Answer:
if there isn't a shorting mechanism, the whole sets will be blown out several lamps and then shortened, the overall resistance of the remaining operating lamps will be decreased resulting in an increased working current that is adequate to blast the fuse
Willie, in a 100.0 m race, initially accelerates uniformly from rest at 2.00 m/s2 until reaching his top speed of 12.0 m/s. He maintained this speed until he is 16.0 m from the finish line but then fades and decelerates uniformly, crossing the line with a speed of only 8.00 m/s. What is Willie’s total time for the race? Please show your steps :)
Answer:
The total time for the race is 11.6 seconds
Explanation:
The parameters given are;
Total distance ran by Willie = 100.0 m
Initial acceleration = 2.00m/s²
Top speed reached with initial acceleration = 12.0 m/s
Point where Willie start to fade and decelerate = 16.0 m from the finish line
Speed with which Willie crosses the finish line = 8.00 m/s
The time and distance covered with the initial acceleration are found using the following equations of motion;
v = u₀ + a·t
v² = u₀² + 2·a·s
Where:
v = Final velocity reached with the initial acceleration = 12.0 m/s
u₀ = Initial velocity at the start of the race = 0 m/s
t = Time during acceleration
a = Initial acceleration = 2.00 m/s²
s = Distance covered during the period of initial acceleration
From, v = u₀ + a·t, we have;
12 = 0 + 2×t
t = 12/2 = 6 seconds
From, v² = u₀² + 2·a·s, we have;
12² = 0² + 2×2×s
144 = 4×s
s = 144/4 =36 meters
Given that the Willie maintained the top speed of 12.0 m/s until he was 16.0 m from the finish line, we have;
Distance covered at top speed = 100 - 36 - 16 = 48 meters
Time, [tex]t_t[/tex] of running at top speed = Distance/velocity = 48/12 = 4 seconds
The deceleration from top speed to crossing the line is found as follows;
v₁² = u₁² + 2·a₁·s₁
Where:
u₁ = v = 12 m/s
v₁ = The speed with which Willie crosses the line = 8.00 m/s
s₁ = Distance covered during decelerating = 16.0 m
a₁ = Deceleration
From which we have;
8² = 12² + 2 × a × 16
64 = 144 + 32·a
64 - 144 = 32·a
32·a = -80
a = -80/32 = -2.5 m/s²
From, v₁ = u₁ + a₁·t₁
Where:
t₁ = Time of deceleration
We have;
8 = 12 + (-2.5)·t₁
t₁ = (8 - 12)/(-2.5) = 1.6 seconds
The total time = t + [tex]t_t[/tex] + t₁ =6 + 4 + 1.6 = 11.6 seconds.
Willie's total time to cover the race is 11.6 seconds.
What is a velocity-time graph?A velocity-time graph is a graph that is used to represent a way in which the motion of an object can be represented with the velocity change on the vertical (y)-axis and change in time on the horizontal (x)-axis.
From the given information:
Willie's total distance covered = 100.0 mInitial acceleration (u) when the race commence = 0 m/s²Final velocity reached = 12.0 m/sUsing the following first equation of motion:
v = u + at (where u = 0; at rest)The time during the first acceleration can be computed as:
v = u + at
12 = 0 + (2 × t)
t = 12/2
t = 6 seconds
Using the fourth equation of motion, the distance covered in the first acceleration is determined as follows:
[tex]\mathbf{v^2 = u^2 + 2as}[/tex]
[tex]\mathbf{12^2 = (0)^2 + 2(2) \times s}[/tex]
144 = 4s
s = 144/4
s = 36 meters
However, he maintained a speed of 12.0 m/s till he is 16.0 m away from the finish line when he starts to decelerate.
