How to do these two questions? ​

Answer:

Step-by-step explanation:

Remark

I have to assume that you know calculus. It is the only way the problem can be done that I know of. If you don't, I'm not sure how you will do this.

The curve is of y  = e^(-2x) + x^2 - 3

The curve crosses the y axis when x = 0. The y value is

y = e^0 + x^2 - 3

yint = 1 + 0 - 3

yint = -2

The slope at point (0,-2) is

y' = -2e^(-2x) +2x

y' = -2 at point A

Therefore the normal will have a slope

m1 * m2 = - 1

The slope of the curve C  at A = -2

The equation of the tangent line at A = -2x - 2

Call this m1

m2 = slope of the normal

-2 * m2 = -1

m2 = 1/2

Equation of the line (l) =

y = 1/2 x  - 2

The graph is shown below. Notice the two lines actually look like they are at a 90 degree angle.

Answer:

See below.

Step-by-step explanation:

So we have the two functions:

[tex]f(x)=5x+4\text{ and } g(x)=-2x+1[/tex]

1)

First, find the values of each function:

[tex]f(x)=5x+4\\f(6)=5(6)+4\\f(6)=30+4=34[/tex]

[tex]g(x)=-2x+1\\g(-8)=-2(-8)+1\\g(-8)=16+1=17[/tex]

Therefore:

[tex]f(6)+g(-8)\\=(34)+(17)=51[/tex]

2)

Plug in the number into the function:

[tex]g(x)=-2x+1\\g(4)=-2(4)+1=-8+1=-7[/tex]

3)

Like the last one:

[tex]f(x)=5x+4\\f(-2)=5(-2)+4=-10+4=-6[/tex]

Answer:

the firsts third and last one

Step-by-step explanation:

hope this helped

Answer: A

Step-by-step explanation:

Answer:

(7×x)+14

Step-by-step explanation: Because we have 14 added to something, we will need a + to whatever we are adding to. The product of 7 and a number is 7×x because product is the number you get after multiplication. So we get 7×x+14. You dont need parenthesis

Hope this helps!

Hey there! I'm happy to help!

PART A

Let's look at our two equations.

y=3x-5

y=6x-8

We will solve this with substitution because we have two different values for y, so it will be be very easy to substitute.

We know that y is equal to 6x-8. This means that we can replace the y in the first equation with 6x-8 and then solve for x.

6x-8=3x-5

We add 8 to both sides.

6x=3x+3

We subtract 3x from both sides.

3x=3

We divide both sides by 3.

x=1

We can plug this x-value into either of our equations to figure out what y is.

y=6(1)-8

y=6-8

y=-2

Therefore, our solution is x=1 and y= -2.

PART B

When graphing the two equations in a systems of equation, the point where they intersect is the solution. We already have our solution, so now we will just write it as a point, which is (1,-2).

Have a wonderful day! :D

Answer:

see below

Step-by-step explanation:

y = 3x − 5

y = 6x − 8

I will use substitution by substituting for y in the first equation

y = 3x − 5

6x -8 = 3x-5

Subtract 3x from each side

6x-3x -8 = 3x-5-3x

3x-8 = -5

Add 8 to each side

3x-8+8 = -5+8

3x =3

Divide by 3

3x/3= 3/3

x =1

Now find y

y = 3x − 5

  = 3(1) -5

  =3-5

  = -2

( 1,-2)

The two lines will intersect at ( 1,-2)

The solution to the two equations is where the lines intersect.

Answer:

35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle [tex]\triangle PQR[/tex] where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And [tex]\angle Q \neq 90^\circ[/tex]

Given that:

PQ = 44 ft

PR = 51 ft

[tex]\angle R = 58^\circ[/tex]

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

[tex]\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/tex]

Where  

a is the side opposite to [tex]\angle A[/tex]

b is the side opposite to [tex]\angle B[/tex]

c is the side opposite to [tex]\angle C[/tex]

[tex]\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ[/tex]

Now,

[tex]\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ[/tex]

Let us use the Sine rule again:

[tex]\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft[/tex]

So, the answer is 35.11 ft.

