4 5 6 7 8 9 10 TIME REMAINING 35:22 Triangle KNM is shown. Triangle K N M is shown. Angle M K N is 25 degrees. Angle K N M is 130 degrees. Angle N M K is 25 degrees. What is true about the sides of KNM? KN = NM KN + NM = KM KM = 2(NM) KN = One-halfKM Mark this and return
Answer:
KN = NM
Step-by-step explanation:
Given that:
In a triangle KNM
angle ∠ MKN = 25°
angle ∠ KNM = 130°
angle ∠ NMK = 25°
The objective is to determine what is true about the side of KNM.
The correct option is:
KN = NM
From the above, we will see that two angles are equal, which implies the triangle is likely to be an isosceles triangle. An isosceles triangle is a triangle that has two equal angles and sides.
Thus, the intersection of NK with KM is at an angle of 25°, so do NM and KM. We can thereby conclude that the two sides are equal in length provided that they possess the same angles and they intersect at the line at the same angle.
Answer: (A)
Step-by-step explanation: trust me!
What is the translation for this graph? O (X-4, Y-3)
O (X-3. y - 4)
O (X-3. y. 4)
O (X- 4. y-3)
Answer:
wow dis might take a while to solve
In the diagram of circle A, what is the measure of
ZXYZ?
35°
70°
75°
140°
Using the intersecting secant theorem:
Angle xyz = 1/2( wz- XX)
Xyz = 1/2(175-105)
Xyz = 1/2(70)
Xyz= 35
The answer is 35 degrees
The measure of <XYZ is 35 degrees
Circle geometryTo find the measure of<XYZ, we will use the expression as shown below:
The angle at the vertex is half the difference of the intercepted arcs
<XYZ = 1/2(175 - 105)
<XYZ = 1/2(70)
<XYZ = 35 degrees
Hence the measure of <XYZ is 35 degrees
Learn more on geometry here: https://brainly.com/question/24375372
Point G ia on line segment FH Given FG = 5x + 2 GH = 3x -1 and FH = 9 determine the numerical length of FG
Answer:
Step-by-step explanation:
FG=7
Crude oil Imports to one country from another for 2009-2013 could be approximated by the following model where t is time in years since the start of 2000,
(1) --33428001 - 1,000 thousand barrels per day (9 st s 13)
According to the model, approximately when were oil imports to the country greatest? HINT (See Example 1) (Round your answer to two decimal places.)
How many barrels per day were imported at that time? (Round your answer to two significant digits.)
thousand barrels
Answer:
Time = approximately mid 2012Oil import rate = 3600 barrelsStep-by-step explanation:
Unclear part of the questionI(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13) According to the model, approximately when were oil imports to the country greatest? t = ? SolutionGiven the quadratic function
The vertex of a quadratic function is found by a formula: x = -b/2aAs per given function:
b = 800, a = -35Then
t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13This time is approximately mid 2012.
Considering this in the function, to get oil import rate for the same time:
l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285Rounded to two significant figures, the greatest oil import rate was:
3600 barrelsDetermine the measure of each angle. Then describe each angle as acute, right, obtuse, or straight.
How hard is 6th grade math?
Answer:
super easy i can help you whenever
Step-by-step explanation:
im in high and i had As in 6th
Answer:
a little hard you just have to understand it
Step-by-step explanation:
Solve 5x - (2x - 1) = 2, Answer is a decimal round to the hundredth (2 digits) or use / for fraction bar.
5x - (2x - 1) = 2
Distribute the - sign.
5x - 2x + 1 = 2
Combine like terms.
3x + 1 = 2
Subtract 1 from both sides.
3x = 1
Divide both sides by 3
x = 1/3 or 0.33
A store offers customers a 40% discount on the price of x of selected items. Then, the store takes off an additional 16% at the cash register. Write a price function P(x) that computes the final price of the item in terms of the original price x.
P(x) = ?