Hence, at his highest speed;
The distance covered = 100 - 36 - 16 = 48 meters.Recall that:
[tex]Time = \dfrac{distance}{velocity}[/tex]
Thus, the time for running at his highest speed is:
[tex]\mathbf{time = \dfrac{48 m}{12 m/s}}[/tex]
time = 4 seconds
His deceleration from his highest speed can be computed as:
[tex]\mathbf{v^2 = u^ 2 + 2as}[/tex]
here:
v = 8.00 m/su = 12.0 m/ss = h = 16.0 m[tex]\mathbf{v^2 - u^2=2as}[/tex]
[tex]\mathbf{a = \dfrac{v^2 - u^2}{2s}}[/tex]
[tex]\mathbf{a = \dfrac{8^2 - 12^2}{2(16)}}[/tex]
[tex]\mathbf{a = \dfrac{64 - 144}{32}}[/tex]
a = -2.5 m/s²
Finally, using the first equation of motion, the total time can be computed as:
[tex]\mathbf{v_1 = u_1 + a_1t_1}[/tex]
[tex]\mathbf{8= 12 + (-2.5)t_1}[/tex]
[tex]\mathbf{t_1 = \dfrac{(8- 12)}{ (-2.5)}}[/tex]
[tex]\mathbf{t_1 = \dfrac{(-4)}{ (-2.5)}}[/tex]
[tex]\mathbf{t_1 = 1.6\ seconds}[/tex]
Thus, the total time = (6+4+1.6) seconds
The total time = 11.6 seconds
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What is the formula for tension
Answer:
the formula for tension is mg + ma. T is equal to tension, N, kg-m/s^2
Explanation:
I hope it helps you
Answer:
Hey!
Your answer is...
T = mg + ma
Explanation:
T = tension, N, kg-m/s^2
m = mass, kg
g = gravitational force, 9.8 m/s^2
a = acceleration, m/s^2
HOPE THIS HELPS!!
Neon gas in a container was heated from 20 degrees celsius to 120 degrees celsius.Its new volume is 150ml.what was the original volume?
Answer:
110 mL
Explanation:
Ideal gas law:
PV = nRT
Assuming the container isn't rigid, and the pressure is constant, then:
V/T = V/T
Plug in values (remember to use absolute temperature).
V / 293 K = 150 mL / 393 K
V = 110 ml
Hope u understood!
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What happens when you decrease the thrust on your scooter? A. You stop B. Nothing happens C. You fall over D. You speed up Reset Selection
Answer:
you fall over
Explanation:
its not D
i already tried it
When you decrease the thrust on your scooter by fall over. The correct option is D.
What is thrust?The thrust is the pressure exerted the on the surface area.
When you decrease the thrust on your scooter by speeding up.
When the speed increases, the thrust decreases.
Thus, the correct option is D.
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An electric motor converts electrical energy into which kind of energy?
potential
kinetic
stored
chemical
Answer:
Kinetic Energy
Answer:
Kinetic
Explanation:
got it on edge
a 2500kg car is travelling at a constant speed of 14 m/s along an icy, but straight and level road. the driver of the car, seeing an approaching traffic light turn red., slams on the brakes. Wheels locked and ttired skidding, the car slide to a halt in a distance of 25m. What is the coefficient of friction
Answer:
0.40
Explanation:
Given that :
the mass of the caer = 250 kg
initial speed = 14 m/s
final speed = 0 m/s
distance s = 25 m
Using the equation of motion
[tex]v^2 = u^2 + 2as[/tex]
making a the subject of the formula ; we have:
[tex]v^2-u^2 = 2as[/tex]
[tex]a= \dfrac{v^2-u^2 }{2 \ s}[/tex]
[tex]a= \dfrac{(0)^2-(14)^2 }{2 \ (25)}[/tex]
[tex]a= \dfrac{0-196 }{50}[/tex]
[tex]a= \dfrac{-196 }{50}[/tex]
a = -3.92 m/s²
However; the relation for the coefficient of the kinetic static friction can be expressed as:
[tex]f= \mu_k *mg= ma[/tex]
[tex]f= \mu_k *g= a[/tex]
[tex]f= \mu_k = \dfrac{a}{g}[/tex]
[tex]f= \mu_k = \dfrac{3.92}{9.8}[/tex]
[tex]f= \mu_k = 0.40[/tex]
Which of these results in kinetic energy of an object? a position b motion c mass d volume
Answer:
Option B
Explanation:
Kinetic Energy is the energy possessed by the body due to "motion".
