Answer:
YAYA MAN
Explanation:
PLS ANSWER FAST THIS IS TIME TEST AND WILL GIVE BRANINLY!!!!
Answer using mass m= F divided by a
Also use kilograms {kg}
A tiny aeroplane accelerates at 35 m/ s2 with a force of 20 N. What is the mass of the aeroplane?
Answer:
0.57 kg
Explanation:
We are given that
Force, F=20 N
Acceleration ,a =[tex]35m/s^2[/tex]
We have to find the mass of Aero-plane.
To find the value of mass we will divide the force by acceleration.
We know that
Force, F=ma
Using the formula
[tex]20=m\times 35[/tex]
[tex]\frac{20}{35}=m[/tex]
[tex]m=0.57 kg[/tex]
Hence, the mass of the aero-plane=0.57 kg
Part C
How many combined bits of storage are there on the two tablets?
Answer:
IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T
Explanation:
Answer:
3.2 x10^11 bits of storage
Explanation:
How does the energy from the person's hand get to the last domino?
Answer:
woh its really exist?
Explanation:
cakra
Suman with a mass of 45kg climbs in 3m heigh ladder in 10 seconds. Calculate her power. Plz help me
Answer:
work done=fdcosø
f=mg=450N
d=+3m
ø=180
450×3×cos(180°) power=work done/
time taken
1350×-1 p=135watts
There is a current of 2.95 A in one of the copper wires for 60 seconds. Calculate the charge flow through the wire.
Answer:
177 coulomb
Explanation:
Given data
I=2.95A
T=60
The relationship between current I and quantity of charge Q.
Q=IT
Substitute
Q=2.95*60
Q=177 coulomb
Which examples best demonstrate likely tasks for Legal Services workers? Check all that apply.
Cisco inspects an office building to make sure it meets fire safety regulations.
Gina gathers information about a court case.
Saul oversees inmates at a correctional facility.
Hana interviews and advises a person who has been accused of a crime.
Pamela pursues and arrests a person suspected of a crime.
Dewayne creates the paperwork for a business contract.
Answer:
b. d. f.
Explanation:
Got it right on Edge
Answer:
2. Gina gathers information about a court case.
4. Hana interviews and advises a person who has been accused of a crime.
6. Dewayne creates the paperwork for a business contract.
Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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Hell it’s due soon??
Explanation:
don't know don't know don't know
can someone do this assignment for me about
force
Answer:
Newtons 3sd law
Force = mass × acceleration
3rd photo about momentum
How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?
Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
Suppose 2 C of positive charge is distributed evenly throughout a sphere of 1.27 cm radius. (a) What is the charge per unit volume for this situation? C/m3 (b) Is the sphere insulating or conducting? How do you know? The sphere is conducting. If it were insulating, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is insulating. If it were conducting, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is conducting. If it were insulating, all of the charge would be in the interior of the sphere; not on the surface. The sphere is insulating. If it were conducting, all of the charge would be in the interior of the sphere; not on the surface.
Answer:
a) ρ = 2.33 10⁵ C / m³, b) INSULATING
Explanation:
a) For this exercise we use the important concept of density
ρ = Q / V
The volume of a sphere is
V = 4/3 πr3
V = 4/3 π (1.27 10⁻²)³
V = 8.58 10⁻⁶ m³
let's calculate
ρ = 2 / 8.58 10⁻⁶
ρ = 2.33 10⁵ C / m³
b) in a conductor the charges are mobile, therefore due to electoral repulsion all the charges must concentrate on the surface.
In an insulator the charges are fixed, therefore they are distributed throughout the volume
Consequently the sphere must be INSULATING
Which process causes the transfer of energy by air currents within the Earth's atmosphere?
Answer:
Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface
A student is preparing to take a bath when she realizes the hot water tap in the bathroom is not working. The student goes to the kitchen and prepares 10 of 100°C water to mix with 10 L of 10°C water.
Answer:
(10 L)(100° C) + (90 L)(10°) = (100 L)T
1,000 + 900 = 100T
1,900 = 100T
100T = 1,900
T = 1,900/100
Explanation:
Which of the following wavelengths have the highest frequency? Group of answer choices a.infrared waves b. radio waves c.microwaves d.visible light
b...radio waves answer
Sound waves are a type of compression wave. In a compression wave, we have areas of compaction and also areas of rarefaction. In
the areas of compression, particles are pushed together and in areas of rarefaction, particle spread apart. Sound waves are different
from light waves in several ways and one is in the type of wave. Light waves are transverse waves that have crests or peaks and
troughs or dips. Which model best shows us a light or transverse wave with very high crests and very low troughs?