Answer:
x-40%-16%
Step-by-step explanation:
help me please. 15 POINTS BRAINLEST ANSWER EVER (y+4)–(y–1)=6y
Answer:
5/6
Step-by-step explanation:
y+4-y+1=6y
5=6y
y=5/6
Solution for (y+4)-(y-1)=6y equation:
Simplifying
(y + 4) + -1(y + -1) = 6y
Reorder the terms:
(4 + y) + -1(y + -1) = 6y
Remove parenthesis around (4 + y)
4 + y + -1(y + -1) = 6y
Reorder the terms:
4 + y + -1(-1 + y) = 6y
4 + y + (-1 * -1 + y * -1) = 6y
4 + y + (1 + -1y) = 6y
Reorder the terms:
4 + 1 + y + -1y = 6y
Combine like terms: 4 + 1 = 5
5 + y + -1y = 6y
Combine like terms: y + -1y = 0
5 + 0 = 6y
5 = 6y
Solving5 = 6y
Solving for variable 'y'.Move all terms containing y to the left, all other terms to the right.
Add '-6y' to each side of the equation.
5 + -6y = 6y + -6y
Combine like terms: 6y + -6y = 0
5 + -6y = 0
Add '-5' to each side of the equation.
5 + -5 + -6y = 0 + -5
Combine like terms: 5 + -5 = 0
0 + -6y = 0 + -5
-6y = 0 + -5
Combine like terms: 0 + -5 = -5
-6y = -5
Divide each side by '-6'.
y = 0.8333333333
Simplifying
y = 0.8333333333
Find the x-intercept of the graph of the linear equation y = -1/2 x+3.
Help me please!!
Due soon!!
Answer:
6
Step-by-step explanation:
got it right
Can someone do this for me? I will give brainliest!
Answer:look it up on quizlet
Step-by-step explanation:
whats - 1/64 as cubed
Answer: 1/4
Step-by-step explanation:
What is the number of solutions in this system?
one solution
no solution
infinitely many solutions
First answer is Brainlyist
compare these numbers
Answer:
[tex]-3.97621,\ -2.5,\ 2\frac{1}{4},\ \sqrt{11},\ 3.\overline{6}[/tex]
Step-by-step explanation:
√11 is about 3.32.
Smallest-to-largest, the numbers are ...
[tex]-3.97621,\ -2.5,\ 2\frac{1}{4},\ \sqrt{11},\ 3.\overline{6}[/tex]
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t) = -4.9t^2 + 148 t + 227. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? The rocket splashes down after 32 seconds. How high above sea-level does the rocket get at its peak? The rocket peaks at meters above sea-level.
Answer:
A.) 24.08 seconds
B.) 825.42 metres
Step-by-step explanation:
function of time is given as
h ( t ) = − 4.9 t 2 + 118 t + 115 .
Where a = -4.9, b = 118, c = 115
Let's assume that the trajectory of the rocket is a perfect parabola.
The time t the rocket will reach its maximum height will be at the symmetry of the parabola.
t = -b/2a
Substitute b and a into the formula
t = -118/-2(4.9)
t = 118/9.8
t = 12.041 seconds
Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.
2t = 2 × 12.041 = 24.08 seconds
Therefore, the rocket splashes down after 24.08 seconds.
B.) At maximum height, time t = 12.041s
Substitute t for 12.041 in the function
h ( t ) = − 4.9 t 2 + 118 t + 115
h(t) = -4.9(12.041)^2 + 118(12.041) + 115
h(t) = -4.9(144.98) + 118(12.041) + 115
h(t) = -710.402 + 1420.82 + 115
h(t) = 825.42 metres
Therefore, the rocket get to the peak at 825.42 metres
Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)
Answer:
[tex]f_x(x,y,z)=4\sin (y-z)[/tex]
[tex]f_x(x,y,z)=4x\cos (y-z)[/tex]
[tex]f_z(x,y,z)=-4x\cos (y-z)[/tex]
Step-by-step explanation:
The given function is
[tex]f(x,y,z)=4x\sin (y-z)[/tex]
We need to find first partial derivatives of the function.
