HURRYYYYY, FASTTT, HELPPP What is the consequence of atoms being a singular closed system?


Atoms of a certain element contain a fixed amount of energy.


Atoms of a certain element can’t be altered by outside forces.


Atoms don’t interact with each other in any way.


Atoms decompose slowly over time as they lose energy.


1

Answers

Answer 1

Answer:

Atoms of a certain element contain a fixed amount of energy.

Explanation:

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such defines the structure of a chemical element.

Generally, these atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

Additionally, all the physical properties of a mineral result from the mineral's internal arrangement of atoms.

The consequence of atoms being a singular closed system is that atoms of a certain element contain a fixed amount of energy because the number of protons, neutrons and electrons are in a fixed proportion.


Related Questions

Which DOES NOT happen during the phase change from liquid to solid?

Kinetic energy decreases

Particles move slower

Freezing occurs

Temperature increases

Answers

Answer:

Temperature increases

During the phase transition from liquid to solid, kinetic energy diminishes, particles move slower, and freezing occurs.

Phase change:

Extreme heat is more likely to occur as a result of rising temperatures, and it will last longer. Heatwaves can indeed be deadly, resulting in manifestations including heat kinks and heat exhaustion, as well as death.

Warmer temperatures have the potential to trigger a cascade of other changes around the world.The greenhouse effect is worsened by these gas emissions, which cause the earth's crust temperature to rise. Burning fossil fuels has the greatest impact on climate change of any human activity.

Since in changement from liquid to solid the temperature will decrease.Therefore, the final answer is "Temperature increases".

Find out more about the phase change here:

brainly.com/question/11490613

A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second.

Answers

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2               ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1                  ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

he inductance of a tuning circuit of an AM radio is 4 mH. Find the capacitance of the circuit required for reception at 1200 kHz.

Answers

Answer:

4.4pF

Explanation:

the capacitance of the circuit required for reception is given:

wL =  [tex]\frac{1}{wC}[/tex]

w = 2π [tex]f[/tex]

Using both equation

Capacitance is given

C =   1 - 4π2  f2 L

1- 4×9.8969×144×10 10 ×0.004

​=4.4pF

A student measured the density of Galena to be 7.9g/cm3 however the known density of Galena is 7.6g/cm3 . Calculate the percent error of the measurements.

Answers

7.9/7.6-1=3.9%
.............

Answer:

~4%

Explanation:

% = |(7.6 - 7.9)|/7.9

= 0.3/7.9 ≈ 0.04 = 4%

A cat dozes on a stationary merry-go-round, at a radius of 7.0 m from the center of the ride. The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 6.9 s. What is the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding

Answers

Answer:

0.6

Explanation:

Given that :

Radius, R = 7m

Period, T = 6.9s

The Coefficient of static friction, μs can be obtained using the relation :

μs = v² / 2gR

Recall, v = 2πR/T

μs becomes ;

μs = (2πR/T)² / 2gR

μs = (4π²R² / T²) ÷ 2gR

μs = (4π²R² / T²) * 1/ 2gR

μs = 4π²R / T²g

μs = 4π²*7 / 6.9^2 * 9.8

μs = 28π² / 466.578

μs = 276.34892 / 466.578

μs = 0.5922887

μs = 0.6

Select the correct answer.
In general, how does an increase in distance from the Sun affect a planet?
ОА. .
The amount of sunlight the planet receives decreases.
OB.
The gravitational force exerted by the Sun increases.
ОС.
The thickness of a planet's atmosphere increases.
OD. The planet's atmosphere absorbs more heat.

Answers

Answer:

a.

gravity decreases by distance

thickness doesn't change

Less heat.

Most stars are _____ compared to the sun.

slightly smaller

much bigger

much smaller

slightly bigger

Answers

Most stars are much smaller compared to the sun.

A 40.0 kg block of lead is heated from -25°C to 200°C.
How much heat is absorbed by the lead block?

A. 2,354,000 J
B. 1,170,000 J
C. 56,891 J
D. 10,650 J

Answers

Answer:

B. 1,170,000 J

Explanation:

Given;

mass of lead block, m = 40 kg

initial temperature, t₁ = -25 ⁰C

final temperature, t₂ = 200 ⁰C

The heat absorbed the lead block is calculated as;

H = mcΔt

where;

c is the specific heat capacity of lead =  130 J/kg⁰C

H = 40 x 130 x (200 - (-25))

H = 40 x 130 x (200 + 25)

H = 40 x 130 x 225

H = 1,170,000 J

Therefore, the heat absorbed the lead block is 1,170,000 J

Attempt 2 You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 15151515 lb and was traveling eastward. Car B weighs 11251125 lb and was traveling westward at 42.042.0 mph. The cars locked bumpers and slid eastward with their wheels locked for 17.517.5 ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.7500.750 . How fast (in miles per hour) was car A traveling just before the collision

