Answer:
Every 11 years The solar cycle is the cycle that the Sun's magnetic field goes through approximately every 11 years.
Explanation:
Our Sun is a Large ball of electrically-charged hot gas. This charged gas moves, generating a powerful magnetic field. The Sun's magnetic field goes through a cycle, called the solar cycle.
Every 11 years or so, the Sun's magnetic field completely flips. This means that the Sun's north and south poles switch places. Then it takes about another 11 years for the Sun’s north and south poles to flip back again.
The solar cycle affects activity on the surface of the Sun, such as sunspots which are caused by the Sun's magnetic fields. As the magnetic fields change, so does the amount of activity on the Sun's surface.
Hope this helps!
Brain-List?
What color is seen when cyan light is shown on magenta paper
Answer:
blue
You see white. What happens when you shine cyan light on a magenta shirt? You see blue.
Explanation:
A sodium ion, Na+ , has a positive charge because it
A. gained an electron.
B. lost a proton.
C. gained a neutron.
D. lost an electron.
D. lost an electron
because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration
proof that the kinetic energy of a moving body is half mv square
Answer:
1
Explanation:
6. The temperature at which water molecules have the
LEAST amount of thermal energy is!
a. 0°C b. 32°F c.-273 K d. 0 k
NEEEED THUs now
8.
Billiard ball A, mass 0.17 kg, is moving due east with a velocity of 4.0
m/s. It strikes stationary billiard ball B, which has the same mass. After
the collision, ball A moves at an angle of 30° north of east with a
velocity of 3.5 m/s. Ball B moves at an angle of 60° south of east.
What is the speed of ball B?
Answer:
2 m/s
Explanation:
The momentum of the colliding system is conserved . Therefore, the velocity of the ball B with the same mass as A is 0.52 m/s.
What is momentum ?Momentum of a body is the ability to bring the applied force makes maximum displacement. it is the product of mass and velocity. For a collision, the sum of initial momentum of the two bodies is equal to the sum of their final momentum.
Thus, u be the initial velocity and v be the final velocity.
Then, m1 u1+ m2 u2 = m1 v1 + m1 v2
m1 = 0.17 kg
u1 = 4 m/s
m2 = 0.17 kg
u2 = 0
Then initial momentum = 0.17 × 4 m/s + 0 = 0.68 kg m/s
v1 = 3.5 m/s
0.68 kg m/s = (0.17 × 3.5 m/s ) + (0.17 × v2)
then v2 = 0.52 m/s.
Therefore, the velocity of ball B after collision will be 0.52 m/s.
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A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted by the source?
Answer:
Please see below as the answer is self-explanatory.
Explanation:
The visible range extends roughly from 400 nm (violet) to 700 nm (red).Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.The wavelengths in the range of 650 to 690 nm have red as the dominant color.Question 6
2 pts
Jenny loves puffed rice cereal. As she is pouring the cereal, two little pieces of cereal each with
equal charges of 1.85 x10-18 coulombs fall into the bowl 0.025 meters apart. Use Coulomb's Law
to find the electrostatic force between them. (Remember, Coulomb's constant is 8.99 x10
N*m²/C2)
4.9 x 10-23 N
6.2 x 10-15 N
9.0 x 10-3N
2.5 x 10-23 N
Answer:
4.9 x 10-23 N
Explanation:
I took the test
Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular aluminum plates, each 20 cm in diameter, separated by 1.0 cm. How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, the field that causes a spark is at the high end of the range pre- sented in the chapter; assume a value of 3 * 106 N/C.