Differentiate partially w.r.t. x and y, z are constants.
[tex]f_x(x,y,z)=4(1)\sin (y-z)[/tex]
[tex]f_x(x,y,z)=4\sin (y-z)[/tex]
Differentiate partially w.r.t. y and x, z are constants.
[tex]f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)[/tex]
[tex]f_y(x,y,z)=4x\cos (y-z)[/tex]
Differentiate partially w.r.t. z and x, y are constants.
[tex]f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)[/tex]
[tex]f_z(x,y,z)=4x\cos (y-z)(-1)[/tex]
[tex]f_z(x,y,z)=-4x\cos (y-z)[/tex]
Therefore, the first partial derivatives of the function are [tex]f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)[/tex].
A small pebble has a mass of
about
20 L
b.
20 ml
20 g
20 kg
d.
Answer:
20g
since mass should be in kg or gram if small then g
One of the most spectacular and least known hummingbirds is the Marvelous Spatuletail, Loddigesia mirabilis, found in only in a single remote valley in northern Peru (see photo below). In this valley the mean density is 3 spatuletails per 100-hectare quadrat. (a) What is the probability a random quadrat contains less than 3 spatuletails
Answer:
P(x < 3) = 0.42319
Step-by-step explanation:
From the given information:
The mean density [tex]\lambda =[/tex] 3
Let x be the random variable that follows a Poisson distribution.
Therefore:
[tex]\mathtt{P(x) = \dfrac{e^{-\lambda} \lambda ^x}{x!}}[/tex] for x =1, 2, 3...
However, the probability that a random quadrat contains less than 3 spatuletails can be computed as:
[tex]\mathtt{P(x <3 ) = \dfrac{e^{-3}3 ^0}{0!}+ \dfrac{e^{-3}3 ^1}{1!}+ \dfrac{e^{-3} 3 ^2}{2!} }[/tex]
[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix} \dfrac{3 ^0}{0!}+ \dfrac{3 ^1}{1!}+ \dfrac{3 ^2}{2!} \end {pmatrix} }[/tex]
[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix} \dfrac{1}{1}+ \dfrac{3 }{1}+ \dfrac{9}{2} \end {pmatrix} }[/tex]
[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix} 1+3+ 4.5 \end {pmatrix} }[/tex]
[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix}8.5 \end {pmatrix} }[/tex]
P(x < 3) = 0.42319
The table shown below displays the distance that students on a track team walked during after-school practice.
Student
Distance (Miles)
John
2.75
Paul
2
Sierra
1.4
Anastasia
31
What was the total distance, in miles, that the students walked during after-school practice?
5.1436 rounded to the nearest tenth
Answer:
5.1
Step-by-step explanation:
we have
5.1436
since 4 is less than five we cannot pass the 1 to 2
so it stays like
5.1
118 meters in 2 seconds, how many meters in 11 seconds?