The answer is:
B. MotionEl dormitorio de Pablo es rectangular, y sus lados miden 3 y 4 metros. Ha decidido dividirlo en dos partes triangulares con una cortina que une dos vértices opuestos. ¿Cuántos metros deberá medir la cortina?
Answer:
c = 5 m
Explanation:
this exercise you want to divide the rectangular room into two triangular rooms
the area of triangles is
A = ½ base height
A = ½ 4 3
A = 6 m²
the length of the curtain can be found using the Pythagorean theorem
c² = b² + a²
c = √ (4² + 3²)
c = 5 m
this is the length of the curtain
The steering wheel of a car has a radius of 36 cm, and part of rest with an acceleration of 1.8m / s. Determine
a) The angular speed after 10s
b) The number of turns the wheel gave in 10s
Answer:
a) 50 rad/s
b) 39.8 rev
Explanation:
Given:
r = 0.36 m
v₀ = 0 m/s
a = 1.8 m/s
t = 10 s
a) Find: ω
v = at + v₀
v = (1.8 m/s) (10 s) + (0 m/s)
v = 18 m/s
ω = (18 m/s) / (0.36 m)
ω = 50 rad/s
b) Find: Δθ
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²
Δx = 90 m
Δθ = (90 m) / (2π × 0.36 m)
Δθ = 39.8 rev
(01.05 LC)
Which of the following bones is classified as part of the axial skeleton?
Answer:c
Explanation:
because it is the same
Answer: skull, vertebrae, ribs and sternum.
Explanation:
Two objects ① and ② are moving along two different circular paths of radii 10 m and 20 m respectively. If the ratio of their speeds ( V₁ : V₂) = 2:1, then the ratio of their time periods (T₁ : T₂) --------- [ Use numerals to write your answer] *
Answer:
The ratio of the time period of object 1 to the time period of object 2 is [tex]\frac{1}{4}[/tex]. (T₁ : T₂) = 1 : 4
Explanation:
Let suppose that both objects are moving along the circular paths at constant speed, such that period of rotation of each object is represented by the following formula:
[tex]\omega = \frac{2\pi}{T}[/tex]
Where:
[tex]\omega[/tex] - Angular speed, measured in radians per second.
[tex]T[/tex] - Period, measured in seconds.
The period is now cleared:
[tex]T = \frac{2\pi}{\omega}[/tex]
Angular speed ([tex]\omega[/tex]) and linear speed ([tex]v[/tex]) are related to each other by this formula:
[tex]\omega = \frac{v}{R}[/tex]
Where [tex]R[/tex] is the radius of rotation, measured in meters.
The angular speed can be replaced and the resultant expression is obtained:
[tex]T = \frac{2\pi\cdot R}{v}[/tex]
Which means that time period is directly proportional to linear speed and directly proportional to radius of rotation. Then, the following relationship is constructed and described below:
[tex]\frac{T_{2}}{T_{1}} = \left(\frac{v_{1}}{v_{2}}\right)\cdot \left(\frac{R_{2}}{R_{1}} \right)[/tex]
Where:
[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Time periods of objects 1 and 2, measured in seconds.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Linear speed of objects 1 and 2, measured in meters per second.
[tex]R_{1}[/tex], [tex]R_{2}[/tex] - Radius of rotation of objects 1 and 2, measured in meters.
If [tex]\frac{v_{1}}{v_{2}} = 2[/tex], [tex]R_{1} = 10\,m[/tex] and [tex]R_{2} = 20\,m[/tex], the ratio of time periods is:
[tex]\frac{T_{2}}{T_{1}} = 2\cdot \left(\frac{20\,m}{10\,m} \right)[/tex]
[tex]\frac{T_{2}}{T_{1}} = 4[/tex]
[tex]\frac{T_{1}}{T_{2}} = \frac{1}{4}[/tex]
The ratio of the time period of object 1 to the time period of object 2 is [tex]\frac{1}{4}[/tex].
PLZ HELP What is necessary condition for production of waves?
Answer:
The length of the rope must be an integral multiple of the wavelength of the wave.
Explanation:
Answer:
The condition necessary for formation or a standing wave is that the length of the rope (or the length over which the wave is distributed) must be an integral multiple of the wavelength of the wave. Therefore, l=nλ where n is a positive integer.
