I need help!I’ve been struggling on this worksheet for so long!

Answer:

42

Step-by-step explanation:

Add all the numbers 20+, 32, 34, 36, 40, 42, 44, 48, 55, 65=416

then divide by total number of digits

(Mean: The mean is the average. It is found by adding all the data values and then dividing by the number of data points.)

41.6 rounded to 42

No need to use pi for this problem! So we're finding the area of a trapezoid. It's made up of: a square with length and width 2, and two triangles with a base 2 and height 2.

Area of a triangle formula is [tex]A = \frac{1}{2} B\cdot h[/tex]

[tex]A = \frac{1}{2}\cdot2\cdot 2[/tex]

[tex]A = \frac{1}{2}\cdot 4[/tex]

[tex]A = 2[/tex] units^2

And since the two triangles are the same, the other triangle has the same area: 2 units^2

For the square we can use [tex]A = l\cdot w[/tex]  

[tex]A = 2 \cdot 2[/tex]

[tex]A = 4[/tex]

Combine the areas: the total area is 2 + 2 + 4 , = 8 units^2

Answer:

8 units²

Step-by-step explanation:

In order to find the area of this trapezoid, you can apply the formula for the area of a trapezoid: ([tex]b_{1}[/tex] + [tex]b_{2}[/tex]) × h/2

In the equation, you already know base one (2) and the height (2), but base two isn't given. To find the length of the whole base, you need the length of the other side of the square: You can tell that it is two because the two given sides of the square are 2.

Since you now know that the length of the missing side of the base is 2, you can add the three values given to get the base length:

2 + 2 + 2 = 6

Now, you have all the information needed to find the area of the trapezoid. Input them all into the equation:

([tex]b_{1}[/tex] + [tex]b_{2}[/tex])*h/2 where [tex]b_{1}[/tex] is 2, [tex]b_{2}[/tex] is 6, and h is 2,

(2 + 6) × 2/2

= 8 × 1

= 8 units²

Answer:

θ ≈ 15°

Step-by-step explanation:

Using the sine rule in the triangle

note 7.56 × 10² = 756 and 2.4 × 10³ = 2400 , then

[tex]\frac{756}{sin0}[/tex] = [tex]\frac{2400}{sin125}[/tex] ( cross- multiply )

2400 × sinθ = 756 × sin125° ( divide both sides by 2400 )

sinθ = [tex]\frac{756sin125}{2400}[/tex] , then

θ = [tex]sin^{-1}[/tex] ( [tex]\frac{756sin125}{2400}[/tex] ) ≈ 15° ( to the nearest degree )

Answer:

Step-by-step explanation:

Answer:

He is making 20 naira profit for every 4 cups that he sells for 100 naira

Therefore, if he selled all this cups for 100 naira per 4 cups he made a total profit of 100 naira

Answer:

2,4 because they are hitting each other at that point

Answer:

D

Step-by-step explanation:

The solution is where the the red and blue line intersect.

Answer:

i dont know

Step-by-step explanation:

.

Answer:

p = 1

Step-by-step explanation:

4 - 5(p + 3/5) = -4

Find P

4 - 5(p + 3/5) = -4

4 - 5p -15/5 = -4

4 - 5p - 3 = -4

-5p + 1 = -4

-5p = -4 - 1

-5p = -5

p = -5/-5

p = 1

Check:

4 - 5(p + 3/5) = -4

4 - 5(1 + 3/5) = -4

4 - 5 - 15/5 = -4

4 - 5 - 3 = -4

4 - 8 = -4

-4 = -4

Answer:

ITS HELLA 1/5 NOT 1

Step-by-step explanation:

>:(

Answer:

1

Step-by-step explanation:

As we know that addition and subtraction are inverse operations, as are multiplication and division.

The given equation is c+3=4

To solve such equations we isolate the unknown( to keep it either to the left or right of = sign) as c = 4-3  

This is also called transposing and the sign of the transposed value changes.

Hence, c = 4-3 = 1

Answer:

750

Step-by-step explanation:

Answer:

22.5km per hour

Step-by-step explanation:

Answer:

E. 1d+0.015d

G. 1.015d

Step-by-step explanation:

A is incorrect, as it only shows the 1.5% raise. B is incorrect, since that would be a 15% raise. C and D are incorrect because it's impossible to add a number with a variable to one without a variable. E is correct because it properly adds 100% (the amount he made without the raise) and 1.5% (the raise) together. F is incorrect because again, it adds 15%. G is correct because it is the total amount he makes, with the raise. H is incorrect because again, it adds 15%.

