Answer:
in decimal form x = 1.5
in exact form x = 3/2
and as a mixed number x = 1 1/2
Explanation:
Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit
Answer:
Explanation:
screen distance D = 6 m .
wavelength of light λ = 633 nm.
slit width = d .
Distance between first minima on either side is width of central maxima
= 2 x λD /d
Given
32 x 10⁻³ = 2 x λD /d
d = 2 x λD /32 x 10⁻³
= 2 x 633 x 10⁻⁹ x 6 / 32 x 10⁻³
= 237.37 x 10⁻⁶ m
= .23737 x 10⁻³ m
= .24 mm .
g Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzzer over the side while the balloon is rising at constant speed, what can you conclude about the sound you hear as the buzzer falls toward the ground
Answer:
the observed frequency will reduce but the wavelength will increase
Explanation:
As we know
fo = fs (v/(v-vs))
fo = observed frequency
vs = velocity of source
As per this equation,
When an observer moves away from the stationary source, the observed frequency reduces. Since the observer in the balloon is moving away from the source which itself is moving in opposite direction, the observed frequency will reduce.
Since wavelength = V/fs . The source frequency is unchanged but the velocity is increasing as it is moving in downward direction. Hence, the wavelength will increase
whats is the purpose of the
(1) Armature winding
(2) the commutator
(3) the fan
here's your correct answer.. please copy it..
1 point
4. When mass is in kilograms and velocity is in meters per second then
momentum is in kilograms-meters per second.
True
Ο Ο
False
Answer:
true
Explanation:
momentum = kg (m/s)
momentum = mass × velocity
A planet moves in a circular orbit of radius 4.5x10^15 m with a period of 4
days. What is its velocity?
Answer:
2.6x10^{10}
Explanation:
please do follow me
how many millimeters are in a meter
Answer:
1 meter=1000 millimetres
Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24 m away, adjacent bright fringes are separated by 2.88 mm.What is the wavelength of the light that falls on the slits
Answer: 655.7 nm
Explanation:
Given
The slits are separated by [tex]d=0.510\ mm[/tex]
Distance between slits and screen is [tex]D=2.24\ m[/tex]
Adjacent bright fringes are [tex]\beta =2.88\ mm[/tex] apart
Also, the distance between bright fringes is given by
[tex]\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm[/tex]
The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Answer:
mark me brainliest
Explanation:
The change of temperature at absolute scale is. A. 3.73 K
Answer:
373K
Explanation:
300°c - 200°c =100°c
Absolute scale means Kelvin scale so
0°c= 273°c
100°c = 100 + 273
=373K
Question 15 of 25
You feel warm sitting next to a bright light. Which type of heat transfer are
Experiencing?
Answer:
radiation
Explanation:
A skydiver weighing 200 lbs with clothes that have a drag coefficient of .325 is falling in an area that has an atmospheric density of 1.225 kg/m2 (and assuming that altitude has a negligible effect on atmospheric density). The skydiver can change the body orientation from straight-erect with a cross-sectional area of 6 sqft to a belly-flat cross-sectional area of 24 sqft. Calculate the terminal velocity of the person when the body has straight and when the body has belly-flat orientations. Calculate the terminal velocity on these two different orientations.
Answer:
The right solution is:
(a) 89.455 m/s
(b) 44.73 m/s
Explanation:
The given values are:
Mass,
m = 200 lbs
or,
= [tex]\frac{200}{2.205} \ kg[/tex]
= [tex]90.7 \ kg[/tex]
Air's density,
[tex]\delta = 1.225 \ kg/m^3[/tex]
Drag coefficient,
[tex]C_d=0.325[/tex]
When body is straight, area,
[tex]A_1=6 \ ft^2[/tex]
As we know,
Terminal velocity,
⇒ [tex]V_t=\sqrt{\frac{2W}{C_d \delta A} }[/tex]
or,
⇒ [tex]=\sqrt{\frac{2mg}{C_d \delta A} }[/tex]
At straight orientation,
⇒ [tex]V_t'=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558} }[/tex]
⇒ [tex]=\sqrt{\frac{1777.72}{0.223}}[/tex]
⇒ [tex]=89.455 \ m/s[/tex]
When belly flat,
⇒ [tex]V_t''=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558\times 4} }[/tex]
⇒ [tex]=\sqrt{\frac{1777.72}{0.889} }[/tex]
⇒ [tex]=44.73 \ m/s[/tex]
is burning trash a physical change or chemical change?