A neutral atom has the same number of protons as it does neutrons.
A. True
O B. False
SUBMIT
Answer:
The answer is False
Hope this helps you
It is false that a neutral atom has the same number of protons as it does neutrons. The correct option is B.
The claim that "A neutral atom has the same number of protons as it does neutrons" is untrue. Protons and electrons in a neutral atom are equal in number, but neutron counts can change.
Electrons have a negative charge, whereas protons have a positive charge. A neutral atom has a net charge of zero because the protons' positive charge is balanced by the electrons' negative charge.
Neutrons don't have an electric charge, though. Within a single element, the amount of neutrons can change, giving rise to many isotopes.
Isotopes contain the same amount of protons, but their atomic masses vary depending on how many neutrons they have.
Thus, the correct option is B. False.
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PLZ HELP Sound is a form of wave. List at least three reasons to support the idea that sound is a wave
Answer:
Sound is a form of wave . Wave is defined as a periodic disturbance in medium.
Reasons:
1. It follows all properties of light at a boudary.
2. Noise cancelling headphones.
3. It carry energy from one place to another.
Explanation:
I hope this will help you guy.
Sound wave is a mechanical type of wave because it requires a material medium for its propagation.
The following are three reasons sound is classified as a wave.
Reflection: sound waves are reflected like other waves when they strike a plane surface. This effect results to a phenomenon called Echo. Echo is the sound heard after the reflection of sound waves from a plane surface.Interference: sound wave like other form of wave exhibits interference. Interference of sound occurs when two waves of same frequency emitted by two close sources are superposed.Refraction: sound wave like other forms of wave also exhibits changes in velocity, frequency and wavelength when it moves from one medium to another.To learn more about sound waves, please visit: https://brainly.com/question/15805783
can we investigate that which fuel
is cheapest
Answer:
yeah..
as we all know that the cheapest fuel is petrol because it is the last product of petroleum.
hope it helps...
Three screens are placed exactly one behind the other. The light of the torch falls on all the three screens. One of the screen is a bathroom mirror which one?
Answer:
Explanation:
Three screens are placed one behind the other and light falls on all of them from a torch . In this case a mirror can be only the last screen . In case of first or second screen being a mirror , light would not have reached the last screen because the nature of mirror is to reflect the light back.
Hence , the only possibility is that , the last screen is mirror.
You notice the flagpole at school vibrating in the breeze. You count the vibrations and find that
the flagpole makes 20 complete vibrations in 10 seconds. You read somewhere that this
flagpole vibrates at a speed of 25 m/s when the wind is blowing. Find the wavelength of these
vibrations
Answer:
Wavelength =50 m
Explanation:
Given:
n=20
t=10sec
V=25m/s
Wavelength =?
Solution:
Wavelength = frequency ×velocity ---> eq 1
Time period=time/no of vibrations
T=10/20=0.5sec
Frequency =1/Time period(T)
f=1/0.5=2
Put the value of frequency in eq 1
Wavelength =2×25
Wavelength =50m...
Hope you understand!
Have a nice day!
HELP! I NEED HELP IN THIS PHYSICS QUESTION!!!
Answer:
79%.
Explanation:
Step 1:
Data obtained from the question. This include:
Input temperature = 100 °C.
Output temperature = 22 °C.
Step 2:
Conversion of celsius temperature to Kelvin temperature.
Temperature (Kelvin) = temperature (celsius) + 273
T (K) = T (°C) + 273
Input temperature = 100 °C.
Input temperature = 100 °C + 273 = 373 K.
Output temperature = 22 °C.
Output temperature = 22 °C + 273 = 295 K.
Step 3:
Determination of the efficiency of the locomotive.
Input temperature = 373 K.
Outpu temperature = 295 K.
Efficiency =...?
Efficiency = output /input x 100
Efficiency = 295/373 x 100
Efficiency = 79.1 ≈ 79%
Therefore, the efficiency of the locomotive is approximately 79%.
A trapezoid shaped dam is 100 meters wide at the top, 80 meters wide at the bottom, and 40 meters deep. To find the total force exerted on the dam by the water, how would you set up the integral?