Answers

Answer:

v = 28.98 ft / s

Explanation:

For this problem we must solve it in parts, let's start by looking for the speed of the two cars after the collision

In the exercise they indicate the weight of each car

          Wₐ = 1500 lb

          W_b = 1125 lb

Car B's velocity from v_b = 42.0 mph westward, car A travels east

let's find the mass of the vehicles

             W = mg

             m = W / g

             mₐ = Wₐ / g

             m_b = W_b / g

             mₐ = 1500/32 = 46.875 slug

             m_b = 125/32 = 35,156 slug

Let's reduce to the english system

             v_b = 42.0 mph (5280 foot / 1 mile) (1h / 3600s) = 61.6 ft / s

We define a system formed by the two vehicles, so that the forces during the crash have been internal and the moment is preserved

we assume the direction to the east (right) positive

initial instant. Before the crash

           p₀ = mₐ v₀ₐ - m_b v_{ob}

final instant. Right after the crash

           p_f = (mₐ + m_b) v

the moment is preserved

           p₀ = p_f

           mₐ v₀ₐ - m_b v_{ob} = (mₐ + m_b) v

           v = [tex]\frac{ m_a \ v_{oa} - m_b \ v_{ob} }{ m_a +m_b}[/tex]

we substitute the values

           v = [tex]\frac{ 46.875}{82.03} \ v_{oa} - \frac{35.156}{82.03} \ 61.6[/tex]

           v = 0.559 v₀ₐ - 26.40                  (1)

Now as the two vehicles united we can use the relationship between work and kinetic energy

the total mass is

              M = mₐ + m_b

              M = 46,875 + 35,156 = 82,031 slug

starting point. Jsto after the crash

              K₀ = ½ M v²

final point. When they stop

             K_f = 0

The work is

             W = - fr x

the negative sign is because the friction forces are always opposite to the displacement

Let's write Newton's second law

Axis y

           N-W = 0

           N = W

the friction force has the expression

            fr = μ N

we substitute

            -μ W x = Kf - Ko

             

            -μ W x = 0 - ½ (W / g) v²

            v² = 2 μ g x  

            v = [tex]\sqrt{ 2 \ 0.750 \ 32 \ 17.5}[/tex]Ra (2 0.750 32 17.5  

            v = 28.98 ft / s

A typical laboratory centrifuge rotates at 4000 rpm. Testtubes have to be placed into a centrifuge very carefully because ofthe very large accelerations.
Part A) What is the acceleration at the end of a test tubethat is 10 cm from the axis of rotation?
Part B) For comparison, what is the magnitude of theacceleration a test tube would experience if dropped from a heightof 1.0 m and stopped in a 1.0-ms-long encounter with a hardfloor?

Answers

Answer:

A)  a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²

Explanation:

Part A) The relation of the test tube is centripetal

               a_c = v² / r

the angular and linear variables are related

              v = w r

we substitute

               a_c = w² r

let's reduce the magnitudes to the SI system

              w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s

               r = 1 cm (1 m / 100 cm) = 0.10 m

let's calculate

              a_c = 418.88² 0.1

               a_c = 1.75 10⁴ m / s²

part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor

as part of rest the initial velocity is zero and on the floor the height is zero

                v² = v₀² - 2g (y- y₀)

                v² = 0 - 2 9.8 (0 + 1)

                v =√19.6

                v = -4.427 m / s

now let's look for the applied steel to stop the test tube

                v_f = v + a t

                0 = v + at

                a = -v / t

                a = 4.427 / 0.001

                a = 4.43 10³ m / s²

A metal pot feels hot to the touch after a short time on the shove. what type of material is the metal pot

Answers

The answer is Copper

Help me with both questions please?

Answers

Answer:

1. They all accelerate at the same rate.

2.The object travels at a constant velocity throughout the fall.

Explanation:

Earths gravitational pull is at a constant 9.08 m/s^2. so when objects are free falling, the objects in question can only fall so fast before it would break gravity so to speak.

HELP PLEASE DUE IN 3 MINUTES

Answers

Answer:

Tectonic Plate Movement

Explanation:

Each continent and ocean sits on its own tectonic plate which floats on the Earths upper mantle. They move very little over time.

Answer:

tectonic plates movement

PLEASE ANSWER THIS WILL MARK AS BRAINLIEST PLEASE USE TRUTHFUL ANSWERS PLEASE



Which best explains why species living in Australia are found nowhere else on Earth? This is an example of Geologic Evolution.