Answer:
It would be 649
Step-by-step explanation:
118 ÷ 2= 59
59 x 11= 649
Answer:
649m
Step-by-step explanation:
[tex]\frac{118m}{2s} =\frac{59m}{s}[/tex]
so that 59m/s we multiply by 11s
[tex]\frac{59m}{s} (11s)=649m[/tex]
Aaron is a high school graduate working as a retail clerk. He earns a median salary for a high school graduate. Aaron is thinking about going to college to get an associate's degree. If he completes his degree in 2 years and college costs total $30,000, how long will it take Aaron to recover his investment, assuming that he earns the median salary and continues to work full time while he is attending school? A graph titled Median Annual Household Income by Educational Attainment of Householder, 1997. Professional degree, 92,228 dollars; doctorate degree, 87,232 dollars; master's degree, 68,115 dollars; Bachelor's degree or more, 63,292 dollars; Bachelor's degree, 59,048 dollars; associate degree, 45,258 dollars; some college, no degree, 40,015 dollars; high school graduate, 33,779 dollars; ninth to twelfth grade, 19,851 dollars; than twelfth grade, 15,541 dollars. a. about 2.5 years b. about 5.5 years c. about 8.5 years d. about 11.5 years
Answer:
i would say c
Step-by-step explanation:
Solve the equation t+ 25 =26
Answer:
t = 1
Step-by-step explanation:
t + 25 = 26
Subtract 25 from each side
t = 1
Given f(x)=3x-1 find f(-1)
Answer:
f( - 1) = - 4Step-by-step explanation:
f(x) = 3x - 1
To find f(-1) substitute the value of x that's
- 1 into f(x). That's for every x in f(x) replace it with - 1 and solve
That's
f( - 1) = 3(-1) - 1
= - 3 - 1
We have the final answer as
f(-1) = - 4Hope this helps you
What is one equivalent ratio for 1/3
Answer: 2/6
Step-by-step explanation:
Answer:
[tex]\frac{2}{6}[/tex]
Step-by-step explanation:
In order to create an equal ratio to [tex]\frac{1}{3}[/tex], we need to find a constant to multiply both the numerator and the denominator by.
Let's do 2.
[tex]1\cdot 2 = 2\\\\3\cdot 2 = 6\\\\[/tex]
So:
[tex]\frac{2}{6}[/tex]
Hope this helped!
An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining. A sample of 71 brakes using Compound 1 yields an average brake life of 41,628 miles. A sample of 31 brakes using Compound 2 yields an average brake life of 36,379 miles. Assume the standard deviation of brake life is known to be 4934 miles for brakes made with Compound 1 and 4180 miles for brakes made with Compound 2. Determine the 98% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval.
Answer:
98% Confidencce Interval is ( 3030.6, 7467.4 )
Step-by-step explanation:
Given that:
Sample size [tex]n_1 =[/tex] 71
Sample size [tex]n_2 =[/tex] 31
Sample mean [tex]\overline x_1 =[/tex] 41628
Sample mean [tex]x_2 =[/tex] 36,379
Population standard deviation [tex]\sigma_1[/tex] = 4934
Population standard deviation [tex]\sigma_2 =[/tex] 4180
At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02
Critical value at [tex]z_{0.02/2} = 2.33[/tex]
The Margin of Error = [tex]z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }[/tex]
= [tex]2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }[/tex]
= [tex]2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }[/tex]
= [tex]2.33 \times \sqrt{906504.06 }[/tex]
= 2218.40
The Lower limit = [tex]( \overline x_1 - \overline x_2) - (Margin \ of \ error)[/tex]
= ( 41628 - 36379 ) - ( 2218.40)
= 5249 - 2218.40
= 3030.6
The upper limit = [tex]( \overline x_1 - \overline x_2) + (Margin \ of \ error)[/tex]
= ( 41628 - 36379 ) + ( 2218.40)
= 5249 + 2218.40
= 7467.4
∴ 98% Confidencce Interval is ( 3030.6, 7467.4 )
Which one of these shapes is not like the other and why?
A and B is not, because if you were to make the A bigger it'll be the same as B, so I think is C
What is the value of -3.5
Answer:
[tex]3.5[/tex]
Step-by-step explanation:
The value of [tex]|-3.5|[/tex] is [tex]3.5[/tex], because you have [tex]|-3.5|[/tex] and it will change to [tex]3.5[/tex] by the absolute value, which it turned from negative to a positive.
For which values of a the system has no solution: x≤5, x≥a
Given:
The system of inequalities is
[tex]x\leq 5[/tex]
[tex]x\geq a[/tex]
To find:
The values of a for which the system has no solution.
Solution:
We have,
[tex]x\leq 5[/tex] ...(1)
It means the value of x is less than or equal to 5.
[tex]x\geq a[/tex] ...(2)
It means the value of x is greater than or equal to a
Using (1) and (2), we get
[tex]a\leq x\leq 5[/tex]
But if a is great than 5, then there is no value of which satisfies this inequality.
Therefore, the system has no solution for a>5.