Answer:
F = 9800(42667 + 16000)
F = 5.75 × 10⁸N
Explanation:
3) A stationary box is acted upon by 5 forces represented by letters of the alphabet as shown figure 1. Under which of these conditions will the box move in the direction shown in figure 2? Assume a frictionless surface. a) S=P+Q and T P or =P and T >Q+R
Answer:
Of course, with a triangle with a 90° angle, a right triangle, you can simply use pythagoras theorem (a2+b2=c2) then SOH-CAH-TOA to solve for the angle (θ=Cos−1(adjacenthypotenuse)) .
But what if it isn't a right triangle? The cosine rule works for all triangles, even if they don't have a 90° angle.
a2=b2+c2−2(b)(c)Cos(A)
Where a is the missing side, and A is the angle opposite to side a.
With this rule, we can find a missing angle or a missing side to any type of triangle, assuming you have the needed variables.
Explanation:
The box acted upon by the force of 5 N will move on a frictionless surface, with the condition S = P + Q.
What is Force?The effect of a push or a pull on the body is known as force. The main types of forces include friction forces, nuclear forces, and gravitational forces. For instance, when a hand strikes a wall, the wall exerts a force on the hand as well as the hand exerting a force on the wall. Newton was given several laws to comprehend force.
Given: with a triangle with a 90° angle, a right triangle, you can simply use Pythagoras theorem (a2+b2=c2) then SOH - CAH - TOA to solve for the angle (θ=Cos−1(adjacent hypotenuse)).
The cosine rule works for all triangles, even if they don't have a 90° angle.
a2=b2+c2−2(b)(c)Cos(A)
A is the angle opposite to side a,
With this rule, we can find a missing angle or a missing side to any type of triangle, assuming you have the needed variables.
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Compare and contrast electric potential energy and electric potential difference? Explain.
Answer:
Electric Potential Energy:
The energy that is needed to move a charge against an electric firld is called Electric Potential Energy
Electric Potential Difference:
The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.
Relation:
Relation between Electric potential and electrical potential energy is given by
[tex]\delta V=\frac{PE}{q}[/tex]
Here PE represents Electric potential energy
and [tex]\delta V[/tex] is Electric potential difference
it means electric potential difference is the difference in electric potential energy divided by the charge.
The student concluded that the current in the LDR is inversely proportional to the potential difference across the LDR. Explain why the student’s conclusion is incorrect.
Answer:
The graph shows direct proportion because it is a straight line
through the origin.
Explanation:
How is speed calculated? A)multiply velocity by displacement B)divide velocity by displacement C)multiply distance by time D)divide distance by time
Answer:
D
Explanation:
to work out units for speed, you need to know the unit for distance and time.
Answer:
divide distance by time, so D
Explanation:
I did it on edge
Calculate the pressure exerted on a surface by a brick of weight 10 N. The area in contact with the surface is 20 cm2
Answer: 5000
Explanation: pressure: force / area
SI unit of force: newton
SI unit of area: metre²
Force exerted: 10 N
Area on which it is exerted : 20 cm²
Since area has to be in m² , we convert cm² to m² by dividing it by 10000( m:100cm, 1m²: 10000 cm²)
Area=20/10000: 0.002 m²
So, pressure= 10/0.002=5000 pa( SI unit of pressure is pascal)
The pressure is the force exerted by unit area. The force on the brick by its weight is 10 N and the surface area is 20cm². Then, the pressure in the given area will be 5000 Pa.
What is pressure ?Pressure on an object is the force exerted per unit area of that object. Pressure is dependent on the volume and temperature as well. It is commonly expressed in the unit of atm. Other units of pressure are bar, pascal, torr, mmHg etc.