A.
Australia has an ecosystem different from any other area on Earth.

B.
Humans have genetically altered many Australian species in laboratories.

C.
Australian species were genetically altered after a comet hit the landmass.

D.
Australia separated from other continents and species there evolved independently.

Answers

Australia separated from other continents and species there evolved independently

Sound waves rely on matter to transmit their energy. They cannot ravel in a vacuum. True or false

Answers

Answer:

false

Explanation:

Answer:

Hello,

QUESTION)True,

Sound travels in a material medium, in space, there is no matter, so sound cannot propagate.

In terms of their location, what is the difference between subcutaneous fat and visceral fat

Answers

Subcutaneous fat is the fat that lies under the skin and isn’t necessarily harmful to your health and visceral fat is the harmful unseen fat surrounding the organs.

explain why radiation is dangerous for humans

Answers

Answer:

because it affects the attom in living things

Radiation is dangerous to humans as it can result in long-term health effects such as cancer and cardiovascular disease.

A 2000-kg elevator is at rest when its cable breaks. The elevator falls 26 m before it encounters a giant spring at the bottom of the elevator shaft. As the elevator falls, its safety clamp applies a constant frictional force of 17,000 N. 1. List all the forces acting on the elevator after the cable breaks but before it hits the spring. Determine the work done by each force on the elevator. Make sure these work terms have the appropriate signs (positive or negative). 2. Calculate the net work done on the elevator. 3. Use the work-kinetic-energy theorem to determine the speed of the elevator right before it encounters the spring. 4. After the elevator encounters the spring, the spring compresses by 0.6 m before the elevator comes to rest. The safety clamp continues to apply a constant 17,000 N force. List all the forces acting on the elevator while it falls this final 0.6 m. 5. For each force listed in question F4, determine an expression for the work it does on the elevator. Make sure each work term has the appropriate sign (positive or negative). 6. Use the work-kinetic-energy theorem to determine the value of the spring constant k.

Answers

Explanation:

work done =force *distance

work done =17000*26

work done=442,000 joules.

A spring in a toy gun has a spring constant of 10 N/m and can be compressed 4 cm.
It is then used to shoot a 1 g ball out of the gun. Find the velocity of the ball as it
leaves the gun

Answers

F=ma
We know from this that a=10,000m/s2

V=at
X=vt


You end up with v^2=ax

Plug in 10,000 and 0.04 and solve for v =20m/s

)) What do these two changes have in common?
mixing chocolate syrup into milk
rain forming in a cloud
) Select all that apply.
Both involve chemical bonds breaking.
Both are changes of state.
Both are only physical changes.
Both are chemical changes.

Answers

Answer:

Both are only physical changes

Explanation:

A physical change is a change that does not involve or alter the chemical composition of the substances involved. Physical changes form no new substance and can be easily separated into individual constituents. Example of physical changes are change in state, boiling, melting etc.

According to this question, two processes were given as follows:

1. mixing chocolate syrup into milk

2. rain forming in a cloud

These two processes are similar in the sense that they are both examples of physical changes.

You are tasked with calibrating the springs for a pinball machine. Your method of testing the springs is by attaching masses onto the end of the springs and measuring the stretch from initial position to final position. You hang a 14kg mass on a spring and notice that it stretches from 50 to 78cm. What is the spring constant for that spring

Answers

Answer:

[tex]490.5\ \text{N/m}[/tex]

Explanation:

m = Mass attached to spring = 14 kg

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

x = Displacement of spring = [tex]78-50=28\ \text{cm}[/tex]

k = Spring constant

The force balance of the system is given by

[tex]kx=mg\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{14\times 9.81}{0.28}\\\Rightarrow k=490.5\ \text{N/m}[/tex]

The spring constant for that spring is [tex]490.5\ \text{N/m}[/tex].

Let's assume raspberries are 10 wt% protein solids and the remainder water. When making jam, raspberries are crushed and mixed with sugar, in a 45:55 berry to sugar ratio, by mass. Afterward, the mixture is heated, boiling off water until the remaining mixture is 0.4 weight fraction water, resulting in the final product, jam. How much water, in kilograms, is boiled off per kilogram of raspberries processed

Answers

Answer:

The mass of water boiled off is [tex]0.0 \overline{185}[/tex] kg

Explanation:

The given percentage by weight of protein solids in raspberries = 10 weight%  

The ratio of sugar to raspberries in ja-m = 45:55

The mass of the mixture after boiling = 0.4 weight fraction water

Let 's' represent the mass of sugar in the mixture, and let 'r' represent the mass of raspberry

The mass of raspberry, r = 1 kg

The percentage by weight of water in raspberry = 90 weight %

The mass of water in 1 kg of raspberry =  90/100 × 1 kg = 0.9 kg

The ratio of the mass of sugar to the mass of raspberry in jam = r/s = 45/55

∴ s = 1 kg × 55/45 = 11/9 kg

The mass of the mixture before boiling = 1 kg + 11/9 kg = 20/9 kg

The weight fraction of water in the remaining mixture after boiling = 0.4 weight fraction