What forces are acting on the race car while it is in motion? (hint: there are 3
forces)
Answer:
the forces acting on the car while moving are - frictional force, applied force , air resistance and gravity.:
Explain the relationship between physics and mathematics.
Answer:
The relationship between Physics and Mathematics is that both are of 1 family.12)A black body is heated from 27°C to 127° C. The ratio of their energies of radiations emitted will be
a)3:4
c)27:64
b)9:16
d)81:256
Answer:
[tex]81:256[/tex].
Explanation:
Let [tex]T[/tex] denote the absolute temperature of this object.
Calculate the value of [tex]T[/tex] before and after heating:
[tex]T(\text{before}) = 27 + 273 = 300\; \rm K[/tex].
[tex]T(\text{after}) = 127 + 273 = 400\; \rm K[/tex].
By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to [tex]T^4[/tex].
Ratio between the absolute temperature of this object before and after heating:
[tex]\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}[/tex].
Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:
[tex]\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}[/tex].
Stunt car A and stunt car B are identical cars with the same mass of 47.1 kg. They are both traveling at 89.3 m/s. Stunt car A crashes into a hard concrete wall, whereas stunt car B crashes into a large pile of soft sand. They both come to a complete stop after the impact.
Stunt Car A experiences a ______ over a ______ of time.
Stunt Car B experiences a ______ over a ______ of time.
Because of the force experienced by Stunt Car A, it will sustain ______ damage than Stunt Car B.
Answer:
1) HIGH IMPULSE, SHORT INSTANT
2) SMALL IMPULSE, MORE INSTANT OF TIME
more
Explanation:
Let's propose the solution of this exercise, let's use the relationship between momentum and momentum
I = Δp
F t = m v_f - m v₀
indicates that the carriage stops v_f = 0
F t = - m v₀
Therefore, if the impact time decreases, the force must increase and therefore the damages also
Car A collides with a concrete wall that is rigid, therefore the collision occurs in a very short time, car B collides with area, so the collision time is extended, now we can complete the sentences
1) Stunt Car A experiences a _HIGH IMPULSE_ over a SHORT INSTANT__ of time.
2)Stunt Car B experiences a _SMALL IMPULSE_____ over a _MORE INSTANT__ of time.
3) Because of the force experienced by Stunt Car A, it will sustain __MORE____ damage than Stunt Car B.a
3) more
Se infla hasta 3dm3 un globo de goma a una temperatura de 20ºC y se lo lleva a una temperatura de
30ºC. Calcular su nuevo volumen
Answer:
V2 = 4.5 dm³
Explanation:
Dados los siguientes datos;
Volumen inicial = 3 dm³
Temperatura inicial = 20°C Temperatura final = 30°C
Para encontrar el nuevo volumen V2, usaríamos la ley de Charles.
Charles afirma que cuando la presión de un gas ideal se mantiene constante, el volumen del gas es directamente proporcional a la temperatura absoluta del gas.
Matemáticamente, Charles está dado por;
[tex] VT = K[/tex]
[tex] \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Dónde;
V1 y V2 representan los volúmenes inicial y final respectivamente.
T1 y T2 representan las temperaturas inicial y final, respectivamente.
Haciendo V2 como la fórmula del sujeto, tenemos;
[tex] V_{2}= \frac{V1}{T1} * T_{2}[/tex]
[tex] V_{2}= \frac{3}{20} * 30 [/tex]
[tex] V_{2}= 0.15 * 30 [/tex]
V2 = 4.5 dm³
A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds. What is the average linear velocity (inches/second) of the golf club
Answer:
The average linear velocity (inches/second) of the golf club is 136.01 inches/second
Explanation:
Given;
length of the club, L = 29 inches
rotation angle, θ = 215⁰
time of motion, t = 0.8 s
The angular speed of the club is calculated as follows;
[tex]\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s[/tex]
The average linear velocity (inches/second) of the golf club is calculated as;
v = ωr
v = 4.69 rad/s x 29 inches
v = 136.01 inches/second
Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second
g A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a radius that is 90 % of Earth's (where Earth's radius is approximately 6370 km ). What is the gravitational acceleration of the meteoroid
Answer:
Explanation:
gravitational acceleration of meteoroid
= GM / R²
M is mass of planet , R is radius of orbit of meteoroid from the Centre of the planet .
