I need the measure of

Answer:

The x intercept is 4 (by substituting y as zero we get x intercept)

And the y intercept is 8 (by substituting x as zero we get y intercept)

Take (4, 0) and take (8, 0) to graph the line

You're welcome!

Answer:

x = 4 y = 8 graph (4,0) and (8,0)

Answer:

all answers are true I think

Answer:

Combine Like Terms:

=1728+−9x^2+−4x+3

=(−9x^2)+(−4x)+(1728+3)

= −9x^2+−4x+1731

Down                            

6. 4,011                          

10. -94

11. 26

13. 178

15. -8

16. 6,861

18. 3,482

20. 385

22. 788

24. -5

25. 44

Across

1. -248

5. -9

7. 4,923

8. 90

9. 67

10. -912

12. 119

14. 16

15. -6

17. 743

19. 8,838

21. 47

23. 68

24. -884

26. 15

27. 7,284

Answer:

83.33 milligrams

Step-by-step explanation:

The equation, [tex] 18x = 1500 [/tex] represents the total dosage of antibiotics to be given to the patient in relation to the hours.

Thus, the each dosage = x.

Let's solve for x

[tex] 18x = 1500 [/tex]

Divide both sides by 18

[tex] \frac{18x}{18} = \frac{1500}{18} [/tex]

[tex] x = 83.33 milligrams [/tex] (nearest hundredth)

Answer:

4,9

Step-by-step explanation:

Answer:

It's B

Step-by-step explanation:

Answer:

Do you have insta cus if u do follow _l.bartlett

Step-by-step explanation:

1. x<-3

2. z[tex]\leq[/tex] -5

3. y<2

4. 3 [tex]\leq[/tex]x<7

Answer:

C. the organization of parts into a whole pattern

Step-by-step explanation:

Answer:

c because 5×4=20 and 3×5÷2=7.5= 27.5

The amount of the school supply kit after the discounted price is $ 20

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the amount of the school supply kit be A

The value of A is $ 25

The percentage discount of the school supply kit = 20 %

So , the value of the percentage amount is given by the equation

The cost of the school supply kit after discount = ( amount of the school supply kit - ( percentage discount of the school supply kit x amount of the school supply kit ) )

Substituting the values in the equation , we get

The cost of the school supply kit after discount = 25 - ( 20/100 x 25 )

The cost of the school supply kit after discount = 25 - ( 25 x 0.2 )

The cost of the school supply kit after discount = 25 - 5

The cost of the school supply kit after discount = $ 20

Therefore , the discounted price is $ 20

Hence ,

The amount of the school supply kit after the discounted price is $ 20

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Answer:

10 2/3 is 32/3

Step-by-step explanation:

10*3=30

30+2=32

32/3

.

Step-by-step explanation:

10 2/3

add 10 + 2/3

continue

Answer:

$420.25

Step-by-step explanation:

Total earnings of the week

[tex] = 400 + 3 \% \: of \:675 \\ \\ = 400 + 0.03 \times 675 \\ \\ = 400 + 20.25 \\ \\ = \$ 420.25[/tex]

Answer:

$460.

Step-by-step explanation:

[tex]Percentage\ change = (\frac{Original\ Price\ - Discounted\ Price}{Original\ Price})100\\\\15=(\frac{x-391}{x})100\\\\15x=(x-391)100 \\\\15x/100=x-391\\0.15x=x-391\\391=x-0.15x\\391=0.85x\\391/0.85=x\\460=x\\[/tex]

So the price yesterday was $460

Answer:

All congruent figures are similar

Step-by-step explanation:

Congruent means "same" in mathematics and you have evidence to prove it. You can look at two puppies with the exact same fur color and be like "yeah they're the same". If they are the same size and shape they're congruent. This is why the AAA postulate can't work because triangles can have the same angles yet be different sizes. If figures are not congruent, they can't be similar and figures that aren't similar can't be congruent either.

All similar figures are congruent is true about similar figures

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

In mathematics, congruent means identical, and you can cite examples to support your claim.

just by looking at them. They are congruent if their dimensions match. Triangles can have the same angles but differ in size, which makes the AAA postulate invalid.

If two figures are not similar, they cannot be congruent, therefore similarly unrelated figures cannot be congruent.