Let 'w' represent the mass of water boiled off, we have;

(0.9 - w)/(20/9 - w) = 0.4

(0.9 - w) = 0.4 × (20/9 - w)

0.9 - w = 8/9 - 0.4·w

9/10 - 8/9 = w - 0.4·w = 0.6·w = (6/10)·w

(81 - 80)/(90) = (6/10)·w

1/90 = (6/10)·w

w = ((10/6) × 1/90) = 1/54

w = 1/54  

The mass of water boiled off, w = (1/54) kg = [tex]0.0 \overline{185}[/tex] kg

A continental polar air mass forms in
a. the Pacific Ocean.
b. northern Canada.
c.
the Gulf of Mexico.
the desert Southwest.
d.
Please select the best answer from the choices provided
А
B
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my uq xbbbnxnjjxjxusjhhhwhhhnn he c x. Yes suhsjjdhhehy yes eirui
M I was going ask m
Iqijjm.ndjbh

Answers

Answer:

B. Northern Canada

Explanation:

A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)

Read the following statements. Which statement provides the correct definition of weather? Select your answer from the options below. * 1 point
Atmospheric conditions at a specific time in a specific area
Atmospheric conditions over a period of time in a specific area
Average atmospheric conditions over a period of time in a region
Average atmospheric conditions across the world

Answers

Answer:

In one day, a store sells 14 pairs of jeans. The 14 jeans represent 20% of the total number of items sold that day. How many items did the store sell in one day? Explain or show how you got your answer.

plz help with the qsn

Explanation:

You are cooking spaghetti and you look into the pot of boiling water before you put the spaghetti in. You notice the water moving around in the pot. What type of thermal energy transfer occurs to heat the water?

Answers

Answer:

Heat transfer is an exchange of thermal energy between two objects. The rate of heat transfer depends upon the temperatures of each entity and the medium through which the thermal energy is being transferred. In cooking, heat transfer refers to heating your food items through a cooking appliance, such as a stove, fryer, microwave, or oven.

Explanation:

I hope it helps

Answer:

Convection

Convection is heat transfer by mass motion of a fluid such as air or water when the heated fluid is caused to move away from the source of heat, carrying energy with it. Convection above a hot surface occurs because hot air expands, becomes less dense, and rises (see Ideal Gas Law).

Explanation:

hope this helps:-)

when the mass of an object increases, the forcé of gravity

Answers

Answer:

increace

Explanation:

they are both going up

Hi I hope you have a good day today

Two long, straight wires are parallel and 20 cm apart. One carries a current of 2.2 A, the other a current of 5.9 A. (a) If the two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire on the other

Answers

Answer: [tex]1.298\times 10^{-5}\ N/m[/tex]

Explanation:

Given

Current in the first wire [tex]I_1=2.2\ A[/tex]

Current in the second wire [tex]I_2=5.9\ A[/tex]

wires are [tex]20\ cm[/tex] apart

Force per unit length between the current-carrying wires is

[tex]\Rightarrow \dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}[/tex]

Force exerted  by the wires is the same

Put the values

[tex]\Rightarrow \frac{F}{l}=f=\dfrac{4\pi \times 10^{-7}\times 2.2\times 5.9}{2\pi \times 0.2}=1.298\times 10^{-5}\ N/m[/tex]

This force will be repulsive in nature as the current is flowing opposite

help meee plisssssssssssssssssssssssssssss

Answers

Answer:

Resistance = 0.22 Ohms

Current = 13.63636 A

Explanation:

Total resistance for resistors in parallel is given by:

[tex]\frac{1}{T} =\frac{1}{R1} +\frac{1}{R2} +...+\frac{1}{Rn}[/tex] where n is the number of resistors

[tex]\frac{1}{T} = \frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1} +\frac{1}{1.1}[/tex]

if you solve that you get [tex]\frac{1}{T} = 5/1.1 \\\\T = 1.1/5T = 0.22 Ohms[/tex]

Solve current using V=IR

I=V/R =

I=3/0.22

I = 13.63636 A

A wave where the oscillation is parallel to the motion is a _______ wave
A-standing
B-longitudinal
C-transverse

Answers

A wave where the oscillation is parallel to the motion is a longitudinal wave

why do the stars rotate​

Answers

Answer:

Angular momentum

Explanation:

Stars are formed as a result of a collapse of a low-temperature cloud of gas and dust. During the colapse conservation of angular momentum causes any small net rotation of the cloud to increase thus forcing the material into rotating

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