Answer:

m∠C = 102°

Step-by-step explanation:

This is a quadrilateral inscribed in a circle

The sum of opposite angles in a cyclic quadrilateral is equal to 180°

m∠D + m∠B = 180°

m∠B = 180° - m∠D

m∠B = 180° - 80°

m∠B = 100°

We know what m∠B

We have external angles outside the circle.

m∠CDA is opposite m∠B

m∠CDA = 2 × m∠B

m∠CDA = 2 × 100°

m∠CDA = 200°

m∠CDA is the sum of m∠CD and m∠DA

m∠CDA = m∠CD + m∠DA

m∠DA = m∠CDA - m∠CD

m∠DA = 200° - 116°

m∠DA = 84°

m∠DAB is an exterior angle also, hence,

m∠DAB is the sum of m∠DA and m∠AB

m∠DAB = m∠DA + m∠AB

m∠DAB = 84° + 120°

m∠DAB = 204°

Finally we can solve for m∠C

m∠DAB is Opposite m∠C

So, m∠C = 1/2 × m∠DAB

m∠C = 1/2 × 204

m∠C = 102°

Answer:

The answer is option D.

Step-by-step explanation:

Hi, there!!!

Here, if you closely look this figure, you will find that AB and CD are interested at a point O.

now, OP is just a line constructed from point "O".

now, 2x°+4x°=150°.....is equation.

{Because, They are vertically opposite angle}

When two st. line intersects at a point then the abgle formed oppositely are equal.

Hope it helps..

Answer:

Evaluate each expression inside both grouping symbols, then multiply the result.

Step-by-step explanation:

[tex]\displaystyle (3 - 1)(4 + 2) = (2)(6) = 12[/tex]

G - Grouping Symbols

E - Exponents

M\D - Division & Multiplication [left to right]

S\A - Subtraction & Addition [right to left OR vice versa]

I am joyous to assist you at any time.

Answer:

m = -3/2

Step-by-step explanation:

To find the slope of the representation, use the slope formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

I'll pick (-4, 9) and (-2, 6) in this instance.

[tex]m=\frac{9-6}{-4-(-2)}\\\\m=-\frac{3}{2}[/tex]

Therefore, the slope of the representation is -3/2.

Answer:

-3/2

Step-by-step explanation:

To find the slope, we can use the formula

m = ( y2-y1)/(x2-x1)

    = ( -6 -9)/(6 - -4)

    = (-6-9)/(6+4)

     -15/10

  -3/2

Answer:

Kindly check explanation

Step-by-step explanation:

SMALL SIZE :

AMOUNT OF LIQUID = 250 milliliters

Sales price = $4.50

Cost per milliliter :

Sales price / amount of liquid

$4.50 / 250 = $0.018

MEDIUM SIZE :

AMOUNT OF LIQUID = 500 milliliters

Sales price = $9.95

Cost per milliliter :

Sales price / amount of liquid

$9.95 / 500 = $0.0199

= $0.020 ( 3 decimal places)

LARGE SIZE :

AMOUNT OF LIQUID = 1 LITRE = 1000 milliliters

Sales price = $16.95

Cost per milliliter :

Sales price / amount of liquid

$16.95 / 500 = $0.0199

= $0.01695

= $0.017 ( 3 decimal places)

A) LARGE < SMALL < MEDIUM

B) LEAST EXPENSIVE WAY TO BUY 1500 milliliters of green cleaner :

1 large size + 2 small sizes

$16.95 + 2($4.50)

$16.95 + $9.00

= $25.95

C.) MOST EXPENSIVE WAY TO BUY 1500 milliliters of green cleaner :

3 medium sizes

3 * ($9.95)

$29.85

Answer:

12 months

Step-by-step explanation:

mental math

Answer:

Step-by-step explanation:

An example of a negative correlation is tv viewing and student test grades.