Answer:
Q = 0.83 μC
Explanation:
Assuming that plates are much larger than the distance between them, we can think the electric field as constant and perpendicular to the outer surface of the plates.Applying Gauss' law to a rectangular surface half inside one of the plates and half outside it, since E and A are parallel each other, and E is zero on the other three faces, we can find the following expression for the electric field created by the charge on the plate:[tex]E = \frac{Q*A}{\epsilon_{0} } (1)[/tex]
Solving for Q, replacing E by the maximum electric field that doesn't cause the dielectric strength to break (3*10⁶ N/C), we get:[tex]Q_{max} = E_{max} * \pi *\frac{d^{2}}{4} *\epsilon_{0} = 3e6N/C*\pi *\frac{(0.2m)^{2} }{4} * 8.85e-12C2/Nm2 = 0.83\mu C (2)[/tex]
Why could the beam of particles not have a neutral charge?
Answer:
The positive and negative charges balance each other. Overall, the atom is uncharged (neutral). However, if something happens to make an atom lose or gain an electron then the atom will no longer be neutral. An atom that gains or loses an electron becomes an ion.
Explanation:
I think this is the answer : D
Universal Gravitation Problem Set
Highlight Given information in GREEN. Highlight what you are solving for in YELLOW.
Formula: Fg= G*M,*M,/d? G= 6.67 * 10-11 N*M°/Kg?
The distance between Earth and its moon is 3.84 x 10 meters. Earth's mass is
m = 5.98 x 1024 kilograms and the mass of the moon is 7.36 x 1022 kilograms.
What is the force between Earth and the moon?
Answer:
The force between Earth and the moon is 1.99x10²⁶ N.
Explanation:
The force between Earth and the moon can be found using the Gravitational Force equation:
[tex] F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} [/tex]
Where:
d: is the distance between Earth and the moon = 3.84x10⁵ m
G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²
[tex]m_{E}[/tex]: is the Earth's mass = 5.98x10²⁴ kg
[tex]m_{m}[/tex]: is the moon's mass = 7.36x10²² kg
Hence, the force is:
[tex] F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.98\cdot 10^{24} kg*7.36\cdot 10^{22} kg}{(3.84\cdot 10^{5} m)^{2}} = 1.99 \cdot 10^{26} N [/tex]
Therefore, the force between Earth and the moon is 1.99x10²⁶ N.
I hope it helps you!
Need help guys please
Answer:
6.378 * 10^6 m
Explanation:
Radius = 6378 km
Changing in metres
6378 km = 6378000 m
Now in scientific notation
= 6.378 * 10 ^ 6 m
14. Convert 22 degrees celsius to fahrenheit.
Please show your work
Answer:71.6 F
Explanation:
(22 x 9/5) + 32
A3 kg mass takes some impulse in order increase its velocity from 11
m/s to 25 m/s. Calculate the impulse it took.
Answer:
JAKSJAKZNPWLAQJZOAKZONZPW
THE ANSWER IS FAILURE
whk is thefounder of pakistan?
Answer:
Muhammad Ali Jinnah (Urdu: محمد علی جناح; born Mahomedali Jinnahbhai; 25 December 1876 – 11 September 1948) was a barrister, politician and the founder of Pakistan.
17. If ice has a density of 0.92g/cm?, what is the mass of a 30 cm block?
I
Answer:
Mass = 27.6 grams
Explanation:
Given the following data;
Density of ice = 0.92g/cm³
Volume = 30cm³
To find mass of ice;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Making mass the subject of formula, we have;
[tex] Mass = density * volume [/tex]
[tex] Mass = 0.92 * 30 [/tex]
Mass = 27.6 grams
Therefore, the mass of ice is 27.6 grams.
Beta radiation consists of what type of sub-atomic particle
At what distance from a 0.100 C
charge will the electric field be
10000 N/C?
(Unit = m)
Answer:
Explanation:
[tex]F = k \frac{Q}{r^{2}} \\10000 = 8.99 * 10^{9} * \frac{0.1}{r^{2}} => r^{2} = 8.99 * 10^{5} * 0.1 = 89900 => r = 299.83 m = 300 m[/tex]
Answer:
The answer would be 299.83
Explanation:
Trust
If a 400 watt motor is left on for 10 minutes, assuming no energy is lost to friction, how fast could a 100 kg cart be moving?