Answer: C
Explanation:
The model which represents best of transverse wave with very high crests and low troughs is the third graph. Hence, option C is correct.
What is Sound?Sound is a physical perturbation from an equilibrium position that travels through an elastic medium of material. It is also possible to define sound solely subjectively, as that which is regarded by the ear, but this definition lacks clarity and is overly constrictive because it is useful to discuss sounds that are produced by devices other than the human ear, such as dog whistles and sonar hardware, which cannot be done here by the auditory system.
The characteristics of sound waves should be examined first in any study of sound. Transverse and longitudinal waves are the two fundamental forms of waves, and they differ by the direction wherein they move.
The first graph is uniform trough and crest, but the third one has higher crest but lower trough.
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The height of a transverse waves is known as its?
Answer:
amplitude
Explanation:
wave is a called the crest, and the low point is called the trough. For longitudinal waves, the compressions and rarefactions are analogous to the crests and troughs of transverse waves. The distance between successive crests or troughs is called the wavelength. The height of a wave is the amplitude.…
An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
A force of 500N Is applied to a steel wire of goss_sectional area 0.2m2 the tensele stress is a. 2.5x10 1nm-2 b. 1 0x102nm-2 c. 2.5x103nw-3 d. 1.0x103nm-2
Answer:
the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
Explanation:
Given;
applied force, F = 5000 N
cross sectional area of the steel wire, A = 0.2 m²
The tensile stress of the steel wire, is calculated as;
[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]
Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, how much weight can he lift on the car
side of the system, if that piston's area is 3.5
square meters?
F₂ = 1.723 x 10⁸ N
Further explanationGiven
Area of small piston : 0.004 m²
Area of large piston : 3.5 m²
Force 225 N
Required
Force applied
Solution
Pascal Law :
F₁/A₁=F₂/A₂
225/0.004 m² = F₂/3.5² m²
F₂ = 1.723 x 10⁸ N
What is the mathematical relationship between height, mass, gravity, and gravitational potential energy?
If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law
Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
Answer:
the bike
Explanation:
it has less mass than the motorcycle so so it would have more acceleration
Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
Need help ASAP
Will mark BRAINLIST and thanks only for correct answers
1.Which property of AM frequencies allow them to travel over long distances?
-high amplitude
-high energy
-constant velocity
-long wavelength
2.what types of waves do cell phones use?
-radio waves
-gamma rays
-microwaves
If a man with
with long-sighted eye want to
a' text book, what shoðld be the distance between
book and the lens? Give reason
Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain
Answer:
it is somewhat frozen
Explanation:
What is the characteristic that allows an object to have kinetic energy?
An object with a potential energy of 981 J is placed at a height of 2m. What is the mass of the object?
Answer:
the mass of object is 2000
John slides down a hill at a 4 m height initially at rest. If all energy is conserved and friction is excluded, what is John's velocity at the bottom of the ramp?
The velocity at the bottom : v = 8.85 m/s
Further explanationGiven
height of the hill = 4 m
Required
The velocity at the bottom
Solution
The law of conservation energy :
ME₁=ME₂
(PE+KE)₁ = (PE+KE)₂
initially at rest⇒vo=0⇒KE₁=0
At the bottom⇒h=0⇒PE₂=0
So the equation becomes :
PE₁=KE₂
mgh=1/2.mv²
gh = 1/2v²
[tex]\tt v=\sqrt{2gh}[/tex]
v = √2x9.8x4
v = 8.85 m/s
5.Which graph above shows an object's acceleration? 1pt
6. Why did you choose that graph in question above (explain why)? 1pt
a car takes 4 hours to cover a distance if it takes at a speed of 40mph. what should be it's speed to cover the same distance in 1.5 hours
Answer:
Speed = 106.67mph
Explanation:
Let the first motion be A.
Given the following data;
Speed A = 40mph
Time A = 4 hours
To find the distance covered in A;
Distance = speed * time
Distance = 40 * 4
Distance = 160 miles.
To find the speed required to cover the above distance in 1.5 hours;
Speed = distance/time
Speed = 160/1.5
Speed = 106.67mph