Another example is the video game playing and test grades

Answer:

The answer to this question is (D)

Answer:

2, 18/b

Step-by-step explanation:

if you divide by the number of bags you will get the number of cookies in each bag.

Answer:2,18/b

Step-by-step explanation:If you multiply the cookies in a bag by b, you will get 18

From the given information; Let the unknown different positive integers be (a, b, c and d).

An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.

Suppose we make an assumption that (a) should be the greatest value of this integer.

Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.

Therefore, the average of this integers = 9

Mathematically;

[tex]\mathbf{\dfrac{(a+b+c+d)}{4} =9}[/tex]

[tex]\mathbf{\dfrac{(a+1+2+3)}{4} =9}[/tex]

[tex]\mathbf{\dfrac{(6+a)}{4} =9}[/tex]

By cross multiplying;

6+a = 9 × 4

6+a = 36

a = 36 - 6

a = 30

Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.

Learn more about integers here:

https://brainly.com/question/15276410?referrer=searchResults

The greatest value for one of the four positive integers is 30.

To find the largest positive integer, you have to minimize the other three positive integers.

Find the average of the four positive integers and equate it to the given value of the average.

[tex]\frac{6 + y}{4} = 9\\\\6+ y = 36\\\\y = 36-6\\\\y = 30[/tex]

Thus, the greatest value for one of the positive integers is 30

learn more here: https://brainly.com/question/20118982

Answer:

Lets start with the top row.

First, add the two values.

5+14=19

Now, divide each value by the total.

5/19=0.26315789473

Round the decimal to the nearest hundredth.

5/19=0.26

14/19=0.73684210526

Round it to the nearest hundredth.

14/19=0.74

Now, The second row.

Add the two values.

16+7=23

Divide the first value by the total.

16/23=0.69565217391

Round it to the nearest hundredth.

16/23=0.70

Divide the second value by the total.

7/23=0.30434782608

Round to the nearest hundredth.

7/23=0.30

Done!

Answer:

Row 1: 0.26 0.74

Row 2: 0.70 0.30

Step-by-step explanation:

Khan

Answer:

B

Step-by-step explanation:

The points where f(x) intersects g(x) are - 4 and 2.5. These points are the solution of the equation f(x)=g(x)

Answer:

(-4,8) and ( 2.5, -8)

Step-by-step explanation:

The solutions are where the two graphs intersect

They intersect at x = -4  and y = 8   and at x = 2.5  and y = -8

(-4,8) and ( 2.5, -8)

Answer:

A. 10

Step-by-step explanation:

As we know that

The length of the major axis of the ellipse is 10

i.e

2 a = 10

Also, the ellipse is the curve that consists of 2 focal points  in order that the total of the distance to the 2 focal points would remain constant for each and every point displayed in the curve

Now we assume that P is the curve point

So,

PF1 + PF2

i.e

2 a (blue line) + (red line)

2 a = 10

Therefore the sum of the length is 10

Answer:

10

Step-by-step explanation:

Answer:

D) 9

Step-by-step explanation:

These angles are equal to each other because they’re alternate interior angles so:

9x + 8 = 15x - 46

9x - 15x = -46 - 8

-6x = -54

x = 9

Answer:

D because even though the flat fee is 150 paying 5$ a hour it will cost less

Answer:

Option (B)

Step-by-step explanation:

From the picture attached,

F1 and F2 are the focii of the hyperbola.

Point P(x, y) is x units distant from F1 and y units distant from the other focus F2.

By the definition of a hyperbola,

"Difference between the distances of a point from the focii is always constant and equals to the measure of transverse axis."

Difference in the distances of point P from focii F1 and F2 = (x - y) units

This distance is equal to the length of the transverse axis = (x - y) units

Therefore, Option (B) will be the answer.

Answer:

x-y

Step-by-step explanation:

Answer:

Does the answer help you?

