [tex]P(X<36.8)[/tex]

[tex]=P(\frac{X-\mu}{\sigma}<\frac{36.8-32}{1.5})\\\\=P(Z<3.2)\ \ \ [Z=\frac{X-\mu}{\sigma}]\\\\=0.9993[/tex][Using P-value calculator]

Therefore, The probability that a value is less than 36.8 is 0.9993.

I need help on this question

Answers

Answer:

C. y = 8x

Step-by-step explanation:

Using the slope formula, we can calculate the rate of Marisol's and Timothy's Machines.

[tex]m = \frac{y_1-y_2}{x_1-x_2}[/tex]

Marisol:

[tex]m = \frac{18-12}{3-2} \\m=6[/tex]

Timothy:

[tex]m=\frac{54-36}{6-4} \\m=\frac{18}{2} \\m=9[/tex]

Now that we know the rate of their machines, we need to choose a rate that is between 6 and 9. Therefore, the rate of Zorian's machine needs to be y = 8x.

a model truck is 13.5 inches long 7.5 inches wide. the original truck was 12 feet long. how wide was the truck?

Answers

Answer:

w = 6ft 8in

Step-by-step explanation:

the proportions will be the same

w/7.5 = 12/13.5

multiply both sides by 7.5

w = 12/13.5 * 7.5

w = 6.6666666667ft

w = 6ft 8in

The original truck was 6.67 feet wide.

What is ratio?

"It is a comparison of two or more numbers that indicates their sizes in relation to each other."

What is proportion?

"It is an equation in which two ratios are set equal to each other."

For given example,

A model truck is 13.5 inches long 7.5 inches wide.

The ratio of length to width of a model truck would be,

13.5 : 7.5                       ...........................(1)

The original truck was 12 feet long.

This means the original truck was 144 inches long.

Let 'x' be the width (in inches) of the original truck.

So, the ratio of the length to the width of the original truck would be,

144 : x                           .................................(2)

Also, the ratios given by (1) and (2) must be in proportion.

[tex]\Rightarrow \frac{13.5}{7.5} = \frac{144}{x} \\\\\Rightarrow 13.5 \times x = 144 \times 7.5\\\\\Rightarrow \bold{x=80~inches}\\\\\Rightarrow \bold{x=6.67~feet}[/tex]

Therefore, the original truck was 6.67 feet wide.

Learn more about ratio and proportion here:

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sume that the change in daily closing prices for stocks on the New York Stock Exchange is a random variable that is normally distributed with a mean of $0.35 and a standard deviation of $0.33. Based on this information, what is the probability that a randomly selected stock will close up $0.75 or mor

Answers

Answer:

0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of $0.35 and a standard deviation of $0.33.

This means that [tex]\mu = 0.35, \sigma = 0.33[/tex].

What is the probability that a randomly selected stock will close up $0.75 or more?

This is 1 subtracted by the p-value of Z when X = 0.75. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{0.75 - 0.35}{0.33}[/tex]

[tex]Z = 1.21[/tex]

[tex]Z = 1.21[/tex] has a p-value of 0.8869.

1 - 0.8869 = 0.1131

0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.

Given f (x) = StartLayout Enlarged left-brace first row x squared minus one-third x, for x not-equals negative 1 second row negative 1, for x = negative 1 EndLayout. What is Limit of f (x) as x approaches negative 1?

Negative five-thirds
Negative four-thirds
Four-thirds
Five-thirds

Answers

Answer:

It's C, 4/3! Just did the question and got it right

Step-by-step explanation:

The limit of f(x) as x approaches negative 1 is four thirds.

What is Limits?

Limits are defined as the value of a function as the input approaches a certain number. Limits are the concepts used essentially in calculus to define continuity, integrals and derivatives.

Given function is,

[tex]f(x) =\left \{ {{x^{2} -\frac{1}{3}x, x\neq -1 } \atop {-1, x=-1}} \right.[/tex]

We have to find the value of the limit as x approaches to negative 1.

This is not the same value as the value of the function at negative 1. Limit of the function as x approaches some value is the value of the function which is closest to the exact value of the function at the input.

We have,

f(x) = x² - [tex]\frac{1}{3}[/tex] x when x ≠ -1

Substitute x = -1 in the above equation

x² - [tex]\frac{1}{3}[/tex] x  = (-1)² - (1 / 3) (-1)

            = 1 + [tex]\frac{1}{3}[/tex]

            =  [tex]\frac{4}{3}[/tex]

[tex]\lim_{x \to -1} x^{2} -\frac{x}{3}[/tex] = [tex]\frac{4}{3}[/tex]

Hence the limit of f(x) = x² - [tex]\frac{1}{3}[/tex] x when x tends to -1 is 4/3.

To learn more about Limits, click on the link given below :

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Which of the following CANNOT be true for a triangle?

A. A triangle can be equilateral and obtuse at the same time.
B. A triangle can be equilateral and equiangular at the same time.
C. A triangle can be isosceles and right at the same time.
D. A triangle can be scalene and obtuse at the same time.

Answers

Answer:

A. A triangle can be equilateral and obtuse at the same time

Step-by-step explanation:

All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°

Solve number 3 please, with explanation

Answers

Answer:

97,655

Step-by-step explanation:

5(5)^(n-1) = 78,125

5^n = 78,125

n = 7

=> S7 = 5(5^7 -1) / (5-1)

= 5/4 (78, 125 -1)

= 5/4 (78 124) = 97,655

Can anyone help me find the function for this trig graph ? i need a specific answer for the function , not just telling me how to find it . 80 pts

Answers

Answer:

y = 5 sin (2x) + 4

Step-by-step explanation:

this is sines function,

the amplitude is [9 - (-1)]/2 = 10/2 = 5

the period is 2πx/π = 2x

the x-axis of actual function is at y = 4

so, the function is :

y = 5 sin (2x) + 4

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