Answer:

Approximately 10.9

Step-by-step explanation:

[tex]a^2+b^2=c^2[/tex]

Plug in b (5) and c (12)

[tex]a^2+5^2=12^2\\a^2+25=144[/tex]

Subtract 25 from both sides

[tex]a^2+25-25=144-25\\a^2=119[/tex]

Take the square root of both sides

[tex]\sqrt{a^2} =\sqrt{119}[/tex]

a = approximately 10.9

I hope this helps!

Answer:

9

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

Answer:

55

Step-by-step explanation:

Just multiply then divide:

55 x 32 = 1760

1760 ÷ 32 = 55

Or just easier like:

55 x 32 ÷ 32 = 55

Hopefully this helps :3 Sorry if wrong :( Plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3

-Bee~

Answer:

THE ARCHITECT VALDIVIA DONATED A LAND, AS IN THE FOLLOWING FIGURE, TO BUILD A PARK.

THE FRACTIONATION COMMITTEE IS GOING TO CLOSE AND FILL IT BEFORE STARTING THE DESIGN OF THE BLUEPRINTS.

Step-by-step explanation:

This is what it says in english

Answer:

what is the dot for?

Step-by-step explanation:

Answer:

The walkway around the pool makes the entire outer dimensions (outer border)  

x+9+2x3=x+15  and  x+8+2x3

hope this helps!  could i get brainliest plz?

The expressions to represent the dimensions of the outside border of the walkway is  (x + 12) meters for the length and (x + 11) meters for the width.

Given area : [tex]x^2 + 17x + 72[/tex]

The factored form of the polynomial is:

[tex]x^2 + 17x + 72[/tex]  = [tex]x^2 + 8x+9x+72[/tex]

                      = x(x+8)+9(x + 8)

                          =(x + 9)(x + 8)

So, the dimensions of the pool are (x + 9) meters and (x + 8) meters.

The length of the walkway = 3 meters wide

So, the length is added to each side of the pool.

Dimensions of the outside border of the walkway:

Length: (x + 9) + 3 = x + 12 meters

Width: (x + 8) + 3 = x + 11 meters

Therefore, the dimensions of the outside border of the walkway are

(x + 12) meters for the length and (x + 11) meters for the width.

Learn more about polynomials here:

https://brainly.com/question/11536910

#SPJ4

Answer:

23 gallons of water

Step-by-step explanation:

People use water to​ cook, clean, and drink every day. An estimate of 33.9​% of the water used each day is for cooking. If a family uses 67.8 gallons of water a day for cooking​, how many gallons do they use every​ day?

This is calculated as:

33.9 % × 67.8 gallons of water

= 0.339 × 67.8 gallons of water

= 22.9842 gallons of water

Approximately = 23 gallons of water

Therefore, 23 gallons of water are used everyday for cooking

Answer:

B

Step-by-step explanation:

This is because 6.5n is the slope and the +1500 is the y-intercept. Remember its y=mx+b.

Answer:

B

Step-by-step explanation:

Hope this helps have a great day :)

The possible outlier may be [tex](0,1)[/tex] as the second component is not greater than second components of the remaining pairs in comparison.

In this data set, we observe that data set observes the rule that first component increases inasmuch the second component of the ordered pairs decreases. Thus, the possible outlier may be [tex](0,1)[/tex] as the second component is not greater than second components of the remaining pairs in comparison. [tex]\blacksquare[/tex]

To learn more on ordered pairs, we kindly invite to check this verified question: https://brainly.com/question/11740961

Answer:

3.667+ 2

Step-by-step explanation:

Area of a rectangle = length x width

11x + 10 = (3x +5) x width

to determine the width, divide both sides of the equation by 3x + 5

(11x + 10) / (3x + 5) = width

width = 3.667 + 2

Respuesta:

183x + 356y = 3763

Explicación paso a paso:

Dejar :

Número de kilos de papel = x; número de kilos de cartón = y

Kilo de papel = 183; kilo de cartón = 356

Cantidad total ganada = 3763

(Costo por kilo de papel * número de kilos de papel) + (costo de kilos de cartón * número de kilos de cartón)

(183 * x) + (356 * y) = 3763

183x + 356y = 3763

Answer:

804.25 units²

Step-by-step explanation:

radius = diameter / 2

Area of a circle = πr²

radius = 32/2 = 16 cm

Area = (16)²π

Area = 256π = 804.247719

Area ≈ 804.25 units²

Answer:

first answer

Step-by-step explanation:

Acceleration is 2.......