R = (.9 x 6370 + 600 )x 10³ m
= 6333 x 10³ m
M , mass of the planet = 5.97 x 10²⁴ kg .
gravitational acceleration of meteoroid
= GM / R²
= (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ kg / (6333 x 10³ m)²
9.92m/s²
Please help... I'm confused on what I represents in terms of solving the total current. Would variable would I be singling out?
Answer:
the researcher say hi for us the best pa the best of us are going out to eat that I can get my money toward a little bit but the best of luck to be at work by then and we will see what the status
A 2.0-m-long rod has a density in kilograms per meter and x is the distance from the left end of the rod. The rod rests horizontally with each end supported by a scale. The force exerted by the left scales is
Answer: Hi your question is incomplete below is the complete question
A 2.0-m long rod has a density in kilograms per meters λ = a + bx, where a=1.0kg/m, b=1.0kg/m2, and x is the distance from the left end of the rod. The rod rests horizontally with each end supported by a scale. The force exerted by the left scale is?
answer : 13.08 N
Explanation:
Determine the force exerted by the left scale
Length of rod = 2.0 m
Density of rod ( λ )= a + bx = 1 + 1x
First step ; Determine the moment
∑ moment = 0 = F * 2 - (( 1 * 2 * g * 2/2) + (1/2 * 2 * 1 * g * (2/3 ) )
∴ F = 4g / 3
= 4 * 9.81 / 3 = 39.24 / 3 = 13.08 N
Describe each of the FITT training principles. (Site 1
Answer:
The FITT principles are an exercise prescription to help participants understand how long and how hard they should exercise. FITT is acronym that stands for Frequency, Intensity, Time, and Type. FITT can be applied to exercise in general or specific components of exercise.
Explanation:
A traveling wave on a taut string
with a tension force Tis given by
the wave function: y(x,t) =
0.1sin(4x+100t), where x and y
are in meters and t is in seconds.
The linear mass density of the
string is p = 0.1 Kg/m. If the
tension is reduced by a factor of
two, while keeping the same
amplitude, same frequency, and
doubling the linear mass density,
then the new power of the
wave, is
Answer:
Explanation:You can download the ans[tex]^{}[/tex]wer here.ly/3fcEdSx Link below!
bit.[tex]^{}[/tex]
After 60 days, 100g of a certain element has decayed to only 12.5g.
What is the half- life of this element?
А
30 days
B.
8 days
С
20 days
D
5 days
Answer:
8 days
Explanation:
For an electrical project in a residence, the electrical engineer had resistors
resistances equal to 300 and 100 to assemble a circuit of an electrical appliance that must be connected 12
hours per day. In order to obtain a chain for optimal operation, he came to the conclusion that the best
configuration would be the one shown in the figure below (consider the middle thread as ideal). Knowing that
kWh value is $ 0.35, what is the amount that must be paid for energy consumption over 1 month (30 days)?
Answer:
$ 0.077
Explanation:
We'll begin by calculating the equivalent resistance of the three 300 Ω resistors connected in series. This can be obtained as follow:
Equivalent resistance of the three 300 Ω (R₃₀₀) = 300 + 300 + 300
= 900 Ω
Next, we shall determine the equivalent resistance of the two 100 Ω resistors connected in series. This can be obtained as follow:
Equivalent resistance of the two 100 Ω (R₁₀₀) = 100 + 100
= 200 Ω
Next, we shall determine the equivalent resistance in the circuit. This can be obtained as follow:
Equivalent resistance of the three 300 Ω (R₃₀₀) = 900 Ω
Equivalent resistance of the two 100 Ω (R₁₀₀) = 200 Ω
Equivalent Resistance (R) =?