Answer:
69.28 m/s
Explanation:
From the question given above, the following data were obtained:
Power = 400 Watt
Time (t) = 10 minutes
Mass (m) = 100 Kg
Velocity (v) =?
Next, we shall convert 10 mins to seconds (s). This can be obtained as follow:
1 min = 60 s
Therefore,
10 mins = 10 × 60
10 mins = 600 s
Next, we shall determine the energy. This can be obtained as follow:
Power = 400 Watt
Time (t) = 600 s
Energy (E) =?
E = Pt
E = 400 × 600
E = 240000 J
Finally, we shall determine how fast the cart is moving. This can be obtained as illustrated below:
Mass (m) = 100 Kg
Energy (E) = Kinetic energy (KE) = 240000 J
Velocity (v) =?
KE = ½mv²
240000 = ½ × 100 × v²
240000 = 50 × v²
Divide both side by 50
v² = 240000 / 50
v² = 4800
Take the square root of both side
v = √4800
v = 69.28 m/s
Thus, the cart is moving with a speed of 69.28 m/s
How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?
image.
A concave lens always produces a(n)
A. inverted
o
B. real
C. virtual
D. magnified
Answer:
Explanation:
Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller
Newton's 3rd Law is based on what type of forces?
Answer: His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.
Explanation:
Explanation:
According to Newton's third law of motion, whenever two objects interact, they exert equal and opposite forces on each other. This is often worded as 'every action has an equal and opposite reaction'.
I need help with this, I can't figure it out.
Here is the link:
https://platform.breakoutedu.com/game/play/fun-in-the-sun-140559-XMWCQF1LPL
Answer:
Star, Triangle, Circle, Rhombus, Square.Left, Down, Right, Down, Up.2,3,2,4.L,O,O,K,I,N,G,F,L,Y.Explanation: You're welcome ✓
Observer A, who is at rest in the laboratory, is studing a particle that is moving through the laboratory at a speed of 0.624c and determines its lifetime to be 159ns a) Obsever A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory? b) Obsever B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
Answer:
a) the markers are 29.76 m far apart in the laboratory
b) According to B, the markers are 23.21 m far apart in the laboratory
Explanation:
Given that;
speed of particle = 0.624c = (0.624 × 3×10⁸m/s)
{ where c is the speed of light}
lifetime of the particle t = 159ns = 1.59 × 10⁻⁷
a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory
lets apply the formula distance = velocity × time
lets substitute
distance = (0.624×3×10⁸ m/s) × (1.59 × 10⁻⁷ s)
distance = 29.76 m
Therefore, the markers are 29.76 m far apart in the laboratory
b) Observer B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
lifetime of the particle t = 124ns = 1.24 × 10⁻⁷
distance = (0.624×3×10⁸ m/s) × (1.24 × 10⁻⁷ s)
distance = 23.21 m
Therefore, According to B, the markers are 23.21 m far apart in the laboratory
write any three applicataion pressure in our daily life ?
Answer:
because the gravity of the earth
200 newtons x 50 meters =
Answer:
10,000J
Explanation:Joules is the si unit for work. To find work you must multiply
the force by the distance. force is measured in Newtons. 200N(Force)x50meters(distance)=10,000J(amount of work) plz mark brainliest.
A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 458 N and have a center of gravity that is 1.34 m above the floor. His upper legs weigh 120 N and have a center of gravity that is 0.766 m above the floor. Finally, his lower legs and feet together weigh 89.8 N and have a center of gravity that is 0.204 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.
Answer:
the location of the center of gravity for the entire body is 1.08 m
Explanation:
Given the data in the question;
w1 = 458 N, y1 = 1.34 m
w2 = 120 N, y2 = 0.766 m
w3 = 89.8 N, y2 = 0.204 m
The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.
so,
[tex]Y_{centre of gravity}[/tex] = (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )
so we substitute in our values
[tex]Y_{centre of gravity}[/tex] = (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )
[tex]Y_{centre of gravity}[/tex] = 723.9592 / 667.8
[tex]Y_{centre of gravity}[/tex] = 1.08 m
Therefore, the location of the center of gravity for the entire body is 1.08 m
A 16 g ball at the end of a 1.4 m string is swung in a horizontal circle. It revolves once every 1.09 s. What is the magnitude of the string's tension?