The normal force acting on the brick is the force by its own weight.
normal force = 10 N
surface area = 20 cm²
20 cm² /(100)² = 0.002 m²
Pressure = force/ area
p = 10 N/0.002 m²
= 5000 N/m² = 5000 pa
Therefore, the pressure exerted on the brick is 5000 Pa
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two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at 4 metre apart
Answer: 0.5N
Explanation:
Gravitational force is calculated using the formula :
F = Gm1m2/r^2
Where G is the gravitational constant (6.67 × 10^-11)
At a distance 'r' of 2metres apart:
Mass of objects are m1 and m2
Gravitational force 'F1' = 2N
Inputting values into the formula :
2 = Gm1m2 / 2^2 - - - - - (1)
At a distance 'r' of 4meters apart:
Mass of objects are m1 and m2
Gravitational force 'F2' = y
Inputting values
F2 = Gm1m2 / 4^2 - - - - - (2)
Dividing equations 1 and 2
2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2
2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)
2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)
2/F2 = 16 / 4
Cross multiply
2 × 4 = 16 × F2
8 = 16F2
F2 = 8/16
F2 = 0.5N
In an obstacle course, runners must jump hurdles that are .84 m high. If the speed of one of the athletes when he is 1.63 meters from the fence is 4m / s on the horizontal axis and 4m / s on the vertical axis. Calculate the maximum height reached and indicate whether or not the jump was successful for that runner. Help :c
Answer:
0.82 m
Explanation:
Given:
v₀ᵧ = 4 m/s
aᵧ = -9.8 m/s²
Find: Δy when vᵧ = 0 m/s
vᵧ² = v₀ᵧ² + 2aᵧΔy
(0 m/s)² = (4 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 0.82 m
The maximum height reached by the athlete is 0.82 meters. The jump is not successful.
Which best describes pitch?
Answer:
Your answer doesn't provide that much evidence that much. But, I try to help you find the answer. I think your answer is the number of cycles per second perceived by the human ear. Well, Pitch is basically our sound of our voice. Sometimes, Our voice can even go 'higher' or 'lower'. Let me give you a example. If we screen our voice go higher than before and sometime it can even pitch. And, Sometime when we talk lower our voice give us a lower tune.
Good Luck!!~
By ♡Itsbrazts♡
Answer:
B. the number of cycles per second perceived by the human ear (edge)
Explanation:
just completed the test. 100%
A car of mass 800 kg is moving at a uniform velocity of 72 km/hr. Find its
momentum.
(Ans: 16000 kgm/s)
Answer:
P = 16,000 kgm/s
Explanation:
Given :
Mass = m = 800 kg
Velocity = v = 72 km/hr = 20 m/s
Required :
Momentum = P = ?
Formula:
P = mv
Solution:
P = (800)(20)
P = 16,000 kgm/s
Answer:
Explanation:
Momentum = Mass × Velocity
Mass = 800 kg
Velocity = 72 km/hr = 20 m/s
∴ Momentum = 800 × 20
= 16000 kgm/s
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A tub has a mass of 0.650 kg and 0.350 kg of rocks are put in it. It floats in fresh water with the top of the tub level with the water line. What is the volume of the tub? PLEASE HELP!!!
Answer: 0.001m^3
Explanation:
Given the following :
Mass of tub = 0.650kg
Mass of rock = 0.350kg
In this scenario:
Upthrust is the weight of fluid displaced
Upthrust = Total weight of tub (since the tub floats, and top of tub is level with the water line )
Recall Weight = mass * acceleration due to gravity(g)
g = 9.8m/s
Total mass = (0.650 + 0.350)kg = 1kg
Weight = 1kg × 9.8m/s = 9.8N
Upthrust = 9.8N
Recall: Upthrust = Density × acceleration due to gravity(g)× displaced body volume of fluid
Density of water = 1000kg/m^3
g = 9.8m/s^2
9.8N = 1000 × 9.8 × Volume
9.8 = 9800V
V = 9.8 / 9800
V = 0.001m^3
Answer:
0.001
Explanation:
acellus
A flat polished area is turned through 15 degrees. If the angle of incidence is 20 degrees, what is the angle between the incident ray and the reflected ray of the turned surface?
Answer:
50°Explanation:
Angle of rotation of the flat polished surface [tex]\theta[/tex] = 15°
angle of incidence i = 20°
Since the polished surface is turned at an angle of 15°, the angle of reflection
r = 2[tex]\theta[/tex] (Note that the angle of rotation only have effect of the angle of reflection)
r = 2*15 = 30°
The angle between the reflected ray and the incident ray will be equal to the sum of the angle of incidence and the angle of reflection i.e i+r
The angle between the reflected ray and the incident ray = 20°+ 30° = 50°