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Answer:

[tex]x = \frac{5 + \sqrt{53}}{2}[/tex]  or  [tex]x = \frac{5 - \sqrt{53}}{2}[/tex]

Step-by-step explanation:

Given

[tex]x^2 - 5x - 7 = 0[/tex]

Required

Solve for x using:

[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

First, we need to identify a, b and c

The general form of a quadratic equation is:

[tex]ax^2 + bx + c = 0[/tex]

So, by comparison with [tex]x^2 - 5x - 7 = 0[/tex]

[tex]a = 1[/tex]     [tex]b = -5[/tex]      [tex]c = -7[/tex]

Substitute these values of a, b and c in

[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}[/tex]

[tex]x = \frac{5 \± \sqrt{25 +28}}{2}[/tex]

[tex]x = \frac{5 \± \sqrt{53}}{2}[/tex]

Split the expression to two

[tex]x = \frac{5 + \sqrt{53}}{2}[/tex]  or  [tex]x = \frac{5 - \sqrt{53}}{2}[/tex]

To solve further in decimal form, we have

[tex]x = \frac{5 + 7.28}{2}[/tex]  or  [tex]x = \frac{5 - 7.28}{2}[/tex]

[tex]x = \frac{12.28}{2}[/tex]  or  [tex]x = \frac{-2.28}{2}[/tex]

[tex]x = 6.14[/tex] or [tex]x = -1.14[/tex]

Answer:

-5 1/8

Step-by-step explanation:

-5 1/8

Answer:

22.5 miles

Step-by-step explanation:

15 miles every hour, and there is 1.5 hours, so cut 15 in half, 7.5 and add that the 15

Answer:

-3 1/3

Step-by-step explanation:

Answer:

10 cups in total.

Step-by-step explanation:

4.8+5.2= 10.00

add the .2 to the 4.8 you get get 5 then add 5.0+5.0

Answer:

Jack earns $37

Mark earns $21

Step-by-step explanation:

m + j = 58

11m + 10j = 601

j = 58 - m

11m + 10(58 - m) = 601

11m + 580 - 10m = 601

1m = 601 - 580

m = 21

j = 58 - m

j = 58 - 21

j = 37

Answer:

3. a=300/30

Step-by-step explanation:

you want to figure out how many packages she received, and there are 30 beads in each package. so, you divide the total amount of beads (300) by the amount in each package to determine how many packages there are. 300/30=10 packages of beads

550 47/100 miles per hour.

Answer:

550.47

Step-by-step explanation:

3669 4/5 ÷ 6 2/3 = 550.47

Hope this helps:)

The slope of the line [tex]\overline{AB}[/tex] is the rate at which the line rises at a point.

Reasons:

The slope of a line is given by the ratio of the rise to the run of the line

The coordinates of point A = (-9, -4)

The coordinates of point B = (-5, 6)

The rise of the line [tex]\overline{AB}[/tex] = The difference in the y-values = (6 - (-4)) = 10

The run of the line [tex]\overline{AB}[/tex] = The difference in the x-values = (-5 - (-9)) = 4

[tex]Slope \ of \ \overline{AB}= \dfrac{Rise \ of \ line \ \overline{AB}}{Run \ of \ line \ \overline{AB}}[/tex]

Therefore

[tex]Slope \ of \ \overline{AB}= \dfrac{10}{4} = \dfrac{5}{2}[/tex]

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Answer:

A.B

Step-by-step explanation:

5 - sqrt1.35 =  ~3.8

A) 3 / sqrt2 = ~2.1

B) 5 / sqrt3 = ~2.9

C) 3 + 2sqrt2 = ~5.8

D) 4 + 8/sqrt50 = ~5.1

Answer:

y = 1/3x + 4

Step-by-step explanation:

Make it into slope intercept form

3y = x + 6

y = 1/3x + 2

parallel = same slope

y = 1/3x + b, plug in (3,5)

5 = 1/3(3) + b, b = 4

y = 1/3x + 4

Answer:

[tex]f(x) = \frac{x - 25}{5x - 5}[/tex]

Domain: [tex]x \ne 1[/tex]

Step-by-step explanation:

Given

[tex]f(5x) = \frac{x - 5}{5x - 1}[/tex]

Required

Determine f(x) and its domain

To determine f(x), we replace 5x with x in f(5x)

So, we have:

[tex]f(5x) = \frac{\frac{5x}{5} - 5}{5x - 1}[/tex]

[tex]f(x) = \frac{\frac{x}{5} - 5}{x - 1}[/tex]

Take LCM

[tex]f(x) = \frac{\frac{x - 25}{5}}{x - 1}[/tex]

[tex]f(x) = \frac{x - 25}{5} * \frac{1}{x-1}[/tex]

[tex]f(x) = \frac{x - 25}{5x - 5}[/tex]

To get the domain, we set the denominator as

[tex]5x - 5 \ne 0[/tex]

[tex]5x \ne 5[/tex]

[tex]x \ne 1[/tex]