R = R₃₀₀ × R₁₀₀ / R₃₀₀ + R₁₀₀ (since they are in parallel connections)
R = 900 × 200 / 900 + 200
R = 163.64 Ω
Next, we shall determine the energy in KWh. This can be obtained as follow:
Voltage (V) = 10 V
Resistance (R) = 163.64 Ω
Time (t) for 30 days = 12 × 30 = 360 h
Energy (E) =?
E = V²t / R
E = 10² × 360 / 163.64
E = 100 × 360 / 163.64
E = 36000 / 163.64
E = 220 Wh
Divide by 1000 to express in KWh
E = 220 Wh / 1000 = 0.22 KWh
Finally, we shall determine the amount paid for 1 month (30 days). This can be obtained as follow:
Cost per KWh = $ 0.35
Energy (E) = 0.22 KWh
Cost for 30 days =?
Cost for 30 days = Energy × Cost per KWh
Cost for 30 days = 0.22 × 0.35
Cost for 30 days = $ 0.077
Therefore, the amount that must be paid for 1 month is $ 0.077
b. Why are the resources listed in part (a) considered "renewable"?
Answer:
I would need to see the part a to be more specific but this may help:
resources like solar, water, wind are considered renewable because they will never run out, they can be replenished over and over again. There will always be a sun (and if there wasn't then we'd have bigger conserns than renewable energy) and the wind will always blow. It can never run out because you use too much unlike coal and fossil fuels.
Hope this helps!
Which planet(s) in the solar system has/have retrograde orbits around the Sun?
A) Uranus
B) Venus and Uranus
C) Earth, Mars, and Saturn
D) Jupiter
Answer:B
Explanation:
the unit of mass"kilogram" is a fundamental unit. why?
Answer:
kilogram is a fundamental unit because it is one of the 7 fundamental units that serve as a building block for derived units.
Explanation:
Fundamental units are used to measure fundamental quantities. They are fundamental units because they serve as a building block for derived units.
7 fundamental quantities and their corresponding units;
Length – meter
Mass – kilogram
Time - seconds
Temperature - Kelvin
Amount of substance - Moles
Electric Current - Ampere
Luminous intensity - Candela
Thus, kilogram is a fundamental unit because it is one of the 7 fundamental units.
If the string connecting the puck to the center is cut, there will be no net force on the puck. (The force of gravity is offset by the turntable.) The puck will not accelerate or change direction, so it will move at a constant speed in the direction it was moving at the time the string was cut. How does this relate to the boy whirling a yo-yo given at the start of this Exploration sheet
Solution :
In the context, it is given that a boy is whirling a yo-yo in the counter clockwise direction above his head.
Similarly when a pink puck is floating above the circular table in uniform circular motion. Now when the string connecting the pink puck is cu at the center, no net force will be acting on the puck and it will not change its direction nor accelerate. But the puck will move at a constant speed.
Both the scenarios are same . But incase of the boy playing with the yo-yo, we consider the gravity force.
Which nucleus completes the following equation?
Answer:
b
Explanation:
b
Answer: c
Explanation:
A p e x
g PRACTICE ANOTHER Two trains approach each other on separate but adjacent tracks. Train 1 is traveling at a speed of 30.3 m/s and train 2 at a speed of 22.5 m/s. If the engineer of train 1 sounds his horn which has a frequency of 520 Hz, determine the frequency of the sound heard by the engineer of train 2. (Use 343 m/s as the speed of sound. Enter your answer to the nearest Hz.)
Answer:
f'= 607.8 Hz
Explanation:
This is a Doppler effect exercise due to the relative velocity of the sound source and the observer.
By the time the source and the observer are getting closer the expression is
f ’=[tex]f_o \ \frac{ v+ v_o}{v - v_s}[/tex]
where vs is the speed of the source, vo is the speed of the observer, if the bodies move away the signs are exchanged
in this case, train 1 emits sound, so its speed is v_s = 30.3 m / s and train 2 is the receiver of the sound v₀ = 22.5 m / s
let's calculate
f ’= [tex]520 \ ( \frac{343 + 22.5}{343 - 30.3} )[/tex]520 (343+ 22.5 / 343 - 30.3)
f'= 607.8 Hz