Answer and I will give you brainiliest
Answer:
6.56
Explanation:
frequency = 1/1.09 = 0.92 Hz
f = 1/(2L) × √T/m
0.92 = 1/2(1.4) × (√T/√16)
0.92 = 0.36 × (√T)/4
multiply all through by 4
3.68 = 1.44 × √T
√T = 3.68/1.44 = 2.56
T = 2.56² = 6.56
The magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton
Given the data in the question;
Mass of the ball;[tex]m = 16g = 0.016kg[/tex]String is swung in a horizontal circle, Radius; [tex]r = 1.4m[/tex]Period of revolution; [tex]T = 1.09s[/tex]Magnitude of the string's tension; [tex]F_T = ?[/tex]First, we need to get magnitude of the centripetal acceleration:
[tex]a_c = \frac{4\pi ^2r}{T^2}[/tex]
We substitute in our given values
[tex]a_c = \frac{4\pi ^2\ *\ 1.4m}{(1.09s)^2} \\\\a_c = 46.519 m/s^2[/tex]
Now, from Newton's Second Law of Motion:
[tex]F = m\ * \ a[/tex]
Where F is the force, m is the mass of the object and a is the acceleration
We substitute into the equation to get the magnitude of the string's tension.
[tex]F = 0.016kg \ *\ 46.519m/s^2[/tex]
[tex]F = 0.744 kg.m/s^2\\\\F = 0.744 N[/tex]
Therefore, the magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton
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A force of 350 N is applied to an object that accelerated at a rate of 5 m/sec2. What is the mass of the object
Answer:
7/ m5sec per minute ckvhxrsuvj
Suppose a meteor of mass 2.50 x 1013 kg is moving at 33.0 km/s relative to the center of the Earth and strikes the Earth. Suppose the meteor creates the maximum possible decrease in the angular speed of the Earth by moving toward the west and striking a point on the equator tangentially. What is the change in the angular speed of the Earth due to this collision
Answer:
change is imperceptible
w_f = 7.272 10⁻⁵ rad / s
Explanation:
For this exercise we can use the conservation of angular momentum.
Initial. Before the crash
L₀ = I w₀
final. After the crash
L_f = I w_f + p r
where the moment is
p = mv
As the system is formed by the two bodies, the forces during the impact are internal, therefore the angular momentum is conserved
L₀ = L_f
I w₀ = I w_f + m v r
w_f = w₀ - [tex]m \frac{ v \ r }{I}[/tex]
We can approximate the Earth to a sphere, so its angular momentum is
I = 2/5 M r²
we substitute
w_f = w₀ - [tex]\frac{5 \ m \ v}{2 \ M \ r}[/tex]
We can find the angular velocity of the Earth with the duration of a spin which is the period of one day
w₀ = 2π / T
T = 24 h (3600 s / 1h) = 86 400 s
w₀ = 2π / 86400
w₀ = 7.272 10⁻⁵ rad / s
let's calculate
w_f = 7.27 10⁻⁵ - [tex]\frac{5 \ 250 \ 10^{13} \ 33.0 \ 10^{3} }{ 2 \ 5.98 \ 10^{24} \ 6.37 10^{6} }[/tex]
w_f = 7.272 10⁻⁵ - 1.0829 10⁻¹³
w_f = 7.27199999 10⁻⁵
this change is imperceptible
w_f = 7.272 10⁻⁵ rad / s
A dolphin has a mass of 740 kg. He swims along the water at a velocity of 12 m/s and
jumps out of the water so that he has Gravitational Potential Energy of 53000 J.
How high does the dolphin jump?
Answer:
I dunno
Explanation:
I really wanted to help you, but then I realized i didnt know how to