Answer: $120

First, create a function

[tex]\left \{ {{5a+b=45} \atop {12a+b=80}} \right.\\\\(5-12)a+(1-1)b=45-80\\\\-7a=-35\\\\a=\frac{-35}{-7} =5\\\\5a+b=45\\\\5(5)+b=45\\\\b=45-25=20[/tex]

Therefore, the function is y = 5x + 20

To find the amount of money at week 20, set x = 20 and solve:

[tex]y=5(20)+20=100+20=120[/tex]

Therefore, the answer is $120.

Using Pythagorean theorem

[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]

[tex]\\ \sf\longmapsto P^2=11^2-9^2[/tex]

[tex]\\ \sf\longmapsto P^2=121-81[/tex]

[tex]\\ \sf\longmapsto P^2=40[/tex]

[tex]\\ \sf\longmapsto P=\sqrt{40}[/tex]

[tex]\\ \sf\longmapsto P=6.2cm[/tex]

Step-by-step explanation:

Given,

Hypotenuse = 11 cm

Base (One of the given leg) = 9 cm

Therefore,

According to Pythagoras Theorem,

[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]

[tex] = > {(9)}^{2} + {height}^{2} = {(11)}^{2} [/tex]

[tex] = > {height}^{2} = {(11)}^{2} - {(9)}^{2} [/tex]

[tex] = > {height}^{2} = 121 - 81[/tex]

[tex] = > {height}^{2} = 4 0[/tex]

[tex] = > height = \sqrt{40} [/tex]

=> height = 6.3245553203

When rounded to nearest tenth,

=> height = 6.3

Hence,

Required length of other leg is 6.3 (Ans)

[tex]\\ \sf \longmapsto 1+6+(-8)[/tex]

[tex]\\ \sf \longmapsto 1+6+(-8)[/tex]

[tex]\\ \sf \longmapsto 1+6-8[/tex]

[tex]\\ \sf \longmapsto 7-8[/tex]

[tex]\\ \sf \longmapsto -1[/tex]

option c is correct

Answer:

$7520.55

Step-by-step explanation:

Cost of truck = $8000

Residual value = $1000

Estimated useful life = 7 years

Depreciation = (cost of asset - salvage value) / useful life

Depreciation = (8000 - 1000) / 7

Depreciation = 7000 / 7

Depreciation = $1000

Truck was purchased on July 9, Therefore, Depreciation by the end of year one will be;

Number of days between July 9 and year end = 175 days

Daily Depreciation = $1000 / 365 = $2.739

Total Depreciation by year end = (daily Depreciation * 175 days) = $479.45.

Book value at the end of year 1 = (8000 - 479.45)

= $7520.55

Answer:

The answer is "$7,500".

Step-by-step explanation:

Formula:

In the month of July-December the depreciation:

[tex]\frac{\text{Cost-Residual}}{\text{Useful life}}\times \frac{6}{12} \\[/tex]

Cost-Residual= costs -residual value

Given:

Cost-Residual = $8, 000 - $ 1,00

                        = $7,000

Useful life= 7 years

Put the value in the above-given formula:

[tex]=\frac{7 000}{7}\times \frac{6}{12}\\\\= 1 000\times \frac{1}{2}\\\\= 5 00\\[/tex]

Therefore, the book value on point at the end of one year is:

= $8,000 -$ 500

= $7,500

Answer:

I used to know this not anymore sry g

Answer:

x = -1.29 and -2.71

Step-by-step explanation:

Use the quadratic formula, which is [tex]x=\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] and [tex]x=\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{-8+\sqrt{8^2-4(2)(7)} }{2(2)}[/tex] and [tex]\frac{-8-\sqrt{8^2-4(2)(7)} }{2(2)}[/tex]

[tex]\frac{-8+\sqrt{8} }{4}[/tex] and [tex]\frac{-8-\sqrt{8} }{4}[/tex]

Further reduced down to:

[tex]\frac{-8+2\sqrt{2} }{4}[/tex] and [tex]\frac{-8-2\sqrt{2} }{4}[/tex]

In decimal form, to the hundredths place, both of these are:

-1.29 and -2.71