I need help on this problem.

Answer:

x^2+7x +49/4 and (x+7/2)^2

x^2+bx +b²/4 and  (x+b/2)^2

Step-by-step explanation:

Given the expression

x^2+7x+c

We need to find the constant that completes the expression

Take the half of the cpeffiecient of x = 7/2

Taking the square of the result

Square of the result  = (7/2)^2

Hence c = (7/2)^2

The expression becomes;

x^2 + 7x + (7/2)^2

= x^2+7x +49/4

= (x+7/2)^2

For x^2+bx+d

We need to find the constant that completes the expression

Take the half of the cpeffiecient of x = b/2

Taking the square of the result

Square of the result  = (b/2)^2

Hence d = (b/2)^2

The expression becomes;

x^2 + bx + (b/2)^2

= x^2+bx +b²/4

= (x+b/2)^2

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